category
stringclasses 5
values | question
stringlengths 20
555
| answer
stringlengths 1
20
| solution_abst
stringlengths 1
287
| solution_code
stringlengths 27
5.97k
|
|---|---|---|---|---|
Possibility | Suppose you make a three-digit natural number by selecting three of the four numbers 1, 2, 3, and 4 and arranging them in a row. How many numbers are divisible by 3? | 22 | [OP_LIST_SOL] 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 1
var_b = 2
var_c = 3
var_d = 4
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = len(list_c)
print(int(var_g)) |
Geometry | Cheolsu's nine classmates are standing in a nonagonal shape facing each other. If every student plays rock-paper-scissors once with everyone except for the person next to him/her, how many times do all students play rock-paper-scissors? | 27 | 9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 9
var_b = 9
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | I would like to exchange 170,000 won for a trip to China. One Chinese yuan equals 161.5 won in Korean won. If you want to exchange 1000 yuan and 10 yuan bills, and you change as many 1000 yuan bills as possible, find how many bills will be converted into 10 yuan bills. | 5 | 17 10000 [OP_MUL] 161.5 1000 [OP_MUL] [OP_MOD] 161.5 10 [OP_MUL] [OP_FDIV] | var_a = 17
var_b = 10000
var_c = var_a * var_b
var_d = 161.5
var_e = 1000
var_f = var_d * var_e
var_g = var_c % var_f
var_h = 161.5
var_i = 10
var_j = var_h * var_i
var_k = var_g // var_j
print(int(var_k)) |
Correspondence | Ji-hoon made a mistake while calculating and subtracted 7 from a number instead of multiplying by 7, and it became 0.45. Find out the answer Jihoon was originally looking for. | 52.15 | 0.45 7 [OP_ADD] 7 [OP_MUL] | var_a = 0.45
var_b = 7
var_c = var_a + var_b
var_d = 7
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | Jaeho and Kyunghwan took a walk for the same amount of time. Jaeho walked a distance of 1/100 of 10.2 kilometers (km), and Kyunghwan walked a distance of 100 meters (m). Who walked more distances, Jaeho or Kyunghwan? | Jaeho | [OP_LIST_SOL] Jaeho Kyunghwan [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 1/100 [OP_MUL] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jaeho'
var_b = 'Kyunghwan'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 10.2
var_d = 1000
var_e = var_c * var_d
var_f = 0.01
var_g = var_e * var_f
var_h = 100
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | There is a prism with a sum of the number of vertices, faces, and corners is 50. How many edges of the pyramid have the same base shape as the prism? | 16 | 50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] | var_a = 50
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = 3
var_f = var_d + var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c / var_h
var_j = 2
var_k = var_i * var_j
print(int(var_k)) |
Possibility | There are 9 number cards with the numbers 1 through 9 written on them. In how many ways can you draw 3 cards so that the sum is 17? | 42 | 1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 17
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g)) |
Arithmetic calculation | Find the certain number if the certain number multiplied by 7 minus 6 equals the certain number multiplied by 4 plus 12. | 6 | 12 6 [OP_ADD] 7 4 [OP_SUB] [OP_DIV] | var_a = 12
var_b = 6
var_c = var_a + var_b
var_d = 7
var_e = 4
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g)) |
Arithmetic calculation | 3 puppies and 7 chicks are playing in the yard of Junho's house. Find how many legs the puppies and chicks have together. | 26 | 3 4 [OP_MUL] 7 2 [OP_MUL] [OP_ADD] | var_a = 3
var_b = 4
var_c = var_a * var_b
var_d = 7
var_e = 2
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g)) |
Possibility | When displaying 2 tangerines and 3 oranges in a line, find the number of cases where the tangerines must be placed next to each other. | 48 | 1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL] | var_a = 1
var_b = 3
var_c = var_a + var_b
var_d = 1
var_e = 3
var_f = var_d + var_e
var_g = 1
var_c = int(var_c)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_c-i)
var_h = 2
var_i = 2
var_j = 1
var_h = int(var_h)
var_i = int(var_i)
for i, elem in enumerate(range(var_i)):
var_j = var_j * (var_h-i)
var_k = var_g * var_j
print(int(var_k)) |
Arithmetic calculation | Find the largest number divided by the next largest number among 4 numbers: 10, 11, 12, and 13. | 1.08 | [OP_LIST_SOL] 10 11 12 13 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_DIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[-var_e]
var_g = 2
list_c=list_a.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = var_f / var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | 128 coins are scattered on the floor. If there are 12 more coins that are heads than coins that are tails, how many coins are heads? | 70 | 128 12 [OP_SUB] 2 [OP_DIV] 12 [OP_ADD] | var_a = 128
var_b = 12
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 12
