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Encontre o nome dos médicos cujo título de posição contenha a palavra "senior". | CREATE TABLE physician (name VARCHAR, POSITION VARCHAR) | SELECT name FROM physician WHERE POSITION LIKE '%senior%' |
Encontrar o paciente que teve o tratamento mais recente? | CREATE TABLE undergoes (patient VARCHAR, dateundergoes VARCHAR) | SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1 |
Encontre os nomes de todos os pacientes que estão a ser tratados e que estão no quarto 111. | CREATE TABLE undergoes (patient VARCHAR, Stay VARCHAR); CREATE TABLE stay (StayID VARCHAR, room VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR) | SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111 |
Enumera os nomes de todas as enfermeiras em ordem alfabética? | CREATE TABLE nurse (name VARCHAR) | SELECT DISTINCT name FROM nurse ORDER BY name |
Encontre os nomes dos enfermeiros que estão a tratar um paciente em tratamento. | CREATE TABLE undergoes (AssistingNurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR) | SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID |
Escreva os nomes de todos os medicamentos, em ordem alfabética. | CREATE TABLE medication (name VARCHAR) | SELECT DISTINCT name FROM medication ORDER BY name |
Qual é o nome do médico que prescreveu a dose mais alta? | CREATE TABLE prescribes (physician VARCHAR, dose VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR) | SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1 |
'Liste os ids dos funcionários médicos juntamente com os ids de seus departamentos de afiliação primária.' | CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR, primaryaffiliation VARCHAR) | SELECT physician, department FROM affiliated_with WHERE primaryaffiliation = 1 |
Escreva os nomes dos departamentos onde alguns médicos são principalmente afiliados. | CREATE TABLE affiliated_with (department VARCHAR); CREATE TABLE department (name VARCHAR, departmentid VARCHAR) | SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1 |
Que enfermeiras estão de serviço no bloco 1 e no bloco 1? | CREATE TABLE on_call (nurse VARCHAR, blockfloor VARCHAR, blockcode VARCHAR) | SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1 |
Quais são os custos mais elevados, os mais baixos e o custo médio dos procedimentos? | CREATE TABLE procedures (cost INTEGER) | SELECT MAX(cost), MIN(cost), AVG(cost) FROM procedures |
Indicar o nome e o custo de todos os procedimentos, ordenados pelo custo, do mais alto para o mais baixo. | CREATE TABLE procedures (name VARCHAR, cost VARCHAR) | SELECT name, cost FROM procedures ORDER BY cost DESC |
Encontre os três procedimentos mais caros. | CREATE TABLE procedures (name VARCHAR, cost VARCHAR) | SELECT name FROM procedures ORDER BY cost LIMIT 3 |
Encontre os médicos que são treinados em um procedimento que custa mais de 5000. | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost INTEGER) | SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000 |
Encontrar o médico que foi treinado no procedimento mais caro? | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost VARCHAR) | SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1 |
Qual é o custo médio dos procedimentos em que o médico John Wen foi treinado? | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (cost INTEGER, code VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR) | SELECT AVG(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen" |
Encontre os nomes dos procedimentos em que o médico John Wen foi treinado. | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) | SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen" |
Encontre todos os procedimentos que custaram mais de mil ou em que o médico John Wen foi treinado. | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) | SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen" |
Encontre os nomes de todos os procedimentos que custaram mais de 1000, mas em que médico John Wen não foi treinado? | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) | SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen" |
Encontre os nomes de todos os procedimentos de tal forma que o custo seja inferior a 5000 e o médico John Wen tenha sido treinado. | CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR) | SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen" |
Encontre o nome dos médicos que estão afiliados ao departamento de Cirurgia e do de Psiquiatria. | CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR) | SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry' |
Encontre o nome dos médicos que estão afiliados ao departamento de Cirurgia ou Psiquiatria. | CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR) | SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry' |
Encontre os nomes dos pacientes que não estão a tomar o medicamento de Procrastin-X. | CREATE TABLE Prescribes (Patient VARCHAR, Medication VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR); CREATE TABLE patient (name VARCHAR) | SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X' |
