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Indicar os títulos dos filmes e os tipos de estimativas de mercado.
CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Type VARCHAR, Film_ID VARCHAR)
SELECT T1.Title, T2.Type FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID
Mostre o diretor distinto de filmes com estimativa de mercado no ano de 1995.
CREATE TABLE film (Director VARCHAR, Film_ID VARCHAR); CREATE TABLE film_market_estimation (Film_ID VARCHAR, Year VARCHAR)
SELECT DISTINCT T1.Director FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID WHERE T2.Year = 1995
Qual é o número médio de cidades de mercados com baixa estimativa de mercado de filmes maior do que 10000?
CREATE TABLE market (Number_cities INTEGER, Market_ID VARCHAR); CREATE TABLE film_market_estimation (Market_ID VARCHAR, Low_Estimate INTEGER)
SELECT AVG(T2.Number_cities) FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T1.Low_Estimate > 10000
Escrever os países e anos de estimativas do mercado do cinema.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Country VARCHAR, Market_ID VARCHAR)
SELECT T2.Country, T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID
Por favor, listem os anos de estimativas do mercado de filmes quando o mercado está no país "Japão" em ordem decrescente.
CREATE TABLE film_market_estimation (Year VARCHAR, Market_ID VARCHAR); CREATE TABLE market (Market_ID VARCHAR, Country VARCHAR)
SELECT T1.Year FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.Market_ID = T2.Market_ID WHERE T2.Country = "Japan" ORDER BY T1.Year DESC
Escreva os estúdios de cada filme e o número de filmes produzidos por esse estúdio.
CREATE TABLE film (Studio VARCHAR)
SELECT Studio, COUNT(*) FROM film GROUP BY Studio
Escreva o nome do estúdio de cinema que tem o maior número de filmes.
CREATE TABLE film (Studio VARCHAR)
SELECT Studio FROM film GROUP BY Studio ORDER BY COUNT(*) DESC LIMIT 1
Escreva os nomes dos estúdios que têm pelo menos dois filmes.
CREATE TABLE film (Studio VARCHAR)
SELECT Studio FROM film GROUP BY Studio HAVING COUNT(*) >= 2
Escreva o título dos filmes que não têm qualquer estimativa de mercado.
CREATE TABLE film_market_estimation (Title VARCHAR, Film_ID VARCHAR); CREATE TABLE film (Title VARCHAR, Film_ID VARCHAR)
SELECT Title FROM film WHERE NOT Film_ID IN (SELECT Film_ID FROM film_market_estimation)
Mostre os estúdios que produziram filmes com o diretor "Nicholas Meyer" e "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
SELECT Studio FROM film WHERE Director = "Nicholas Meyer" INTERSECT SELECT Studio FROM film WHERE Director = "Walter Hill"
Encontre os títulos e estúdios dos filmes produzidos por alguns estúdios de cinema que continham a palavra "Universal".
CREATE TABLE film (title VARCHAR, Studio VARCHAR)
SELECT title, Studio FROM film WHERE Studio LIKE "%Universal%"
Mostre os estúdios que não produziram filmes com o diretor "Walter Hill".
CREATE TABLE film (Studio VARCHAR, Director VARCHAR)
SELECT Studio FROM film EXCEPT SELECT Studio FROM film WHERE Director = "Walter Hill"
Escreva os estúdios cuja média de receita é superior a 4500000.
CREATE TABLE film (Studio VARCHAR, Gross_in_dollar INTEGER)
SELECT Studio FROM film GROUP BY Studio HAVING AVG(Gross_in_dollar) >= 4500000
Qual é o título do filme que tem a maior estimativa de mercado?
CREATE TABLE film_market_estimation (Film_ID VARCHAR); CREATE TABLE film (Film_ID VARCHAR)
SELECT t1.title FROM film AS T1 JOIN film_market_estimation AS T2 ON T1.Film_ID = T2.Film_ID ORDER BY high_estimate DESC LIMIT 1
Quais são os títulos e os realizadores dos filmes que nunca foram apresentados na China?
