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Qual é a idade máxima e mínima dos estudantes com 600 cursos?
CREATE TABLE STUDENT (Age INTEGER, Major VARCHAR)
SELECT MAX(Age), MIN(Age) FROM STUDENT WHERE Major = 600
Quem são os conselheiros para estudantes que vivem em uma cidade com código de cidade "BAL"?
CREATE TABLE STUDENT (Advisor VARCHAR, city_code VARCHAR)
SELECT Advisor FROM STUDENT WHERE city_code = "BAL"
Quais são os votos dos secretários no ciclo eleitoral de outono?
CREATE TABLE VOTING_RECORD (Secretary_Vote VARCHAR, ELECTION_CYCLE VARCHAR)
SELECT DISTINCT Secretary_Vote FROM VOTING_RECORD WHERE ELECTION_CYCLE = "Fall"
Quais são as votações presidenciais distintas de 30/08/2015?
CREATE TABLE VOTING_RECORD (PRESIDENT_Vote VARCHAR, Registration_Date VARCHAR)
SELECT DISTINCT PRESIDENT_Vote FROM VOTING_RECORD WHERE Registration_Date = "08/30/2015"
Indicar a data de registo e o ciclo eleitoral.
CREATE TABLE VOTING_RECORD (Registration_Date VARCHAR, Election_Cycle VARCHAR)
SELECT DISTINCT Registration_Date, Election_Cycle FROM VOTING_RECORD
Relata a votação do presidente e a do vice-presidente.
CREATE TABLE VOTING_RECORD (President_Vote VARCHAR, VICE_President_Vote VARCHAR)
SELECT DISTINCT President_Vote, VICE_President_Vote FROM VOTING_RECORD
Encontre os nomes dos alunos que votaram no presidente da turma.
CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (CLASS_President_VOTE VARCHAR)
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_President_VOTE
Encontre os nomes dos estudantes que têm votos de senadores.
CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (CLASS_Senator_VOTE VARCHAR)
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.CLASS_Senator_VOTE
Encontre as idades distintas dos estudantes que têm votos de secretário no ciclo de eleições de outono.
CREATE TABLE VOTING_RECORD (Secretary_Vote VARCHAR, Election_Cycle VARCHAR); CREATE TABLE STUDENT (Age VARCHAR, StuID VARCHAR)
SELECT DISTINCT T1.Age FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Secretary_Vote WHERE T2.Election_Cycle = "Fall"
Encontre o conselheiro distinto dos estudantes que têm votos de tesoureiro no ciclo de eleições de primavera.
CREATE TABLE STUDENT (Advisor VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Treasurer_Vote VARCHAR, Election_Cycle VARCHAR)
SELECT DISTINCT T1.Advisor FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote WHERE T2.Election_Cycle = "Spring"
Encontre os principais cursos dos estudantes que têm votos de tesoureiro.
CREATE TABLE VOTING_RECORD (Treasurer_Vote VARCHAR); CREATE TABLE STUDENT (Major VARCHAR, StuID VARCHAR)
SELECT DISTINCT T1.Major FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.Treasurer_Vote
Encontre o nome e o apelido de todas as estudantes do sexo feminino (sexo é F) que têm votos para o presidente.
CREATE TABLE STUDENT (Fname VARCHAR, LName VARCHAR, StuID VARCHAR, sex VARCHAR); CREATE TABLE VOTING_RECORD (President_VOTE VARCHAR)
SELECT DISTINCT T1.Fname, T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.President_VOTE WHERE T1.sex = "F"
Encontre o nome e o apelido de todos os estudantes com 18 anos que têm votos de vice-presidente.
CREATE TABLE STUDENT (Fname VARCHAR, LName VARCHAR, StuID VARCHAR, age VARCHAR); CREATE TABLE VOTING_RECORD (VICE_President_VOTE VARCHAR)
SELECT DISTINCT T1.Fname, T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_President_VOTE WHERE T1.age = 18
Quantos estudantes do sexo masculino (sexo é M) têm votos de senadores da classe no ciclo de eleições de outono?
CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR); CREATE TABLE STUDENT (StuID VARCHAR, Sex VARCHAR)
SELECT COUNT(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.Sex = "M" AND T2.Election_Cycle = "Fall"
Encontre o número de estudantes cujo código de cidade é NYC e que têm votos de senadores de classe no ciclo de eleições de primavera.
CREATE TABLE STUDENT (StuID VARCHAR, city_code VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR)
SELECT COUNT(*) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = Class_Senator_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
Encontre a idade média dos estudantes que vivem na cidade com código "NYC" e têm votos de secretário no ciclo de eleições de primavera.
CREATE TABLE STUDENT (Age INTEGER, StuID VARCHAR, city_code VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR)
SELECT AVG(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.city_code = "NYC" AND T2.Election_Cycle = "Spring"
Encontre a idade média das estudantes do sexo feminino (sexo é F) que têm votos de secretária no ciclo de eleições da primavera.
CREATE TABLE STUDENT (Age INTEGER, StuID VARCHAR, Sex VARCHAR); CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR)
SELECT AVG(T1.Age) FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = SECRETARY_Vote WHERE T1.Sex = "F" AND T2.Election_Cycle = "Spring"
Encontre os nomes de todos os estudantes que votaram no vice-presidente e cujo código da cidade não é PIT.
CREATE TABLE STUDENT (Fname VARCHAR, city_code VARCHAR); CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (VICE_PRESIDENT_Vote VARCHAR)
SELECT DISTINCT T1.Fname FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = T2.VICE_PRESIDENT_Vote EXCEPT SELECT DISTINCT Fname FROM STUDENT WHERE city_code = "PIT"
Encontre os nomes de todos os estudantes que têm votos de presidente e cujo conselheiro não é 2192.
CREATE TABLE STUDENT (LName VARCHAR, PRESIDENT_Vote VARCHAR, Advisor VARCHAR); CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Id VARCHAR)
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote EXCEPT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "2192"
Encontre os nomes de todos os estudantes que têm votos para presidente e cujo conselheiro é 8741.
CREATE TABLE STUDENT (LName VARCHAR, PRESIDENT_Vote VARCHAR, Advisor VARCHAR); CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE VOTING_RECORD (Id VARCHAR)
SELECT DISTINCT T1.LName FROM STUDENT AS T1 JOIN VOTING_RECORD AS T2 ON T1.StuID = PRESIDENT_Vote INTERSECT SELECT DISTINCT LName FROM STUDENT WHERE Advisor = "8741"
Para cada orientador, indicar o número total de alunos orientados por ele.
CREATE TABLE STUDENT (Advisor VARCHAR)
SELECT Advisor, COUNT(*) FROM STUDENT GROUP BY Advisor
Relatar todos os conselheiros que aconselham mais de 2 alunos.
CREATE TABLE STUDENT (Advisor VARCHAR)
SELECT Advisor FROM STUDENT GROUP BY Advisor HAVING COUNT(*) > 2
Relata todas as especialidades que têm menos de 3 alunos.
CREATE TABLE STUDENT (Major VARCHAR)
SELECT Major FROM STUDENT GROUP BY Major HAVING COUNT(*) < 3
Para cada ciclo eleitoral, notificar o número de registos de votação.
CREATE TABLE VOTING_RECORD (Election_Cycle VARCHAR)
SELECT Election_Cycle, COUNT(*) FROM VOTING_RECORD GROUP BY Election_Cycle
Qual é a especialidade que tem mais alunos?
CREATE TABLE STUDENT (Major VARCHAR, major VARCHAR)
SELECT Major FROM STUDENT GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1
Qual é a especialidade mais comum entre estudantes do sexo feminino (sexo é F)?
CREATE TABLE STUDENT (Major VARCHAR, major VARCHAR, Sex VARCHAR)
SELECT Major FROM STUDENT WHERE Sex = "F" GROUP BY major ORDER BY COUNT(*) DESC LIMIT 1
Qual é o código da cidade em que mais estudantes vivem?
CREATE TABLE STUDENT (city_code VARCHAR)
SELECT city_code FROM STUDENT GROUP BY city_code ORDER BY COUNT(*) DESC LIMIT 1
Quantos produtos há?
