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Possibility | Of the five cards with the numbers 6, 7, 8, 9, and 1 written on them, we want to select two cards allowing duplicates. How many possible cases are there? | 15 | [OP_LIST_SOL] 6 7 8 9 1 [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | var_a = 6
var_b = 7
var_c = 8
var_d = 9
var_e = 1
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 2
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = 2
var_l = 1
var_j = int(var_j)
var_k = int(var_k)
for i, elem in enumerate(range(var_k)):
var_l = var_l * (var_j-i)
for i, elem in enumerate(range(var_k)):
var_l = var_l / (i+1)
print(int(var_l)) |
Correspondence | I multiplied a particular number by 1.87, when I should have divided that particular number by 25 and the result of that erroneous calculation was 231.88. Find what the quotient will be when calculated correctly. | 4 | 231.88 1.87 [OP_DIV] 25 [OP_FDIV] | var_a = 231.88
var_b = 1.87
var_c = var_a / var_b
var_d = 25
var_e = var_c // var_d
print(int(var_e)) |
Comparison | Namjoon has fewer marbles than Eunji and also has fewer marbles than Taehyung. Eunji has fewer marbles than Taehyung. Who has the most marbles among them? | Taehyung | [OP_LIST_SOL] Namjoon Eunji Taehyung [OP_LIST_EOL] [OP_LIST_SOL] Namjoon Eunji < Namjoon Taehyung < Eunji Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Namjoon'
var_b = 'Eunji'
var_c = 'Taehyung'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Namjoon'
var_e = 'Eunji'
var_f = '<'
var_g = 'Namjoon'
var_h = 'Taehyung'
var_i = '<'
var_j = 'Eunji'
var_k = 'Taehyung'
var_l = '<'
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_m = 1
var_n = list_c[var_m-1]
print(var_n) |
Possibility | How many three-digit numbers contain all 5, 7, and 8? | 6 | [OP_LIST_SOL] 5 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 5
var_b = 7
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | Find the surface area of a cube made up of 6 squares with a perimeter of 24 centimeters (cm). | 216 | 24 4 [OP_DIV] 24 4 [OP_DIV] [OP_MUL] 6 [OP_MUL] | var_a = 24
var_b = 4
var_c = var_a / var_b
var_d = 24
var_e = 4
var_f = var_d / var_e
var_g = var_c * var_f
var_h = 6
var_i = var_g * var_h
print(int(var_i)) |
Geometry | If a perimeter of a rectangle whose width is 2 centimeters (cm) longer than its length is 16 centimeters (cm), what is its width? | 5 | 16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD] | var_a = 16
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g + var_h
print(int(var_i)) |
Comparison | You are trying to compare the weight of paint and crayons by placing a weight of 100 grams (g) on the scale. Paint is equal to the weight of 3 weights, and crayons are equal to the weight of 5 weights. Get the lighter one between paint and crayons. | paint | [OP_LIST_SOL] paint crayons [OP_LIST_EOL] [OP_LIST_SOL] 100 3 [OP_MUL] 100 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'paint'
var_b = 'crayons'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 100
var_d = 3
var_e = var_c * var_d
var_f = 100
var_g = 5
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | What is the area of a parallelogram with a base of 9.51 centimeters (cm) and a height of 4.8 centimeters (cm)? | 45.65 | 9.51 4.8 [OP_MUL] | var_a = 9.51
var_b = 4.8
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | It is said that at a stationery store, there are more heart patterned postcards than star patterned postcards, and more star patterned postcards than flower patterned postcards. Which pattern has the most postcards in this stationery store? | heart | [OP_LIST_SOL] heart star flower [OP_LIST_EOL] [OP_LIST_SOL] heart star > star flower > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'heart'
var_b = 'star'
var_c = 'flower'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'heart'
var_e = 'star'
var_f = '>'
var_g = 'star'
var_h = 'flower'
var_i = '>'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Arithmetic calculation | There are three numbers 10, 11 and 12. What is the value of second largest number divided by the smallest number? | 1.1 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
var_f = 1
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e / var_g
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Arithmetic calculation | The bottle was full of water. Yooseung drank 2/5 of the water in the bottle and weighed the bottle and found it to be 144 grams (g). After a while, Hansol drank 2/3 of the remaining water and weighed the bottle again and it was 96 grams (g). How many grams (g) would you get if you drank all the water and weighed only the bottle? | 72 | 144 144 96 [OP_SUB] 1 2/5 [OP_SUB] [OP_DIV] 2/3 [OP_DIV] 1 2/5 [OP_SUB] [OP_MUL] [OP_SUB] | var_a = 144
