pergunta
stringlengths 8
31.4k
| contexto
stringlengths 27
489
| resposta
stringlengths 18
557
|
|---|---|---|
Qual é o nome da tempestade e a velocidade máxima que afetou o maior número de regiões? | CREATE TABLE storm (name VARCHAR, max_speed VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR) | SELECT T1.name, T1.max_speed FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre o nome das tempestades que não afetaram a região registrada. | CREATE TABLE affected_region (name VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT name FROM storm WHERE NOT storm_id IN (SELECT storm_id FROM affected_region) |
Mostrar o nome da tempestade com pelo menos duas regiões e 10 cidades afetadas. | CREATE TABLE affected_region (storm_id VARCHAR, number_city_affected INTEGER); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING SUM(T2.number_city_affected) >= 10 |
Mostrar todos os nomes de tempestades, exceto aqueles com pelo menos duas regiões afetadas. | CREATE TABLE storm (name VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT name FROM storm EXCEPT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 |
Quais são os nomes das regiões afetadas pela tempestade com um número de mortes de pelo menos 10? | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, number_deaths VARCHAR) | SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T3.number_deaths >= 10 |
Mostrar todos os nomes de tempestades que afetam a região "Dinamarca". | CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR) | SELECT T3.name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.region_name = 'Denmark' |
Mostrar o nome da região com pelo menos duas tempestades. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR) | SELECT T1.region_name FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id HAVING COUNT(*) >= 2 |
Encontre os nomes das regiões que foram afetadas pela tempestade que matou o maior número de pessoas. | CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, Number_Deaths VARCHAR) | SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id ORDER BY T3.Number_Deaths DESC LIMIT 1 |
Encontre o nome da tempestade que afetou as regiões do Afeganistão e da Albânia. | CREATE TABLE storm (Name VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE region (region_id VARCHAR, Region_name VARCHAR) | SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Afghanistan' INTERSECT SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Albania' |
Quantos condados há no total? | CREATE TABLE county (Id VARCHAR) | SELECT COUNT(*) FROM county |
Indicar o nome do condado e a população de todos os condados. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name, Population FROM county |
Mostrar a população média de todos os condados. | CREATE TABLE county (Population INTEGER) | SELECT AVG(Population) FROM county |
Retorne a população máxima e mínima entre todos os condados. | CREATE TABLE county (Population INTEGER) | SELECT MAX(Population), MIN(Population) FROM county |
Mostre todos os distritos para as eleições. | CREATE TABLE election (District VARCHAR) | SELECT DISTINCT District FROM election |
Mostre o código postal do condado com o nome "Howard". | CREATE TABLE county (Zip_code VARCHAR, County_name VARCHAR) | SELECT Zip_code FROM county WHERE County_name = "Howard" |
Mostre o delegado do distrito 1 nas eleições. | CREATE TABLE election (Delegate VARCHAR, District VARCHAR) | SELECT Delegate FROM election WHERE District = 1 |
Mostre ao delegado e à comissão informações sobre as eleições. | CREATE TABLE election (Delegate VARCHAR, Committee VARCHAR) | SELECT Delegate, Committee FROM election |
Quantos governadores diferentes há? | CREATE TABLE party (Governor VARCHAR) | SELECT COUNT(DISTINCT Governor) FROM party |
Mostre o vice-governador e o controlador do Partido Democrata. | CREATE TABLE party (Lieutenant_Governor VARCHAR, Comptroller VARCHAR, Party VARCHAR) | SELECT Lieutenant_Governor, Comptroller FROM party WHERE Party = "Democratic" |
Em que anos diferentes foi o governador "Eliot Spitzer"? | CREATE TABLE party (YEAR VARCHAR, Governor VARCHAR) | SELECT DISTINCT YEAR FROM party WHERE Governor = "Eliot Spitzer" |
Mostra-me todas as informações sobre a eleição. | CREATE TABLE election (Id VARCHAR) | SELECT * FROM election |
