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Correspondence | Dividing a number by 8, adding 8, subtracting 30, and multiplying by 6 equals 12. Find the number. | 192 | 12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL] | var_a = 12
var_b = 6
var_c = var_a / var_b
var_d = 30
var_e = var_c + var_d
var_f = 8
var_g = var_e - var_f
var_h = 8
var_i = var_g * var_h
print(int(var_i)) |
Comparison | There are two circles of A and B. The area of A is 198.4 square centimeters (cm2), and the area of B is 251.1 square centimeters (cm2). On the condition that pi is calculated as 3.1, what is the number of centimeters (cm) when you subtract the circumference of A from the circumference of B, including the decimal point? | 6.2 | 198.4 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] 251.1 3.1 [OP_DIV] 1 2 [OP_DIV] [OP_POW] 2 [OP_MUL] 3.1 [OP_MUL] [OP_SUB] [OP_ABS] | var_a = 198.4
var_b = 3.1
var_c = var_a / var_b
var_d = 1
var_e = 2
var_f = var_d / var_e
var_g = var_c ** var_f
var_h = 2
var_i = var_g * var_h
var_j = 3.1
var_k = var_i * var_j
var_l = 251.1
var_m = 3.1
var_n = var_l / var_m
var_o = 1
var_p = 2
var_q = var_o / var_p
var_r = var_n ** var_q
var_s = 2
var_t = var_r * var_s
var_u = 3.1
var_v = var_t * var_u
var_w = var_k - var_v
var_x = abs(var_w)
print('{:.2f}'.format(round(var_x+1e-10,2))) |
Arithmetic calculation | Find the sum of the sum of all even numbers and the sum of all odd numbers from 1 to 50. | 1275 | 1 50 [OP_LIST_EVEN] [OP_LIST_SUM] 1 50 [OP_LIST_ODD] [OP_LIST_SUM] [OP_ADD] | var_a = 1
var_b = 50
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
list_a = [float(i) for i in list_a]
var_c = sum(list_a)
var_d = 1
var_e = 50
list_b = []
if var_d%2==0:
for i in range(var_d+1, var_e+1, 2):
list_b.append(i)
else:
for i in range(var_d, var_e+1, 2):
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
var_g = var_c + var_f
print(int(var_g)) |
Arithmetic calculation | What is the smallest three-digit number that is divisible by the numbers 4 and 5? | 100 | 100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 100
var_b = 999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[var_f-1]
print(int(var_g)) |
Comparison | There are four numbers 0.8, 1/2, 0.9, 1/3. How many numbers are greater than 3? | 0 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Arithmetic calculation | You can make 60 toys in 5 days. How many days will it take to make 540? | 45 | 540 60 [OP_DIV] 5 [OP_MUL] | var_a = 540
var_b = 60
var_c = var_a / var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e)) |
Possibility | You are going to use 2 of 4 number cards 3, 5, 6, and 7 to create a two-digit number. How many multiples of 7 can you make? | 3 | [OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 3
var_b = 5
var_c = 6
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 7
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = len(list_c)
print(int(var_g)) |
Comparison | Minyoung jumped rope 52 times yesterday, and today she jumped 19 fewer times than yesterday. Yoojung jumped rope 18 times yesterday, and today she jumped 21 times more than yesterday. Who jumped more ropes today? | Yoojung | [OP_LIST_SOL] Minyoung Yoojung [OP_LIST_EOL] [OP_LIST_SOL] 52 19 [OP_SUB] 18 21 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Minyoung'
var_b = 'Yoojung'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 52
var_d = 19
var_e = var_c - var_d
var_f = 18
var_g = 21
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | The average score for Korean, English, social studies, and science is 90 points, and when math scores are included, the average score drops by 3 points. What is math score? | 75 | 90 3 [OP_SUB] 5 [OP_MUL] 90 4 [OP_MUL] [OP_SUB] | var_a = 90
var_b = 3
var_c = var_a - var_b
var_d = 5
var_e = var_c * var_d
var_f = 90
var_g = 4
var_h = var_f * var_g
var_i = var_e - var_h
print(int(var_i)) |
Arithmetic calculation | Namjoon took the test of 3 subjects: Korean, Mathematics, and English. If his math score is 100, his English 95, and the average score of 3 subjects is 95, what score did Namjoon's get in his Korean test? | 90 | 95 3 [OP_MUL] 100 [OP_SUB] 95 [OP_SUB] | var_a = 95
var_b = 3
var_c = var_a * var_b
var_d = 100
var_e = var_c - var_d
var_f = 95
var_g = var_e - var_f
print(int(var_g)) |
Correspondence | If A and B are different numbers and A2-5A=B3 is true, find the value of AxB. | 27 | A2-5A=B3 A [OP_DIGIT_UNK_SOLVER] A2-5A=B3 B [OP_DIGIT_UNK_SOLVER] [OP_MUL] | var_a = 'A2-5A=B3'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'A2-5A=B3'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c * var_f
print(int(var_g)) |