Calcule o número de pacientes que não estão a tomar o medicamento de Procrastin-X. | CREATE TABLE Prescribes (patient VARCHAR, Medication VARCHAR); CREATE TABLE patient (SSN VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR) | SELECT COUNT(*) FROM patient WHERE NOT SSN IN (SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X') |
Quantas consultas há? | CREATE TABLE appointment (Id VARCHAR) | SELECT COUNT(*) FROM appointment |
Encontre os nomes das enfermeiras que estão de serviço. | CREATE TABLE on_call (nurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR) | SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse |
Quantos navios há? | CREATE TABLE ship (Id VARCHAR) | SELECT COUNT(*) FROM ship |
Indicar o nome dos navios em ordem ascendente de tonelagem. | CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR) | SELECT Name FROM ship ORDER BY Tonnage |
Qual é o tipo e a nacionalidade dos navios? | CREATE TABLE ship (TYPE VARCHAR, Nationality VARCHAR) | SELECT TYPE, Nationality FROM ship |
Indique o nome dos navios cuja nacionalidade não seja "Estados Unidos". | CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR) | SELECT Name FROM ship WHERE Nationality <> "United States" |
Indicar o nome dos navios cuja nacionalidade seja os Estados Unidos ou o Reino Unido. | CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR) | SELECT Name FROM ship WHERE Nationality = "United States" OR Nationality = "United Kingdom" |
Qual é o nome do navio com a maior tonelagem? | CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR) | SELECT Name FROM ship ORDER BY Tonnage DESC LIMIT 1 |
Indicar os diferentes tipos de navios e o número de navios de cada tipo. | CREATE TABLE ship (TYPE VARCHAR) | SELECT TYPE, COUNT(*) FROM ship GROUP BY TYPE |
Indicar o tipo de navio mais comum. | CREATE TABLE ship (TYPE VARCHAR) | SELECT TYPE FROM ship GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1 |
Escreva as nações que têm mais de dois navios. | CREATE TABLE ship (Nationality VARCHAR) | SELECT Nationality FROM ship GROUP BY Nationality HAVING COUNT(*) > 2 |
Indicar os diferentes tipos de navios e a tonelagem média de cada tipo de navios. | CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER) | SELECT TYPE, AVG(Tonnage) FROM ship GROUP BY TYPE |
Mostrar códigos e destinos de missões, e nomes de naves envolvidas. | CREATE TABLE mission (Code VARCHAR, Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) | SELECT T1.Code, T1.Fate, T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID |
Mostrar os nomes dos navios envolvidos numa missão lançada após 1928. | CREATE TABLE mission (Ship_ID VARCHAR, Launched_Year INTEGER); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) | SELECT T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T1.Launched_Year > 1928 |
Mostrar o destino distinto das missões que envolvem navios com nacionalidade "Estados Unidos" | CREATE TABLE mission (Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Ship_ID VARCHAR, Nationality VARCHAR) | SELECT DISTINCT T1.Fate FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T2.Nationality = "United States" |
Indicar o nome dos navios que não estão envolvidos em nenhuma missão | CREATE TABLE mission (Name VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR) | SELECT Name FROM ship WHERE NOT Ship_ID IN (SELECT Ship_ID FROM mission) |
Indicar os tipos de navios que têm navios com arqueação superior a 6000 e navios com arqueação inferior a 4000. | CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER) | SELECT TYPE FROM ship WHERE Tonnage > 6000 INTERSECT SELECT TYPE FROM ship WHERE Tonnage < 4000 |
Encontre o número total de alunos. | CREATE TABLE list (Id VARCHAR) | SELECT COUNT(*) FROM list |
Encontre os sobrenomes dos estudantes que estudam no quarto 111. | CREATE TABLE list (lastname VARCHAR, classroom VARCHAR) | SELECT lastname FROM list WHERE classroom = 111 |
Encontre os nomes dos alunos que estudam no quarto 108. | CREATE TABLE list (firstname VARCHAR, classroom VARCHAR) | SELECT firstname FROM list WHERE classroom = 108 |
Quais são os primeiros nomes dos estudantes que estudam no quarto 107? | CREATE TABLE list (firstname VARCHAR, classroom VARCHAR) | SELECT DISTINCT firstname FROM list WHERE classroom = 107 |
Para cada sala de aula, relate a série que é ensinada nela. Relate apenas o número da sala de aula e o número da série. | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT DISTINCT classroom, grade FROM list |
Que classe está a estudar na sala 103? | CREATE TABLE list (grade VARCHAR, classroom VARCHAR) | SELECT DISTINCT grade FROM list WHERE classroom = 103 |
Encontre a nota de estudo no quarto 105. | CREATE TABLE list (grade VARCHAR, classroom VARCHAR) | SELECT DISTINCT grade FROM list WHERE classroom = 105 |
Que salas de aula são usadas pelo 4o ano? | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT DISTINCT classroom FROM list WHERE grade = 4 |