Mostre os delegados e os nomes do condado a que pertencem. | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T2.Delegate, T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District |
Que delegados são de condados com população inferior a 100000? | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) | SELECT T2.Delegate FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population < 100000 |
Quantos delegados são de condados com população superior a 50.000? | CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER) | SELECT COUNT(DISTINCT T2.Delegate) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population > 50000 |
Quais são os nomes do condado de onde pertencem os delegados do comité de dotações? | CREATE TABLE election (District VARCHAR, Committee VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T2.Committee = "Appropriations" |
Mostre os delegados e os nomes do partido a que pertencem. | CREATE TABLE election (Delegate VARCHAR, Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T1.Delegate, T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID |
Quem eram os governadores dos partidos associados com os delegados do distrito 1? | CREATE TABLE party (Governor VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) | SELECT T2.Governor FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 |
Quem eram os controladores dos partidos associados aos delegados do distrito 1 ou do distrito 2? | CREATE TABLE party (Comptroller VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR) | SELECT T2.Comptroller FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 OR T1.District = 2 |
Devolva todas as comissões que têm delegados do Partido Democrata. | CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) | SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" |
Indique o nome de cada condado, juntamente com o número correspondente de delegados desse condado. | CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name, COUNT(*) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id |
Indicar o nome de cada partido e o número correspondente de delegados desse partido. | CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party, COUNT(*) FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party |
Retornar os nomes de todos os condados ordenados por população em ordem ascendente. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population |
Retornar os nomes de todos os condados ordenados por nome de condado em ordem alfabética decrescente. | CREATE TABLE county (County_name VARCHAR) | SELECT County_name FROM county ORDER BY County_name DESC |
Mostrar o nome do condado com a maior população. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population DESC LIMIT 1 |
Mostre os 3 condados com a menor população. | CREATE TABLE county (County_name VARCHAR, Population VARCHAR) | SELECT County_name FROM county ORDER BY Population LIMIT 3 |
Mostrar os nomes dos condados que têm pelo menos dois delegados. | CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR) | SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id HAVING COUNT(*) >= 2 |
Mostrar o nome da parte que tem pelo menos dois registos. | CREATE TABLE party (Party VARCHAR) | SELECT Party FROM party GROUP BY Party HAVING COUNT(*) >= 2 |
Mostre o nome do partido que tem mais delegados. | CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party ORDER BY COUNT(*) DESC LIMIT 1 |
Mostra as pessoas que foram governador mais vezes. | CREATE TABLE party (Governor VARCHAR) | SELECT Governor FROM party GROUP BY Governor ORDER BY COUNT(*) DESC LIMIT 1 |
Mostrar as pessoas que foram controlador o maior número de vezes e o número correspondente de vezes. | CREATE TABLE party (Comptroller VARCHAR) | SELECT Comptroller, COUNT(*) FROM party GROUP BY Comptroller ORDER BY COUNT(*) DESC LIMIT 1 |
Quais são os nomes dos partidos que não têm delegados nas eleições? | CREATE TABLE election (Party VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT Party FROM party WHERE NOT Party_ID IN (SELECT Party FROM election) |
Quais são os nomes dos partidos que têm delegados no comité "Aprovisões" e | CREATE TABLE election (Party VARCHAR, Committee VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR) | SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Appropriations" INTERSECT SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Economic Matters" |