Possibility | A three-digit number was created by choosing three unequal numbers from 0 to 4. How many of these numbers have a remainder of 0 when divided by 2, 3, or 5? | 4 | [OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 3 [OP_LCM] 5 [OP_LCM] [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 2
var_h = 3
var_i = var_h * var_g / math.gcd(int(var_h), int(var_g))
var_j = 5
var_k = var_j * var_i / math.gcd(int(var_j), int(var_i))
list_c = []
var_k = int(var_k)
for i in list_b:
i = int(i)
if i % var_k == 0:
list_c.append(i)
var_l = len(list_c)
print(int(var_l)) |
Arithmetic calculation | The total number of students at Yerin's school is 32 fewer than eight times the number of 5th graders, and there are 10 more 5th grade boys than 5th grade girls. If the total number of students in Yerin's school is 1152, how many female students are there in the 5th grade? | 69 | 1152 32 [OP_ADD] 8 [OP_DIV] 10 [OP_SUB] 2 [OP_DIV] | var_a = 1152
var_b = 32
var_c = var_a + var_b
var_d = 8
var_e = var_c / var_d
var_f = 10
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | Find the sum of three-digit even natural numbers. | 247050 | 100 999 [OP_LIST_EVEN] [OP_LIST_SUM] | var_a = 100
var_b = 999
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
list_a = [float(i) for i in list_a]
var_c = sum(list_a)
print(int(var_c)) |
Possibility | Gwangho has four number magnets of 2, 6, 0, and 7. When playing the game of making three-digit numbers by choosing three of those magnets, find the difference between the third largest number and the third smallest number that he can make. | 466 | [OP_LIST_SOL] 2 6 0 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] | var_a = 2
var_b = 6
var_c = 0
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 3
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g - var_i
print(int(var_j)) |
Arithmetic calculation | Mingi solves 256 questions in 4 hours. If Somin can solve 111 questions in 3 hours, how many questions did Mingi and Somin solve in 3 hours? | 303 | 256 3 4 [OP_DIV] [OP_MUL] 111 [OP_ADD] | var_a = 256
var_b = 3
var_c = 4
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 111
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | There are 58 cucumbers in the mart. There are 24 fewer carrots than cucumbers, and 49 more tomatoes than cucumbers. The number of radishes equals the number of carrots. How many cucumbers, carrots, tomatoes, and radishes are in the mart in total? | 233 | 58 58 24 [OP_SUB] [OP_ADD] 58 49 [OP_ADD] [OP_ADD] 58 24 [OP_SUB] [OP_ADD] | var_a = 58
var_b = 58
var_c = 24
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 58
var_g = 49
var_h = var_f + var_g
var_i = var_e + var_h
var_j = 58
var_k = 24
var_l = var_j - var_k
var_m = var_i + var_l
print(int(var_m)) |
Arithmetic calculation | Yoojung is 5 years old this year. In the year when Yoojung turns 10, her grandmother is 60. Find what age is her grandmother this year. | 55 | 60 10 5 [OP_SUB] [OP_SUB] | var_a = 60
var_b = 10
var_c = 5
var_d = var_b - var_c
var_e = var_a - var_d
print(int(var_e)) |
Geometry | Find the value of adding 3 to the number of diagonals in the rectangle. | 5 | 4 4 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] 3 [OP_ADD] | var_a = 4
var_b = 4
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Possibility | You want to arrange 4 identical ballpoint pens and 1 mechanical pencil in a line. What is the number of cases to arrange them? | 5 | 4 1 [OP_ADD] | var_a = 4
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | The eight-digit number 757AB384 is divisible by 357. Get A. | 5 | 757AB384 [OP_GEN_POSSIBLE_LIST] 357 [OP_LIST_DIVISIBLE] 757AB384 B [OP_LIST_FIND_UNK] | var_a = '757AB384'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 357
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = '757AB384'
var_d = 'B'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
print(int(var_e)) |
Possibility | In Hyunseung's closet, there are 3 types of tops, 2 types of bottoms, and 5 types of shoes. How many types of tops, bottoms, and shoes can Hyunseung wear? | 30 | 3 2 [OP_MUL] 5 [OP_MUL] | var_a = 3
var_b = 2
var_c = var_a * var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | The money Minyoung had was enough to buy A pieces of candy worth 90 won. If he bought A pieces of 60 won candies instead of 90 won candies, and he had 270 won left, how much money does Minyoung have at first? | 810 | 270 90 60 [OP_SUB] [OP_DIV] 90 [OP_MUL] | var_a = 270
var_b = 90
var_c = 60
var_d = var_b - var_c
var_e = var_a / var_d
var_f = 90
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | There is 13/4 liter (L) of water in the water tank. From this water tank, 12/5 liter (L) was scooped out and 11/6 liter (L) was put back in. Find how many liters (L) of water are left in the water tank. | 2.68 | 13/4 12/5 [OP_SUB] 11/6 [OP_ADD] | var_a = 3.25
var_b = 2.4
var_c = var_a - var_b
var_d = 1.8333333333333333
