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Calcule o montante total dos empréstimos oferecidos por cada filial bancária. | CREATE TABLE loan (branch_id VARCHAR); CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR) | SELECT SUM(amount), T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname |
Encontre o nome de clientes que têm mais de um empréstimo. | CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR); CREATE TABLE loan (cust_id VARCHAR) | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING COUNT(*) > 1 |
Encontre o nome e o saldo da conta dos clientes que têm empréstimos com uma quantia total superior a 5000. | CREATE TABLE loan (cust_id VARCHAR, amount INTEGER); CREATE TABLE customer (cust_name VARCHAR, acc_type VARCHAR, cust_id VARCHAR) | SELECT T1.cust_name, T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING SUM(T2.amount) > 5000 |
Encontre o nome da filial do banco que forneceu a maior quantidade total de empréstimos. | CREATE TABLE loan (branch_id VARCHAR, amount INTEGER); CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR) | SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY SUM(T2.amount) DESC LIMIT 1 |
Encontre o nome da filial do banco que forneceu o maior montante total de empréstimos para clientes com pontuação de crédito é menor que 100. | CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR, amount INTEGER); CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR); CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER) | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY SUM(T1.amount) DESC LIMIT 1 |
Encontre o nome das agências bancárias que forneceram alguns empréstimos. | CREATE TABLE loan (branch_id VARCHAR); CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR) | SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id |
Encontre o nome e a pontuação de crédito dos clientes que possuem empréstimos. | CREATE TABLE customer (cust_name VARCHAR, credit_score VARCHAR, cust_id VARCHAR); CREATE TABLE loan (cust_id VARCHAR) | SELECT DISTINCT T1.cust_name, T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id |
Encontre o nome dos clientes que têm um empréstimo com montante superior a 3000. | CREATE TABLE customer (cust_name VARCHAR, cust_id VARCHAR); CREATE TABLE loan (cust_id VARCHAR) | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000 |
Encontre a cidade e o nome das agências bancárias que oferecem empréstimos para negócios. | CREATE TABLE bank (bname VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE loan (branch_id VARCHAR, loan_type VARCHAR) | SELECT T1.bname, T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = 'Business' |
Encontre os nomes das sucursais bancárias que tenham concedido um empréstimo a qualquer cliente cujo crédito seja inferior a 100. | CREATE TABLE bank (bname VARCHAR, branch_id VARCHAR); CREATE TABLE customer (cust_id VARCHAR, credit_score INTEGER); CREATE TABLE loan (branch_id VARCHAR, cust_id VARCHAR) | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 |
Encontre o valor total dos empréstimos concedidos pelas agências bancárias no estado de Nova York. | CREATE TABLE bank (branch_id VARCHAR, state VARCHAR); CREATE TABLE loan (amount INTEGER, branch_id VARCHAR) | SELECT SUM(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = 'New York' |
Encontre a pontuação de crédito média dos clientes que têm algum empréstimo. | CREATE TABLE loan (credit_score INTEGER, cust_id VARCHAR); CREATE TABLE customer (credit_score INTEGER, cust_id VARCHAR) | SELECT AVG(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) |
Encontre a pontuação de crédito média dos clientes que não têm nenhum empréstimo. | CREATE TABLE loan (credit_score INTEGER, cust_id VARCHAR); CREATE TABLE customer (credit_score INTEGER, cust_id VARCHAR) | SELECT AVG(credit_score) FROM customer WHERE NOT cust_id IN (SELECT cust_id FROM loan) |
