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Arithmetic calculation | When three numbers are given: 10, 11 and 12, find the 2nd largest number divided by the 2nd smallest number. | 1 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_DIV] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b=list_a.copy()
list_b.sort()
var_e = list_b[-var_d]
var_f = 2
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e / var_g
print(int(var_h)) |
Correspondence | You need to find the sum of 9 and a certain number, but mistakenly calculated the difference of them and got 1 as the answer. If the number is less than 10, find the sum of 9 and the number. | 17 | 9 1 [OP_SUB] 9 [OP_ADD] | var_a = 9
var_b = 1
var_c = var_a - var_b
var_d = 9
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are a total of 20 telephone poles at 25m (m) intervals between Seokgi's and Dongmin's houses. If there is no telephone pole in front of their houses, what is the distance in meters (m) between Seokgi's and Dongmin's houses? | 525 | 20 1 [OP_ADD] 25 [OP_MUL] | var_a = 20
var_b = 1
var_c = var_a + var_b
var_d = 25
var_e = var_c * var_d
print(int(var_e)) |
Possibility | There are 20 people in Seokjin's class. If you are trying to pick 11 people to play in a soccer tournament, what are possible cases to pick a team? | 167960 | 20 11 [OP_COMB] | var_a = 20
var_b = 11
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Arithmetic calculation | Jisoo got 30 robots. Heeyoung has four times as many robots as Jisoo. How many robots do Heeyoung and Jisoo have in total? | 120 | 40 4 [OP_MUL] 40 [OP_SUB] | var_a = 40
var_b = 4
var_c = var_a * var_b
var_d = 40
var_e = var_c - var_d
print(int(var_e)) |
Comparison | Given that 8 people are standing between Eunjung and Yoojung, how many students are in a line when Eunjeong is the 5th student from the front and Yoojung is the last student in the line? | 14 | 5 8 [OP_ADD] 1 [OP_ADD] | var_a = 5
var_b = 8
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Minsu, Changhyun, and Seonghyun are standing in line at the bus stop. If Minsu is standing in front of Changhyun and Changhyun is standing in front of Seonghyun, find out who is standing at the back. | Seonghyun | [OP_LIST_SOL] Minsu Changhyun Seonghyun [OP_LIST_EOL] [OP_LIST_SOL] Minsu Changhyun < Changhyun Seonghyun < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Minsu'
var_b = 'Changhyun'
var_c = 'Seonghyun'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Minsu'
var_e = 'Changhyun'
var_f = '<'
var_g = 'Changhyun'
var_h = 'Seonghyun'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Possibility | Yoo-ah left one of the digits 5, 2, 8, or 0 out and tried to form a three-digit number with the remaining digits. How many of the numbers Yoo-ah made are greater than 550 and less than 850? | 6 | [OP_LIST_SOL] 5 2 8 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 550 [OP_LIST_MORE] 850 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 5
var_b = 2
var_c = 8
var_d = 0
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 550
list_c = []
for i in list_b:
if i > var_f:
list_c.append(i)
var_g = 850
list_d = []
for i in list_c:
if i < var_g:
list_d.append(i)
var_h = len(list_d)
print(int(var_h)) |
Geometry | If you draw a diagonal from one vertex of a figure made of 9 angles, how many figures made of 3 angles are made? | 7 | 9 3 [OP_SUB] 1 [OP_ADD] | var_a = 9
var_b = 3
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Comparison | 22 people of different heights stand in a line in order, tallest first. (a) stands 13th from the back. If you line up again in order of shortest to tallest, what number will you stand from the back? | 10 | 22 13 [OP_SUB] 1 [OP_ADD] | var_a = 22
var_b = 13
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | How many grams (g) of water must be evaporated from 300 grams (g) of 4% salt water to make 10% salt water? | 180 | 300 300 4 100 [OP_DIV] [OP_MUL] 100 10 [OP_DIV] [OP_MUL] [OP_SUB] | var_a = 300
var_b = 300
var_c = 4
var_d = 100
var_e = var_c / var_d
var_f = var_b * var_e
var_g = 100
var_h = 10
var_i = var_g / var_h
var_j = var_f * var_i
var_k = var_a - var_j
print(int(var_k)) |
Comparison | Yoongi collected 4 apples and Jungkook collected 6 times 3 apples. Who has fewer apples? | Yoongi | [OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jungkook'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4
var_d = 6
var_e = 3
var_f = var_d * var_e