var_b = 144
var_c = 96
var_d = var_b - var_c
var_e = 1
var_f = 0.4
var_g = var_e - var_f
var_h = var_d / var_g
var_i = 0.6666666666666666
var_j = var_h / var_i
var_k = 1
var_l = 0.4
var_m = var_k - var_l
var_n = var_j * var_m
var_o = var_a - var_n
print(int(var_o)) |
Geometry | Two triangles with a base length of 8 centimeters (cm) are joined to form a parallelogram. The area is 78.88 square cm (cm2). What is the height in centimeters (cm) of this parallelogram? | 9.86 | 78.88 8 [OP_DIV] | var_a = 78.88
var_b = 8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | The four-digit number 22AB, when divided by 3, has a remainder of 2, which is a multiple of 5. How many possible A's are there? | 6 | 22AB [OP_GEN_POSSIBLE_LIST] 3 2 [OP_LIST_DIVIDE_AND_REMAIN] 5 [OP_LIST_DIVISIBLE] 22AB A [OP_LIST_FIND_UNK] [OP_LIST_LEN] | var_a = '22AB'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 3
var_c = 2
list_b = []
var_b = int(var_b)
var_c = int(var_c)
if var_c < 0:
var_c = var_c + var_b
for i in list_a:
i = int(i)
if i%var_b == var_c:
list_b.append(i)
var_d = 5
list_c = []
var_d = int(var_d)
for i in list_b:
i = int(i)
if i % var_d == 0:
list_c.append(i)
var_e = '22AB'
var_f = 'A'
var_e = str(var_e)
var_f = str(var_f)
unk_idx = var_e.index(var_f)
list_d = []
for elem in list_c:
elem = str(elem)
list_d.append(int(elem[unk_idx]))
list_d = list(set(list_d))
var_g = len(list_d)
print(int(var_g)) |
Geometry | The perimeter of the rectangle is 54 centimeters (cm), and the horizontal length of the rectangle is 3 centimeters (cm) longer than the vertical length of the rectangle. Find the horizontal length. | 15 | 54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD] | var_a = 54
var_b = 2
var_c = var_a / var_b
var_d = 3
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Arithmetic calculation | I counted the telephone poles between Seokgi's house and Dongmin's house along the way, and there were 20 in total. If the distance between telephone poles is 25 meters (m), how many meters (m) must Seokgi walk to Dongmin's house? (However, there are no telephone poles in front of Seokgi’s house and Dongmin’s house, and the distance from each house to the first telephone pole is 25 meters (m).) | 525 | 20 1 [OP_ADD] 25 [OP_MUL] | var_a = 20
var_b = 1
var_c = var_a + var_b
var_d = 25
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | There is a set of two books, volumes one and two. I bought 3 sets of this book and paid 21,000 won. If the price of the first volume is 300 won more than the price of the second volume, how much is the price of the second volume? | 3350 | 21000 3 [OP_DIV] 300 [OP_SUB] 2 [OP_DIV] | var_a = 21000
var_b = 3
var_c = var_a / var_b
var_d = 300
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Comparison | Jihee used 1 and 1/5 meters (m) for shoelaces, and Hyunji used 8/5 meters (m). Find the answer to who used more shoelaces. | Hyunji | [OP_LIST_SOL] Jihee Hyunji [OP_LIST_EOL] [OP_LIST_SOL] 1 1/5 [OP_ADD] 8/5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jihee'
var_b = 'Hyunji'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
var_d = 0.2
var_e = var_c + var_d
var_f = 1.6
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Correspondence | Which of 12, 14, 15, and 20 is not divisible by 3 and is less than 18? | 14 | [OP_LIST_SOL] 12 14 15 20 [OP_LIST_EOL] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 18 [OP_LIST_LESS] 1 [OP_LIST_GET] | var_a = 12
var_b = 14
var_c = 15
var_d = 20
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
list_c = list(set(list_a) - set(list_b))
var_f = 18
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = 1
var_h = list_d[var_g-1]
print(int(var_h)) |
Arithmetic calculation | There are 58 roses. The number of roses is 15 more than the number of tulips and 25 less than the number of lilies. How many roses, tulips, and lilies are there in total? | 184 | 58 58 15 [OP_SUB] [OP_ADD] 58 25 [OP_ADD] [OP_ADD] | var_a = 58
var_b = 58
var_c = 15
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 58
var_g = 25
var_h = var_f + var_g
var_i = var_e + var_h
print(int(var_i)) |
Geometry | If the area of a rectangular swimming pool is 143.2 square meters (m2) and the length is 4 meters (m), how many meters (m) is the width? | 35.8 | 143.2 4 [OP_DIV] | var_a = 143.2
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | There is a children's book with 220 pages. If Jinwoo wants to read this book in a week, at least how many pages does Jinwoo have to read in a day? | 32 | 220 7 [OP_DIV] 1 [OP_CEIL] | var_a = 220
var_b = 7
var_c = var_a / var_b
var_d = 1
var_e=int(((var_c+9*10**(var_d-2))//(10**(var_d-1)))*10**(var_d-1))