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Roses were planted in one-third of the 2.4 square meters (m2) flower bed, and tulips were planted in the remaining one-quarter. Find the area of the area where the tulips are planted. | 0.4 | 2.4 1 1/3 [OP_SUB] [OP_MUL] 1/4 [OP_MUL] | var_a = 2.4
var_b = 1
var_c = 0.3333333333333333
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 0.25
var_g = var_e * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Possibility | You want to create a three-digit number using 5, 9, and 2 once. When the difference between the two numbers made is the largest, find the difference. | 693 | [OP_LIST_SOL] 5 9 2 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] [OP_ABS] | var_a = 5
var_b = 9
var_c = 2
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 1
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
var_j = abs(var_i)
print(int(var_j)) |
Geometry | The red confetti has a square shape with a side length of 11 centimeters (cm), and the blue confetti has a square shape with a side length of 5 centimeters (cm). What is the sum of the areas of the two pieces of colored paper in square centimeters (cm2)? | 146 | 11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] | var_a = 11
var_b = 2
var_c = var_a ** var_b
var_d = 5
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
print(int(var_g)) |
Arithmetic calculation | It is said that the balloon 3 meters (m) underground reached the ground in 4 seconds after it went into the air. Assuming that the balloon pops when it travels 0.09 kilometers (km) above the ground, how many seconds after it rises into the sky will it burst, if the balloon moves at the same speed? | 124 | 0.09 1000 [OP_MUL] 3 [OP_ADD] 3 [OP_DIV] 4 [OP_MUL] | var_a = 0.09
var_b = 1000
var_c = var_a * var_b
var_d = 3
var_e = var_c + var_d
var_f = 3
var_g = var_e / var_f
var_h = 4
var_i = var_g * var_h
print(int(var_i)) |
Arithmetic calculation | Three more boys and 10 girls entered the class, and now the total number of girls became 22. If there were 5 more boys than girls initially, how many boys are still in the classroom? | 20 | 22 10 [OP_SUB] 5 [OP_ADD] 3 [OP_ADD] | var_a = 22
var_b = 10
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
var_f = 3
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | 3rd grade students from Min's school split into 18 15-seater buses to go on a field trip. If 3 seats are empty in each bus, how many 3rd grade students are there at Min's school? | 216 | 15 3 [OP_SUB] 18 [OP_MUL] | var_a = 15
var_b = 3
var_c = var_a - var_b
var_d = 18
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | How many times does the figure '9' appear in odd numbers from 1 to 100? | 15 | 1 100 [OP_LIST_ODD] [OP_LIST2NUM] [OP_NUM2LIST] 9 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 100
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c=""
for i in list_a:
i = str(i)
var_c = var_c + i
list_b = []
var_c = int(var_c)
while var_c//10 > 0:
list_b.append(var_c%10)
var_c = var_c//10
list_b.append(var_c%10)
list_b = list_b[::-1]
var_d = 9
var_e = 0
var_d = int(var_d)
for i in list_b:
i = int(i)
if i == var_d:
var_e = var_e + 1
print(int(var_e)) |
Possibility | If there are 6 students A, B, C, D, E, and F, find the number of ways to select 2 representatives and 1 secretary. | 60 | [OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_LEN] 2 1 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_DIV] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
var_f = 'F'
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = len(list_a)
var_h = 2
var_i = 1
var_j = var_h + var_i
var_k = 1
var_g = int(var_g)
var_j = int(var_j)
for i, elem in enumerate(range(var_j)):
var_k = var_k * (var_g-i)
var_l = 2
var_m = 2
var_n = 1
var_l = int(var_l)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
var_n = var_n * (var_l-i)
var_o = var_k / var_n
print(int(var_o)) |
Arithmetic calculation | If you add up Yoongi and Hoseok's ages this year, it is 16. Hoseok is 2 years younger than Yoongi. How old is Yoongi this year? | 9 | 16 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD] | var_a = 16
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | The four-digit number 4A8B is a multiple of 93. Find the value of A+B at this time. | 6 | 4A8B [OP_GEN_POSSIBLE_LIST] 93 [OP_LIST_DIVISIBLE] 4A8B A [OP_LIST_FIND_UNK] 4A8B B [OP_LIST_FIND_UNK] [OP_ADD] | var_a = '4A8B'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 93
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = '4A8B'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
var_f = '4A8B'
var_g = 'B'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_b:
elem = str(elem)
var_h = int(elem[unk_idx])
var_i = var_e + var_h
print(int(var_i)) |
Correspondence | When you add 2 to a number and then subtract 3, you get 7. Find out this number | 8 | 7 3 [OP_ADD] 2 [OP_SUB] | var_a = 7
var_b = 3
var_c = var_a + var_b
var_d = 2