Quantas notas de avaliação há no total? | CREATE TABLE ASSESSMENT_NOTES (Id VARCHAR) | SELECT COUNT(*) FROM ASSESSMENT_NOTES |
Qual é a data das notas de avaliação? | CREATE TABLE Assessment_Notes (date_of_notes VARCHAR) | SELECT date_of_notes FROM Assessment_Notes |
Quantos endereços têm código postal 197? | CREATE TABLE ADDRESSES (zip_postcode VARCHAR) | SELECT COUNT(*) FROM ADDRESSES WHERE zip_postcode = "197" |
Quantos códigos de tipo de incidente há? | CREATE TABLE Behavior_Incident (incident_type_code VARCHAR) | SELECT COUNT(DISTINCT incident_type_code) FROM Behavior_Incident |
Devolver todos os códigos de tipo de detenção. | CREATE TABLE Detention (detention_type_code VARCHAR) | SELECT DISTINCT detention_type_code FROM Detention |
Qual é a data de início e de fim dos incidentes com código de tipo de incidente "ROIDO"? | CREATE TABLE Behavior_Incident (date_incident_start VARCHAR, date_incident_end VARCHAR, incident_type_code VARCHAR) | SELECT date_incident_start, date_incident_end FROM Behavior_Incident WHERE incident_type_code = "NOISE" |
Devolva todos os resumos da detenção. | CREATE TABLE Detention (detention_summary VARCHAR) | SELECT detention_summary FROM Detention |
Devolva o número de telemóvel e o endereço de e-mail de todos os alunos. | CREATE TABLE STUDENTS (cell_mobile_number VARCHAR, email_address VARCHAR) | SELECT cell_mobile_number, email_address FROM STUDENTS |
Qual é o e-mail da estudante com o nome "Emma" e o apelido "Rohan"? | CREATE TABLE Students (email_address VARCHAR, first_name VARCHAR, last_name VARCHAR) | SELECT email_address FROM Students WHERE first_name = "Emma" AND last_name = "Rohan" |
Quantos estudantes diferentes foram detidos? | CREATE TABLE Students_in_Detention (student_id VARCHAR) | SELECT COUNT(DISTINCT student_id) FROM Students_in_Detention |
Qual é o sexo da professora com o sobrenome "Medhurst"? | CREATE TABLE TEACHERS (gender VARCHAR, last_name VARCHAR) | SELECT gender FROM TEACHERS WHERE last_name = "Medhurst" |
Qual é a descrição do tipo de incidente para o tipo de incidente com código "VIOLÊNCIA"? | CREATE TABLE Ref_Incident_Type (incident_type_description VARCHAR, incident_type_code VARCHAR) | SELECT incident_type_description FROM Ref_Incident_Type WHERE incident_type_code = "VIOLENCE" |
Encontre o aluguel mensal máximo e mínimo para todos os endereços de estudantes. | CREATE TABLE Student_Addresses (monthly_rental INTEGER) | SELECT MAX(monthly_rental), MIN(monthly_rental) FROM Student_Addresses |
Encontre os nomes dos professores cujo endereço de e-mail contém a palavra "homem". | CREATE TABLE Teachers (first_name VARCHAR, email_address VARCHAR) | SELECT first_name FROM Teachers WHERE email_address LIKE '%man%' |
A lista de todas as informações sobre as notas de avaliação ordenadas por data em ordem crescente. | CREATE TABLE Assessment_Notes (date_of_notes VARCHAR) | SELECT * FROM Assessment_Notes ORDER BY date_of_notes |
Escreva todas as cidades em ordem alfabética. | CREATE TABLE Addresses (city VARCHAR) | SELECT city FROM Addresses ORDER BY city |
Encontre os nomes e apelidos dos professores em ordem alfabética de sobrenome. | CREATE TABLE Teachers (first_name VARCHAR, last_name VARCHAR) | SELECT first_name, last_name FROM Teachers ORDER BY last_name |
Encontre todas as informações sobre endereços de estudantes e classifique por aluguel mensal em ordem decrescente. | CREATE TABLE Student_Addresses (monthly_rental VARCHAR) | SELECT * FROM Student_Addresses ORDER BY monthly_rental DESC |
Encontre o nome e o nome do aluno que tem o maior número de notas de avaliação? | CREATE TABLE Students (first_name VARCHAR, student_id VARCHAR); CREATE TABLE Assessment_Notes (student_id VARCHAR) | SELECT T1.student_id, T2.first_name FROM Assessment_Notes AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre os nomes dos 3 professores que têm mais notas de avaliação? | CREATE TABLE Assessment_Notes (teacher_id VARCHAR); CREATE TABLE Teachers (first_name VARCHAR, teacher_id VARCHAR) | SELECT T1.teacher_id, T2.first_name FROM Assessment_Notes AS T1 JOIN Teachers AS T2 ON T1.teacher_id = T2.teacher_id GROUP BY T1.teacher_id ORDER BY COUNT(*) DESC LIMIT 3 |