Quais comitês têm delegados tanto do partido democrata quanto do partido liberal? | CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR) | SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" INTERSECT SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Liberal" |
Quantos jornalistas há? | CREATE TABLE journalist (Id VARCHAR) | SELECT COUNT(*) FROM journalist |
Escreva os nomes dos jornalistas em ordem ascendente de anos de trabalho. | CREATE TABLE journalist (Name VARCHAR, Years_working VARCHAR) | SELECT Name FROM journalist ORDER BY Years_working |
Quais são as nacionalidades e idades dos jornalistas? | CREATE TABLE journalist (Nationality VARCHAR, Age VARCHAR) | SELECT Nationality, Age FROM journalist |
Mostre os nomes de jornalistas de "Inglaterra" ou "Gales". | CREATE TABLE journalist (Name VARCHAR, Nationality VARCHAR) | SELECT Name FROM journalist WHERE Nationality = "England" OR Nationality = "Wales" |
Qual é o número médio de anos de trabalho como jornalista? | CREATE TABLE journalist (Years_working INTEGER) | SELECT AVG(Years_working) FROM journalist |
Qual é a nacionalidade do jornalista com o maior número de anos de trabalho? | CREATE TABLE journalist (Nationality VARCHAR, Years_working VARCHAR) | SELECT Nationality FROM journalist ORDER BY Years_working DESC LIMIT 1 |
Indicar as diferentes nacionalidades e o número de jornalistas de cada nacionalidade. | CREATE TABLE journalist (Nationality VARCHAR) | SELECT Nationality, COUNT(*) FROM journalist GROUP BY Nationality |
Mostrar a nacionalidade mais comum dos jornalistas. | CREATE TABLE journalist (Nationality VARCHAR) | SELECT Nationality FROM journalist GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre os países que têm jornalistas com mais de 10 anos de trabalho e jornalistas com menos de 3 anos de trabalho. | CREATE TABLE journalist (Nationality VARCHAR, Years_working INTEGER) | SELECT Nationality FROM journalist WHERE Years_working > 10 INTERSECT SELECT Nationality FROM journalist WHERE Years_working < 3 |
Mostre as datas, os locais e os nomes dos eventos em ordem decrescente de número de presentes. | CREATE TABLE event (Date VARCHAR, Name VARCHAR, venue VARCHAR, Event_Attendance VARCHAR) | SELECT Date, Name, venue FROM event ORDER BY Event_Attendance DESC |
Mostrar os nomes dos jornalistas e as datas dos eventos que relataram. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Date VARCHAR, Event_ID VARCHAR) | SELECT T3.Name, T2.Date FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID |
Mostrar os nomes dos jornalistas e os nomes dos eventos que relataram em ordem crescente | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Name VARCHAR, Event_ID VARCHAR, Event_Attendance VARCHAR) | SELECT T3.Name, T2.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID ORDER BY T2.Event_Attendance |
Mostrar os nomes dos jornalistas e o número de eventos que relataram. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) | SELECT T3.Name, COUNT(*) FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name |
Mostrar os nomes dos jornalistas que reportaram mais de um evento. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR) | SELECT T3.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name HAVING COUNT(*) > 1 |
Escreva os nomes dos jornalistas que não relataram nenhum evento. | CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Name VARCHAR, journalist_ID VARCHAR) | SELECT Name FROM journalist WHERE NOT journalist_ID IN (SELECT journalist_ID FROM news_report) |
Qual a média e a média máxima de assistência de todos os eventos? | CREATE TABLE event (Event_Attendance INTEGER) | SELECT AVG(Event_Attendance), MAX(Event_Attendance) FROM event |
Encontre a idade média e a duração do trabalho dos jornalistas que trabalham em diferentes tipos de funções. | CREATE TABLE news_report (work_type VARCHAR, journalist_id VARCHAR); CREATE TABLE journalist (age INTEGER, journalist_id VARCHAR) | SELECT AVG(t1.age), AVG(Years_working), t2.work_type FROM journalist AS t1 JOIN news_report AS t2 ON t1.journalist_id = t2.journalist_id GROUP BY t2.work_type |
Liste os locais do evento e os nomes que têm o número de pessoas mais frequentadas. | CREATE TABLE event (venue VARCHAR, name VARCHAR, Event_Attendance VARCHAR) | SELECT venue, name FROM event ORDER BY Event_Attendance DESC LIMIT 2 |