CREATE TABLE film (title VARCHAR, director VARCHAR, film_id VARCHAR, country VARCHAR); CREATE TABLE market (Market_ID VARCHAR); CREATE TABLE film_market_estimation (market_id VARCHAR)
SELECT title, director FROM film WHERE NOT film_id IN (SELECT film_id FROM film_market_estimation AS T1 JOIN market AS T2 ON T1.market_id = T2.Market_ID WHERE country = 'China')
Quantos itens de calendário temos?
CREATE TABLE Ref_calendar (Id VARCHAR)
SELECT COUNT(*) FROM Ref_calendar
Mostrar todas as datas do calendário e números de dias.
CREATE TABLE Ref_calendar (calendar_date VARCHAR, day_Number VARCHAR)
SELECT calendar_date, day_Number FROM Ref_calendar
Mostrar o número de tipos de documento.
CREATE TABLE Ref_document_types (Id VARCHAR)
SELECT COUNT(*) FROM Ref_document_types
Apresentação de todos os códigos e nomes dos tipos de documentos.
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
SELECT document_type_code, document_type_name FROM Ref_document_types
Qual é o nome e a descrição do código RV do tipo de documento?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_description VARCHAR, document_type_code VARCHAR)
SELECT document_type_name, document_type_description FROM Ref_document_types WHERE document_type_code = "RV"
Qual é o código do tipo de documento para o tipo de documento "Papel"?
CREATE TABLE Ref_document_types (document_type_code VARCHAR, document_type_name VARCHAR)
SELECT document_type_code FROM Ref_document_types WHERE document_type_name = "Paper"
Indicar o número de documentos com o código de tipo de documento CV ou BK.
CREATE TABLE All_documents (document_type_code VARCHAR)
SELECT COUNT(*) FROM All_documents WHERE document_type_code = "CV" OR document_type_code = "BK"
Qual a data de armazenamento do documento "Civilo de casamento"?
CREATE TABLE All_documents (date_stored VARCHAR, Document_name VARCHAR)
SELECT date_stored FROM All_documents WHERE Document_name = "Marry CV"
Qual é o número e data de todos os documentos?
CREATE TABLE All_documents (Date_Stored VARCHAR, date_stored VARCHAR); CREATE TABLE Ref_calendar (day_Number VARCHAR, calendar_date VARCHAR)
SELECT T2.day_Number, T1.Date_Stored FROM All_documents AS T1 JOIN Ref_calendar AS T2 ON T1.date_stored = T2.calendar_date
Qual é o nome do tipo de documento para o documento com o nome "Como ler um livro"?
CREATE TABLE Ref_document_types (document_type_name VARCHAR, document_type_code VARCHAR); CREATE TABLE All_documents (document_type_code VARCHAR, document_name VARCHAR)
SELECT T2.document_type_name FROM All_documents AS T1 JOIN Ref_document_types AS T2 ON T1.document_type_code = T2.document_type_code WHERE T1.document_name = "How to read a book"
Mostrar o número de localizações.
CREATE TABLE Ref_locations (Id VARCHAR)
SELECT COUNT(*) FROM Ref_locations
Escreve todos os códigos e nomes de localização.
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
SELECT location_code, location_name FROM Ref_locations
Qual é o nome e a descrição do código de localização x?
CREATE TABLE Ref_locations (location_name VARCHAR, location_description VARCHAR, location_code VARCHAR)
SELECT location_name, location_description FROM Ref_locations WHERE location_code = "x"
Qual é o código de localização para o país "Canadá"?
CREATE TABLE Ref_locations (location_code VARCHAR, location_name VARCHAR)
SELECT location_code FROM Ref_locations WHERE location_name = "Canada"
Quantos papéis existem?
CREATE TABLE ROLES (Id VARCHAR)
SELECT COUNT(*) FROM ROLES
Escrever todos os códigos de funções, nomes de funções e descrições de funções.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR, role_description VARCHAR)
SELECT role_code, role_name, role_description FROM ROLES
Qual é o nome e a descrição do código de função "MG"?
CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
SELECT role_name, role_description FROM ROLES WHERE role_code = "MG"
Mostrar a descrição do nome do papel "Reader de provas".
CREATE TABLE ROLES (role_description VARCHAR, role_name VARCHAR)
SELECT role_description FROM ROLES WHERE role_name = "Proof Reader"
Indicar o nome, o código de função e a data de nascimento do empregado com o nome "Armani".
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR, date_of_birth VARCHAR, employee_Name VARCHAR)
SELECT employee_name, role_code, date_of_birth FROM Employees WHERE employee_Name = 'Armani'
Qual é a identificação do empregado chamado Ebba?
CREATE TABLE Employees (employee_ID VARCHAR, employee_name VARCHAR)
SELECT employee_ID FROM Employees WHERE employee_name = "Ebba"
Mostrar os nomes de todos os funcionários com função "RH".
CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
SELECT employee_name FROM Employees WHERE role_code = "HR"
Indicar todos os códigos de funções e o número de empregados em cada função.
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code, COUNT(*) FROM Employees GROUP BY role_code
Qual é o código de funções com o maior número de empregados?
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) DESC LIMIT 1
Mostrar todos os códigos de funções com pelo menos 3 funcionários.
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code HAVING COUNT(*) >= 3
Mostrar o código de funções com menos funcionários.
CREATE TABLE Employees (role_code VARCHAR)
SELECT role_code FROM Employees GROUP BY role_code ORDER BY COUNT(*) LIMIT 1
Qual é o nome e a descrição do papel para o empregado chamado Ebba?
CREATE TABLE Employees (role_code VARCHAR, employee_name VARCHAR); CREATE TABLE ROLES (role_name VARCHAR, role_description VARCHAR, role_code VARCHAR)
SELECT T2.role_name, T2.role_description FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T1.employee_name = "Ebba"
Mostrar os nomes dos funcionários com o nome de função Editor.
CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR); CREATE TABLE Employees (employee_name VARCHAR, role_code VARCHAR)
SELECT T1.employee_name FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Editor"
Mostrar as identidades dos funcionários para todos os funcionários com o nome de função "Resouros Humanos" ou "Gerenciador".
CREATE TABLE Employees (employee_id VARCHAR, role_code VARCHAR); CREATE TABLE ROLES (role_code VARCHAR, role_name VARCHAR)
SELECT T1.employee_id FROM Employees AS T1 JOIN ROLES AS T2 ON T1.role_code = T2.role_code WHERE T2.role_name = "Human Resource" OR T2.role_name = "Manager"
Quais são os diferentes códigos de localização dos documentos?
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT DISTINCT location_code FROM Document_locations
Indicar o nome do local para o documento "CV Robin".
CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR); CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (document_id VARCHAR, location_code VARCHAR)
SELECT T3.location_name FROM All_documents AS T1 JOIN Document_locations AS T2 ON T1.document_id = T2.document_id JOIN Ref_locations AS T3 ON T2.location_code = T3.location_code WHERE T1.document_name = "Robin CV"
Mostrar o código de localização, a data de início e os dados de fim nesse local para todos os documentos.
CREATE TABLE Document_locations (location_code VARCHAR, date_in_location_from VARCHAR, date_in_locaton_to VARCHAR)
SELECT location_code, date_in_location_from, date_in_locaton_to FROM Document_locations
Qual é a "data em localização de" e "a data em localização para" para o documento com o nome "Robin CV"?
CREATE TABLE All_documents (document_id VARCHAR, document_name VARCHAR); CREATE TABLE Document_locations (date_in_location_from VARCHAR, date_in_locaton_to VARCHAR, document_id VARCHAR)
SELECT T1.date_in_location_from, T1.date_in_locaton_to FROM Document_locations AS T1 JOIN All_documents AS T2 ON T1.document_id = T2.document_id WHERE T2.document_name = "Robin CV"
Mostrar os códigos de localização e o número de documentos em cada localização.