print(int(var_e)) |
Geometry | You have a plank that is 6 meters (m) wide and 4 meters (m) long. Rectangular colored paper measuring 60 centimeters (cm) in width and 20 centimeters (cm) in height was attached to this plank without overlapping. How many sheets of colored paper did you use at this time? | 200 | 6 100 [OP_MUL] 4 100 [OP_MUL] [OP_MUL] 60 20 [OP_MUL] [OP_DIV] | var_a = 6
var_b = 100
var_c = var_a * var_b
var_d = 4
var_e = 100
var_f = var_d * var_e
var_g = var_c * var_f
var_h = 60
var_i = 20
var_j = var_h * var_i
var_k = var_g / var_j
print(int(var_k)) |
Comparison | Which of the three numbers 5, 8, and 4 is the largest? | 8 | [OP_LIST_SOL] 5 8 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] | var_a = 5
var_b = 8
var_c = 4
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
print(int(var_e)) |
Arithmetic calculation | If there are 7 pigs and 6 giraffes, what is the total number of giraffes and pigs? | 13 | 7 6 [OP_ADD] | var_a = 7
var_b = 6
var_c = var_a + var_b
print(int(var_c)) |
Geometry | Two cubes with one edge 5 cm (cm) long were placed in a line to make one cuboid. What is the volume of the cuboid made in cubic centimeters (cm3)? | 250 | 5 5 2 [OP_MUL] [OP_MUL] 5 [OP_MUL] | var_a = 5
var_b = 5
var_c = 2
var_d = var_b * var_c
var_e = var_a * var_d
var_f = 5
var_g = var_e * var_f
print(int(var_g)) |
Comparison | Nine people are standing in a line in order from shortest to tallest. Hoseok stands in the forefront. If you line up again in order from tallest to shortest, what number will Hoseok stand from the front? | 9 | 9 1 [OP_SUB] 1 [OP_ADD] | var_a = 9
var_b = 1
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | My father is 44 years old and my mother is 42 this year. How old is the father when the sum of the ages of the father and mother becomes 100? | 51 | 44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD] | var_a = 44
var_b = 100
var_c = 44
var_d = 42
var_e = var_c + var_d
var_f = var_b - var_e
var_g = 2
var_h = var_f / var_g
var_i = var_a + var_h
print(int(var_i)) |
Geometry | A square was made by arranging pieces of colored paper of the same size, 12 pieces in each width and 12 pieces in each length. How many colored papers are there in the border? | 44 | 12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD] | var_a = 12
var_b = 2
var_c = var_a - var_b
var_d = 4
var_e = var_c * var_d
var_f = 4
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Thirty pieces of tissue, each 25 centimeters (cm) long, were overlapped by 6 centimeters (cm) and attached in a long line. Find the total length in centimeters (cm) of 30 pieces of toilet paper attached. | 576 | 25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD] | var_a = 25
var_b = 25
var_c = 6
var_d = var_b - var_c
var_e = 30
var_f = 1
var_g = var_e - var_f
var_h = var_d * var_g
var_i = var_a + var_h
print(int(var_i)) |
Arithmetic calculation | Hoseok has 2 candies of (A) and 5 candies of (B). How many candies does Hoseok have in all? | 7 | 2 5 [OP_ADD] | var_a = 2
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | The number was supposed to be divided by 2.5, but it is divided by 2 and 2/5 by mistake, resulting in 15/32. What is the correct answer without mistakes? | 0.45 | 15/32 2 2/5 [OP_ADD] [OP_MUL] 2.5 [OP_DIV] | var_a = 0.46875
var_b = 2
var_c = 0.4
var_d = var_b + var_c
var_e = var_a * var_d
var_f = 2.5
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | There are 24 colored pencils, and red colored pencils makes 1/4 of the total. There are 6 more blue colored pencils than the red colored pencils, and the rest are all yellow colored pencils. Find what color pencils you have the most. | blue | [OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_SOL] 24 1/4 [OP_MUL] 24 1/4 [OP_MUL] 6 [OP_ADD] 24 24 1/4 [OP_MUL] 6 [OP_ADD] [OP_SUB] 24 1/4 [OP_MUL] [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'red'
var_b = 'blue'
var_c = 'yellow'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 24
var_e = 0.25
var_f = var_d * var_e
var_g = 24
var_h = 0.25
var_i = var_g * var_h
var_j = 6
var_k = var_i + var_j
var_l = 24
var_m = 24
var_n = 0.25
var_o = var_m * var_n
var_p = 6
var_q = var_o + var_p
var_r = var_l - var_q
var_s = 24
var_t = 0.25
var_u = var_s * var_t
var_v = var_r - var_u
list_b= []
if "/" in str(var_v):
var_v = eval(str(var_v))
list_b.append(var_v)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_w = 1
list_c=list_b.copy()
list_c.sort()
var_x = list_c[-var_w]
var_y = list_b.index(var_x)+1
var_z = list_a[var_y-1]
print(var_z) |
Correspondence | 6/11 of a number is 48. What is 1/8 of the number? | 11 | 48 6/11 [OP_DIV] 1/8 [OP_MUL] | var_a = 48