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Geometry | A regular hexagon with an area of 54.3 square centimeters (cm2) is divided into 6 equal parts. How many square centimeters (cm2) is the area of one of the 6 equal parts? | 9.05 | 54.3 6 [OP_DIV] | var_a = 54.3
var_b = 6
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | A number multiplied by 2 minus 3 equals 7. After finding the number, find the remainder when dividing the number by 2. | 1 | 7 3 [OP_ADD] 2 [OP_DIV] 2 [OP_MOD] | var_a = 7
var_b = 3
var_c = var_a + var_b
var_d = 2
var_e = var_c / var_d
var_f = 2
var_g = var_e % var_f
print(int(var_g)) |
Arithmetic calculation | There are three numbers: 3/8, 0.125, and 9.51. What is the sum of all three numbers? | 10.01 | 3/8 0.125 [OP_ADD] 9.51 [OP_ADD] | var_a = 0.375
var_b = 0.125
var_c = var_a + var_b
var_d = 9.51
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | There is a machine that makes 32 toys per hour. Find how many boxes are needed to put 4 of the toys the machine made for 3 hours into each box. | 24 | 32 3 [OP_MUL] 4 [OP_DIV] | var_a = 32
var_b = 3
var_c = var_a * var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | A is 680. A is greater than B by 157. B is greater than C by 185. Find what number C is. | 338 | 680 157 [OP_SUB] 185 [OP_SUB] | var_a = 680
var_b = 157
var_c = var_a - var_b
var_d = 185
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | The number of students entering an art school is the same every year, and there are more female students than male students. This year, compared to last year, 16 more female students entered the school, and 64 more female students enrolled this year than male students enrolled. Find how many more female students entered school than male students last year. | 32 | 64 16 [OP_SUB] 16 [OP_SUB] | var_a = 64
var_b = 16
var_c = var_a - var_b
var_d = 16
var_e = var_c - var_d
print(int(var_e)) |
Geometry | A coin has a diameter of 100 millimeters (mm) and a circumference of 314 millimeters (mm). How many times bigger is the circumference compared to the diameter of this coin? | 3.14 | 314 100 [OP_DIV] | var_a = 314
var_b = 100
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | There are 7 bundles of 10 pencils each. There are 3 more colored pencils than pencils. Find how many colored pencils there are. | 73 | 7 10 [OP_MUL] 3 [OP_ADD] | var_a = 7
var_b = 10
var_c = var_a * var_b
var_d = 3
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | There are three natural numbers A, B and C. When A is divided by 9, the quotient is B and the remainder is C. In this expression, the remainder is 3 less than the quotient. Find the smallest number that can fit A. | 27 | 9 3 [OP_MUL] 0 [OP_ADD] | var_a = 9
var_b = 3
var_c = var_a * var_b
var_d = 0
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There were 8 rabbits. The next day, 5 new rabbits were born. How many rabbits are there now in total? | 13 | 8 5 [OP_ADD] | var_a = 8
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | I need to subtract 4 from a certain number, but I mistakenly subtracted 5 and it became 4. Find this certain number. | 9 | 4 5 [OP_ADD] | var_a = 4
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Comparison | Jungkook collected the quotient of 6 divided by 3, Yoongi collected 4, and Yuna collected 5. Who collected the smallest number? | Jungkook | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_FDIV] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d // var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | There are 20 rabbits in a row. How many rabbits are there between the 13th from the left and the 19th from the left? | 5 | 19 13 [OP_SUB] 1 [OP_SUB] | var_a = 19
var_b = 13
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Kyu-yeon and Na-eun are going to share 12 liters (L) and 400 milliliters (㎖) of apple juice for a week. If Kyu-yeon drank 2 liters (L) and 600 meters (m) liters (L) more than Na-eun when comparing the amount of apple juice she drank in a week, how many liters (L) of apple juice did Kyu-yeon drink? | 7.5 | 12 400 1000 [OP_DIV] [OP_ADD] 2 600 1000 [OP_DIV] [OP_ADD] [OP_ADD] 2 [OP_DIV] | var_a = 12
var_b = 400
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 2
var_g = 600
var_h = 1000
var_i = var_g / var_h
var_j = var_f + var_i
var_k = var_e + var_j
var_l = 2
var_m = var_k / var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Possibility | There are number cards from 1 to 9. If you make a 3-digit natural number by picking it by allowing duplicates, find how many possible numbers there are. | 729 | 1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | When you make a square by arranging 12 beads of the same size, 12 by 12 vertically and horizontally, find the number of beads placed around the perimeter. | 44 | 12 2 [OP_SUB] 4 [OP_MUL] 4 [OP_ADD] | var_a = 12