CREATE TABLE products (Id VARCHAR)
SELECT COUNT(*) FROM products
Quantas cores há?
CREATE TABLE ref_colors (Id VARCHAR)
SELECT COUNT(*) FROM ref_colors
Quantas características há?
CREATE TABLE CHARACTERISTICS (Id VARCHAR)
SELECT COUNT(*) FROM CHARACTERISTICS
Quais são os nomes e os preços de compra de todos os produtos?
CREATE TABLE products (product_name VARCHAR, typical_buying_price VARCHAR)
SELECT product_name, typical_buying_price FROM products
Escreva a descrição de todas as cores.
CREATE TABLE ref_colors (color_description VARCHAR)
SELECT color_description FROM ref_colors
Encontre os nomes de todas as características do produto.
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR)
SELECT DISTINCT characteristic_name FROM CHARACTERISTICS
Quais são os nomes dos produtos da categoria "Especiarias"?
CREATE TABLE products (product_name VARCHAR, product_category_code VARCHAR)
SELECT product_name FROM products WHERE product_category_code = "Spices"
Indicar os nomes, as descrições de cores e as descrições dos produtos da categoria "Ervas".
CREATE TABLE Ref_colors (color_description VARCHAR, color_code VARCHAR); CREATE TABLE products (product_name VARCHAR, product_description VARCHAR, color_code VARCHAR)
SELECT T1.product_name, T2.color_description, T1.product_description FROM products AS T1 JOIN Ref_colors AS T2 ON T1.color_code = T2.color_code WHERE product_category_code = "Herbs"
Quantos produtos estão na categoria "Sementes"?
CREATE TABLE products (product_category_code VARCHAR)
SELECT COUNT(*) FROM products WHERE product_category_code = "Seeds"
Encontre o número de produtos da categoria "Especiarias" e normalmente vendidos acima de 1000.
CREATE TABLE products (product_category_code VARCHAR, typical_buying_price VARCHAR)
SELECT COUNT(*) FROM products WHERE product_category_code = "Spices" AND typical_buying_price > 1000
Qual é a categoria e o preço de compra típico do produto com o nome "cominho"?
CREATE TABLE products (product_category_code VARCHAR, typical_buying_price VARCHAR, product_name VARCHAR)
SELECT product_category_code, typical_buying_price FROM products WHERE product_name = "cumin"
A que categoria pertence o produto denominado "linho"?
CREATE TABLE products (product_category_code VARCHAR, product_name VARCHAR)
SELECT product_category_code FROM products WHERE product_name = "flax"
Qual é o nome do produto com a descrição da cor "amarelo"?
CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_name VARCHAR, color_code VARCHAR)
SELECT T1.product_name FROM products AS T1 JOIN ref_colors AS T2 ON T1.color_code = T2.color_code WHERE T2.color_description = 'yellow'
Encontrar as descrições das categorias dos produtos cujas descrições incluem a letra "t".
CREATE TABLE ref_product_categories (product_category_description VARCHAR, product_category_code VARCHAR); CREATE TABLE products (product_category_code VARCHAR, product_description VARCHAR)
SELECT T1.product_category_description FROM ref_product_categories AS T1 JOIN products AS T2 ON T1.product_category_code = T2.product_category_code WHERE T2.product_description LIKE '%t%'
Qual é a descrição da cor do produto com o nome "catnip"?
CREATE TABLE products (color_code VARCHAR, product_name VARCHAR); CREATE TABLE ref_colors (color_description VARCHAR, color_code VARCHAR)
SELECT t2.color_description FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code WHERE t1.product_name = "catnip"
Qual é o código de cores e a descrição do produto chamado "chervil"?
CREATE TABLE products (color_code VARCHAR, product_name VARCHAR); CREATE TABLE ref_colors (color_description VARCHAR, color_code VARCHAR)
SELECT t1.color_code, t2.color_description FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code WHERE t1.product_name = "chervil"
Encontre a identificação e a descrição da cor dos produtos com pelo menos duas características.