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT location_code, COUNT(*) FROM Document_locations GROUP BY location_code
Qual é o código de localização com mais documentos?
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT location_code FROM Document_locations GROUP BY location_code ORDER BY COUNT(*) DESC LIMIT 1
Mostrar os códigos de localização com pelo menos 3 documentos.
CREATE TABLE Document_locations (location_code VARCHAR)
SELECT location_code FROM Document_locations GROUP BY location_code HAVING COUNT(*) >= 3
Mostrar o nome e o código do local com menos documentos.
CREATE TABLE Document_locations (location_code VARCHAR); CREATE TABLE Ref_locations (location_name VARCHAR, location_code VARCHAR)
SELECT T2.location_name, T1.location_code FROM Document_locations AS T1 JOIN Ref_locations AS T2 ON T1.location_code = T2.location_code GROUP BY T1.location_code ORDER BY COUNT(*) LIMIT 1
Quais são os nomes dos empregados que autorizaram a destruição e os empregados que destruíram os documentos correspondentes?
CREATE TABLE Employees (employee_name VARCHAR, employee_id VARCHAR); CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR, Destroyed_by_Employee_ID VARCHAR)
SELECT T2.employee_name, T3.employee_name FROM Documents_to_be_destroyed AS T1 JOIN Employees AS T2 ON T1.Destruction_Authorised_by_Employee_ID = T2.employee_id JOIN Employees AS T3 ON T1.Destroyed_by_Employee_ID = T3.employee_id
Indicar o número de identificação de cada empregado e o número de documentos que esse empregado autorizou a destruir.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT Destruction_Authorised_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destruction_Authorised_by_Employee_ID
Mostrar as identidades dos empregados e o número de documentos destruídos por cada empregado.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
SELECT Destroyed_by_Employee_ID, COUNT(*) FROM Documents_to_be_destroyed GROUP BY Destroyed_by_Employee_ID
Mostre as identidades dos funcionários que não autorizam a destruição de qualquer documento.
CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR); CREATE TABLE Employees (employee_id VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT employee_id FROM Employees EXCEPT SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
Mostre as identidades de todos os funcionários que autorizaram a destruição.
CREATE TABLE Documents_to_be_destroyed (Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT DISTINCT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
Mostre as identidades de todos os funcionários que destruíram um documento.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR)
SELECT DISTINCT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed
Mostre as identidades de todos os funcionários que não destruam nenhum documento.
CREATE TABLE Employees (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR); CREATE TABLE Documents_to_be_destroyed (employee_id VARCHAR, Destroyed_by_Employee_ID VARCHAR)
SELECT employee_id FROM Employees EXCEPT SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed
Mostrar as identidades de todos os funcionários que destruíram um documento ou fizeram uma autorização para fazê-lo.
CREATE TABLE Documents_to_be_destroyed (Destroyed_by_Employee_ID VARCHAR, Destruction_Authorised_by_Employee_ID VARCHAR)
SELECT Destroyed_by_Employee_ID FROM Documents_to_be_destroyed UNION SELECT Destruction_Authorised_by_Employee_ID FROM Documents_to_be_destroyed
Quais são os nomes de todos os clubes?
CREATE TABLE club (clubname VARCHAR)
SELECT clubname FROM club
Quantos alunos há?
CREATE TABLE student (Id VARCHAR)
SELECT COUNT(*) FROM student
Quais são os primeiros nomes de todos os estudantes?
CREATE TABLE student (fname VARCHAR)
SELECT DISTINCT fname FROM student
Encontre os sobrenomes dos membros do clube "Bootup Baltimore".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore"
Quem são os membros do clube chamado "Hopkins Student Enterprises"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises"
Quantos membros tem o clube "Clube de Tênis"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club"
Encontre o número de membros do clube "Pen and Paper Gaming".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Pen and Paper Gaming"
A quantos clubes pertence "Linda Smith"?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Linda" AND t3.lname = "Smith"
Encontre o número de clubes onde "Tracy Kim" é membro.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Tracy" AND t3.lname = "Kim"
Encontre todas as mulheres do clube "Bootup Baltimore".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.sex = "F"
Encontre todos os membros do clube "Hopkins Student Enterprises".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t3.sex = "M"
Encontre todos os membros de "Bootup Baltimore" cuja especialização é "600". Mostre o primeiro nome e o sobrenome.