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | When traveling for 2 hours and 36 minutes at a speed of 80 kilometers (km) per hour using a car that uses 0.08 liters (L) of gasoline to travel 1 kilometer (km), how many liters (L) of gasoline are used? | 16.64 | 0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL] | var_a = 0.08
var_b = 80
var_c = 2
var_d = 36
var_e = 60
var_f = var_d / var_e
var_g = var_c + var_f
var_h = var_b * var_g
var_i = var_a * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | In Jungkook's class, there are 9 students who wear glasses and 16 students who do not wear glasses. How many students are there? | 25 | 16 9 [OP_ADD] | var_a = 16
var_b = 9
var_c = var_a + var_b
print(int(var_c)) |
Geometry | Find the total volume if you stack 7 rows, 5 columns, and 3 layers of Legos, each measuring 1 centimeter (cm) in length, width, and height. | 105 | 1 7 [OP_MUL] 1 5 [OP_MUL] [OP_MUL] 1 3 [OP_MUL] [OP_MUL] | var_a = 1
var_b = 7
var_c = var_a * var_b
var_d = 1
var_e = 5
var_f = var_d * var_e
var_g = var_c * var_f
var_h = 1
var_i = 3
var_j = var_h * var_i
var_k = var_g * var_j
print(int(var_k)) |
Possibility | Find the number of natural numbers that can be made by drawing three of the number cards 0, 1, 2, 4, and 9. | 48 | [OP_LIST_SOL] 0 1 2 4 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 4
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Correspondence | There is a four-digit number that has A in the tens place. If the thousands, hundreds, and ones place of this four-digit number are 1, 8, and 4, and it is less than 1853, how many digits can be written in A in 18A4? | 5 | 18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = '18A4'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 1853
list_b = []
for i in list_a:
if i < var_b:
list_b.append(i)
var_c = len(list_b)
print(int(var_c)) |
Correspondence | Subtracting 2.95 twice from a number gives 9.28. Find this number. | 15.18 | 9.28 2.95 [OP_ADD] 2.95 [OP_ADD] | var_a = 9.28
var_b = 2.95
var_c = var_a + var_b
var_d = 2.95
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Geometry | The area of the base triangle of a triangular prism with a volume of 576 cubic centimeters (cm3) is 3 square centimeters (cm2). How many centimeters (cm) is half of the height of this triangular prisim? | 96 | 576 3 [OP_DIV] 2 [OP_DIV] | var_a = 576
var_b = 3
var_c = var_a / var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Possibility | When 2 coins and 1 dice are tossed at the same time, in how many ways can both coins come up equal and the dice roll is a multiple of 3? | 4 | 2 1 6 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] [OP_MUL] | var_a = 2
var_b = 1
var_c = 6
var_d = 1
list_a = [i for i in range(var_b, var_c + 1, var_d)]
var_e = 3
list_b = []
var_e = int(var_e)
for i in list_a:
i = int(i)
if i % var_e == 0:
list_b.append(i)
var_f = len(list_b)
var_g = var_a * var_f
print(int(var_g)) |
Arithmetic calculation | Min-young and Hoseok each had 1.5 million won of money. If Minyoung earns 320,000 won more and Hoseok earns 490,000 won more, how much more money does Hoseok have than Minyoung? | 170000 | 150 49 [OP_ADD] 150 32 [OP_ADD] [OP_SUB] 10000 [OP_MUL] | var_a = 150
var_b = 49
var_c = var_a + var_b
var_d = 150
var_e = 32
var_f = var_d + var_e
var_g = var_c - var_f
var_h = 10000
var_i = var_g * var_h
print(int(var_i)) |
Arithmetic calculation | The amount of water that Seokgi's family drinks during the day are 3 liters (L) and 200 milliliters (㎖). If out of this, the amount of water Seokgi and his father drink per day is 1 liter (L) and 100 milliliters (㎖) and every member drinks the same amount of water daily, how many liters (L) of water do the other members except Seokgi and his father drink for 2 weeks? | 29.4 | 3 200 1000 [OP_DIV] [OP_ADD] 1 100 1000 [OP_DIV] [OP_ADD] [OP_SUB] 2 7 [OP_MUL] [OP_MUL] | var_a = 3
var_b = 200
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 1
var_g = 100
var_h = 1000
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_e - var_j
var_l = 2
var_m = 7
var_n = var_l * var_m
var_o = var_k * var_n
print('{:.2f}'.format(round(var_o+1e-10,2))) |
Comparison | Double B plus 4 is C, and the quotient of A divided by 3 is B. When A is 8 multiplied by 9 minus 3. Find the sum of the largest number and the smallest number. | 92 | [OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD] | var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 3
var_e = var_c - var_d
var_f = 8
var_g = 9
var_h = var_f * var_g
var_i = 3
var_j = var_h - var_i
var_k = 3
var_l = var_j / var_k
var_m = 8
var_n = 9
var_o = var_m * var_n
var_p = 3
var_q = var_o - var_p
var_r = 3
var_s = var_q / var_r
var_t = 2
var_u = var_s * var_t
var_v = 4
var_w = var_u + var_v
list_a= []
if "/" in str(var_w):
var_w = eval(str(var_w))
list_a.append(var_w)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_a.append(var_l)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
list_a.reverse()
var_x = 1
list_b=list_a.copy()