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Comparison | Jungkook ate 3 out of 6 apples. When Yoongi has 4 apples, who has fewer apples? | Jungkook | [OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 3
var_e = var_c - var_d
var_f = 4
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Arithmetic calculation | There are apples, bananas and persimmons in the fruit shop. The number of apples is 4 times the number of bananas, and the number of persimmons is 3 times the number of bananas. If the sum of apples and persimmons is 210, how many bananas are there? | 30 | 210 4 3 [OP_ADD] [OP_DIV] | var_a = 210
var_b = 4
var_c = 3
var_d = var_b + var_c
var_e = var_a / var_d
print(int(var_e)) |
Arithmetic calculation | There are 23 more soccer balls at Hoseok's school than basketballs and 18 fewer volleyballs than soccer balls. If there are 40 volleyballs, how many basketballs are there? | 35 | 40 18 [OP_ADD] 23 [OP_SUB] | var_a = 40
var_b = 18
var_c = var_a + var_b
var_d = 23
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | Multiplying a number by 0.55 in a row gives you 4.235. Find the number. | 14 | 4.235 0.55 [OP_DIV] 0.55 [OP_DIV] | var_a = 4.235
var_b = 0.55
var_c = var_a / var_b
var_d = 0.55
var_e = var_c / var_d
print(int(var_e)) |
Comparison | If Eunji stands in line for a bus and there are 6 people waiting in front and 5 people behind, how many people are there? | 12 | 6 1 [OP_ADD] 5 [OP_ADD] | var_a = 6
var_b = 1
var_c = var_a + var_b
var_d = 5
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | The circumference of Suyeong's school playground is 242.7 meters (m). If Suyeong ran 5 laps around the playground, how many meters (m) did she run? | 1213.5 | 242.7 5 [OP_MUL] | var_a = 242.7
var_b = 5
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | There are 3 red balls, 2 blue balls, and 5 green balls in the bag. When a ball is drawn from the bag, what will be the color of the ball with the highest probability? | green | [OP_LIST_SOL] red blue green [OP_LIST_EOL] [OP_LIST_SOL] 3 2 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'red'
var_b = 'blue'
var_c = 'green'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
var_e = 2
var_f = 5
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Possibility | Soyun chooses and discards one of the number cards 3, 5, 8, and 9, and wants to make a three-digit natural number with the remaining cards. How many total numbers can Soyun make? | 24 | [OP_LIST_SOL] 3 5 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 3
var_b = 5
var_c = 8
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = len(list_b)
print(int(var_f)) |
Possibility | If you choose three different numbers from 0, 3, 5, and 9 and use them once to make a three-digit number, what is the sum of the smallest and largest numbers? | 1258 | [OP_LIST_SOL] 0 3 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_ADD] | var_a = 0
var_b = 3
var_c = 5
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[-var_h]
var_j = var_g + var_i
print(int(var_j)) |
Arithmetic calculation | There is a hot air balloon that is 115 meters (m) high. How many minutes does it take to pass through the stratosphere of 1.625 kilometers (km) if it ascends 400 meters (m) in 1 minute? | 3.78 | 1.625 1000 [OP_MUL] 115 [OP_SUB] 400 [OP_DIV] | var_a = 1.625
var_b = 1000
var_c = var_a * var_b
var_d = 115
var_e = var_c - var_d
var_f = 400
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | The wire Yeongju has is 97.5 centimeters (cm), and the wire Minho has is 3 millimeters (mm) longer than 97 centimeters (cm). Who has a shorter wire? | Minho | [OP_LIST_SOL] Yeongju Minho [OP_LIST_EOL] [OP_LIST_SOL] 97.5 97 3 10 [OP_DIV] [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yeongju'
var_b = 'Minho'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 97.5
var_d = 97
var_e = 3
var_f = 10
var_g = var_e / var_f
var_h = var_d + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | Among the multiples of 123, there are is a number shaped162ABC6. Find the smallest of these numbers shaped like that. | 1620156 | 1620006 1629996 1 [OP_LIST_ARANGE] 123 [OP_LIST_DIVISIBLE] 10 6 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN] | var_a = 1620006
var_b = 1629996
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 123
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 10
var_f = 6
list_c = []
var_e = int(var_e)
var_f = int(var_f)
if var_f < 0:
var_f = var_f + var_e
for i in list_b:
i = int(i)
if i%var_e == var_f:
list_c.append(i)
var_g = 1