var_b = 0.5454545454545454
var_c = var_a / var_b
var_d = 0.125
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | If we round 7A7 up to the tens place, we get a value of 730. Find the right value for A. | 2 | 7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK] | var_a = '7A7'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 730
list_b = []
for i in list_a:
if i <= var_b:
list_b.append(i)
var_c = 730
var_d = 10
var_e = var_c - var_d
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = '7A7'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Geometry | What is the volume, in cubic centimeters (cm3), of the largest cube you can make by cutting a rectangular cuboid block of wood that is 15 centimeters (cm) wide, 12 centimeters (cm) long, and 8 centimeters (cm) high? | 512 | [OP_LIST_SOL] 15 12 8 [OP_LIST_EOL] 1 [OP_LIST_MIN] 3 [OP_POW] | var_a = 15
var_b = 12
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[var_d-1]
var_f = 3
var_g = var_e ** var_f
print(int(var_g)) |
Correspondence | There is a number obtained by adding 45 to 159, dividing this by 3, and adding 32. Divide this number by 12 to find the value. | 8.33 | 159 45 [OP_ADD] 3 [OP_DIV] 32 [OP_ADD] 12 [OP_DIV] | var_a = 159
var_b = 45
var_c = var_a + var_b
var_d = 3
var_e = var_c / var_d
var_f = 32
var_g = var_e + var_f
var_h = 12
var_i = var_g / var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Geometry | Find the number of diagonals that can be drawn from one vertex of a dodecagon. | 9 | 12 3 [OP_SUB] | var_a = 12
var_b = 3
var_c = var_a - var_b
print(int(var_c)) |
Arithmetic calculation | Find the remainder when 28 is divided by 10.02. | 7.96 | 28 10.02 [OP_MOD] | var_a = 28
var_b = 10.02
var_c = var_a % var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | There are four whales of (a), (b), (c), and (d). (a) Whales are faster than (b) whales. (b) Whales are faster than (c) whales. (c) Whales are slower than (d) whales. (d) Whales are faster than (a) whales. Which whale is the slowest? | (c) | [OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (b) > (b) (c) > (c) (d) < (d) (a) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
var_c = '(c)'
var_d = '(d)'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = '(a)'
var_f = '(b)'
var_g = '>'
var_h = '(b)'
var_i = '(c)'
var_j = '>'
var_k = '(c)'
var_l = '(d)'
var_m = '<'
var_n = '(d)'
var_o = '(a)'
var_p = '>'
list_b= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_q = len(list_c)
var_r = list_c[var_q-1]
print(var_r) |
Arithmetic calculation | You went to the bank with 25 checks for 1 million won and 8 checks for 100,000 won and put them in your bank account. If there was no money in the account before then, how much money is in the account now? | 25800000 | 100 10000 [OP_MUL] 25 [OP_MUL] 10 10000 [OP_MUL] 8 [OP_MUL] [OP_ADD] | var_a = 100
var_b = 10000
var_c = var_a * var_b
var_d = 25
var_e = var_c * var_d
var_f = 10
var_g = 10000
var_h = var_f * var_g
var_i = 8
var_j = var_h * var_i
var_k = var_e + var_j
print(int(var_k)) |
Geometry | What is the total number of vertices in a tetrahedron? | 4 | 3 1 [OP_ADD] | var_a = 3
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Comparison | Jungkook has the number 6 minus 3, Yoongi collected 4, and Yuna collected 5. Who has the smallest number? | Jungkook | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d - var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | When the older brother is 10, the younger brother is 7 years old, and when the younger brother is 5 years old, the mother is 32 years old. Find the sum of the ages of the younger brother and mother when the older brother is 12 years old. | 45 | 12 7 10 [OP_SUB] [OP_ADD] 12 7 10 [OP_SUB] [OP_ADD] 32 5 [OP_SUB] [OP_ADD] [OP_ADD] | var_a = 12
var_b = 7
var_c = 10
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 12
var_g = 7
var_h = 10
var_i = var_g - var_h
var_j = var_f + var_i
var_k = 32
var_l = 5
var_m = var_k - var_l
var_n = var_j + var_m
var_o = var_e + var_n
print(int(var_o)) |
Comparison | I listed the numbers of 2.38, 2.83, and 2.401 in descending order. What number comes in the second? | 2.4 | [OP_LIST_SOL] 2.38 2.83 2.401 [OP_LIST_EOL] 2 [OP_LIST_MAX] | var_a = 2.38
var_b = 2.83
var_c = 2.401
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Geometry | There is a rectangle with a length of 5.4 centimeters (cm) and an area of 48.6 square centimeters (cm2). How many centimeters (cm) is the width of this rectangle? | 9 | 48.6 5.4 [OP_DIV] | var_a = 48.6
var_b = 5.4
var_c = var_a / var_b
print(int(var_c)) |
Correspondence | Two-digit number that is a multiple of 6 and 9 has a remainder of 1 when divided by 7. Find this two digit number. | 36 | 10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET] | var_a = 10
