pergunta
stringlengths 8
31.4k
| contexto
stringlengths 27
489
| resposta
stringlengths 18
557
|
---|---|---|
Indicar os títulos dos filmes e os tipos de estimativas de mercado. | CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR) | SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID |
Mostre o diretor distinto de filmes com estimativa de mercado no ano de 1995. | CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR) | SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995 |
Qual é o número médio de cidades de mercados com baixa estimativa de mercado de filmes maior do que 10000? | CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER) | SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000 |
Escrever os países e anos de estimativas do mercado do cinema. | CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR) | SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID |
Por favor, listem os anos de estimativas do mercado de filmes quando o mercado está no país "Japão" em ordem decrescente. | CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR) | SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC |
Escreva os estúdios de cada filme e o número de filmes produzidos por esse estúdio. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio, COUNT(*) FROM film GROUP BY Studio |
Escreva o nome do estúdio de cinema que tem o maior número de filmes. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1 |
Escreva os nomes dos estúdios que têm pelo menos dois filmes. | CREATE TABLE film (Studio VARCHAR) | SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2 |
Escreva o título dos filmes que não têm qualquer estimativa de mercado. | CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR) | SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation) |
Mostre os estúdios que produziram filmes com o diretor "Nicholas Meyer" e "Walter Hill". | CREATE TABLE film (Studio VARCHAR, Director VARCHAR) | SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill" |
Encontre os títulos e estúdios dos filmes produzidos por alguns estúdios de cinema que continham a palavra "Universal". | CREATE TABLE film (title VARCHAR, Studio VARCHAR) | SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%" |
Mostre os estúdios que não produziram filmes com o diretor "Walter Hill". | CREATE TABLE film (Studio VARCHAR, Director VARCHAR) | SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill" |
Escreva os estúdios cuja média de receita é superior a 4500000. | CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER) | SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000 |
Qual é o título do filme que tem a maior estimativa de mercado? | CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR) | SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1 |
Quais são os títulos e os realizadores dos filmes que nunca foram apresentados na China? | CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR) | SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China') |
Quantos itens de calendário temos? | CREATE TABLE Ref_calendar (Id VARCHAR) | SELECT COUNT(*) FROM Ref_calendar |
Mostrar todas as datas do calendário e números de dias. | CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR) | SELECT calendar_date, day_Number FROM Ref_calendar |
Mostrar o número de tipos de documento. | CREATE TABLE Ref_document_types (Id VARCHAR) | SELECT COUNT(*) FROM Ref_document_types |
Apresentação de todos os códigos e nomes dos tipos de documentos. | CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) | SELECT document_type_code, document_type_name FROM Ref_document_types |
Qual é o nome e a descrição do código RV do tipo de documento? | CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR) | SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV" |
Qual é o código do tipo de documento para o tipo de documento "Papel"? | CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR) | SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper" |
Indicar o número de documentos com o código de tipo de documento CV ou BK. | CREATE TABLE All_documents (document_type_code VARCHAR) | SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK" |
Qual a data de armazenamento do documento "Civilo de casamento"? | CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR) | SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV" |
Qual é o número e data de todos os documentos? | CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR) | SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date |
Qual é o nome do tipo de documento para o documento com o nome "Como ler um livro"? | CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR) | SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book" |
Mostrar o número de localizações. | CREATE TABLE Ref_locations (Id VARCHAR) | SELECT COUNT(*) FROM Ref_locations |
Escreve todos os códigos e nomes de localização. | CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) | SELECT location_code, location_name FROM Ref_locations |
Qual é o nome e a descrição do código de localização x? | CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR) | SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x" |
Qual é o código de localização para o país "Canadá"? | CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR) | SELECT location_code FROM Ref_locations WHERE location_name = "Canada" |
Quantos papéis existem? | CREATE TABLE ROLES (Id VARCHAR) | SELECT COUNT(*) FROM ROLES |
Escrever todos os códigos de funções, nomes de funções e descrições de funções. | CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR) | SELECT role_code, role_name, role_description FROM ROLES |
Qual é o nome e a descrição do código de função "MG"? | CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) | SELECT role_name, role_description FROM ROLES WHERE role_code = "MG" |
Mostrar a descrição do nome do papel "Reader de provas". | CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR) | SELECT role_description FROM ROLES WHERE role_name = "Proof Reader" |
Indicar o nome, o código de função e a data de nascimento do empregado com o nome "Armani". | CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR) | SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani' |
Qual é a identificação do empregado chamado Ebba? | CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR) | SELECT employee_ID FROM Employees WHERE employee_name = "Ebba" |
Mostrar os nomes de todos os funcionários com função "RH". | CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) | SELECT employee_name FROM Employees WHERE role_code = "HR" |
Indicar todos os códigos de funções e o número de empregados em cada função. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code |
Qual é o código de funções com o maior número de empregados? | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1 |
Mostrar todos os códigos de funções com pelo menos 3 funcionários. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3 |
Mostrar o código de funções com menos funcionários. | CREATE TABLE Employees (role_code VARCHAR) | SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1 |
Qual é o nome e a descrição do papel para o empregado chamado Ebba? | CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR) | SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba" |
Mostrar os nomes dos funcionários com o nome de função Editor. | CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR) | SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor" |
Mostrar as identidades dos funcionários para todos os funcionários com o nome de função "Resouros Humanos" ou "Gerenciador". | CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR) | SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager" |
Quais são os diferentes códigos de localização dos documentos? | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT DISTINCT location_code FROM Document_locations |
Indicar o nome do local para o documento "CV Robin". | CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR) | SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV" |
Mostrar o código de localização, a data de início e os dados de fim nesse local para todos os documentos. | CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR) | SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations |
Qual é a "data em localização de" e "a data em localização para" para o documento com o nome "Robin CV"? | CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR) | SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV" |
Mostrar os códigos de localização e o número de documentos em cada localização. | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code |
Qual é o código de localização com mais documentos? | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1 |
Mostrar os códigos de localização com pelo menos 3 documentos. | CREATE TABLE Document_locations (location_code VARCHAR) | SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3 |
Mostrar o nome e o código do local com menos documentos. | CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR) | SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1 |
Quais são os nomes dos empregados que autorizaram a destruição e os empregados que destruíram os documentos correspondentes? | CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR) | SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id |
Indicar o número de identificação de cada empregado e o número de documentos que esse empregado autorizou a destruir. | CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID |
Mostrar as identidades dos empregados e o número de documentos destruídos por cada empregado. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) | SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID |
Mostre as identidades dos funcionários que não autorizam a destruição de qualquer documento. | CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
Mostre as identidades de todos os funcionários que autorizaram a destruição. | CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
Mostre as identidades de todos os funcionários que destruíram um documento. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR) | SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed |
Mostre as identidades de todos os funcionários que não destruam nenhum documento. | CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR) | SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed |
Mostrar as identidades de todos os funcionários que destruíram um documento ou fizeram uma autorização para fazê-lo. | CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR) | SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed |
Quais são os nomes de todos os clubes? | CREATE TABLE club (clubname VARCHAR) | SELECT clubname FROM club |
Quantos alunos há? | CREATE TABLE student (Id VARCHAR) | SELECT COUNT(*) FROM student |
Quais são os primeiros nomes de todos os estudantes? | CREATE TABLE student (fname VARCHAR) | SELECT DISTINCT fname FROM student |
Encontre os sobrenomes dos membros do clube "Bootup Baltimore". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" |
Quem são os membros do clube chamado "Hopkins Student Enterprises"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" |
Quantos membros tem o clube "Clube de Tênis"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" |
Encontre o número de membros do clube "Pen and Paper Gaming". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming" |
A quantos clubes pertence "Linda Smith"? | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith" |
Encontre o número de clubes onde "Tracy Kim" é membro. | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim" |
Encontre todas as mulheres do clube "Bootup Baltimore". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F" |
Encontre todos os membros do clube "Hopkins Student Enterprises". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M" |
Encontre todos os membros de "Bootup Baltimore" cuja especialização é "600". Mostre o primeiro nome e o sobrenome. | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600" |
Qual clube tem mais membros que se especializam em "600"? | CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre o nome do clube que tem mais estudantes do sexo feminino. | CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é a descrição do clube chamado "Clube de Tênis"? | CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) | SELECT clubdesc FROM club WHERE clubname = "Tennis Club" |
Encontre a descrição do clube "Pen and Paper Gaming". | CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR) | SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming" |
Onde está o clube chamado "Clube de Tênis"? | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Tennis Club" |
Encontre a localização do clube "Pen and Paper Gaming". | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming" |
Onde está localizado o clube "Hopkins Student Enterprises"? | CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR) | SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises" |
Encontre o nome de todos os clubes da "AKW". | CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR) | SELECT clubname FROM club WHERE clublocation = "AKW" |
Quantos clubes estão localizados em "HHH"? | CREATE TABLE club (clublocation VARCHAR) | SELECT COUNT(*) FROM club WHERE clublocation = "HHH" |
Qual é o primeiro e último nome do presidente do clube "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President" |
Quem é o "CTO" do clube "Hopkins Student Enterprises"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR) | SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO" |
Quantos papéis diferentes há no clube "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR) | SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore" |
Quantos membros do "Bootup Baltimore" têm mais de 18 anos? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18 |
Quantos membros do clube "Bootup Baltimore" têm menos de 18 anos? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18 |
Encontre os nomes de todos os clubes que têm pelo menos um membro da cidade com código de cidade "BAL". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL" |
Encontre os nomes dos clubes que têm pelo menos um membro da cidade com código de cidade "HOU". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU" |
A quantos clubes pertence o estudante chamado "Eric Tai"? | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai" |
Escreva os clubes que têm "Davis Steven" como membro. | CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven" |
Escreva os clubes que têm pelo menos um membro com um conselheiro "1121". | CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR) | SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121 |
Qual é a idade média dos membros do clube "Bootup Baltimore"? | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" |
Encontre a idade média dos membros do clube "Hopkins Student Enterprises". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" |
Retrocedir a idade média dos membros do clube "Clube de tênis". | CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR) | SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club" |
Qual é o montante da subvenção em caso de envio dos documentos antes de "1986-08-26 20:49:27" e de cessação da subvenção após "1989-03-16 18:27:16"? | CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER) | SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16' |
Liste os detalhes do projeto do projeto que produz tanto patente quanto papel como resultados. | CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR) | SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent' |
Qual é o montante total das subvenções concedidas às organizações descritas como pesquisadoras? | CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR) | SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research' |
Lista a partir de que data e até que data trabalham estes funcionários: pessoal do projeto do projeto que contrata mais pessoal | CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR) | SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader' |
Encontrar os identificadores e os dados das organizações que participam na | CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR) | SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000 |
Qual é o tipo de organização e a identificação da organização que tem o maior número de investigadores? | CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) | SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1 |
Qual o tipo de organização que contrata mais pessoal de investigação? | CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR) | SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.