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Encontre o primeiro nome do companheiro de banda que tocou na maioria das músicas. | CREATE TABLE Songs (SongId VARCHAR); CREATE TABLE Band (firstname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR) | SELECT t2.firstname FROM Performance AS t1 JOIN Band AS t2 ON t1.bandmate = t2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY firstname ORDER BY COUNT(*) DESC LIMIT 1 |
Que tipo de voz é que o colega de banda com o nome "Marianne" tocou mais? | CREATE TABLE vocals (bandmate VARCHAR); CREATE TABLE band (id VARCHAR) | SELECT TYPE FROM vocals AS T1 JOIN band AS T2 ON T1.bandmate = T2.id WHERE firstname = "Marianne" GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1 |
Quem está a tocar no fundo da cena na canção "Der Kapitan"? | CREATE TABLE Band (firstname VARCHAR, lastname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR, SongId VARCHAR, StagePosition VARCHAR); CREATE TABLE Songs (SongId VARCHAR, Title VARCHAR) | SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Der Kapitan" AND T1.StagePosition = "back" |
Quais são as canções do álbum "A Kiss Before You Go: Live in Hamburg"? | CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR, title VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) | SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE T1.title = "A Kiss Before You Go: Live in Hamburg" |
Quais são as músicas dos álbuns da Universal Music Group? | CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) | SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.label = "Universal Music Group" |
Encontre o número de músicas em todos os álbuns de estúdio. | CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR) | SELECT COUNT(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.type = "Studio" |
Quem é o fundador da Sony? | CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR) | SELECT founder FROM manufacturers WHERE name = 'Sony' |
Onde está a sede da empresa fundada por James? | CREATE TABLE manufacturers (headquarter VARCHAR, founder VARCHAR) | SELECT headquarter FROM manufacturers WHERE founder = 'James' |
Encontre os nomes de todos os fabricantes e a sede, ordenados pelos que têm mais receita. | CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR) | SELECT name, headquarter FROM manufacturers ORDER BY revenue DESC |
Quais são as receitas médias, máximas e totais de todas as empresas? | CREATE TABLE manufacturers (revenue INTEGER) | SELECT AVG(revenue), MAX(revenue), SUM(revenue) FROM manufacturers |
Quantas empresas foi criado por Andy? | CREATE TABLE manufacturers (founder VARCHAR) | SELECT COUNT(*) FROM manufacturers WHERE founder = 'Andy' |
Encontre a receita total criada pelas empresas cuja sede está localizada em Austin. | CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR) | SELECT SUM(revenue) FROM manufacturers WHERE headquarter = 'Austin' |
Quais são as diferentes cidades listadas? | CREATE TABLE manufacturers (headquarter VARCHAR) | SELECT DISTINCT headquarter FROM manufacturers |
Encontre o número de fabricantes que estão baseados em Tóquio ou Pequim. | CREATE TABLE manufacturers (headquarter VARCHAR) | SELECT COUNT(*) FROM manufacturers WHERE headquarter = 'Tokyo' OR headquarter = 'Beijing' |
Encontre o fundador da empresa cujo nome começa com a letra "S". | CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR) | SELECT founder FROM manufacturers WHERE name LIKE 'S%' |
Encontre o nome das empresas cuja receita está entre 100 e 150. | CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) | SELECT name FROM manufacturers WHERE revenue BETWEEN 100 AND 150 |
Qual é a receita total de todas as empresas cuja sede principal está em Tóquio ou em Taiwan? | CREATE TABLE manufacturers (revenue INTEGER, Headquarter VARCHAR) | SELECT SUM(revenue) FROM manufacturers WHERE Headquarter = 'Tokyo' OR Headquarter = 'Taiwan' |
Encontre o nome do produto que é produzido por ambas as empresas Creative Labs e Sony. | CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) | SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Creative Labs' INTERSECT SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony' |
Encontre o nome, sede e fundador do fabricante que tem a maior receita. | CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, founder VARCHAR, revenue VARCHAR) | SELECT name, headquarter, founder FROM manufacturers ORDER BY revenue DESC LIMIT 1 |
Encontre o nome, sede e receita de todos os fabricantes ordenados por sua receita em ordem decrescente. | CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR) | SELECT name, headquarter, revenue FROM manufacturers ORDER BY revenue DESC |
Encontre o nome das empresas cuja receita é maior do que a receita média de todas as empresas. | CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) | SELECT name FROM manufacturers WHERE revenue > (SELECT AVG(revenue) FROM manufacturers) |
Encontre o nome das empresas cuja receita é menor do que a receita de todas as empresas baseadas em Austin. | CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR) | SELECT name FROM manufacturers WHERE revenue < (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin') |
Encontre a receita total de empresas cuja receita é maior do que a receita de algumas empresas baseadas em Austin. | CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR) | SELECT SUM(revenue) FROM manufacturers WHERE revenue > (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin') |