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
var_e = 9
var_f = var_e * var_d / math.gcd(int(var_e), int(var_d))
var_g = 0
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 7
var_i = 1
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k)) |
Correspondence | There are one-digit numbers A and B. 757AB384 is a multiple of 357. Find the value of B. | 5 | 757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK] | var_a = '757AB384'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 357
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = '757AB384'
var_d = 'B'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
print(int(var_e)) |
Comparison | Among 5.21, 2/3, 3.21, 3.42, and 1/3, find the product of the smallest and the second smallest number. | 0.22 | [OP_LIST_SOL] 5.21 2/3 3.21 3.42 1/3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_MUL] | var_a = 5.21
var_b = 0.6666666666666666
var_c = 3.21
var_d = 3.42
var_e = 0.3333333333333333
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g * var_i
print('{:.2f}'.format(round(var_j+1e-10,2))) |
Correspondence | When 6AB+3=691, find A. | 8 | 6AB+3=691 A [OP_DIGIT_UNK_SOLVER] | var_a = '6AB+3=691'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | My mother is 42 years old this year, and my father is 44 years old. How old is the father in the year when the sum of their ages is 100? | 51 | 44 100 44 42 [OP_ADD] [OP_SUB] 2 [OP_DIV] [OP_ADD] | var_a = 44
var_b = 100
var_c = 44
var_d = 42
var_e = var_c + var_d
var_f = var_b - var_e
var_g = 2
var_h = var_f / var_g
var_i = var_a + var_h
print(int(var_i)) |
Geometry | When the bottles were arranged in a square, there were 36 bottles left. I increased the width and height of the square by one column each, and there were still 3 bottles left out. How many bottles are there in total? | 292 | 36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD] | var_a = 36
var_b = 3
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g ** var_h
var_j = 36
var_k = var_i + var_j
print(int(var_k)) |
Comparison | Yoongi had 4 apples, Yuna had 5 apples, and Jungkook had 6 apples, but he ate 3. Who has the most apples? | Yuna | [OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Yuna'
var_c = 'Jungkook'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 5
var_f = 6
var_g = 3
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Possibility | There are three chicken restaurants, two pizza restaurants, and two Chinese restaurants near Minsu's house. When ordering delivery food from 3 of these places at the same time, find the number of cases. | 35 | 3 2 [OP_ADD] 2 [OP_ADD] 3 [OP_COMB] | var_a = 3
var_b = 2
var_c = var_a + var_b
var_d = 2
var_e = var_c + var_d
var_f = 3
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
for i, elem in enumerate(range(var_f)):
var_g = var_g / (i+1)
print(int(var_g)) |
Possibility | Use the all number cards 1, 6, and 8 once and find the third largest three-digit number. | 681 | [OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] | var_a = 1
var_b = 6
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 3
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print(int(var_f)) |
Geometry | The width of the square paper is 8 centimeters (cm). If the perimeter is 40 centimeters (cm), how long is the length? | 12 | 40 2 [OP_DIV] 8 [OP_SUB] | var_a = 40
var_b = 2
var_c = var_a / var_b
var_d = 8
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | You want to give dolls to students in a class. When 4 dolls were given to each student, 3 dolls were left, and when 5 dolls were given, 6 dolls were in short. How many dolls did you have? | 39 | 3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] 4 [OP_MUL] 3 [OP_ADD] | var_a = 3
var_b = 6
var_c = var_a + var_b
var_d = 5
var_e = 4
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 4
var_i = var_g * var_h
var_j = 3
var_k = var_i + var_j
print(int(var_k)) |
Geometry | There is a pentagon whose all sides have the same length. If one side of this pentagon is 15 centimeters (cm) long, how many centimeters (cm) is the sum of all the side lengths? | 75 | 15 5 [OP_MUL] | var_a = 15
var_b = 5
var_c = var_a * var_b
print(int(var_c)) |
Possibility | How many three-digit integers greater than 600 and less than 950 have 4, 6, and 9 in each digit? | 3 | [OP_LIST_SOL] 4 6 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 600 [OP_LIST_MORE] 950 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 4
var_b = 6
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 600
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = 950