Encontrar a identidade e o nome do aluno que tem mais incidentes de comportamento? | CREATE TABLE Students (last_name VARCHAR, student_id VARCHAR); CREATE TABLE Behavior_Incident (student_id VARCHAR) | SELECT T1.student_id, T2.last_name FROM Behavior_Incident AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre a identificação e o nome do professor que tem mais detenções com o código de detenção "AFTER"? | CREATE TABLE Detention (teacher_id VARCHAR, detention_type_code VARCHAR); CREATE TABLE Teachers (last_name VARCHAR, teacher_id VARCHAR) | SELECT T1.teacher_id, T2.last_name FROM Detention AS T1 JOIN Teachers AS T2 ON T1.teacher_id = T2.teacher_id WHERE T1.detention_type_code = "AFTER" GROUP BY T1.teacher_id ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é o nome e o nome do estudante cujo endereço tem a renda média mensal mais alta? | CREATE TABLE Students (first_name VARCHAR, student_id VARCHAR); CREATE TABLE Student_Addresses (student_id VARCHAR) | SELECT T1.student_id, T2.first_name FROM Student_Addresses AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY AVG(monthly_rental) DESC LIMIT 1 |
Encontre o número e o endereço da cidade do estudante com o aluguel mensal médio mais alto. | CREATE TABLE Student_Addresses (address_id VARCHAR); CREATE TABLE Addresses (city VARCHAR, address_id VARCHAR) | SELECT T2.address_id, T1.city FROM Addresses AS T1 JOIN Student_Addresses AS T2 ON T1.address_id = T2.address_id GROUP BY T2.address_id ORDER BY AVG(monthly_rental) DESC LIMIT 1 |
Qual é o código e a descrição do tipo de incidente de comportamento mais frequente? | CREATE TABLE Ref_Incident_Type (incident_type_description VARCHAR, incident_type_code VARCHAR); CREATE TABLE Behavior_Incident (incident_type_code VARCHAR) | SELECT T1.incident_type_code, T2.incident_type_description FROM Behavior_Incident AS T1 JOIN Ref_Incident_Type AS T2 ON T1.incident_type_code = T2.incident_type_code GROUP BY T1.incident_type_code ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é o código e a descrição do tipo de detenção menos frequente ? | CREATE TABLE Ref_Detention_Type (detention_type_description VARCHAR, detention_type_code VARCHAR); CREATE TABLE Detention (detention_type_code VARCHAR) | SELECT T1.detention_type_code, T2.detention_type_description FROM Detention AS T1 JOIN Ref_Detention_Type AS T2 ON T1.detention_type_code = T2.detention_type_code GROUP BY T1.detention_type_code ORDER BY COUNT(*) LIMIT 1 |
Encontre as datas das notas de avaliação para estudantes com nome de bateria "Fanny". | CREATE TABLE Students (student_id VARCHAR, first_name VARCHAR); CREATE TABLE Assessment_Notes (date_of_notes VARCHAR, student_id VARCHAR) | SELECT T1.date_of_notes FROM Assessment_Notes AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.first_name = "Fanny" |
Encontre os textos das notas de avaliação para professores com sobrenome "Schuster". | CREATE TABLE Assessment_Notes (text_of_notes VARCHAR, teacher_id VARCHAR); CREATE TABLE Teachers (teacher_id VARCHAR, last_name VARCHAR) | SELECT T1.text_of_notes FROM Assessment_Notes AS T1 JOIN Teachers AS T2 ON T1.teacher_id = T2.teacher_id WHERE T2.last_name = "Schuster" |
Encontre as datas de início e fim dos incidentes de comportamento de estudantes com sobrenome "Fahey". | CREATE TABLE Behavior_Incident (date_incident_start VARCHAR, student_id VARCHAR); CREATE TABLE Students (student_id VARCHAR, last_name VARCHAR) | SELECT T1.date_incident_start, date_incident_end FROM Behavior_Incident AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id WHERE T2.last_name = "Fahey" |