Encontre a receita total das empresas de cada fundador. | CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER) | SELECT SUM(revenue), founder FROM manufacturers GROUP BY founder |
Encontre o nome e a receita da empresa que ganha a maior receita em cada cidade. | CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER) | SELECT name, MAX(revenue), Headquarter FROM manufacturers GROUP BY Headquarter |
Calcule a receita total de cada fabricante. | CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER) | SELECT SUM(revenue), name FROM manufacturers GROUP BY name |
Encontre os preços médios de todos os produtos de cada fabricante e liste o nome de cada empresa. | CREATE TABLE products (price INTEGER, Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR) | SELECT AVG(T1.price), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name |
Encontre o número de produtos diferentes que são produzidos por empresas em diferentes cidades sede. | CREATE TABLE manufacturers (Headquarter VARCHAR, code VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) | SELECT COUNT(DISTINCT T1.name), T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter |
Encontre o número de produtos que a Sony não faz. | CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR) | SELECT COUNT(DISTINCT name) FROM products WHERE NOT name IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony') |
Encontre o nome das empresas que não fazem a unidade de DVD. | CREATE TABLE manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Manufacturer VARCHAR, name VARCHAR); CREATE TABLE manufacturers (name VARCHAR) | SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive' |
Encontre o número de produtos de cada fabricante, indicando o nome de cada empresa. | CREATE TABLE products (Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR) | SELECT COUNT(*), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name |
Selecione os nomes de todos os produtos da loja. | CREATE TABLE Products (Name VARCHAR) | SELECT Name FROM Products |
Selecione os nomes e os preços de todos os produtos da loja. | CREATE TABLE products (name VARCHAR, price VARCHAR) | SELECT name, price FROM products |
Selecione o nome dos produtos com um preço inferior ou igual a US$ 200. | CREATE TABLE products (name VARCHAR, price VARCHAR) | SELECT name FROM products WHERE price <= 200 |
Encontre todas as informações de todos os produtos com um preço entre US $ 60 e US $ 120. | CREATE TABLE products (price INTEGER) | SELECT * FROM products WHERE price BETWEEN 60 AND 120 |
Calcular o preço médio de todos os produtos. | CREATE TABLE products (price INTEGER) | SELECT AVG(price) FROM products |
Calcular o preço médio de todos os produtos com código do fabricante igual a 2. | CREATE TABLE products (price INTEGER, Manufacturer VARCHAR) | SELECT AVG(price) FROM products WHERE Manufacturer = 2 |
Calcule o número de produtos com um preço maior ou igual a US $ 180. | CREATE TABLE products (price VARCHAR) | SELECT COUNT(*) FROM products WHERE price >= 180 |
Selecione o nome e o preço de todos os produtos com um preço superior ou igual a R$ 180, e classifique primeiro por preço (em ordem decrescente), e depois por nome (em ordem ascendente). | CREATE TABLE products (name VARCHAR, price VARCHAR) | SELECT name, price FROM products WHERE price >= 180 ORDER BY price DESC, name |
Selecionar todos os dados dos produtos e do fabricante de cada produto. | CREATE TABLE products (manufacturer VARCHAR); CREATE TABLE Manufacturers (code VARCHAR) | SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code |
Selecionar o preço médio dos produtos de cada fabricante, indicando apenas o código do fabricante. | CREATE TABLE Products (Manufacturer VARCHAR, Price INTEGER) | SELECT AVG(Price), Manufacturer FROM Products GROUP BY Manufacturer |
Selecionar o preço médio dos produtos de cada fabricante, indicando o nome do fabricante. | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR) | SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name |
Selecione os nomes do fabricante cujos produtos têm um preço médio superior ou igual a US$ 150. | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER) | SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING AVG(T1.price) >= 150 |
Selecione o nome e o preço do produto mais barato. | CREATE TABLE Products (name VARCHAR, price VARCHAR) | SELECT name, price FROM Products ORDER BY price LIMIT 1 |
Selecione o nome de cada fabricante, juntamente com o nome e o preço do produto mais caro. | CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Name VARCHAR, Price INTEGER, manufacturer VARCHAR) | SELECT T1.Name, MAX(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name |
Selecionar o código do produto que é mais barato em cada categoria de produto. | CREATE TABLE products (code VARCHAR, name VARCHAR, price INTEGER) | SELECT code, name, MIN(price) FROM products GROUP BY name |
Qual é o id do log de problemas que foi criado mais recentemente? | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR) | SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1 |
Qual é a identificação de registo mais antiga e a identificação do problema correspondente? | CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR) | SELECT problem_log_id, problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1 |
Encontre todas as ids e datas dos registros para o problema cujo id é 10. | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR, problem_id VARCHAR) | SELECT problem_log_id, log_entry_date FROM problem_log WHERE problem_id = 10 |