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Possibility | There are weights of 1 gram (g), 2 grams (g), 4 grams (g), and 8 grams (g) each in the lab. How many different weights can you measure using these weights? | 15 | 2 4 [OP_POW] 1 [OP_SUB] | var_a = 2
var_b = 4
var_c = var_a ** var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Comparison | Yoongi has 4 apples, Yuna has 5, and Jungkook has 6 plus 3 apples. Who has the smallest number of apples? | Yoongi | [OP_LIST_SOL] Yoongi Yuna Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 5 6 3 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Yuna'
var_c = 'Jungkook'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 5
var_f = 6
var_g = 3
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | How many pairs of sides are parallel in a regular hexagon? | 3 | 6 2 [OP_FDIV] | var_a = 6
var_b = 2
var_c = var_a // var_b
print(int(var_c)) |
Correspondence | When you multiply a number by 3 and then subtract 4, you get 5. Find the number. | 3 | 5 4 [OP_ADD] 3 [OP_DIV] | var_a = 5
var_b = 4
var_c = var_a + var_b
var_d = 3
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | When 90 is divided by any number, how many divisible numbers are there? | 12 | 90 [OP_LIST_GET_DIVISOR] [OP_LIST_LEN] | var_a = 90
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = len(list_a)
print(int(var_b)) |
Geometry | There is a piece of colored paper in the shape of a square with a side length of 11 centimeters (cm). What is the area of this sheet of colored paper? | 121 | 11 2 [OP_POW] | var_a = 11
var_b = 2
var_c = var_a ** var_b
print(int(var_c)) |
Correspondence | When A is divided by 8, the quotient is B and the remainder is C. A, B, and C are natural numbers. If B and C are equal, what is the largest possible number of A? | 63 | 8 1 [OP_SUB] 8 [OP_MUL] 8 1 [OP_SUB] [OP_ADD] | var_a = 8
var_b = 1
var_c = var_a - var_b
var_d = 8
var_e = var_c * var_d
var_f = 8
var_g = 1
var_h = var_f - var_g
var_i = var_e + var_h
print(int(var_i)) |
Possibility | There are 1 red marble, 1 blue marble, and 1 yellow marble. Find the number of ways in which two of these can be placed in two boxes of the same shape. | 3 | [OP_LIST_SOL] red blue yellow [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 'red'
var_b = 'blue'
var_c = 'yellow'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
print(int(var_f)) |
Geometry | There is a square with a side of 14 centimeters (cm). You want to subdivide this square into rectangles that are 2 centimeters (cm) wide and 8 centimeters (cm) long. How many such rectangles can you get at most? | 12 | 14 2 [OP_POW] 8 2 [OP_MUL] [OP_FDIV] | var_a = 14
var_b = 2
var_c = var_a ** var_b
var_d = 8
var_e = 2
var_f = var_d * var_e
var_g = var_c // var_f
print(int(var_g)) |
Possibility | If you throw three coins that are distinguishable from each other, how many outcomes will you get? | 8 | 2 3 [OP_POW] | var_a = 2
var_b = 3
var_c = var_a ** var_b
print(int(var_c)) |
Correspondence | You need to multiply a number by 3 and add 49. But you subtract 3 and add 49 mistakenly and get 66. Find the difference between the correctly calculated value and the incorrectly calculated value. | 43 | 66 49 [OP_SUB] 3 [OP_ADD] 3 [OP_MUL] 49 [OP_ADD] 66 [OP_SUB] | var_a = 66
var_b = 49
var_c = var_a - var_b
var_d = 3
var_e = var_c + var_d
var_f = 3
var_g = var_e * var_f
var_h = 49
var_i = var_g + var_h
var_j = 66
var_k = var_i - var_j
print(int(var_k)) |
Arithmetic calculation | Dohyun divided the donut into 3 equal pieces and ate one piece. Dongmin divided a donut of the same size into 12 equal pieces. How many donuts must Dongmin eat to eat the same amount as Dohyun? | 4 | 12 3 [OP_DIV] | var_a = 12
var_b = 3
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | If you give 1 kg (kg) 900 grams (g) out of 3 kg (kg) 300 grams (g) of strawberries to a friend, how many grams (g) of strawberries are left? | 1400 | 3 1000 [OP_MUL] 300 [OP_ADD] 1 1000 [OP_MUL] 900 [OP_ADD] [OP_SUB] | var_a = 3
var_b = 1000
var_c = var_a * var_b
var_d = 300
var_e = var_c + var_d
var_f = 1
var_g = 1000
var_h = var_f * var_g
var_i = 900
var_j = var_h + var_i
var_k = var_e - var_j
print(int(var_k)) |
Geometry | Chae Song-i made a square with a side length of 13 centimeters (cm) using thread. What is the length of the thread that Chaesongi has? | 52 | 13 4 [OP_MUL] | var_a = 13
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Geometry | There are two points with an actual distance of 5 kilometers (km). On a map with a scale of 1/250000, how many centimeters (cm) would be the length of the two points when measured with a ruler? | 2 | 5 100 1000 [OP_MUL] [OP_MUL] 1/250000 [OP_MUL] | var_a = 5
var_b = 100
var_c = 1000