var_b = 2
var_c = var_a - var_b
var_d = 4
var_e = var_c * var_d
var_f = 4
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Pillars are embedded at intervals of 30 meters (m) along the circular track. If the length of the circular track is 1 kilometer (km) and 200 meters (m), how many poles are there? | 40 | 1 1000 [OP_MUL] 200 [OP_ADD] 30 [OP_DIV] | var_a = 1
var_b = 1000
var_c = var_a * var_b
var_d = 200
var_e = var_c + var_d
var_f = 30
var_g = var_e / var_f
print(int(var_g)) |
Possibility | How many different ways can father, mother, and Hoseok stand side by side? | 6 | [OP_LIST_SOL] father mother Hoseok [OP_LIST_EOL] [OP_LIST_LEN] 3 [OP_PERM] | var_a = 'father'
var_b = 'mother'
var_c = 'Hoseok'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 3
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
print(int(var_f)) |
Correspondence | 76 is the result of subtracting 29 from and adding 64 to a particular number. What is that particular number? | 41 | 76 64 [OP_SUB] 29 [OP_ADD] | var_a = 76
var_b = 64
var_c = var_a - var_b
var_d = 29
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | Seung-hyeon gave Su-yeon 2 pieces of pizza, and Seung-hyeon had 5 more pieces of pizza than Su-yeon had. Find how many more pieces Seung-hyeon had before giving them. | 9 | 5 2 [OP_ADD] 2 [OP_ADD] | var_a = 5
var_b = 2
var_c = var_a + var_b
var_d = 2
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | Find the two-digit number from 2 to 56. | 47 | 10 56 1 [OP_LIST_ARANGE] [OP_LIST_LEN] | var_a = 10
var_b = 56
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = len(list_a)
print(int(var_d)) |
Correspondence | Rounding down the number A567 to the nearest tens gives 2560. What is A? | 2 | A567 [OP_GEN_POSSIBLE_LIST] 2560 [OP_LIST_MORE_EQUAL] 2560 10 [OP_ADD] [OP_LIST_LESS] A567 A [OP_LIST_FIND_UNK] | var_a = 'A567'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 2560
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 2560
var_d = 10
var_e = var_c + var_d
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = 'A567'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Geometry | You made a round loop by gluing twelve sheets of paper tape that are each 18 centimeters (cm) long. If they are overlapped by the same length and the shape has a perimeter of 210 centimeters (cm), how many millimeters (mm) are the overlapped parts? | 5 | 18 12 [OP_MUL] 210 [OP_SUB] 12 [OP_DIV] 10 [OP_MUL] | var_a = 18
var_b = 12
var_c = var_a * var_b
var_d = 210
var_e = var_c - var_d
var_f = 12
var_g = var_e / var_f
var_h = 10
var_i = var_g * var_h
print(int(var_i)) |
Correspondence | Subtract a number from 48, multiply it by 4, subtract 26, and divide it by 2. Then, the result is 37. Find the number. | 23 | 48 37 2 [OP_MUL] 26 [OP_ADD] 4 [OP_DIV] [OP_SUB] | var_a = 48
var_b = 37
var_c = 2
var_d = var_b * var_c
var_e = 26
var_f = var_d + var_e
var_g = 4
var_h = var_f / var_g
var_i = var_a - var_h
print(int(var_i)) |
Comparison | Which number is greater, 70 or 68? | 70 | [OP_LIST_SOL] 70 68 [OP_LIST_EOL] 1 [OP_LIST_MAX] | var_a = 70
var_b = 68
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
print(int(var_d)) |
Arithmetic calculation | There are 6 cucumbers and 8 tomatoes on the farm. There are also 2 apples and 4 bananas. Find the number of vegetables on the farm minus the number of fruits. | 8 | 6 8 [OP_ADD] 2 4 [OP_ADD] [OP_SUB] | var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 2
var_e = 4
var_f = var_d + var_e
var_g = var_c - var_f
print(int(var_g)) |
Correspondence | When you add 3 to a number, you get 6. What number is it when you add 5 to the number? | 8 | 6 3 [OP_SUB] 5 [OP_ADD] | var_a = 6
var_b = 3
var_c = var_a - var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e)) |
Comparison | The distance from Bogyeom's house to Haneul's house is 150 meters (m) farther than 3 kilometers (km), and the distance to Seongju's house is 3096 meters (m). Of the two friends, Haneul and Seongju, who lives farther away from Bogyeom? | Haneul | [OP_LIST_SOL] Haneul Seongju [OP_LIST_EOL] [OP_LIST_SOL] 3 1000 [OP_MUL] 150 [OP_ADD] 3096 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Haneul'
var_b = 'Seongju'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 3
var_d = 1000
var_e = var_c * var_d
var_f = 150
var_g = var_e + var_f
var_h = 3096
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | Nine people stand in a line in ascending order according to their heights. Hoseok is third from the front, and Yuna is 2 position before Hoseok. If you line them up again in descending order, in what position will Yuna be? Answer in ordinal number. | 9 | 9 3 [OP_SUB] 2 [OP_ADD] 1 [OP_ADD] | var_a = 9
var_b = 3
var_c = var_a - var_b
var_d = 2