Mostra-me todos os restaurantes. | CREATE TABLE Restaurant (ResName VARCHAR) | SELECT ResName FROM Restaurant |
Qual é o endereço do restaurante Subway? | CREATE TABLE Restaurant (Address VARCHAR, ResName VARCHAR) | SELECT Address FROM Restaurant WHERE ResName = "Subway" |
Qual é a classificação do restaurante Subway? | CREATE TABLE Restaurant (Rating VARCHAR, ResName VARCHAR) | SELECT Rating FROM Restaurant WHERE ResName = "Subway" |
Escreva todos os tipos de restaurantes. | CREATE TABLE Restaurant_Type (ResTypeName VARCHAR) | SELECT ResTypeName FROM Restaurant_Type |
Qual é a descrição do restaurante tipo Sandwich? | CREATE TABLE Restaurant_Type (ResTypeDescription VARCHAR, ResTypeName VARCHAR) | SELECT ResTypeDescription FROM Restaurant_Type WHERE ResTypeName = "Sandwich" |
Que restaurantes têm a classificação mais alta? | CREATE TABLE Restaurant (ResName VARCHAR, Rating VARCHAR) | SELECT ResName, Rating FROM Restaurant ORDER BY Rating DESC LIMIT 1 |
Que idade tem a estudante Linda Smith? | CREATE TABLE Student (Age VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT Age FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
Qual é o sexo da estudante Linda Smith? | CREATE TABLE Student (Sex VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT Sex FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
Escreve os nomes e apelidos de todos os estudantes que se especializaram em 600. | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Major = 600 |
Em que cidade vive a estudante Linda Smith? | CREATE TABLE Student (city_code VARCHAR, Fname VARCHAR, Lname VARCHAR) | SELECT city_code FROM Student WHERE Fname = "Linda" AND Lname = "Smith" |
O conselheiro 1121 tem quantos alunos? | CREATE TABLE Student (Advisor VARCHAR) | SELECT COUNT(*) FROM Student WHERE Advisor = 1121 |
Qual é o conselheiro que tem mais alunos? | CREATE TABLE Student (Advisor VARCHAR) | SELECT Advisor, COUNT(*) FROM Student GROUP BY Advisor ORDER BY COUNT(Advisor) DESC LIMIT 1 |
Qual é a especialidade que tem menos alunos? | CREATE TABLE Student (Major VARCHAR) | SELECT Major, COUNT(*) FROM Student GROUP BY Major ORDER BY COUNT(Major) LIMIT 1 |
Qual é a especialidade que tem entre 2 e 30 alunos? | CREATE TABLE Student (Major VARCHAR) | SELECT Major, COUNT(*) FROM Student GROUP BY Major HAVING COUNT(Major) BETWEEN 2 AND 30 |
Qual aluno tem mais de 18 anos e está a fazer a especialização em 600? | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major = 600 |
Lista todas as estudantes do sexo feminino com mais de 18 anos que não estão se especializando em 600. | CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Sex VARCHAR, Age VARCHAR, Major VARCHAR) | SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major <> 600 AND Sex = 'F' |
Quantos restaurantes são do tipo Sandwich? | CREATE TABLE Type_Of_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR); CREATE TABLE Restaurant_Type (Id VARCHAR) | SELECT COUNT(*) FROM Restaurant JOIN Type_Of_Restaurant ON Restaurant.ResID = Type_Of_Restaurant.ResID JOIN Restaurant_Type ON Type_Of_Restaurant.ResTypeID = Restaurant_Type.ResTypeID GROUP BY Type_Of_Restaurant.ResTypeID HAVING Restaurant_Type.ResTypeName = 'Sandwich' |
Quanto tempo a estudante Linda Smith gasta no restaurante no total? | CREATE TABLE Visits_Restaurant (Spent INTEGER); CREATE TABLE Student (Spent INTEGER) | SELECT SUM(Spent) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" |
Quantas vezes a estudante Linda Smith visitou o Subway? | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) | SELECT COUNT(*) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" |
Quando é que a Linda Smith visitou a Subway? | CREATE TABLE Restaurant (TIME VARCHAR); CREATE TABLE Visits_Restaurant (TIME VARCHAR); CREATE TABLE Student (TIME VARCHAR) | SELECT TIME FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway" |
Em que restaurante os estudantes passaram menos tempo? | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR) | SELECT Restaurant.ResName, SUM(Visits_Restaurant.Spent) FROM Visits_Restaurant JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID GROUP BY Restaurant.ResID ORDER BY SUM(Visits_Restaurant.Spent) LIMIT 1 |