Encontre as datas de início e fim das detenções de professores com o sobrenome "Schultz". | CREATE TABLE Detention (datetime_detention_start VARCHAR, teacher_id VARCHAR); CREATE TABLE Teachers (teacher_id VARCHAR, last_name VARCHAR) | SELECT T1.datetime_detention_start, datetime_detention_end FROM Detention AS T1 JOIN Teachers AS T2 ON T1.teacher_id = T2.teacher_id WHERE T2.last_name = "Schultz" |
Qual é o código postal do endereço com o aluguel mais alto? | CREATE TABLE Student_Addresses (address_id VARCHAR); CREATE TABLE Addresses (zip_postcode VARCHAR, address_id VARCHAR) | SELECT T2.address_id, T1.zip_postcode FROM Addresses AS T1 JOIN Student_Addresses AS T2 ON T1.address_id = T2.address_id ORDER BY monthly_rental DESC LIMIT 1 |
Qual é o número de celular do aluno cujo endereço tem o menor aluguel mensal? | CREATE TABLE Students (cell_mobile_number VARCHAR, student_id VARCHAR); CREATE TABLE Student_Addresses (student_id VARCHAR, monthly_rental VARCHAR) | SELECT T2.cell_mobile_number FROM Student_Addresses AS T1 JOIN Students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.monthly_rental LIMIT 1 |
Qual é o aluguel mensal de moradias de estudantes no estado do Texas? | CREATE TABLE Addresses (address_id VARCHAR, state_province_county VARCHAR); CREATE TABLE Student_Addresses (monthly_rental VARCHAR, address_id VARCHAR) | SELECT T2.monthly_rental FROM Addresses AS T1 JOIN Student_Addresses AS T2 ON T1.address_id = T2.address_id WHERE T1.state_province_county = "Texas" |
Quais são os nomes e apelidos de estudantes com morada em Wisconsin? | CREATE TABLE Addresses (address_id VARCHAR, state_province_county VARCHAR); CREATE TABLE Students (first_name VARCHAR, last_name VARCHAR, address_id VARCHAR) | SELECT T2.first_name, T2.last_name FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id WHERE T1.state_province_county = "Wisconsin" |
Qual é a linha 1 e o aluguel mensal médio de todos os endereços de estudantes? | CREATE TABLE Addresses (line_1 VARCHAR, address_id VARCHAR); CREATE TABLE Student_Addresses (monthly_rental INTEGER, address_id VARCHAR) | SELECT T1.line_1, AVG(T2.monthly_rental) FROM Addresses AS T1 JOIN Student_Addresses AS T2 ON T1.address_id = T2.address_id GROUP BY T2.address_id |
Qual é o código postal do endereço onde vive a professora com o nome de "Lyla"? | CREATE TABLE Teachers (address_id VARCHAR, first_name VARCHAR); CREATE TABLE Addresses (zip_postcode VARCHAR, address_id VARCHAR) | SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Teachers AS T2 ON T1.address_id = T2.address_id WHERE T2.first_name = "Lyla" |
Quais são os endereços de e-mail de professores cujo endereço tem código postal "918"? | CREATE TABLE Addresses (address_id VARCHAR, zip_postcode VARCHAR); CREATE TABLE Teachers (email_address VARCHAR, address_id VARCHAR) | SELECT T2.email_address FROM Addresses AS T1 JOIN Teachers AS T2 ON T1.address_id = T2.address_id WHERE T1.zip_postcode = "918" |
Quantos alunos não estão envolvidos em nenhum incidente de comportamento? | CREATE TABLE STUDENTS (student_id VARCHAR); CREATE TABLE Behavior_Incident (student_id VARCHAR) | SELECT COUNT(*) FROM STUDENTS WHERE NOT student_id IN (SELECT student_id FROM Behavior_Incident) |
Encontre os sobrenomes de professores que não estão envolvidos em nenhuma detenção. | CREATE TABLE Teachers (last_name VARCHAR); CREATE TABLE Teachers (last_name VARCHAR, teacher_id VARCHAR); CREATE TABLE Detention (teacher_id VARCHAR) | SELECT last_name FROM Teachers EXCEPT SELECT T1.last_name FROM Teachers AS T1 JOIN Detention AS T2 ON T1.teacher_id = T2.teacher_id |
Qual é a linha 1 de endereços compartilhados por alguns alunos e alguns professores? | CREATE TABLE Teachers (address_id VARCHAR); CREATE TABLE Students (address_id VARCHAR); CREATE TABLE Addresses (line_1 VARCHAR, address_id VARCHAR) | SELECT T1.line_1 FROM Addresses AS T1 JOIN Students AS T2 ON T1.address_id = T2.address_id INTERSECT SELECT T1.line_1 FROM Addresses AS T1 JOIN Teachers AS T2 ON T1.address_id = T2.address_id |