var_d = var_b * var_c
var_e = var_a * var_d
var_f = 4e-06
var_g = var_e * var_f
print(int(var_g)) |
Geometry | Find the number of vertices of the rectangular prism. | 8 | 4 2 [OP_MUL] | var_a = 4
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Comparison | I drew three circles with colored pencils. The radius of the orange circle is 4 centimeters (cm), the diameter of the light-green circle is 6 centimeters (cm), and the radius of the sky-blue circle is 5 centimeters (cm). What color circle is with the widest area? | sky-blue | [OP_LIST_SOL] orange light-green sky-blue [OP_LIST_EOL] [OP_LIST_SOL] 4 6 2 [OP_DIV] 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'orange'
var_b = 'light-green'
var_c = 'sky-blue'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 6
var_f = 2
var_g = var_e / var_f
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | To make dumplings with 45 grams (g) of dough, each dumpling needs 4 grams (g). Find the maximum number of dumplings you can make. | 11 | 45 4 [OP_FDIV] | var_a = 45
var_b = 4
var_c = var_a // var_b
print(int(var_c)) |
Correspondence | Divide 90.1 by some number to get 5.3. Find out what the number is. | 17 | 90.1 5.3 [OP_DIV] | var_a = 90.1
var_b = 5.3
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | How many three-digit numbers are multiples of 6, multiples of 5, multiples of 8, and multiples of 9? | 2 | 100 999 1 [OP_LIST_ARANGE] 6 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 8 [OP_LIST_DIVISIBLE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 100
var_b = 999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 8
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 9
list_e = []
var_g = int(var_g)
for i in list_d:
i = int(i)
if i % var_g == 0:
list_e.append(i)
var_h = len(list_e)
print(int(var_h)) |
Geometry | The shape of the base side of the pyramid is a dodecagon. How many faces does this pyramid have? | 13 | 12 1 [OP_ADD] | var_a = 12
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | Seokgi and Yeseul shared a wire. The length of this wire is 1 meter (m) and 50 centimeters (cm), and it is said that the Seokgi's share is 16 centimeters (cm) shorter than Yeseul. How many centimeters (cm) of wire does Seokgi have? | 67 | 1 100 [OP_MUL] 50 [OP_ADD] 16 [OP_SUB] 2 [OP_DIV] | var_a = 1
var_b = 100
var_c = var_a * var_b
var_d = 50
var_e = var_c + var_d
var_f = 16
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | There are 8 apples in the basket. Jungkook put 7 more apples in the basket. How many apples are in the basket? | 15 | 8 7 [OP_ADD] | var_a = 8
var_b = 7
var_c = var_a + var_b
print(int(var_c)) |
Possibility | I am trying to pick two different numbers at the same time from natural numbers from 1 to 9. Find the number of ways in which the sum of two numbers is greater than 10. | 32 | 1 9 1 [OP_LIST_ARANGE] 2 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 10 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 10
list_d = []
for i in list_c:
if i > var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Correspondence | 4 is the result of mistakenly subtracting 5 from a number instead of subtracting 4. Find this number | 9 | 4 5 [OP_ADD] | var_a = 4
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | 4A5B+C2D7=8070. Find C when there are four different numbers A, B, C, and D. | 3 | 4A5B+C2D7=8070 C [OP_DIGIT_UNK_SOLVER] | var_a = '4A5B+C2D7=8070'
var_b = 'C'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | There is a quadrangular pyramid with the sum of the lengths of its edges being 14.8 meters (m). Find the length of one edge of this quadrangular pyramid when all the edge lengths are the same. | 1.85 | 14.8 4 2 [OP_MUL] [OP_DIV] | var_a = 14.8
var_b = 4
var_c = 2
var_d = var_b * var_c
var_e = var_a / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | Each box contains 3 balls. If you have 2 boxes, how many balls do you have in total? | 6 | 3 2 [OP_MUL] | var_a = 3
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Comparison | There are numbers 0.8, 1/2, and 0.9. Find the largest of all numbers less than 0.6. | 0.5 | [OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 0.6 [OP_LIST_LESS] 1 [OP_LIST_MAX] | var_a = 0.8
var_b = 0.5
var_c = 0.9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.6
list_b = []
for i in list_a:
if i < var_d:
list_b.append(i)
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | If Junhyeok and Hyeonyoung do a certain task together for 8 days, they can do 7/12 of the total work. After the two of them worked together for eight days, Junhyeok decided to do the rest by himself. If Junhyeok worked alone for 10 days, how many days would it take to finish the job if Heonyeong did it alone from the beginning? | 32 | 1 7/12 8 [OP_DIV] 1 7/12 [OP_SUB] 10 [OP_DIV] [OP_SUB] [OP_DIV] | var_a = 1