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR, major VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.major = "600"
Qual clube tem mais membros que se especializam em "600"?
CREATE TABLE student (stuid VARCHAR, major VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.major = "600" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
Encontre o nome do clube que tem mais estudantes do sexo feminino.
CREATE TABLE student (stuid VARCHAR, sex VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.sex = "F" GROUP BY t1.clubname ORDER BY COUNT(*) DESC LIMIT 1
Qual é a descrição do clube chamado "Clube de Tênis"?
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
SELECT clubdesc FROM club WHERE clubname = "Tennis Club"
Encontre a descrição do clube "Pen and Paper Gaming".
CREATE TABLE club (clubdesc VARCHAR, clubname VARCHAR)
SELECT clubdesc FROM club WHERE clubname = "Pen and Paper Gaming"
Onde está o clube chamado "Clube de Tênis"?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Tennis Club"
Encontre a localização do clube "Pen and Paper Gaming".
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Pen and Paper Gaming"
Onde está localizado o clube "Hopkins Student Enterprises"?
CREATE TABLE club (clublocation VARCHAR, clubname VARCHAR)
SELECT clublocation FROM club WHERE clubname = "Hopkins Student Enterprises"
Encontre o nome de todos os clubes da "AKW".
CREATE TABLE club (clubname VARCHAR, clublocation VARCHAR)
SELECT clubname FROM club WHERE clublocation = "AKW"
Quantos clubes estão localizados em "HHH"?
CREATE TABLE club (clublocation VARCHAR)
SELECT COUNT(*) FROM club WHERE clublocation = "HHH"
Qual é o primeiro e último nome do presidente do clube "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t2.position = "President"
Quem é o "CTO" do clube "Hopkins Student Enterprises"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (fname VARCHAR, lname VARCHAR, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR, position VARCHAR)
SELECT t3.fname, t3.lname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises" AND t2.position = "CTO"
Quantos papéis diferentes há no clube "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE member_of_club (position VARCHAR, clubid VARCHAR)
SELECT COUNT(DISTINCT t2.position) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid WHERE t1.clubname = "Bootup Baltimore"
Quantos membros do "Bootup Baltimore" têm mais de 18 anos?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age > 18
Quantos membros do clube "Bootup Baltimore" têm menos de 18 anos?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (stuid VARCHAR, age VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT COUNT(*) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore" AND t3.age < 18
Encontre os nomes de todos os clubes que têm pelo menos um membro da cidade com código de cidade "BAL".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "BAL"
Encontre os nomes dos clubes que têm pelo menos um membro da cidade com código de cidade "HOU".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, city_code VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.city_code = "HOU"
A quantos clubes pertence o estudante chamado "Eric Tai"?
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT COUNT(DISTINCT t1.clubname) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Eric" AND t3.lname = "Tai"
Escreva os clubes que têm "Davis Steven" como membro.
CREATE TABLE student (stuid VARCHAR, fname VARCHAR, lname VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.fname = "Davis" AND t3.lname = "Steven"
Escreva os clubes que têm pelo menos um membro com um conselheiro "1121".
CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR); CREATE TABLE club (clubname VARCHAR, clubid VARCHAR); CREATE TABLE student (stuid VARCHAR, advisor VARCHAR)
SELECT DISTINCT t1.clubname FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t3.advisor = 1121
Qual é a idade média dos membros do clube "Bootup Baltimore"?
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Bootup Baltimore"
Encontre a idade média dos membros do clube "Hopkins Student Enterprises".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Hopkins Student Enterprises"
Retrocedir a idade média dos membros do clube "Clube de tênis".