Quais os ativos que têm 2 partes e menos de 2 registros de falhas? | CREATE TABLE Assets (asset_id VARCHAR, asset_details VARCHAR); CREATE TABLE Asset_Parts (asset_id VARCHAR); CREATE TABLE Fault_Log (asset_id VARCHAR) | SELECT T1.asset_id, T1.asset_details FROM Assets AS T1 JOIN Asset_Parts AS T2 ON T1.asset_id = T2.asset_id GROUP BY T1.asset_id HAVING COUNT(*) = 2 INTERSECT SELECT T1.asset_id, T1.asset_details FROM Assets AS T1 JOIN Fault_Log AS T2 ON T1.asset_id = T2.asset_id GROUP BY T1.asset_id HAVING COUNT(*) < 2 |
Quantos activos contém cada contrato de manutenção? | CREATE TABLE Assets (maintenance_contract_id VARCHAR); CREATE TABLE Maintenance_Contracts (maintenance_contract_id VARCHAR) | SELECT COUNT(*), T1.maintenance_contract_id FROM Maintenance_Contracts AS T1 JOIN Assets AS T2 ON T1.maintenance_contract_id = T2.maintenance_contract_id GROUP BY T1.maintenance_contract_id |
Quantos activos fornece cada empresa de terceiros? | CREATE TABLE Assets (supplier_company_id VARCHAR); CREATE TABLE Third_Party_Companies (company_id VARCHAR) | SELECT COUNT(*), T1.company_id FROM Third_Party_Companies AS T1 JOIN Assets AS T2 ON T1.company_id = T2.supplier_company_id GROUP BY T1.company_id |
Quais empresas terceiras têm pelo menos 2 engenheiros de manutenção ou pelo menos 2 contratos de manutenção? | CREATE TABLE Maintenance_Contracts (maintenance_contract_company_id VARCHAR); CREATE TABLE Maintenance_Engineers (company_id VARCHAR); CREATE TABLE Third_Party_Companies (company_id VARCHAR, company_name VARCHAR) | SELECT T1.company_id, T1.company_name FROM Third_Party_Companies AS T1 JOIN Maintenance_Engineers AS T2 ON T1.company_id = T2.company_id GROUP BY T1.company_id HAVING COUNT(*) >= 2 UNION SELECT T3.company_id, T3.company_name FROM Third_Party_Companies AS T3 JOIN Maintenance_Contracts AS T4 ON T3.company_id = T4.maintenance_contract_company_id GROUP BY T3.company_id HAVING COUNT(*) >= 2 |
Qual é o nome e o número do pessoal que registou o registo de falhas, mas que não contatou nenhum engenheiro visitante? | CREATE TABLE Engineer_Visits (contact_staff_id VARCHAR); CREATE TABLE Staff (staff_name VARCHAR, staff_id VARCHAR); CREATE TABLE Fault_Log (recorded_by_staff_id VARCHAR) | SELECT T1.staff_name, T1.staff_id FROM Staff AS T1 JOIN Fault_Log AS T2 ON T1.staff_id = T2.recorded_by_staff_id EXCEPT SELECT T3.staff_name, T3.staff_id FROM Staff AS T3 JOIN Engineer_Visits AS T4 ON T3.staff_id = T4.contact_staff_id |
Que engenheiro foi visitado mais vezes? | CREATE TABLE Maintenance_Engineers (engineer_id VARCHAR, first_name VARCHAR, last_name VARCHAR); CREATE TABLE Engineer_Visits (Id VARCHAR) | SELECT T1.engineer_id, T1.first_name, T1.last_name FROM Maintenance_Engineers AS T1 JOIN Engineer_Visits AS T2 GROUP BY T1.engineer_id ORDER BY COUNT(*) DESC LIMIT 1 |
Que partes têm mais de 2 falhas? | CREATE TABLE Parts (part_name VARCHAR, part_id VARCHAR); CREATE TABLE Part_Faults (part_id VARCHAR) | SELECT T1.part_name, T1.part_id FROM Parts AS T1 JOIN Part_Faults AS T2 ON T1.part_id = T2.part_id GROUP BY T1.part_id HAVING COUNT(*) > 2 |
Lista todos os nomes de engenheiro, sobrenomes, detalhes e descrição de habilidades correspondentes. | CREATE TABLE Maintenance_Engineers (first_name VARCHAR, last_name VARCHAR, other_details VARCHAR, engineer_id VARCHAR); CREATE TABLE Engineer_Skills (engineer_id VARCHAR, skill_id VARCHAR); CREATE TABLE Skills (skill_description VARCHAR, skill_id VARCHAR) | SELECT T1.first_name, T1.last_name, T1.other_details, T3.skill_description FROM Maintenance_Engineers AS T1 JOIN Engineer_Skills AS T2 ON T1.engineer_id = T2.engineer_id JOIN Skills AS T3 ON T2.skill_id = T3.skill_id |
Para todas as falhas de diferentes partes, quais são todas as descrições das habilidades necessárias para corrigi-las? | CREATE TABLE Skills_Required_To_Fix (part_fault_id VARCHAR, skill_id VARCHAR); CREATE TABLE Part_Faults (fault_short_name VARCHAR, part_fault_id VARCHAR); CREATE TABLE Skills (skill_description VARCHAR, skill_id VARCHAR) | SELECT T1.fault_short_name, T3.skill_description FROM Part_Faults AS T1 JOIN Skills_Required_To_Fix AS T2 ON T1.part_fault_id = T2.part_fault_id JOIN Skills AS T3 ON T2.skill_id = T3.skill_id |