list_b.sort()
var_y = list_b[-var_x]
var_z = 3
list_c=list_a.copy()
list_c.sort()
var_A = list_c[-var_z]
var_B = var_y + var_A
print(int(var_B)) |
Comparison | A giraffe is 2.3 meters (m) tall, a baby is 9/10 meters (m) tall, a gorilla is 1.8 meters (m) tall, and a dinosaur is 2.5 meters (m) tall. What is the second tallest creature? | giraffe | [OP_LIST_SOL] giraffe baby gorilla dinosaur [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'giraffe'
var_b = 'baby'
var_c = 'gorilla'
var_d = 'dinosaur'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2.3
var_f = 0.9
var_g = 1.8
var_h = 2.5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 2
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | Buses run at 92 kilometers (km) per hour, and taxis run at 1500 meters (m) per minute. Which of the buses or taxis is faster? | buses | [OP_LIST_SOL] buses taxis [OP_LIST_EOL] [OP_LIST_SOL] 92 1500 1000 [OP_DIV] 60 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'buses'
var_b = 'taxis'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 92
var_d = 1500
var_e = 1000
var_f = var_d / var_e
var_g = 60
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | I mistakenly subtracted a certain number that should have been added to 5.46, and the result was 3.97. Find the result of the correct calculation. | 6.95 | 5.46 5.46 3.97 [OP_SUB] [OP_ADD] | var_a = 5.46
var_b = 5.46
var_c = 3.97
var_d = var_b - var_c
var_e = var_a + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | When the division was calculated by changing the tens and units digits of the divisor, the quotient and remainder were 25 each. When the divisor is 65, find the sum of the correctly calculated quotient and remainder. | 81 | 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_FDIV] 56 25 [OP_MUL] 25 [OP_ADD] 65 [OP_MOD] [OP_ADD] | var_a = 56
var_b = 25
var_c = var_a * var_b
var_d = 25
var_e = var_c + var_d
var_f = 65
var_g = var_e // var_f
var_h = 56
var_i = 25
var_j = var_h * var_i
var_k = 25
var_l = var_j + var_k
var_m = 65
var_n = var_l % var_m
var_o = var_g + var_n
print(int(var_o)) |
Possibility | When you want to take a picture of 2 dogs and 3 cats standing in one line, find the number of cases where the dogs should be placed next to each other. | 48 | 1 3 [OP_ADD] 1 3 [OP_ADD] [OP_PERM] 2 2 [OP_PERM] [OP_MUL] | var_a = 1
var_b = 3
var_c = var_a + var_b
var_d = 1
var_e = 3
var_f = var_d + var_e
var_g = 1
var_c = int(var_c)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_c-i)
var_h = 2
var_i = 2
var_j = 1
var_h = int(var_h)
var_i = int(var_i)
for i, elem in enumerate(range(var_i)):
var_j = var_j * (var_h-i)
var_k = var_g * var_j
print(int(var_k)) |
Correspondence | When the six-digit number A4461B is divisible by 72, find A+B. | 12 | A4461B [OP_GEN_POSSIBLE_LIST] 72 [OP_LIST_DIVISIBLE] A4461B A [OP_LIST_FIND_UNK] A4461B B [OP_LIST_FIND_UNK] [OP_ADD] | var_a = 'A4461B'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 72
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = 'A4461B'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
var_f = 'A4461B'
var_g = 'B'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_b:
elem = str(elem)
var_h = int(elem[unk_idx])
var_i = var_e + var_h
print(int(var_i)) |
Arithmetic calculation | You want to cut 360 meters (m) of wire into 3.6 meters (m) long pieces. In how many pieces can you cut the wire? | 100 | 360 3.6 [OP_DIV] | var_a = 360
var_b = 3.6
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | 1260 people visited the park last Sunday. Of those, 7/18 were men, and 6/11 of the women were students. Find how many female students visited the park. | 420 | 1260 1 7/18 [OP_SUB] [OP_MUL] 6/11 [OP_MUL] | var_a = 1260
var_b = 1
var_c = 0.3888888888888889
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 0.5454545454545454
var_g = var_e * var_f
print(int(eval('{:.2f}'.format(round(var_g+1e-10,2))))) |
Arithmetic calculation | Eunji has 44 ping pong balls. If she gives 4 ping pong balls to her friends each, how many friends will get the ping pong balls? | 11 | 44 4 [OP_DIV] | var_a = 44
var_b = 4
var_c = var_a / var_b
print(int(var_c)) |
Geometry | How many vertices are there in a tetrahedron? | 4 | 3 1 [OP_ADD] | var_a = 3
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Geometry | There is a rectangle with a width three times its height. If the length of this rectangle is 0.06 meters (m), how many square meters (m2) is its area? | 0.01 | 0.06 3 [OP_MUL] 0.06 [OP_MUL] | var_a = 0.06
var_b = 3
var_c = var_a * var_b
var_d = 0.06
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | There are 12 more volleyballs and 23 fewer basketballs than soccer balls. If there are 68 soccer balls, how many soccer balls, volleyballs, and basketballs are there? | 193 | 68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD] | var_a = 68
var_b = 12
var_c = var_a + var_b
var_d = 68
var_e = 23
var_f = var_d - var_e
var_g = var_c + var_f
var_h = 68
var_i = var_g + var_h