Que salas de aula são usadas pelo 5o ano? | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT DISTINCT classroom FROM list WHERE grade = 5 |
Encontre os sobrenomes dos professores que ensinam o quinto ano. | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR) | SELECT DISTINCT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 5 |
Encontre os nomes dos professores que ensinam o primeiro ano. | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR) | SELECT DISTINCT T2.firstname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 1 |
Encontre os primeiros nomes de todos os professores que ensinam na sala de aula 110. | CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR) | SELECT firstname FROM teachers WHERE classroom = 110 |
Encontre os sobrenomes dos professores que ensinam na sala 109. | CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR) | SELECT lastname FROM teachers WHERE classroom = 109 |
Indique o nome e o apelido de todos os professores. | CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR) | SELECT DISTINCT firstname, lastname FROM teachers |
Relata o nome e apelido de todos os alunos. | CREATE TABLE list (firstname VARCHAR, lastname VARCHAR) | SELECT DISTINCT firstname, lastname FROM list |
Encontre todos os alunos ensinados por Otha Moyer. | CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER" |
Encontre todos os alunos ensinados por MARROTTE KIRK. Exiba os primeiros e últimos nomes dos alunos. | CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "MARROTTE" AND T2.lastname = "KIRK" |
Encontre o nome e o apelido de todos os professores que ensinam a EVELINA BROMLEY. | CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "EVELINA" AND T1.lastname = "BROMLEY" |
Encontre os sobrenomes de todos os professores que ensinam GELL TAMI. | CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "GELL" AND T1.lastname = "TAMI" |
Quantos alunos a Loria Ondersma ensina? | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "LORIA" AND T2.lastname = "ONDERSMA" |
Quantos alunos é que o Kawa Gordon ensina? | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "KAWA" AND T2.lastname = "GORDON" |
Encontre o número de alunos ensinados por TARRING LEIA. | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "TARRING" AND T2.lastname = "LEIA" |
Quantos professores tem a aluna chamada Chrissy Nabozny? | CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "CHRISSY" AND T1.lastname = "NABOZNY" |
Quantos professores tem o aluno chamado MADLOCK RAY? | CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "MADLOCK" AND T1.lastname = "RAY" |
Encontre todos os alunos de 1o ano que não são ensinados pela OTHA MOYER. | CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR) | SELECT DISTINCT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 1 EXCEPT SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER" |
Encontre os sobrenomes dos alunos da terceira série que não são ensinados por COVIN JEROME. | CREATE TABLE list (lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, lastname VARCHAR, firstname VARCHAR) | SELECT DISTINCT T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 3 AND T2.firstname <> "COVIN" AND T2.lastname <> "JEROME" |
Para cada grau, indique o grau, o número de salas de aula em que é ministrado e o número total de alunos no grau. | CREATE TABLE list (grade VARCHAR, classroom VARCHAR) | SELECT grade, COUNT(DISTINCT classroom), COUNT(*) FROM list GROUP BY grade |
Para cada sala de aula, notifique o número da sala e o número de notas que a utilizam. | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT classroom, COUNT(DISTINCT grade) FROM list GROUP BY classroom |
Qual sala de aula tem mais alunos? | CREATE TABLE list (classroom VARCHAR) | SELECT classroom FROM list GROUP BY classroom ORDER BY COUNT(*) DESC LIMIT 1 |
Relate o número de alunos em cada sala de aula. | CREATE TABLE list (classroom VARCHAR) | SELECT classroom, COUNT(*) FROM list GROUP BY classroom |
Para cada sala de aula do grau 0, informar o número total de alunos. | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT classroom, COUNT(*) FROM list WHERE grade = "0" GROUP BY classroom |
Relata o número total de alunos para cada sala de aula de 4o ano. | CREATE TABLE list (classroom VARCHAR, grade VARCHAR) | SELECT classroom, COUNT(*) FROM list WHERE grade = "4" GROUP BY classroom |
Encontre o nome do professor que ensina o maior número de alunos. | CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR) | SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom GROUP BY T2.firstname, T2.lastname ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre o número de alunos em uma sala de aula. | CREATE TABLE list (classroom VARCHAR) | SELECT COUNT(*), classroom FROM list GROUP BY classroom |
Quantas empresas têm sede nos EUA? | CREATE TABLE company (Headquarters VARCHAR) | SELECT COUNT(*) FROM company WHERE Headquarters = 'USA' |