Em quantos recursos podem ser usadas cada parte? | CREATE TABLE Parts (part_name VARCHAR, part_id VARCHAR); CREATE TABLE Asset_Parts (part_id VARCHAR) | SELECT T1.part_name, COUNT(*) FROM Parts AS T1 JOIN Asset_Parts AS T2 ON T1.part_id = T2.part_id GROUP BY T1.part_name |
Quais são as descrições de falhas e o estado de falhas de todas as falhas registradas nos registos? | CREATE TABLE Fault_Log (fault_description VARCHAR, fault_log_entry_id VARCHAR); CREATE TABLE Fault_Log_Parts (fault_status VARCHAR, fault_log_entry_id VARCHAR) | SELECT T1.fault_description, T2.fault_status FROM Fault_Log AS T1 JOIN Fault_Log_Parts AS T2 ON T1.fault_log_entry_id = T2.fault_log_entry_id |
Quantas visitas de engenheiro são necessárias no máximo para um único registro de falhas? | CREATE TABLE Fault_Log (fault_log_entry_id VARCHAR); CREATE TABLE Engineer_Visits (fault_log_entry_id VARCHAR) | SELECT COUNT(*), T1.fault_log_entry_id FROM Fault_Log AS T1 JOIN Engineer_Visits AS T2 ON T1.fault_log_entry_id = T2.fault_log_entry_id GROUP BY T1.fault_log_entry_id ORDER BY COUNT(*) DESC LIMIT 1 |
Quais são os apelidos dos engenheiros? | CREATE TABLE Maintenance_Engineers (last_name VARCHAR) | SELECT DISTINCT last_name FROM Maintenance_Engineers |
Quantos códigos de estado de falha são registados na tabela de partes do log de falhas? | CREATE TABLE Fault_Log_Parts (fault_status VARCHAR) | SELECT DISTINCT fault_status FROM Fault_Log_Parts |
Que engenheiros nunca foram para manter os ativos? | CREATE TABLE Engineer_Visits (first_name VARCHAR, last_name VARCHAR, engineer_id VARCHAR); CREATE TABLE Maintenance_Engineers (first_name VARCHAR, last_name VARCHAR, engineer_id VARCHAR) | SELECT first_name, last_name FROM Maintenance_Engineers WHERE NOT engineer_id IN (SELECT engineer_id FROM Engineer_Visits) |
Indicar a identificação do activo, os pormenores, a marca e o modelo de cada activo. | CREATE TABLE Assets (asset_id VARCHAR, asset_details VARCHAR, asset_make VARCHAR, asset_model VARCHAR) | SELECT asset_id, asset_details, asset_make, asset_model FROM Assets |
Quando foi adquirido o primeiro activo? | CREATE TABLE Assets (asset_acquired_date VARCHAR) | SELECT asset_acquired_date FROM Assets ORDER BY asset_acquired_date LIMIT 1 |
Qual é a falha da parte que requer mais habilidades para corrigir? | CREATE TABLE Part_Faults (part_id VARCHAR, part_fault_id VARCHAR); CREATE TABLE Skills_Required_To_Fix (part_fault_id VARCHAR); CREATE TABLE Parts (part_id VARCHAR, part_name VARCHAR) | SELECT T1.part_id, T1.part_name FROM Parts AS T1 JOIN Part_Faults AS T2 ON T1.part_id = T2.part_id JOIN Skills_Required_To_Fix AS T3 ON T2.part_fault_id = T3.part_fault_id GROUP BY T1.part_id ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é o tipo de peça que tem o menor número de falhas? | CREATE TABLE Parts (part_name VARCHAR, part_id VARCHAR); CREATE TABLE Part_Faults (part_id VARCHAR) | SELECT T1.part_name FROM Parts AS T1 JOIN Part_Faults AS T2 ON T1.part_id = T2.part_id GROUP BY T1.part_name ORDER BY COUNT(*) LIMIT 1 |
Entre os engenheiros que visitaram, qual engenheiro faz o menor número de visitas? | CREATE TABLE Engineer_Visits (engineer_id VARCHAR); CREATE TABLE Maintenance_Engineers (engineer_id VARCHAR, first_name VARCHAR, last_name VARCHAR) | SELECT T1.engineer_id, T1.first_name, T1.last_name FROM Maintenance_Engineers AS T1 JOIN Engineer_Visits AS T2 ON T1.engineer_id = T2.engineer_id GROUP BY T1.engineer_id ORDER BY COUNT(*) LIMIT 1 |