CREATE TABLE product_characteristics (product_id VARCHAR); CREATE TABLE ref_colors (color_description VARCHAR, color_code VARCHAR); CREATE TABLE products (product_id VARCHAR, color_code VARCHAR)
SELECT t1.product_id, t2.color_description FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code JOIN product_characteristics AS t3 ON t1.product_id = t3.product_id GROUP BY t1.product_id HAVING COUNT(*) >= 2
Lista todos os nomes dos produtos com a descrição da cor "branco".
CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_name VARCHAR, color_code VARCHAR)
SELECT t1.product_name FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code WHERE t2.color_description = "white"
Qual é o nome e os preços típicos de compra e venda dos produtos que têm a cor descrita como "amarelo"?
CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_name VARCHAR, typical_buying_price VARCHAR, typical_selling_price VARCHAR, color_code VARCHAR)
SELECT t1.product_name, t1.typical_buying_price, t1.typical_selling_price FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code WHERE t2.color_description = "yellow"
Quantas características tem o produto chamado "sésamo"?
CREATE TABLE product_characteristics (product_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id WHERE t1.product_name = "sesame"
Quantos nomes característicos distintos tem o produto "cominho"?
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(DISTINCT t3.characteristic_name) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "sesame"
Quais são os nomes característicos do produto "sésamo"?
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "sesame"
Indicar todos os nomes característicos e tipos de dados do produto "cominho".
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_data_type VARCHAR, characteristic_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT t3.characteristic_name, t3.characteristic_data_type FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "cumin"
Indicar todas as características do produto denominado "sésamo" com o código de tipo "Grad".
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_id VARCHAR, characteristic_type_code VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "sesame" AND t3.characteristic_type_code = "Grade"
Quantas características tem o produto chamado "laurel"?
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "laurel"
Determine o número de características do produto "linho".
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t1.product_name = "flax"
Encontre o nome dos produtos que têm a descrição de cor "vermelho" e têm o nome característico "rápido".
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR, characteristic_name VARCHAR); CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_id VARCHAR, color_code VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code = t4.color_code WHERE t4.color_description = "red" AND t3.characteristic_name = "fast"
Quantos produtos têm a característica chamada "quente"?
CREATE TABLE products (product_id VARCHAR); CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR, characteristic_name VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t3.characteristic_name = "hot"
Indicar todas as denominações dos produtos com o nome característico "quente".
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR, characteristic_name VARCHAR); CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT DISTINCT t1.product_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id WHERE t3.characteristic_name = "warm"
Encontre o número de produtos que têm a cor descrita como "vermelho" e têm uma característica chamada "lento".
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR, characteristic_name VARCHAR); CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_id VARCHAR, color_code VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code = t4.color_code WHERE t4.color_description = "red" AND t3.characteristic_name = "slow"
Contar os produtos que tenham a descrição da cor "branco" ou que tenham o nome característico "quente".
CREATE TABLE CHARACTERISTICS (characteristic_id VARCHAR, characteristic_name VARCHAR); CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE products (product_id VARCHAR, color_code VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT COUNT(*) FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id JOIN ref_colors AS t4 ON t1.color_code = t4.color_code WHERE t4.color_description = "white" OR t3.characteristic_name = "hot"
Qual é a unidade de medida do código da categoria de produtos "Ervas"?
CREATE TABLE ref_product_categories (unit_of_measure VARCHAR, product_category_code VARCHAR)
SELECT unit_of_measure FROM ref_product_categories WHERE product_category_code = "Herbs"
Encontre a descrição da categoria de produtos da categoria de produtos com o código "Especiarias".
CREATE TABLE ref_product_categories (product_category_description VARCHAR, product_category_code VARCHAR)
SELECT product_category_description FROM ref_product_categories WHERE product_category_code = "Spices"
Qual é a descrição da categoria de produtos e a unidade de medida da categoria "Ervas"?
CREATE TABLE ref_product_categories (product_category_description VARCHAR, unit_of_measure VARCHAR, product_category_code VARCHAR)
SELECT product_category_description, unit_of_measure FROM ref_product_categories WHERE product_category_code = "Herbs"
Qual é a unidade de medida do produto chamado "cumin"?