print(int(var_i)) |
Correspondence | You need to multiply a certain number by 6, but you mistakenly multiplied it by 9, and I got 153. Find the result of the correct calculation. | 102 | 153 9 [OP_DIV] 6 [OP_MUL] | var_a = 153
var_b = 9
var_c = var_a / var_b
var_d = 6
var_e = var_c * var_d
print(int(var_e)) |
Comparison | Jinho gave 3 of the 9 pencils he had to his younger brother, and Youngsu gave 7 of the 14 pencils he had to his friend. Who has more pencils between Jinho and Youngsu? | Youngsu | [OP_LIST_SOL] Jinho Youngsu [OP_LIST_EOL] [OP_LIST_SOL] 9 3 [OP_SUB] 14 7 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jinho'
var_b = 'Youngsu'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 9
var_d = 3
var_e = var_c - var_d
var_f = 14
var_g = 7
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Possibility | Among 2, 4, 6, 8, and 9, you want to create a two-digit number by drawing two cards and using them only once. Find the sum of the largest and smallest two-digit numbers that can be made. | 122 | [OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD] | var_a = 2
var_b = 4
var_c = 6
var_d = 8
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 1
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h + var_j
print(int(var_k)) |
Possibility | You want to pick two fruits out of an apple, a peach and a pear and place them in different fruit baskets. What are the number of cases? | 6 | [OP_LIST_SOL] apple peach pear [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM] | var_a = 'apple'
var_b = 'peach'
var_c = 'pear'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
print(int(var_f)) |
Geometry | A cube-shaped fishbowl with an edge length of 20 centimeters (cm) was filled with water up to 15 centimeters (cm) high. Here, a cube-shaped piece of iron whose edge is 10 centimeters (cm) long was placed to be completely submerged in the water. Find how many centimeters (cm) the water level in this fish tank has risen, including the decimal point. | 2.5 | 10 10 [OP_MUL] 10 [OP_MUL] 20 20 [OP_MUL] [OP_DIV] | var_a = 10
var_b = 10
var_c = var_a * var_b
var_d = 10
var_e = var_c * var_d
var_f = 20
var_g = 20
var_h = var_f * var_g
var_i = var_e / var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | You are going to make chocolate necklaces for 134 kindergarteners at Seonhee's Kindergarten this year. If you need 7 chocolates for each chocolate necklace, how many bags of 28 chocolates should you buy at least? | 34 | 134 7 [OP_MUL] 28 [OP_DIV] 1 [OP_CEIL] | var_a = 134
var_b = 7
var_c = var_a * var_b
var_d = 28
var_e = var_c / var_d
var_f = 1
var_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))
print(int(var_g)) |
Arithmetic calculation | If the rabbits are color coded, 12 are white and 9 are black. If 8 rabbits are female, how many male rabbits are there? | 13 | 12 9 [OP_ADD] 8 [OP_SUB] | var_a = 12
var_b = 9
var_c = var_a + var_b
var_d = 8
var_e = var_c - var_d
print(int(var_e)) |
Possibility | There are 5 students in Yoongi's class, and they are trying to select a class president. At this time, how many cases can Yoongi vote for the 3 class president candidates? | 243 | 3 5 [OP_POW] | var_a = 3
var_b = 5
var_c = var_a ** var_b
print(int(var_c)) |
Arithmetic calculation | If the sum of three consecutive natural numbers is 30, find the middle number among the three natural numbers. | 10 | 30 0 3 1 [OP_SUB] 1 [OP_LIST_ARANGE] [OP_LIST_SUM] [OP_SUB] 3 [OP_DIV] 3 2 [OP_FDIV] [OP_ADD] | var_a = 30
var_b = 0
var_c = 3
var_d = 1
var_e = var_c - var_d
var_f = 1
list_a = [i for i in range(var_b, var_e + 1, var_f)]
list_a = [float(i) for i in list_a]
var_g = sum(list_a)
var_h = var_a - var_g
var_i = 3
var_j = var_h / var_i
var_k = 3
var_l = 2
var_m = var_k // var_l
var_n = var_j + var_m
print(int(var_n)) |
Geometry | Find the area of a flower field in the shape of a circle with a radius of 0.6 meters (m) when the pi is 3. | 1.08 | 3 0.6 2 [OP_POW] [OP_MUL] | var_a = 3
var_b = 0.6
var_c = 2
var_d = var_b ** var_c
var_e = var_a * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Geometry | There is a rectangular parallelepiped with three distinct edges whose length is 4 centimeters (cm), 6 centimeters (cm), and 15 centimeters (cm) each. Find what is the volume of this rectangular parallelepiped. | 360 | 15 6 [OP_MUL] 4 [OP_MUL] | var_a = 15
var_b = 6
var_c = var_a * var_b
var_d = 4
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | If you add 82, add 90, add 88, add 84 to a number and divide it by 5, the quotient is 88. Find the number. | 96 | 88 5 [OP_MUL] 82 [OP_SUB] 90 [OP_SUB] 88 [OP_SUB] 84 [OP_SUB] | var_a = 88
var_b = 5
var_c = var_a * var_b
var_d = 82
var_e = var_c - var_d
var_f = 90
var_g = var_e - var_f
var_h = 88
var_i = var_g - var_h
var_j = 84
var_k = var_i - var_j
print(int(var_k)) |
Arithmetic calculation | There are five numbers: 10, 11, 12, 13, and 14. What is the remainder if the largest number is divided by the second largest number? | 1 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MAX] [OP_MOD] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = var_g % var_i