Lista todas as ids de log e suas descrições dos logs de problemas. | CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_description VARCHAR) | SELECT problem_log_id, log_entry_description FROM problem_log |
Escrever os nomes e apelidos de todos os membros do pessoal que são designados para o problema cujo id é 1. | CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | SELECT DISTINCT staff_first_name, staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1 |
Escreva o problema e o ID do log que são atribuídos ao pessoal chamado Rylan Homenick. | CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR) | SELECT DISTINCT T2.problem_id, T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick" |
Quantos problemas há para o produto voluptatem? | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) | SELECT COUNT(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem" |
Quantos problemas tem o produto com mais problemas? | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | SELECT COUNT(*), T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY COUNT(*) DESC LIMIT 1 |
Dê-me uma lista de descrições dos problemas que são relatados pela equipe cujo primeiro nome é Christop. | CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR); CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR) | SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" |
Encontre os identificadores dos problemas que são relatados pelo pessoal cujo sobrenome é Bosco. | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR) | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco" |
Quais são as identidades dos problemas que são relatados após 1978-06-26? | CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) | SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26" |
Quais são as identidades dos problemas que são relatados antes de 1978-06-26? | CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER) | SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26" |
Para cada produto que tenha problemas, qual o número de problemas e a identificação do produto? | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR) | SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id |
Para cada produto com problemas, encontrar o número de problemas notificados após 1986-11-13 e o id do produto? | CREATE TABLE product (product_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER) | SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id |
Enumere os nomes de todos os nomes distintos dos produtos em ordem alfabética? | CREATE TABLE product (product_name VARCHAR) | SELECT DISTINCT product_name FROM product ORDER BY product_name |
A lista de todos os nomes de produtos distintos ordenados por id do produto? | CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | SELECT DISTINCT product_name FROM product ORDER BY product_id |
Quais são os problemas relatados pelo pessoal chamado Dameon Frami ou Jolie Weber? | CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR) | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber" |
Quais são os identificadores dos produtos para os problemas relatados por Christop Berge com o fechamento autorizado por Ashley Medhurst? | CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR) | SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst" |
Quais são as ids dos problemas relatados antes da data de qualquer problema relatado por Lysanne Turcotte? | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < (SELECT MIN(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte") |
Quais são as ids dos problemas relatados após a data de qualquer problema relatado por Rylan Homenick? | CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR) | SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > (SELECT MAX(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick") |
Encontrar os três produtos que apresentam o maior número de problemas? | CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR) | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3 |
A lista dos problemas do produto "voluptatem" que foram notificados após 1995? | CREATE TABLE problems (problem_id VARCHAR, product_id VARCHAR, date_problem_reported VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR) | SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995" |
Encontrar o nome e o apelido dos funcionários que relataram problemas com o produto "rem" mas não com o "aut"? | CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_first_name VARCHAR, staff_last_name VARCHAR, staff_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR) | SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut" |
Encontrar os produtos que têm problemas relatados por Lacey Bosco e Kenton Champlin? | CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR) | SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin" |
Quantas filiais têm mais do que o número médio de membros? | CREATE TABLE branch (membership_amount INTEGER) | SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch) |
Mostrar o nome, a estrada e a cidade de todas as filiais ordenadas por ano de abertura. | CREATE TABLE branch (name VARCHAR, address_road VARCHAR, city VARCHAR, open_year VARCHAR) | SELECT name, address_road, city FROM branch ORDER BY open_year |
Quais são os nomes dos três ramos com o maior número de membros? | CREATE TABLE branch (name VARCHAR, membership_amount VARCHAR) | SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3 |