Escreva os nomes das empresas por número ascendente de vendas. | CREATE TABLE company (Name VARCHAR, Sales_in_Billion VARCHAR) | SELECT Name FROM company ORDER BY Sales_in_Billion |
Quais são as sedes e as indústrias de todas as empresas? | CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR) | SELECT Headquarters, Industry FROM company |
Mostrar os nomes das empresas do setor bancário ou do varejo? | CREATE TABLE company (Name VARCHAR, Industry VARCHAR) | SELECT Name FROM company WHERE Industry = "Banking" OR Industry = "Retailing" |
Qual é o valor de mercado máximo e mínimo das empresas? | CREATE TABLE company (Market_Value_in_Billion INTEGER) | SELECT MAX(Market_Value_in_Billion), MIN(Market_Value_in_Billion) FROM company |
Qual é a sede da empresa com as maiores vendas? | CREATE TABLE company (Headquarters VARCHAR, Sales_in_Billion VARCHAR) | SELECT Headquarters FROM company ORDER BY Sales_in_Billion DESC LIMIT 1 |
Indicar as diferentes sedes e o número de empresas em cada sede. | CREATE TABLE company (Headquarters VARCHAR) | SELECT Headquarters, COUNT(*) FROM company GROUP BY Headquarters |
Mostrar a sede mais comum para empresas. | CREATE TABLE company (Headquarters VARCHAR) | SELECT Headquarters FROM company GROUP BY Headquarters ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre a sede que tem pelo menos duas companhias. | CREATE TABLE company (Headquarters VARCHAR) | SELECT Headquarters FROM company GROUP BY Headquarters HAVING COUNT(*) >= 2 |
Mostrar a sede que tem ambas as empresas na indústria bancária e empresas na indústria de petróleo e gás. | CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR) | SELECT Headquarters FROM company WHERE Industry = "Banking" INTERSECT SELECT Headquarters FROM company WHERE Industry = "Oil and gas" |
Indicar os nomes das empresas e dos trabalhadores. | CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) | SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID |
Indicar os nomes das empresas e os dos empregados em ordem decrescente do número de anos de trabalho para esse empregado. | CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR, Year_working VARCHAR) | SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID ORDER BY T1.Year_working |
Mostre os nomes dos funcionários que trabalham para empresas com vendas maiores que 200. | CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE company (Company_ID VARCHAR, Sales_in_Billion INTEGER); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) | SELECT T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID WHERE T3.Sales_in_Billion > 200 |
Indicar os nomes das empresas e o número de empregados que têm | CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE people (People_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR) | SELECT T3.Name, COUNT(*) FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID GROUP BY T3.Name |
Escrever os nomes das pessoas que não são empregadas por nenhuma empresa | CREATE TABLE employment (Name VARCHAR, People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR) | SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM employment) |
A Comissão considera que a Comissão não pode ter a menor dúvida sobre a existência de um auxílio estatal. | CREATE TABLE company (name VARCHAR, Sales_in_Billion INTEGER, Profits_in_Billion VARCHAR) | SELECT name FROM company WHERE Sales_in_Billion > 200 ORDER BY Sales_in_Billion, Profits_in_Billion DESC |
Quantos filmes há? | CREATE TABLE film (Id VARCHAR) | SELECT COUNT(*) FROM film |
Escreva o diretor de todos os filmes. | CREATE TABLE film (Director VARCHAR) | SELECT DISTINCT Director FROM film |
Qual é a média das vendas de bilhetes brutos em dólares de filmes? | CREATE TABLE film (Gross_in_dollar INTEGER) | SELECT AVG(Gross_in_dollar) FROM film |
Quais são as estimativas baixas e altas dos mercados cinematográficos? | CREATE TABLE film_market_estimation (Low_Estimate VARCHAR, High_Estimate VARCHAR) | SELECT Low_Estimate, High_Estimate FROM film_market_estimation |
Quais são os tipos de estimativas do mercado cinematográfico no ano de 1995? | CREATE TABLE film_market_estimation (TYPE VARCHAR, YEAR VARCHAR) | SELECT TYPE FROM film_market_estimation WHERE YEAR = 1995 |
Qual é o número máximo e mínimo de cidades em todos os mercados. | CREATE TABLE market (Number_cities INTEGER) | SELECT MAX(Number_cities), MIN(Number_cities) FROM market |
Quantos mercados têm cidades com menos de 300 habitantes? | CREATE TABLE market (Number_cities INTEGER) | SELECT COUNT(*) FROM market WHERE Number_cities < 300 |
Lista todos os países de mercados em ordem alfabética ascendente. | CREATE TABLE market (Country VARCHAR) | SELECT Country FROM market ORDER BY Country |
Lista todos os países de mercados em ordem decrescente do número de cidades. | CREATE TABLE market (Country VARCHAR, Number_cities VARCHAR) | SELECT Country FROM market ORDER BY Number_cities DESC |
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