var_b = 0.5833333333333334
var_c = 8
var_d = var_b / var_c
var_e = 1
var_f = 0.5833333333333334
var_g = var_e - var_f
var_h = 10
var_i = var_g / var_h
var_j = var_d - var_i
var_k = var_a / var_j
print(int(eval('{:.2f}'.format(round(var_k+1e-10,2))))) |
Comparison | There are a total of three numbers: 0.8, 1/2, and 0.5. What is the smallest of these numbers greater than or equal to 0.1? | 0.5 | [OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 0.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN] | var_a = 0.8
var_b = 0.5
var_c = 0.5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.1
list_b = []
for i in list_a:
if i >= var_d:
list_b.append(i)
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[var_e-1]
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | Find the sum of all numbers between 1 and 100. | 5050 | 1 100 1 [OP_LIST_ARANGE] [OP_LIST_SUM] | var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
list_a = [float(i) for i in list_a]
var_d = sum(list_a)
print(int(var_d)) |
Possibility | Find the number of two-digit natural numbers that can be made by selecting two figures among 0, 1, and 2. | 4 | [OP_LIST_SOL] 0 1 2 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Correspondence | Subtracting 5 from a number and dividing it by 3 gives you 4. Find the number. | 17 | 4 3 [OP_MUL] 5 [OP_ADD] | var_a = 4
var_b = 3
var_c = var_a * var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e)) |
Geometry | If the diameter of a circle is 8 centimeters (cm) and the circumference is 25.12 centimeters (cm), what is the pi of the circle? | 3.14 | 25.12 8 [OP_DIV] | var_a = 25.12
var_b = 8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | The volleyball teams A, B, C, and D are playing volleyball. A beat B 3-2, and B lost to D 2-5. When C beats D 3-2, find the last-place team. | B | [OP_LIST_SOL] A B C D [OP_LIST_EOL] [OP_LIST_SOL] A B > B D < C D > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 'A'
var_f = 'B'
var_g = '>'
var_h = 'B'
var_i = 'D'
var_j = '<'
var_k = 'C'
var_l = 'D'
var_m = '>'
list_b= []
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_n = len(list_c)
var_o = list_c[var_n-1]
print(var_o) |
Geometry | How many diagonals can you draw in a 10-sided figure? | 35 | 10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 10
var_b = 10
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | Among the three people, the heaviest weight person differs from the middle weight person by 7 kilograms (kg) and 700 grams (g), and the lightest weight person differs from the middle weight person by 4.8 kilograms (kg). If the sum of the weights of the three people is 106 kilograms (kg) and 600 grams (g), how many kilograms (kg) does the heaviest person weigh? | 42.27 | 106 600 1000 [OP_DIV] [OP_ADD] 7 700 1000 [OP_DIV] [OP_ADD] 2 [OP_MUL] [OP_ADD] 4.8 [OP_ADD] 3 [OP_DIV] | var_a = 106
var_b = 600
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 7
var_g = 700
var_h = 1000
var_i = var_g / var_h
var_j = var_f + var_i
var_k = 2
var_l = var_j * var_k
var_m = var_e + var_l
var_n = 4.8
var_o = var_m + var_n
var_p = 3
var_q = var_o / var_p
print('{:.2f}'.format(round(var_q+1e-10,2))) |
Correspondence | I had to divide a number by 4, but I accidentally divided a number by 2, and the share became 8. How much is it if I calculate it correctly? | 4 | 8 2 [OP_MUL] 4 [OP_DIV] | var_a = 8
var_b = 2
var_c = var_a * var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Geometry | How many times the surface area of a sphere with a radius of 6 centimeters (cm) is greater than the surface area of a sphere with a radius of 3 centimeters (cm)? | 4 | 6 3 [OP_DIV] 2 [OP_POW] | var_a = 6
var_b = 3
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
print(int(var_e)) |
Comparison | Seokjin walked up the stairs from the building entrance and arrived on the 5th floor. Hoseok took the elevator from the entrance of the same building and reached the 8th floor. Who climbed higher? | Hoseok | [OP_LIST_SOL] Seokjin Hoseok [OP_LIST_EOL] [OP_LIST_SOL] 5 8 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Seokjin'
var_b = 'Hoseok'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 5
var_d = 8
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = list_b.index(var_f)+1
var_h = list_a[var_g-1]
print(var_h) |
Geometry | What is the sum of all the sides of an equilateral triangle with sides of 13/12 meters (m)? | 3.25 | 13/12 3 [OP_MUL] | var_a = 1.0833333333333333
var_b = 3
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
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