Mostrar todas as cidades onde estão localizadas filiais com pelo menos 100 membros. | CREATE TABLE branch (city VARCHAR, membership_amount VARCHAR) | SELECT DISTINCT city FROM branch WHERE membership_amount >= 100 |
Lista todos os anos em que foram abertas pelo menos duas lojas. | CREATE TABLE branch (open_year VARCHAR) | SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2 |
Indicar o número mínimo e máximo de membros para todas as sucursais abertas em 2011 ou localizadas na cidade de Londres. | CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR) | SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London' |
Mostre a cidade e o número de filiais abertas antes de 2010 para cada cidade. | CREATE TABLE branch (city VARCHAR, open_year INTEGER) | SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city |
Quantos níveis diferentes têm os membros? | CREATE TABLE member (LEVEL VARCHAR) | SELECT COUNT(DISTINCT LEVEL) FROM member |
Mostre o número do cartão, o nome e a cidade natal de todos os membros em ordem decrescente de nível. | CREATE TABLE member (card_number VARCHAR, name VARCHAR, hometown VARCHAR, LEVEL VARCHAR) | SELECT card_number, name, hometown FROM member ORDER BY LEVEL DESC |
Mostrar o nível de adesão com o maior número de membros. | CREATE TABLE member (LEVEL VARCHAR) | SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY COUNT(*) DESC LIMIT 1 |
Mostrar todos os nomes dos membros e das sucursais registadas, ordenados por ano de registo. | CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR) | SELECT T3.name, T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year |
Mostre todos os nomes de filiais com o número de membros em cada filial registrada após 2015. | CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year INTEGER) | SELECT T2.name, COUNT(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id |
Mostrar nomes de membros sem qualquer filial registrada. | CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (name VARCHAR, member_id VARCHAR) | SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch) |
Escreva o nome e a cidade da filial sem membros registrados. | CREATE TABLE membership_register_branch (name VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE branch (name VARCHAR, city VARCHAR, branch_id VARCHAR) | SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch) |
Qual é o nome e ano de abertura da filial com o maior número de membros registrados em 2016? | CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, open_year VARCHAR, branch_id VARCHAR) | SELECT T2.name, T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY COUNT(*) DESC LIMIT 1 |
Mostrar o nome e a cidade natal dos membros que registraram uma filial em 2016. | CREATE TABLE member (name VARCHAR, hometown VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (member_id VARCHAR, register_year VARCHAR) | SELECT T2.name, T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016 |
Mostre todas as cidades com uma filial aberta em 2001 e uma filial com mais de 100 membros. | CREATE TABLE branch (city VARCHAR, open_year VARCHAR, membership_amount VARCHAR) | SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100 |
Mostre todas as cidades sem filiais com mais de 100 membros. | CREATE TABLE branch (city VARCHAR, membership_amount INTEGER) | SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100 |
Qual é a soma de libras totais de compra no ano de 2018 para todas as filiais em Londres? | CREATE TABLE purchase (branch_id VARCHAR, year VARCHAR); CREATE TABLE branch (branch_id VARCHAR, city VARCHAR) | SELECT SUM(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018 |
Qual é o número total de compras para membros com nível 6? | CREATE TABLE member (member_id VARCHAR, level VARCHAR); CREATE TABLE purchase (member_id VARCHAR) | SELECT COUNT(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6 |
Encontre o nome de filiais onde alguns membros têm a cidade natal em Louisville, Kentucky e alguns em Hiram, Georgia. | CREATE TABLE member (member_id VARCHAR, Hometown VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR) | SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia' |
Escreva o número de cartão de todos os membros cujo endereço de casa inclua a palavra "Kentucky". | CREATE TABLE member (card_number VARCHAR, Hometown VARCHAR) | SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%" |
Encontre o número total de alunos. | CREATE TABLE STUDENT (Id VARCHAR) | SELECT COUNT(*) FROM STUDENT |
Encontre o número total de registos de votação. | CREATE TABLE VOTING_RECORD (Id VARCHAR) | SELECT COUNT(*) FROM VOTING_RECORD |
Encontre o número distinto de votos presidenciais. | CREATE TABLE VOTING_RECORD (President_Vote VARCHAR) | SELECT COUNT(DISTINCT President_Vote) FROM VOTING_RECORD |
Encontre a idade máxima de todos os alunos. | CREATE TABLE STUDENT (Age INTEGER) | SELECT MAX(Age) FROM STUDENT |
Encontre os sobrenomes dos estudantes com 50 anos. | CREATE TABLE STUDENT (LName VARCHAR, Major VARCHAR) | SELECT LName FROM STUDENT WHERE Major = 50 |
Encontre os nomes dos alunos com mais de 22 anos. | CREATE TABLE STUDENT (Fname VARCHAR, Age INTEGER) | SELECT Fname FROM STUDENT WHERE Age > 22 |
Quais são os cursos de estudantes do sexo masculino? | CREATE TABLE STUDENT (Major VARCHAR, Sex VARCHAR) | SELECT Major FROM STUDENT WHERE Sex = "M" |
Qual é a idade média dos estudantes do sexo feminino (sexo é F)? | CREATE TABLE STUDENT (Age INTEGER, Sex VARCHAR) | SELECT AVG(Age) FROM STUDENT WHERE Sex = "F" |
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