var_e = var_c + var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) |
Comparison | There is a regular-pentagon with a length of 7 centimeters (cm) on one side and a regular-hexagon with a length of 6 centimeters (cm) on one side. Which shape has the greater perimeter? | regular-hexagon | [OP_LIST_SOL] regular-hexagon regular-pentagon [OP_LIST_EOL] [OP_LIST_SOL] 6 6 [OP_MUL] 7 5 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'regular-hexagon'
var_b = 'regular-pentagon'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 6
var_e = var_c * var_d
var_f = 7
var_g = 5
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | When I wrongly multiplied a number by 12 that should actually be divided by 12, I got 84.6. Find out how much it is if you calculate it correctly. | 0.59 | 84.6 12 [OP_DIV] 12 [OP_DIV] | var_a = 84.6
var_b = 12
var_c = var_a / var_b
var_d = 12
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | If an elevator starts at 120 meters (m) above the ground and descends at a speed of 4 meters (m) per second without stopping, find how many seconds after departure it will reach 20 meters (m) above the ground. | 25 | 120 20 [OP_SUB] 4 [OP_DIV] | var_a = 120
var_b = 20
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | The chicken laid 30 eggs today and 19 eggs yesterday. How many eggs did it lay in total? | 49 | 30 19 [OP_ADD] | var_a = 30
var_b = 19
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | At Seoul Elementary School, milk is distributed equally to the students, but when milk was distributed to 6 classes that should have been distributed to 8 classes, 124 packs were given to each class and 4 packs left over. Calculate how many milks are left if divided normally. | 4 | 124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_MOD] | var_a = 124
var_b = 6
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
var_f = 8
var_g = var_e % var_f
print(int(var_g)) |
Possibility | What is the largest minus the smallest six-digit number that can be formed using 1, 4, and 0 twice? | 340956 | [OP_LIST_SOL] 1 1 4 4 0 0 [OP_LIST_EOL] 6 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 1
var_b = 1
var_c = 4
var_d = 4
var_e = 0
var_f = 0
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 6
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_g))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_h = 1
list_c=list_b.copy()
list_c.sort()
var_i = list_c[-var_h]
var_j = 1
list_d=list_b.copy()
list_d.sort()
var_k = list_d[var_j-1]
var_l = var_i - var_k
print(int(var_l)) |
Correspondence | If you divide a number by 10, the result is 6. Find the exact result of subtracting 15 from the number. | 45 | 6 10 [OP_MUL] 15 [OP_SUB] | var_a = 6
var_b = 10
var_c = var_a * var_b
var_d = 15
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | When Minhyuk asked Kihyun's math test score, Kihyun answered it would be 90 if he rounded it off to 10 digits. What is the biggest number possible with Kihyun's math score? | 94 | [OP_LIST_SOL] 9 A [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 90 5 [OP_ADD] [OP_LIST_LESS] 1 [OP_LIST_MAX] | var_a = 9
var_b = 'A'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c=""
for i in list_a:
i = str(i)
var_c = var_c + i
ans_dict = dict()
var_c = str(var_c)
list_b = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_c):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_c
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_c) == len(str(int(temp))):
new_elem = int(temp)
list_b.append(new_elem)
var_d = 90
var_e = 5
var_f = var_d + var_e
list_c = []
for i in list_b:
if i < var_f:
list_c.append(i)
var_g = 1
list_d=list_c.copy()
list_d.sort()
var_h = list_d[-var_g]
print(int(var_h)) |
Possibility | You can place a magnet with the natural numbers 6 and 3 on it, one in the tens place and one in the ones place. What is the largest number you can make? | 63 | [OP_LIST_SOL] 6 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] | var_a = 6
var_b = 3
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = 1
list_c=list_b.copy()
list_c.sort()
var_e = list_c[-var_d]
print(int(var_e)) |
Possibility | How many two-digit numbers can be made with 0, 6, and 3? Note that the tens and ones places must be different. | 4 | [OP_LIST_SOL] 6 0 3 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 6
var_b = 0
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Correspondence | There are 3 boxes of carrots which contains 32 of them each, and you are going to put 4 of these carrots in each basket. How many baskets do you need to put carrots in? | 24 | 32 3 [OP_MUL] 4 [OP_DIV] | var_a = 32
var_b = 3
var_c = var_a * var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There is a box with 3 cabbages and 2 radishes. How many vegetables are in the box? | 5 | 3 2 [OP_ADD] | var_a = 3