CREATE TABLE ref_product_categories (unit_of_measure VARCHAR, product_category_code VARCHAR); CREATE TABLE products (product_category_code VARCHAR, product_name VARCHAR)
SELECT t2.unit_of_measure FROM products AS t1 JOIN ref_product_categories AS t2 ON t1.product_category_code = t2.product_category_code WHERE t1.product_name = "cumin"
Encontre a unidade de medida e o código da categoria de produto do produto denominado "chervil".
CREATE TABLE ref_product_categories (unit_of_measure VARCHAR, product_category_code VARCHAR); CREATE TABLE products (product_category_code VARCHAR, product_name VARCHAR)
SELECT t2.unit_of_measure, t2.product_category_code FROM products AS t1 JOIN ref_product_categories AS t2 ON t1.product_category_code = t2.product_category_code WHERE t1.product_name = "chervil"
Encontre os nomes dos produtos coloridos "branco", mas sem unidade de medida "Handful".
CREATE TABLE products (product_name VARCHAR, product_category_code VARCHAR, color_code VARCHAR); CREATE TABLE ref_colors (color_code VARCHAR, color_description VARCHAR); CREATE TABLE ref_product_categories (product_category_code VARCHAR, unit_of_measure VARCHAR)
SELECT t1.product_name FROM products AS t1 JOIN ref_product_categories AS t2 ON t1.product_category_code = t2.product_category_code JOIN ref_colors AS t3 ON t1.color_code = t3.color_code WHERE t3.color_description = "white" AND t2.unit_of_measure <> "Handful"
Qual é a descrição da cor da maioria dos produtos?
CREATE TABLE ref_colors (color_description VARCHAR, color_code VARCHAR); CREATE TABLE products (color_code VARCHAR)
SELECT t2.color_description FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code GROUP BY t2.color_description ORDER BY COUNT(*) DESC LIMIT 1
Qual é a descrição da cor utilizada pelos produtos menos utilizados?
CREATE TABLE ref_colors (color_description VARCHAR, color_code VARCHAR); CREATE TABLE products (color_code VARCHAR)
SELECT t2.color_description FROM products AS t1 JOIN ref_colors AS t2 ON t1.color_code = t2.color_code GROUP BY t2.color_description ORDER BY COUNT(*) LIMIT 1
Qual é o nome característico utilizado pela maioria dos produtos?
CREATE TABLE products (product_id VARCHAR); CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_id VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id GROUP BY t3.characteristic_name ORDER BY COUNT(*) DESC LIMIT 1
Quais são os nomes, detalhes e tipos de dados das características que nunca são utilizados por nenhum produto?
CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, other_characteristic_details VARCHAR, characteristic_data_type VARCHAR, characteristic_id VARCHAR); CREATE TABLE product_characteristics (characteristic_id VARCHAR); CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, other_characteristic_details VARCHAR, characteristic_data_type VARCHAR)
SELECT characteristic_name, other_characteristic_details, characteristic_data_type FROM CHARACTERISTICS EXCEPT SELECT t1.characteristic_name, t1.other_characteristic_details, t1.characteristic_data_type FROM CHARACTERISTICS AS t1 JOIN product_characteristics AS t2 ON t1.characteristic_id = t2.characteristic_id
Quais são os nomes característicos utilizados pelo menos duas vezes em todos os produtos?
CREATE TABLE products (product_id VARCHAR); CREATE TABLE CHARACTERISTICS (characteristic_name VARCHAR, characteristic_id VARCHAR); CREATE TABLE product_characteristics (product_id VARCHAR, characteristic_id VARCHAR)
SELECT t3.characteristic_name FROM products AS t1 JOIN product_characteristics AS t2 ON t1.product_id = t2.product_id JOIN CHARACTERISTICS AS t3 ON t2.characteristic_id = t3.characteristic_id GROUP BY t3.characteristic_name HAVING COUNT(*) >= 2
Quantas cores nunca são usadas por nenhum produto?