CREATE TABLE club (clubid VARCHAR, clubname VARCHAR); CREATE TABLE student (age INTEGER, stuid VARCHAR); CREATE TABLE member_of_club (clubid VARCHAR, stuid VARCHAR)
SELECT AVG(t3.age) FROM club AS t1 JOIN member_of_club AS t2 ON t1.clubid = t2.clubid JOIN student AS t3 ON t2.stuid = t3.stuid WHERE t1.clubname = "Tennis Club"
Qual é o montante da subvenção em caso de envio dos documentos antes de "1986-08-26 20:49:27" e de cessação da subvenção após "1989-03-16 18:27:16"?
CREATE TABLE grants (grant_amount VARCHAR, grant_end_date INTEGER); CREATE TABLE Grants (grant_amount VARCHAR, grant_id VARCHAR); CREATE TABLE Documents (grant_id VARCHAR, sent_date INTEGER)
SELECT T1.grant_amount FROM Grants AS T1 JOIN Documents AS T2 ON T1.grant_id = T2.grant_id WHERE T2.sent_date < '1986-08-26 20:49:27' INTERSECT SELECT grant_amount FROM grants WHERE grant_end_date > '1989-03-16 18:27:16'
Liste os detalhes do projeto do projeto que produz tanto patente quanto papel como resultados.
CREATE TABLE Project_outcomes (project_id VARCHAR, outcome_code VARCHAR); CREATE TABLE Projects (project_details VARCHAR, project_id VARCHAR)
SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Paper' INTERSECT SELECT T1.project_details FROM Projects AS T1 JOIN Project_outcomes AS T2 ON T1.project_id = T2.project_id WHERE T2.outcome_code = 'Patent'
Qual é o montante total das subvenções concedidas às organizações descritas como pesquisadoras?
CREATE TABLE organisation_Types (organisation_type VARCHAR, organisation_type_description VARCHAR); CREATE TABLE Grants (organisation_id VARCHAR); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_type VARCHAR)
SELECT SUM(grant_amount) FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id JOIN organisation_Types AS T3 ON T2.organisation_type = T3.organisation_type WHERE T3.organisation_type_description = 'Research'
Lista a partir de que data e até que data trabalham estes funcionários: pessoal do projeto do projeto que contrata mais pessoal
CREATE TABLE Project_Staff (date_from VARCHAR, date_to VARCHAR, project_id VARCHAR, role_code VARCHAR)
SELECT date_from, date_to FROM Project_Staff WHERE project_id IN (SELECT project_id FROM Project_Staff GROUP BY project_id ORDER BY COUNT(*) DESC LIMIT 1) UNION SELECT date_from, date_to FROM Project_Staff WHERE role_code = 'leader'
Encontrar os identificadores e os dados das organizações que participam na
CREATE TABLE Grants (organisation_id VARCHAR, grant_amount INTEGER); CREATE TABLE Organisations (organisation_id VARCHAR, organisation_details VARCHAR)
SELECT T2.organisation_id, T2.organisation_details FROM Grants AS T1 JOIN Organisations AS T2 ON T1.organisation_id = T2.organisation_id GROUP BY T2.organisation_id HAVING SUM(T1.grant_amount) > 6000
Qual é o tipo de organização e a identificação da organização que tem o maior número de investigadores?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)
SELECT T1.organisation_type, T1.organisation_id FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_id ORDER BY COUNT(*) DESC LIMIT 1
Qual o tipo de organização que contrata mais pessoal de investigação?
CREATE TABLE Research_Staff (employer_organisation_id VARCHAR); CREATE TABLE Organisations (organisation_type VARCHAR, organisation_id VARCHAR)
SELECT T1.organisation_type FROM Organisations AS T1 JOIN Research_Staff AS T2 ON T1.organisation_id = T2.employer_organisation_id GROUP BY T1.organisation_type ORDER BY COUNT(*) DESC LIMIT 1