var_b = 2
var_c = var_a + var_b
print(int(var_c)) |
Arithmetic calculation | One pear weighs 0.36 kilograms (kg). When a basket contains 30 pears, the weight of the entire basket is 11.26 kilograms (kg). Find the weight in kilograms (kg) of the empty basket. | 0.46 | 11.26 0.36 30 [OP_MUL] [OP_SUB] | var_a = 11.26
var_b = 0.36
var_c = 30
var_d = var_b * var_c
var_e = var_a - var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | The bag contains 2 fewer blue marbles than yellow marbles. If the sum of the yellow and blue marbles is 240, how many yellow marbles are there? | 121 | 240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD] | var_a = 240
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Hyeonil rode a bicycle and moved for an hour at a speed of 4.25 meters (m) per minute. After that, if he moved 29.75 meters (m) at the same speed, find how many minutes Hyunil rode the bicycle. | 67 | 29.75 4.25 [OP_DIV] 1 60 [OP_MUL] [OP_ADD] | var_a = 29.75
var_b = 4.25
var_c = var_a / var_b
var_d = 1
var_e = 60
var_f = var_d * var_e
var_g = var_c + var_f
print(int(var_g)) |
Possibility | If all divisors of 75 are written once, how many times the number 5 must be written? | 4 | 75 [OP_LIST_GET_DIVISOR] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM] | var_a = 75
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
if var_a % i == 0:
list_a.append(i)
list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b=""
for i in list_a:
i = str(i)
var_b = var_b + i
list_b = []
var_b = int(var_b)
while var_b//10 > 0:
list_b.append(var_b%10)
var_b = var_b//10
list_b.append(var_b%10)
list_b = list_b[::-1]
var_c = 5
var_d = 0
var_c = int(var_c)
for i in list_b:
i = int(i)
if i == var_c:
var_d = var_d + 1
print(int(var_d)) |
Geometry |
There is a rhombic hairpin with two diagonals measuring 9 centimeters (cm) and 14 centimeters (cm), respectively. How wide is this hairpin? | 63 | 9 14 [OP_MUL] 2 [OP_DIV] | var_a = 9
var_b = 14
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There are 2180 tangerines. You distribute them in boxes of 200 and 150 to have organized 12 boxes in total, and then 30 tangerines are left. How many boxes of 200 are there? | 7 | 2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV] | var_a = 2180
var_b = 30
var_c = var_a - var_b
var_d = 150
var_e = 12
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 200
var_i = 150
var_j = var_h - var_i
var_k = var_g / var_j
print(int(var_k)) |
Comparison | There are 9/10 liters (L) of milk. Suyeon drank 1/3 of the total, and Hyunwoo 4/9 of the total. Who drank more milk, Suyeon or Hyunwoo? | Hyunwoo | [OP_LIST_SOL] Suyeon Hyunwoo [OP_LIST_EOL] [OP_LIST_SOL] 1 3 [OP_DIV] 4 9 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Suyeon'
var_b = 'Hyunwoo'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
var_d = 3
var_e = var_c / var_d
var_f = 4
var_g = 9
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | 6A5+B03=748. How much is B? | 1 | 6A5+B03=748 B [OP_DIGIT_UNK_SOLVER] | var_a = '6A5+B03=748'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | How many of the numbers between 40 and 80 are multiples of 8? | 6 | 40 80 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 40
var_b = 80
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 8
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Possibility | Jungkook wants to buy two different fruits and give them to Jimin and Yoongi as a present. If the fruits sold at the fruit store are apples, peaches, and pears, in how many ways can you gift them? | 6 | [OP_LIST_SOL] apples peaches pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM] | var_a = 'apples'
var_b = 'peaches'
var_c = 'pears'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
print(int(var_f)) |
Comparison | Taehyung, Minju, Sangmin, Yoonjeong, and Yoojung crossed the finish line in turn. Who came in last? | Yoojung | [OP_LIST_SOL] Taehyung Minju Sangmin Yoonjeong Yoojung [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'Taehyung'
var_b = 'Minju'
var_c = 'Sangmin'
var_d = 'Yoonjeong'
var_e = 'Yoojung'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = list_a[var_f-1]
print(var_g) |
Possibility | You want to create a four-digit number where the sum of each digit is 15. How many numbers can you make in total? | 519 | 1000 9999 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 15 [OP_LIST_LESS_EQUAL] 15 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] | var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
list_b=[]
for i in list_a:
var_d = 0
i = int(i)
while i//10 > 0:
var_d = var_d + i%10
i = i//10
var_d = var_d + i%10
list_b.append(var_d)
var_e = 15
list_c = []
for i in list_b:
if i <= var_e:
list_c.append(i)
var_f = 15
list_d = []
for i in list_c:
if i >= var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Arithmetic calculation | A hybrid car has two or more types of power units. Jaeho's family rode a hybrid car and arrived at his aunt's house, which is 120 kilometers (km) away, in an hour and 50 minutes. At first, they used electricity only, and later on gasoline only for an hour and ten minutes. This car needs 6 liters of gasoline to go 40.8 kilometers (km), and if Jaeho's family used 14 liters of gasoline to go to his aunt's house, how many kilometers (km) is the distance that this car used only electricity for 1 minute? | 0.62 | 120 40.8 6 [OP_DIV] 14 [OP_MUL] [OP_SUB] 1 60 [OP_MUL] 50 [OP_ADD] 1 60 [OP_MUL] 10 [OP_ADD] [OP_SUB] [OP_DIV] | var_a = 120
var_b = 40.8
var_c = 6
var_d = var_b / var_c
var_e = 14
var_f = var_d * var_e
var_g = var_a - var_f
var_h = 1
var_i = 60
var_j = var_h * var_i
var_k = 50
var_l = var_j + var_k
var_m = 1
var_n = 60
var_o = var_m * var_n
var_p = 10
var_q = var_o + var_p
var_r = var_l - var_q
var_s = var_g / var_r
print('{:.2f}'.format(round(var_s+1e-10,2))) |
Correspondence | 397 is 236 lesser than a certain number. What is the value of a number that is 496 lesser than this certain number? | 137 | 397 236 [OP_ADD] 496 [OP_SUB] | var_a = 397
var_b = 236
var_c = var_a + var_b
var_d = 496
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There are three numbers 10, 11 and 12. What is the quotient of the largest number divided by the smallest number? | 1 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
var_f = 1
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e // var_g
print(int(var_h)) |
Correspondence | Subtract 5 from a number and divide by 3. Find the number for the result to be 4. | 17 | 4 3 [OP_MUL] 5 [OP_ADD] | var_a = 4
var_b = 3
var_c = var_a * var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are 7 different boxes with 2, 3, 3, 2, 1, 2, 1 chocolates, respectively. How many boxes contain 2 chocolates? | 3 | [OP_LIST_SOL] 2 3 3 2 1 2 1 [OP_LIST_EOL] 2 [OP_LIST_FIND_NUM] | var_a = 2
var_b = 3
var_c = 3
var_d = 2
var_e = 1
var_f = 2
var_g = 1
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 2
var_i = 0
var_h = int(var_h)
for i in list_a:
i = int(i)
if i == var_h:
var_i = var_i + 1
print(int(var_i)) |
Geometry | I used all 12/25 meters (m) of wire to make one of the largest squares. What is the side length of this square in meters (m)? | 0.12 | 12/25 4 [OP_DIV] | var_a = 0.48
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | The fee for renting a bicycle for 30 minutes is 4,000 won. How much does one person get to pay when renting 4 bikes for 3 hours with 6 people paying equally? | 16000 | 3 60 [OP_MUL] 30 [OP_DIV] 4000 [OP_MUL] 4 [OP_MUL] 6 [OP_DIV] | var_a = 3
var_b = 60
var_c = var_a * var_b
var_d = 30
var_e = var_c / var_d
var_f = 4000
var_g = var_e * var_f
var_h = 4
var_i = var_g * var_h
var_j = 6
var_k = var_i / var_j
print(int(var_k)) |
Possibility | When you ask a passerby to pick random two numbers from 1 to 4, what is the number of cases where they pick two even numbers or only one even number? | 5 | 2 2 [OP_COMB] 2 1 [OP_COMB] 2 1 [OP_COMB] [OP_MUL] [OP_ADD] | var_a = 2
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
var_d = 2
var_e = 1
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
var_g = 2
var_h = 1
var_i = 1
var_g = int(var_g)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_g-i)
for i, elem in enumerate(range(var_h)):
var_i = var_i / (i+1)
var_j = var_f * var_i
var_k = var_c + var_j
print(int(var_k)) |
Correspondence | Of the 15 people, 7 are women. If only men carry 48 loads, find how many loads each person can carry if they all share the same load. | 6 | 48 15 7 [OP_SUB] [OP_DIV] | var_a = 48
var_b = 15
var_c = 7
var_d = var_b - var_c
var_e = var_a / var_d
print(int(var_e)) |
Arithmetic calculation | Sunmi scored 75 points in Korean, 85 points in math, 90 points in science, and 65 points in English in the midterm exam. In how many subjects was Sunmi above the midterm average? | 2 | [OP_LIST_SOL] 75 85 90 65 [OP_LIST_EOL] [OP_LIST_MEAN] [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 75
var_b = 85
var_c = 90
var_d = 65
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_e = sum(list_a)/len(list_a)
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Comparison | Youngbin and Yechan are playing knocking down cans with a slingshot. Youngbin fired 25 shots and knocked down 19, and Yechan shot 16 and knocked down 10. Which of the two has a higher success rate? | Youngbin | [OP_LIST_SOL] Youngbin Yechan [OP_LIST_EOL] [OP_LIST_SOL] 19 25 [OP_DIV] 10 16 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Youngbin'
var_b = 'Yechan'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 19
var_d = 25
var_e = var_c / var_d
var_f = 10
var_g = 16