Qual o pessoal que contatou qual o engenheiro? | CREATE TABLE Engineer_Visits (contact_staff_id VARCHAR, engineer_id VARCHAR); CREATE TABLE Staff (staff_name VARCHAR, staff_id VARCHAR); CREATE TABLE Maintenance_Engineers (first_name VARCHAR, last_name VARCHAR, engineer_id VARCHAR) | SELECT T1.staff_name, T3.first_name, T3.last_name FROM Staff AS T1 JOIN Engineer_Visits AS T2 ON T1.staff_id = T2.contact_staff_id JOIN Maintenance_Engineers AS T3 ON T2.engineer_id = T3.engineer_id |
Qual o registro de falhas que incluiu o maior número de peças defeituosas? | CREATE TABLE Fault_Log (fault_log_entry_id VARCHAR, fault_description VARCHAR, fault_log_entry_datetime VARCHAR); CREATE TABLE Fault_Log_Parts (fault_log_entry_id VARCHAR) | SELECT T1.fault_log_entry_id, T1.fault_description, T1.fault_log_entry_datetime FROM Fault_Log AS T1 JOIN Fault_Log_Parts AS T2 ON T1.fault_log_entry_id = T2.fault_log_entry_id GROUP BY T1.fault_log_entry_id ORDER BY COUNT(*) DESC LIMIT 1 |
Qual habilidade é usada para corrigir o maior número de falhas? | CREATE TABLE Skills (skill_id VARCHAR, skill_description VARCHAR); CREATE TABLE Skills_Required_To_Fix (skill_id VARCHAR) | SELECT T1.skill_id, T1.skill_description FROM Skills AS T1 JOIN Skills_Required_To_Fix AS T2 ON T1.skill_id = T2.skill_id GROUP BY T1.skill_id ORDER BY COUNT(*) DESC LIMIT 1 |
Quais são os diferentes modelos de ativos? | CREATE TABLE Assets (asset_model VARCHAR) | SELECT DISTINCT asset_model FROM Assets |
Lista todos os ativos, marca, modelo, detalhes pela data de venda em ascendência. | CREATE TABLE Assets (asset_make VARCHAR, asset_model VARCHAR, asset_details VARCHAR, asset_disposed_date VARCHAR) | SELECT asset_make, asset_model, asset_details FROM Assets ORDER BY asset_disposed_date |
Qual a parte que tem o menor montante cobrado? | CREATE TABLE Parts (part_id VARCHAR, chargeable_amount VARCHAR) | SELECT part_id, chargeable_amount FROM Parts ORDER BY chargeable_amount LIMIT 1 |
Qual empresa iniciou o contrato de manutenção mais cedo? | CREATE TABLE Third_Party_Companies (company_name VARCHAR, company_id VARCHAR); CREATE TABLE Maintenance_Contracts (maintenance_contract_company_id VARCHAR, contract_start_date VARCHAR) | SELECT T1.company_name FROM Third_Party_Companies AS T1 JOIN Maintenance_Contracts AS T2 ON T1.company_id = T2.maintenance_contract_company_id ORDER BY T2.contract_start_date LIMIT 1 |
Qual é a descrição do tipo de empresa que concluiu os seus contratos mais recentemente? | CREATE TABLE Maintenance_Contracts (maintenance_contract_company_id VARCHAR, contract_end_date VARCHAR); CREATE TABLE Third_Party_Companies (company_name VARCHAR, company_id VARCHAR, company_type_code VARCHAR); CREATE TABLE Ref_Company_Types (company_type_code VARCHAR) | SELECT T1.company_name FROM Third_Party_Companies AS T1 JOIN Maintenance_Contracts AS T2 ON T1.company_id = T2.maintenance_contract_company_id JOIN Ref_Company_Types AS T3 ON T1.company_type_code = T3.company_type_code ORDER BY T2.contract_end_date DESC LIMIT 1 |
Que sexo é a maioria da equipa? | CREATE TABLE staff (gender VARCHAR) | SELECT gender FROM staff GROUP BY gender ORDER BY COUNT(*) DESC LIMIT 1 |
Quantos engenheiros contataram cada pessoal? | CREATE TABLE Engineer_Visits (contact_staff_id VARCHAR); CREATE TABLE Staff (staff_name VARCHAR, staff_id VARCHAR) | SELECT T1.staff_name, COUNT(*) FROM Staff AS T1 JOIN Engineer_Visits AS T2 ON T1.staff_id = T2.contact_staff_id GROUP BY T1.staff_name |
Quais os ativos que não tiveram qualquer log de falhas? | CREATE TABLE Fault_Log (asset_model VARCHAR, asset_id VARCHAR); CREATE TABLE Assets (asset_model VARCHAR, asset_id VARCHAR) | SELECT asset_model FROM Assets WHERE NOT asset_id IN (SELECT asset_id FROM Fault_Log) |
A lista das autoridades locais e dos serviços prestados por todas as estações. | CREATE TABLE station (local_authority VARCHAR, services VARCHAR) | SELECT local_authority, services FROM station |
Mostrar todos os números e nomes dos comboios ordenados por horário, de manhã até tarde. | CREATE TABLE train (train_number VARCHAR, name VARCHAR, TIME VARCHAR) | SELECT train_number, name FROM train ORDER BY TIME |