print(int(var_j)) |
Arithmetic calculation | There are 288 red marbles in 12 bags, and 243 blue marbles in 9 bags. Find the difference between the number of marbles in one bag of red and blue marbles. | 3 | 288 12 [OP_DIV] 243 9 [OP_DIV] [OP_SUB] [OP_ABS] | var_a = 288
var_b = 12
var_c = var_a / var_b
var_d = 243
var_e = 9
var_f = var_d / var_e
var_g = var_c - var_f
var_h = abs(var_g)
print(int(var_h)) |
Comparison | There are three numbers 0.8, 1/2, and 0.9. What is the largest number that is less than 2? | 0.9 | [OP_LIST_SOL] 0.8 1/2 0.9 [OP_LIST_EOL] 2 [OP_LIST_LESS] 1 [OP_LIST_MAX] | var_a = 0.8
var_b = 0.5
var_c = 0.9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = []
for i in list_a:
if i < var_d:
list_b.append(i)
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | If you fold and unfold the paper once making them overlap, you get 2 squares, and if you fold and unfold it twice, you get 4 squares, and if you fold and unfold it 3 times, you get 8 squares. How many squares will there be on the paper if you fold and unfold it 8 times in the same way? | 256 | 2 8 [OP_POW] | var_a = 2
var_b = 8
var_c = var_a ** var_b
print(int(var_c)) |
Geometry | There is a square with the sum of the lengths of its four sides measuring 52 centimeters (cm). Find the area of this square. | 169 | 52 4 [OP_DIV] 2 [OP_POW] | var_a = 52
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
print(int(var_e)) |
Arithmetic calculation | A person consumes 0.08 milliliters (ml) of water per 1 kilometer (km). Find the amount of water consumed in milliliters (㎖) when traveling for 2 hours and 36 minutes at the speed of moving 80 kilometers (㎞) in 1 hour. | 16.64 | 0.08 80 2 36 60 [OP_DIV] [OP_ADD] [OP_MUL] [OP_MUL] | var_a = 0.08
var_b = 80
var_c = 2
var_d = 36
var_e = 60
var_f = var_d / var_e
var_g = var_c + var_f
var_h = var_b * var_g
var_i = var_a * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | Given that there are 18 apples and the sum of apples and persimmons are 33. Find the number of persimmons. | 15 | 33 18 [OP_SUB] | var_a = 33
var_b = 18
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | Yoongi wants to add two-digit to three-digit numbers. Yoongi confused the 9 in the ones place of a two-digit number with 6, and switched the digits in the hundreds and ones place of a three-digit number and saw it as 253. If the sum obtained by Yoongi is 299, find the two-digit number. | 49 | 299 253 [OP_SUB] 6 9 [OP_SUB] [OP_SUB] | var_a = 299
var_b = 253
var_c = var_a - var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
print(int(var_g)) |
Comparison | There are numbers 0.8, 1/2, 0.9, and 1/3. Find the sum of all numbers greater than 0.3. | 2.53 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 0.3 [OP_LIST_MORE] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.3
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Correspondence | When 5A8-B14=364 is valid, find B. | 2 | 5A8-B14=364 B [OP_DIGIT_UNK_SOLVER] | var_a = '5A8-B14=364'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Possibility | If you buy only 2 fruits out of Apples, Peaches, Pears, and Melons, how many combinations are possible? | 6 | [OP_LIST_SOL] Apple Peach Pear Melon [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 'Apple'
var_b = 'Peach'
var_c = 'Pear'
var_d = 'Melon'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 2
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
for i, elem in enumerate(range(var_f)):
var_g = var_g / (i+1)
print(int(var_g)) |
Geometry | There is a square-shaped park. It is said that the perimeter of a park is the largest multiple of 4 and is less than 35. If Seong-hoon tries to walk 35 kilometers (km) around the perimeter of the park, how many more kilometers (km) must he walk after one lap? | 3 | 35 4 [OP_MOD] | var_a = 35
var_b = 4
var_c = var_a % var_b
print(int(var_c)) |
Possibility | You are making new numbers using all 3, 9, and 8. What is the number of cases in which the number you made is more than or equal to 850 and less than or equal to 920? | 1 | [OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 3
var_b = 9
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 850
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = 920
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Geometry | If the volume of the cube is 729 cubic centimeters (cm3), how many centimeters (cm) is the length of one side of the cube? | 9 | 729 1/3 [OP_POW] | var_a = 729
var_b = 0.3333333333333333
var_c = var_a ** var_b
print(int(eval('{:.2f}'.format(round(var_c+1e-10,2))))) |
Geometry | There is a tetragon having all four sides the same length. If the lengths of the two diagonals of this figure are 9 centimeters (cm) and 14 centimeters (cm), what is the area? | 63 | 9 14 [OP_MUL] 2 [OP_DIV] | var_a = 9
var_b = 14