Qual aluno visitou o restaurante com mais frequência? Escreva o nome e o apelido do aluno. | CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR) | SELECT Student.Fname, Student.Lname FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID GROUP BY Student.StuID ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre as ids de ordens cujo estado é "Successo". | CREATE TABLE actual_orders (actual_order_id VARCHAR, order_status_code VARCHAR) | SELECT actual_order_id FROM actual_orders WHERE order_status_code = 'Success' |
Encontre o nome e o preço do produto que foi encomendado o maior número de vezes. | CREATE TABLE products (product_name VARCHAR, product_price VARCHAR, product_id VARCHAR); CREATE TABLE regular_order_products (product_id VARCHAR) | SELECT t1.product_name, t1.product_price FROM products AS t1 JOIN regular_order_products AS t2 ON t1.product_id = t2.product_id GROUP BY t2.product_id ORDER BY COUNT(*) DESC LIMIT 1 |
Encontre o número total de clientes. | CREATE TABLE customers (Id VARCHAR) | SELECT COUNT(*) FROM customers |
Quantos métodos de pagamento diferentes existem? | CREATE TABLE customers (payment_method VARCHAR) | SELECT COUNT(DISTINCT payment_method) FROM customers |
Mostre os detalhes de todos os camiões na ordem do número de matrícula. | CREATE TABLE trucks (truck_details VARCHAR, truck_licence_number VARCHAR) | SELECT truck_details FROM trucks ORDER BY truck_licence_number |
Encontre o nome do produto mais caro. | CREATE TABLE products (product_name VARCHAR, product_price VARCHAR) | SELECT product_name FROM products ORDER BY product_price DESC LIMIT 1 |
Encontre os nomes dos clientes que não moram no estado da Califórnia. | CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) | SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' |
Escreva os nomes e e-mails dos clientes que pagaram com cartão Visa. | CREATE TABLE customers (customer_email VARCHAR, customer_name VARCHAR, payment_method VARCHAR) | SELECT customer_email, customer_name FROM customers WHERE payment_method = 'Visa' |
Encontre os nomes e números de telefone de clientes que vivem no estado da Califórnia. | CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR) | SELECT t1.customer_name, t1.customer_phone FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California' |
Encontre os estados que não têm nenhum empregado no seu registo. | CREATE TABLE Employees (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR) | SELECT state_province_county FROM addresses WHERE NOT address_id IN (SELECT employee_address_id FROM Employees) |
Escreva os nomes, números de telefone e e-mails de todos os clientes, ordenados por suas datas de se tornarem clientes. | CREATE TABLE Customers (customer_name VARCHAR, customer_phone VARCHAR, customer_email VARCHAR, date_became_customer VARCHAR) | SELECT customer_name, customer_phone, customer_email FROM Customers ORDER BY date_became_customer |
Encontre o nome dos primeiros cinco clientes. | CREATE TABLE Customers (customer_name VARCHAR, date_became_customer VARCHAR) | SELECT customer_name FROM Customers ORDER BY date_became_customer LIMIT 5 |
Encontre o método de pagamento mais utilizado. | CREATE TABLE Customers (payment_method VARCHAR) | SELECT payment_method FROM Customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1 |
"Liste os nomes de todas as rotas em ordem alfabética." | CREATE TABLE Delivery_Routes (route_name VARCHAR) | SELECT route_name FROM Delivery_Routes ORDER BY route_name |
Encontre o nome da rota que tem o maior número de entregas. | CREATE TABLE Delivery_Routes (route_name VARCHAR, route_id VARCHAR); CREATE TABLE Delivery_Route_Locations (route_id VARCHAR) | SELECT t1.route_name FROM Delivery_Routes AS t1 JOIN Delivery_Route_Locations AS t2 ON t1.route_id = t2.route_id GROUP BY t1.route_id ORDER BY COUNT(*) DESC LIMIT 1 |
Escreva os nomes dos estados e o número de clientes que vivem em cada estado. | CREATE TABLE customer_addresses (address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR) | SELECT t2.state_province_county, COUNT(*) FROM customer_addresses AS t1 JOIN addresses AS t2 ON t1.address_id = t2.address_id GROUP BY t2.state_province_county |
Quantos autores há? | CREATE TABLE authors (Id VARCHAR) | SELECT COUNT(*) FROM authors |
Subsets and Splits
No saved queries yet
Save your SQL queries to embed, download, and access them later. Queries will appear here once saved.