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | The quotient of 59 divided by 8 is A and the remainder is 3. What is the value of A? | 7 | 59 3 [OP_SUB] 8 [OP_DIV] | var_a = 59
var_b = 3
var_c = var_a - var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | I made a mistake in dividing a number by 4, and instead added by 4 to get 40. Find the correctly calculated value. | 9 | 40 4 [OP_SUB] 4 [OP_DIV] | var_a = 40
var_b = 4
var_c = var_a - var_b
var_d = 4
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | There are two different numbers A and B. Find the sum of A and B in the two-digit subtraction formula, A5-2A=B7. | 13 | A5-2A=B7 A [OP_DIGIT_UNK_SOLVER] A5-2A=B7 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = 'A5-2A=B7'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'A5-2A=B7'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Possibility | I want to paint the 4 parts A, B, C,and D with 4 colors red, yellow, blue and green. Find the number of ways to color each part with a different color. | 24 | 4 4 [OP_PERM] | var_a = 4
var_b = 4
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) |
Comparison | Dongguk drinks water 5 times a day and drinks 0.2 liters (L) each time. Yoonji drinks water 6 times a day and drinks 0.3 liters (L) per drink. Heejin drinks water 4 times a day and drinks 500 milliliters (ml) per drink. Who drinks the most water per day? | Heejin | [OP_LIST_SOL] Dongguk Yoonji Heejin [OP_LIST_EOL] [OP_LIST_SOL] 5 0.2 1000 [OP_MUL] [OP_MUL] 6 0.3 1000 [OP_MUL] [OP_MUL] 4 500 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Dongguk'
var_b = 'Yoonji'
var_c = 'Heejin'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 5
var_e = 0.2
var_f = 1000
var_g = var_e * var_f
var_h = var_d * var_g
var_i = 6
var_j = 0.3
var_k = 1000
var_l = var_j * var_k
var_m = var_i * var_l
var_n = 4
var_o = 500
var_p = var_n * var_o
list_b= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_q = 1
list_c=list_b.copy()
list_c.sort()
var_r = list_c[-var_q]
var_s = list_b.index(var_r)+1
var_t = list_a[var_s-1]
print(var_t) |
Geometry | There is a rectangular frame with a width of 81/4 centimeters (cm) and a depth of 148/9 centimeters (cm). Find the area of this frame. | 333 | 81/4 148/9 [OP_MUL] | var_a = 20.25
var_b = 16.444444444444443
var_c = var_a * var_b
print(int(eval('{:.2f}'.format(round(var_c+1e-10,2))))) |
Possibility | You want to create a four-digit number using all 4, 5, 8, and 9. When you made the third smallest number, two numbers in the middle were swapped, resulting in 4958. Find the sum of the number created and the number changed. | 9817 | [OP_LIST_SOL] 4 5 8 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 3 [OP_LIST_MIN] 4958 [OP_ADD] | var_a = 4
var_b = 5
var_c = 8
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 3
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = 4958
var_i = var_g + var_h
print(int(var_i)) |
Correspondence | Ji-woo used half of his money and 2,000 won to buy snacks at the mart. Then, he used half of the remaining money to buy chocolate, and 2,000 won and 1,000 won to buy drinks and water. How much money does Ji-woo have at first if he has no money left? | 16000 | 0 2000 [OP_ADD] 1000 [OP_ADD] 2 [OP_MUL] 2000 [OP_ADD] 2 [OP_MUL] | var_a = 0
var_b = 2000
var_c = var_a + var_b
var_d = 1000
var_e = var_c + var_d
var_f = 2
var_g = var_e * var_f
var_h = 2000
var_i = var_g + var_h
var_j = 2
var_k = var_i * var_j
print(int(var_k)) |
Correspondence | A fisherman catches three fish per one fishing line. Out of 226 fishing lines, 3 were broken and discarded. How many fish did the fisherman catch? | 669 | 226 3 [OP_SUB] 3 [OP_MUL] | var_a = 226
var_b = 3
var_c = var_a - var_b
var_d = 3
var_e = var_c * var_d
print(int(var_e)) |
Geometry | Jimin randomly picked 4 numbers between 50 and 200, and 3 of them were 75, 80, and 120, respectively. What should be the other number so that the sum of them is equal to interior angles of the quadrilateral? | 85 | 360 75 [OP_SUB] 80 [OP_SUB] 120 [OP_SUB] | var_a = 360
var_b = 75
var_c = var_a - var_b
var_d = 80
var_e = var_c - var_d
var_f = 120
var_g = var_e - var_f
print(int(var_g)) |
Geometry | What is the length of the other side of a right triangle with hypotenuse and non-hypotenuse sides equal to 5 and 3 respectively? | 4 | 5 2 [OP_POW] 3 2 [OP_POW] [OP_SUB] 1/2 [OP_POW] | var_a = 5
var_b = 2
var_c = var_a ** var_b
var_d = 3
var_e = 2
var_f = var_d ** var_e
var_g = var_c - var_f
var_h = 0.5
var_i = var_g ** var_h
print(int(var_i)) |
Correspondence | When you add 8 and multiply by 3 to this number it becomes 36. Find the number. | 4 | 36 3 [OP_DIV] 8 [OP_SUB] | var_a = 36
var_b = 3
var_c = var_a / var_b
var_d = 8
var_e = var_c - var_d
print(int(var_e)) |
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