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | Divide 49 erasers and 66 pencils equally to the students in the class, leaving 4 erasers and 6 pencils. Find how many students are in the class. | 15 | 49 4 [OP_SUB] 66 6 [OP_SUB] [OP_GCD] | var_a = 49
var_b = 4
var_c = var_a - var_b
var_d = 66
var_e = 6
var_f = var_d - var_e
var_g = math.gcd(int(var_f), int(var_c))
print(int(var_g)) |
Comparison | Jungkook collected 6 divided by 3 apples, Yoongi collected 4 apples, and Yuna collected 5 apples. Who has the fewest apples? | Jungkook | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d // var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | How many two-digit numbers meet the condition where the sum of the numbers in the ones and in the tens is greater than or equal to 8? | 62 | 10 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 8 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] | var_a = 10
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
list_b=[]
for i in list_a:
var_d = 0
i = int(i)
while i//10 > 0:
var_d = var_d + i%10
i = i//10
var_d = var_d + i%10
list_b.append(var_d)
var_e = 8
list_c = []
for i in list_b:
if i >= var_e:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Correspondence | When 6A5+B03=748, find A. | 4 | 6A5+B03=748 A [OP_DIGIT_UNK_SOLVER] | var_a = '6A5+B03=748'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Comparison | There are boxes A, B, and C with balls in them. Box A has fewer balls than Box B, and Box C has more balls than Box A. If Box C contains more balls than Box B, which box has the most balls? | C | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] C A > A B < C B > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'C'
var_e = 'A'
var_f = '>'
var_g = 'A'
var_h = 'B'
var_i = '<'
var_j = 'C'
var_k = 'B'
var_l = '>'
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_m = 1
var_n = list_c[var_m-1]
print(var_n) |
Geometry | I drew the largest rhombus in a circle with a radius of 10 centimeters (cm), and then drew a smaller rhombus by connecting the middle of all four sides of the rhombus. What is the area of the small rhombus in square centimeters (cm2)? | 100 | 10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV] | var_a = 10
var_b = 2
var_c = var_a * var_b
var_d = 2
var_e = var_c ** var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Possibility | I'm trying to draw 2 fruits out of apples, peaches, and pears and line them up. How many possible cases are there? | 6 | [OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM] | var_a = 'apples'
var_b = 'peaches'
var_c = 'pears'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
print(int(var_f)) |
Geometry | Find the area in square centimeters (cm2) of a rhombus where the length of one diagonal is three times 6 centimeters (cm), and the length of the other diagonal is three times 4 centimeters (cm). | 108 | 6 3 [OP_MUL] 4 3 [OP_MUL] [OP_MUL] 2 [OP_DIV] | var_a = 6
var_b = 3
var_c = var_a * var_b
var_d = 4
var_e = 3
var_f = var_d * var_e
var_g = var_c * var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Correspondence | Jiho used 13/5 pieces of rubber clay to make a model. After making another identical piece, the remaining rubber clay was 9/7. Find the amount of rubber clay Jiho had at the beginning. | 6.49 | 9/7 13/5 [OP_ADD] 13/5 [OP_ADD] | var_a = 1.2857142857142858
var_b = 2.6
var_c = var_a + var_b
var_d = 2.6
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | Find the number of three-digit numbers where each digit is even. | 100 | 0 9 [OP_LIST_EVEN] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 0
var_b = 9
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d)) |
Arithmetic calculation | You decided to put 235 candies in a box of 10 and sell them for 3,000 won. What is the maximum amount of money you can make selling boxed candy? | 69000 | 235 10 [OP_FDIV] 3000 [OP_MUL] | var_a = 235
var_b = 10
var_c = var_a // var_b
var_d = 3000
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | A turtle moves 15 meters (m) in 3 minutes at a constant speed. How many minutes does it take for a tortoise to travel 140 meters (m)? | 28 | 140 15 3 [OP_DIV] [OP_DIV] | var_a = 140
var_b = 15
var_c = 3
var_d = var_b / var_c
var_e = var_a / var_d
print(int(var_e)) |
Geometry | Jaeho has a field in the shape of a rectangle. One side of this field is 5.9 meters (m) long and the other side is 3 meters (m) long. Find the area of this field. | 17.7 | 5.9 3 [OP_MUL] | var_a = 5.9
var_b = 3
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | Namjoon was the second to arrive at school, and Jimin arrived just before Namjoon. In what place did Jimin enter school? | 1 | 2 1 [OP_SUB] | var_a = 2
var_b = 1
var_c = var_a - var_b
print(int(var_c)) |
Comparison | There are vineyards in the village (a), (b) and (c). If village (c) harvested fewer bunches of grapes than village (a), and village (b) harvested more bunches of grapes than village (a), find which village harvested the fewest bunches of grapes. | (c) | [OP_LIST_SOL] (a) (b) (c) [OP_LIST_EOL] [OP_LIST_SOL] (b) (a) > (c) (a) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