CREATE TABLE products (color_code VARCHAR); CREATE TABLE Ref_colors (color_code VARCHAR)
SELECT COUNT(*) FROM Ref_colors WHERE NOT color_code IN (SELECT color_code FROM products)
Quantos eventos há?
CREATE TABLE event (Id VARCHAR)
SELECT COUNT(*) FROM event
Lista todos os nomes de eventos por ano, do mais recente ao mais antigo.
CREATE TABLE event (name VARCHAR, YEAR VARCHAR)
SELECT name FROM event ORDER BY YEAR DESC
Qual é o nome do evento que aconteceu no ano mais recente?
CREATE TABLE event (name VARCHAR, YEAR VARCHAR)
SELECT name FROM event ORDER BY YEAR DESC LIMIT 1
Quantos estádios há?
CREATE TABLE stadium (Id VARCHAR)
SELECT COUNT(*) FROM stadium
Encontre o nome do estádio que tem a capacidade máxima.
CREATE TABLE stadium (name VARCHAR, capacity VARCHAR)
SELECT name FROM stadium ORDER BY capacity DESC LIMIT 1
Encontre os nomes dos estádios cuja capacidade é menor que a média.
CREATE TABLE stadium (name VARCHAR, capacity INTEGER)
SELECT name FROM stadium WHERE capacity < (SELECT AVG(capacity) FROM stadium)
Encontre o país que tem mais estádios.
CREATE TABLE stadium (country VARCHAR)
SELECT country FROM stadium GROUP BY country ORDER BY COUNT(*) DESC LIMIT 1
Qual país tem no máximo 3 estádios listados?
CREATE TABLE stadium (country VARCHAR)
SELECT country FROM stadium GROUP BY country HAVING COUNT(*) <= 3
Qual país tem estádios com capacidade superior a 60000 e estádios com capacidade inferior a 50000?
CREATE TABLE stadium (country VARCHAR, capacity INTEGER)
SELECT country FROM stadium WHERE capacity > 60000 INTERSECT SELECT country FROM stadium WHERE capacity < 50000
Quantas cidades têm estádios que foram inaugurados antes do ano de 2006?
CREATE TABLE stadium (city VARCHAR, opening_year INTEGER)
SELECT COUNT(DISTINCT city) FROM stadium WHERE opening_year < 2006
Quantos estádios tem cada país?
CREATE TABLE stadium (country VARCHAR)
SELECT country, COUNT(*) FROM stadium GROUP BY country
Que países não têm estádios inaugurados após 2006?
CREATE TABLE stadium (country VARCHAR, opening_year INTEGER)
SELECT country FROM stadium EXCEPT SELECT country FROM stadium WHERE opening_year > 2006
Quantos estádios não estão no país "Rússia"?
CREATE TABLE stadium (country VARCHAR)
SELECT COUNT(*) FROM stadium WHERE country <> 'Russia'
Encontre os nomes de todos os nadadores, ordenados por suas pontuações de 100 metros em ordem ascendente.
CREATE TABLE swimmer (name VARCHAR, meter_100 VARCHAR)
SELECT name FROM swimmer ORDER BY meter_100
De quantos países são todos os nadadores?
CREATE TABLE swimmer (nationality VARCHAR)
SELECT COUNT(DISTINCT nationality) FROM swimmer
Lista os países que têm mais de um nadador.
CREATE TABLE swimmer (nationality VARCHAR)
SELECT nationality, COUNT(*) FROM swimmer GROUP BY nationality HAVING COUNT(*) > 1
Encontre todos os resultados de 200 metros e 300 metros de nadadores com nacionalidade "Austrália".
CREATE TABLE swimmer (meter_200 VARCHAR, meter_300 VARCHAR, nationality VARCHAR)
SELECT meter_200, meter_300 FROM swimmer WHERE nationality = 'Australia'
Encontre os nomes dos nadadores que tiveram um resultado de "ganhar".
CREATE TABLE record (swimmer_id VARCHAR); CREATE TABLE swimmer (name VARCHAR, id VARCHAR)
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win'
Como se chama o estádio que mais eventos realizou?