Dê-me as horas e números de todos os trens que vão para Chennai, ordenados por tempo. | CREATE TABLE train (TIME VARCHAR, train_number VARCHAR, destination VARCHAR) | SELECT TIME, train_number FROM train WHERE destination = 'Chennai' ORDER BY TIME |
Quantos trens têm "Express" em seus nomes? | CREATE TABLE train (name VARCHAR) | SELECT COUNT(*) FROM train WHERE name LIKE "%Express%" |
Encontre o número e a hora do trem que vai de Chennai para Guruvayur. | CREATE TABLE train (train_number VARCHAR, TIME VARCHAR, origin VARCHAR, destination VARCHAR) | SELECT train_number, TIME FROM train WHERE origin = 'Chennai' AND destination = 'Guruvayur' |
Encontre o número de trens a partir de cada origem. | CREATE TABLE train (origin VARCHAR) | SELECT origin, COUNT(*) FROM train GROUP BY origin |
Encontre o nome do trem cuja rota atravessa o maior número de estações. | CREATE TABLE route (train_id VARCHAR); CREATE TABLE train (name VARCHAR, id VARCHAR) | SELECT t1.name FROM train AS t1 JOIN route AS t2 ON t1.id = t2.train_id GROUP BY t2.train_id ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre o número de trens para cada estação, bem como o nome da rede de estações e os serviços. | CREATE TABLE route (station_id VARCHAR); CREATE TABLE station (network_name VARCHAR, services VARCHAR, id VARCHAR) | SELECT COUNT(*), t1.network_name, t1.services FROM station AS t1 JOIN route AS t2 ON t1.id = t2.station_id GROUP BY t2.station_id |
Qual é a temperatura média máxima para cada dia da semana? | CREATE TABLE weekly_weather (day_of_week VARCHAR, high_temperature INTEGER) | SELECT AVG(high_temperature), day_of_week FROM weekly_weather GROUP BY day_of_week |
Dê-me a temperatura máxima e a precipitação média na estação de Amersham. | CREATE TABLE weekly_weather (low_temperature INTEGER, precipitation INTEGER, station_id VARCHAR); CREATE TABLE station (id VARCHAR, network_name VARCHAR) | SELECT MAX(t1.low_temperature), AVG(t1.precipitation) FROM weekly_weather AS t1 JOIN station AS t2 ON t1.station_id = t2.id WHERE t2.network_name = "Amersham" |
Encontre nomes e horários de trens que atravessam estações para a autoridade local Chiltern. | CREATE TABLE station (id VARCHAR, local_authority VARCHAR); CREATE TABLE route (station_id VARCHAR, train_id VARCHAR); CREATE TABLE train (name VARCHAR, time VARCHAR, id VARCHAR) | SELECT t3.name, t3.time FROM station AS t1 JOIN route AS t2 ON t1.id = t2.station_id JOIN train AS t3 ON t2.train_id = t3.id WHERE t1.local_authority = "Chiltern" |
Quantos serviços diferentes são prestados por todas as estações? | CREATE TABLE station (services VARCHAR) | SELECT COUNT(DISTINCT services) FROM station |
Encontre o número e a autoridade local da estação com a temperatura média mais alta. | CREATE TABLE weekly_weather (station_id VARCHAR); CREATE TABLE station (id VARCHAR, local_authority VARCHAR) | SELECT t2.id, t2.local_authority FROM weekly_weather AS t1 JOIN station AS t2 ON t1.station_id = t2.id GROUP BY t1.station_id ORDER BY AVG(high_temperature) DESC LIMIT 1 |
Encontre o número e a autoridade local da estação cuja precipitação máxima seja superior a 50. | CREATE TABLE weekly_weather (station_id VARCHAR, precipitation INTEGER); CREATE TABLE station (id VARCHAR, local_authority VARCHAR) | SELECT t2.id, t2.local_authority FROM weekly_weather AS t1 JOIN station AS t2 ON t1.station_id = t2.id GROUP BY t1.station_id HAVING MAX(t1.precipitation) > 50 |
Mostrar a menor temperatura baixa e a maior velocidade do vento em quilómetros por hora. | CREATE TABLE weekly_weather (low_temperature INTEGER, wind_speed_mph INTEGER) | SELECT MIN(low_temperature), MAX(wind_speed_mph) FROM weekly_weather |
Encontre as origens a partir das quais mais de um trem parte. | CREATE TABLE train (origin VARCHAR) | SELECT origin FROM train GROUP BY origin HAVING COUNT(*) > 1 |
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