var_c = '(c)'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = '(b)'
var_e = '(a)'
var_f = '>'
var_g = '(c)'
var_h = '(a)'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = len(list_c)
var_k = list_c[var_j-1]
print(var_k) |
Arithmetic calculation | The barrel has contained 4 fish (a) and 3 fish (b). I bought some more fish today and put them in the barrel, so there are 10 fish in total. How many more fish did I put in today? | 3 | 10 4 3 [OP_ADD] [OP_SUB] | var_a = 10
var_b = 4
var_c = 3
var_d = var_b + var_c
var_e = var_a - var_d
print(int(var_e)) |
Comparison | How many numbers greater than 256 have 5 in the tens digit and 2 in the hundreds digit? | 3 | [OP_LIST_SOL] 2 5 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 256 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 2
var_b = 5
var_c = 'A'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
ans_dict = dict()
var_d = str(var_d)
list_b = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_d) == len(str(int(temp))):
new_elem = int(temp)
list_b.append(new_elem)
var_e = 256
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Geometry | A square has two pairs of parallel sides. If the height of this square is 8 centimeters (cm) and the area is 78.88 square cm (cm2), what is the length? | 9.86 | 78.88 8 [OP_DIV] | var_a = 78.88
var_b = 8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | When Jiyoung opened the fairy tale book, the sum of the pages on the two pages she opened was 217. What is the product of the number of pages unfolded? | 11772 | 217 2 [OP_FDIV] 217 2 [OP_FDIV] 1 [OP_ADD] [OP_MUL] | var_a = 217
var_b = 2
var_c = var_a // var_b
var_d = 217
var_e = 2
var_f = var_d // var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c * var_h
print(int(var_i)) |
Geometry | The area of a trapezoid is 96.9 square centimeters (cm2). If the lower side is 3.6 centimeters (cm) shorter than the upper side and the height is 5.2 centimeters (cm), how many centimeters (cm) is the lower side? | 16.85 | 96.98 2 [OP_MUL] 5.2 [OP_DIV] 3.6 [OP_SUB] 2 [OP_DIV] | var_a = 96.98
var_b = 2
var_c = var_a * var_b
var_d = 5.2
var_e = var_c / var_d
var_f = 3.6
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | Find how many single digits are in all from 2 to 100. | 8 | 2 100 1 [OP_LIST_ARANGE] 9 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 2
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 9
list_b = []
for i in list_a:
if i <= var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Possibility | We are going to divide 54 apples equally into every plate. How many different ways can you portion it out on a plate? (However, not all 54 apples are placed on one plate.) | 7 | 54 [OP_LIST_GET_DIVISOR] [OP_LIST_SOL] 54 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] | var_a = 54
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = 54
list_b= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_b.append(var_b)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_c = len(list_c)
print(int(var_c)) |
Geometry | You are going to make as many small square pieces as possible by cutting out a large rectangular piece of paper measuring 262 centimeters (cm) long and 185 centimeters (cm) wide. Find how many square pieces of paper you can make. | 140 | 262 18 [OP_FDIV] 185 18 [OP_FDIV] [OP_MUL] | var_a = 262
var_b = 18
var_c = var_a // var_b
var_d = 185
var_e = 18
var_f = var_d // var_e
var_g = var_c * var_f
print(int(var_g)) |
Correspondence | If 2A3+36=269, what number should go in A? | 3 | 2A3+36=269 A [OP_DIGIT_UNK_SOLVER] | var_a = '2A3+36=269'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | Taehyung and Namjoon bought 10 pieces of colored paper each and used several of them. When Taehyung gave 3 of the remaining pieces of colored paper to Namjoon, the number of pieces of colored paper they both had ended up to 6. How many pieces of colored paper did Namjoon use? | 7 | 10 6 3 [OP_SUB] [OP_SUB] | var_a = 10
var_b = 6
var_c = 3
var_d = var_b - var_c
var_e = var_a - var_d
print(int(var_e)) |
Correspondence | Twelve candies that cost 530 won each, cost 5,400 won more than 8 chocolates. How much is one chocolate? | 120 | 530 12 [OP_MUL] 5400 [OP_SUB] 8 [OP_DIV] | var_a = 530
var_b = 12
var_c = var_a * var_b
var_d = 5400
var_e = var_c - var_d
var_f = 8
var_g = var_e / var_f
print(int(var_g)) |
Possibility | You are about to make two-digit numbers by using two of the four cards 3, 5, 6, and 7. Find the average of the multiples of 7 you can make. | 51.33 | [OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MEAN] | var_a = 3
var_b = 5
var_c = 6
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 7
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = 1
list_c = [float(i) for i in list_c]
var_h = sum(list_c)/len(list_c)
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.