CREATE TABLE stadium (name VARCHAR, id VARCHAR); CREATE TABLE event (stadium_id VARCHAR)
SELECT t1.name FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
Encontre o nome e a capacidade do estádio onde o evento chamado "World Junior" aconteceu.
CREATE TABLE event (stadium_id VARCHAR, name VARCHAR); CREATE TABLE stadium (name VARCHAR, capacity VARCHAR, id VARCHAR)
SELECT t1.name, t1.capacity FROM stadium AS t1 JOIN event AS t2 ON t1.id = t2.stadium_id WHERE t2.name = 'World Junior'
Encontre os nomes dos estádios que nunca tiveram nenhum evento.
CREATE TABLE stadium (name VARCHAR, id VARCHAR, stadium_id VARCHAR); CREATE TABLE event (name VARCHAR, id VARCHAR, stadium_id VARCHAR)
SELECT name FROM stadium WHERE NOT id IN (SELECT stadium_id FROM event)
Encontre o nome do nadador que tem mais recordes.
CREATE TABLE record (swimmer_id VARCHAR); CREATE TABLE swimmer (name VARCHAR, id VARCHAR)
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id ORDER BY COUNT(*) DESC LIMIT 1
Encontre o nome do nadador que tem pelo menos 2 registos.
CREATE TABLE record (swimmer_id VARCHAR); CREATE TABLE swimmer (name VARCHAR, id VARCHAR)
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id GROUP BY t2.swimmer_id HAVING COUNT(*) >= 2
Encontre o nome e a nacionalidade do nadador que tenha vencido (ou seja, tenha um resultado de "vencer") mais de 1 vez.
CREATE TABLE record (swimmer_id VARCHAR); CREATE TABLE swimmer (name VARCHAR, nationality VARCHAR, id VARCHAR)
SELECT t1.name, t1.nationality FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' GROUP BY t2.swimmer_id HAVING COUNT(*) > 1
Encontre os nomes dos nadadores que não têm cadastro.
CREATE TABLE swimmer (name VARCHAR, id VARCHAR, swimmer_id VARCHAR); CREATE TABLE record (name VARCHAR, id VARCHAR, swimmer_id VARCHAR)
SELECT name FROM swimmer WHERE NOT id IN (SELECT swimmer_id FROM record)
Encontre os nomes dos nadadores que tiveram resultados de "ganho" e "perda" no registro.
CREATE TABLE record (swimmer_id VARCHAR); CREATE TABLE swimmer (name VARCHAR, id VARCHAR)
SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Win' INTERSECT SELECT t1.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id WHERE RESULT = 'Loss'
Encontre os nomes dos estádios que alguns nadadores australianos foram.
CREATE TABLE swimmer (id VARCHAR, nationality VARCHAR); CREATE TABLE record (swimmer_id VARCHAR, event_id VARCHAR); CREATE TABLE stadium (name VARCHAR, id VARCHAR); CREATE TABLE event (id VARCHAR, stadium_id VARCHAR)
SELECT t4.name FROM swimmer AS t1 JOIN record AS t2 ON t1.id = t2.swimmer_id JOIN event AS t3 ON t2.event_id = t3.id JOIN stadium AS t4 ON t4.id = t3.stadium_id WHERE t1.nationality = 'Australia'
Encontre os nomes dos estádios onde mais nadadores estiveram.
CREATE TABLE record (event_id VARCHAR); CREATE TABLE stadium (name VARCHAR, id VARCHAR); CREATE TABLE event (stadium_id VARCHAR, id VARCHAR)
SELECT t3.name FROM record AS t1 JOIN event AS t2 ON t1.event_id = t2.id JOIN stadium AS t3 ON t3.id = t2.stadium_id GROUP BY t2.stadium_id ORDER BY COUNT(*) DESC LIMIT 1
Encontre todos os detalhes de cada nadador.
CREATE TABLE swimmer (Id VARCHAR)
SELECT * FROM swimmer
Qual é a capacidade média dos estádios inaugurados no ano de 2005?
CREATE TABLE stadium (capacity INTEGER, opening_year VARCHAR)
SELECT AVG(capacity) FROM stadium WHERE opening_year = 2005