list_d=list_c.copy()
list_d.sort()
var_h = list_d[var_g-1]
print(int(var_h)) |
Correspondence | Divide 11 by a number and you get 2 as a result. How much is 6 multiplied by a number? | 132 | 2 11 [OP_MUL] 6 [OP_MUL] | var_a = 2
var_b = 11
var_c = var_a * var_b
var_d = 6
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | Hot air balloons are said to ascend into the sky at 3.8 kilometers (km) per hour. How high in kilometers (km) does a hot air balloon rise without stopping in 2 hours and 45 minutes? | 10.45 | 3.8 2 45 60 [OP_DIV] [OP_ADD] [OP_MUL] | var_a = 3.8
var_b = 2
var_c = 45
var_d = 60
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | There are 12 liters (L) and 400 milliliters (㎖) of oil. You are trying to divide this into two bottles. A large bottle can hold 2 liters (L) and 600 milliliters (㎖) more than a small bottle. How many liters (liters) will the large bottle hold? | 7.5 | 12 400 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] 2 600 1000 [OP_DIV] [OP_ADD] 2 [OP_DIV] [OP_ADD] | var_a = 12
var_b = 400
var_c = 1000
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = 600
var_j = 1000
var_k = var_i / var_j
var_l = var_h + var_k
var_m = 2
var_n = var_l / var_m
var_o = var_g + var_n
print('{:.2f}'.format(round(var_o+1e-10,2))) |
Geometry | How many diagonals can be drawn from one vertex of a 10-angle figure? | 7 | 10 3 [OP_SUB] | var_a = 10
var_b = 3
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | The five-digit number A375B is divisible by 24. How many numbers fit for A? | 3 | A375B [OP_GEN_POSSIBLE_LIST] 24 [OP_LIST_DIVISIBLE] A375B A [OP_LIST_FIND_UNK] [OP_LIST_LEN] | var_a = 'A375B'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 24
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = 'A375B'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
list_c = []
for elem in list_b:
elem = str(elem)
list_c.append(int(elem[unk_idx]))
list_c = list(set(list_c))
var_e = len(list_c)
print(int(var_e)) |
Geometry | What is the total number of vertices of a figure with 21 edges, 9 faces, and two polygonal base sides that are parallel and congruent? | 14 | 21 3 [OP_DIV] 2 [OP_MUL] | var_a = 21
var_b = 3
var_c = var_a / var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Comparison | There are four numbers 0.8, 1/2, 0.9, and 1/3. How many numbers are less than or equal to 3? | 4 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
for i in list_a:
if i <= var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Correspondence | If the six-digit number A15B94 is a multiple of 99, find the sum of A and B. | 8 | A15B94 [OP_GEN_POSSIBLE_LIST] 99 [OP_LIST_DIVISIBLE] A15B94 A [OP_LIST_FIND_UNK] A15B94 B [OP_LIST_FIND_UNK] [OP_ADD] | var_a = 'A15B94'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 99
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = 'A15B94'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
var_e = 0
for elem in list_b:
elem = str(elem)
var_e = int(elem[unk_idx])
var_f = 'A15B94'
var_g = 'B'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_b:
elem = str(elem)
var_h = int(elem[unk_idx])
var_i = var_e + var_h
print(int(var_i)) |
Geometry | You have a rectangular piece of dough measuring 34 centimeters (cm) wide. When the dough is cut without gaps using a square mold with a side length of 4 centimeters (cm), if the width of the dough is 2 centimeters (cm) left and 24 cookies are made in total, Find the minimum perimeter of the dough before the mold is stamped in centimeters (cm). | 92 | 24 34 4 [OP_FDIV] [OP_DIV] 4 [OP_MUL] 34 [OP_ADD] 2 [OP_MUL] | var_a = 24
var_b = 34
var_c = 4
var_d = var_b // var_c
var_e = var_a / var_d
var_f = 4
var_g = var_e * var_f
var_h = 34
var_i = var_g + var_h
var_j = 2
var_k = var_i * var_j
print(int(var_k)) |
Possibility | At a fruit store that sells apples, peaches, pears, and strawberries, you want to buy two fruits allowing duplicates. How many possible cases are there? | 10 | [OP_LIST_SOL] apples peaches pears strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | var_a = 'apples'
var_b = 'peaches'
var_c = 'pears'
var_d = 'strawberries'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 2
var_g = var_e + var_f
var_h = 1
var_i = var_g - var_h
var_j = 2
var_k = 1
var_i = int(var_i)
var_j = int(var_j)
for i, elem in enumerate(range(var_j)):
var_k = var_k * (var_i-i)
for i, elem in enumerate(range(var_j)):
var_k = var_k / (i+1)
print(int(var_k)) |
Arithmetic calculation | You have 200 grams (g) of salt water with 5% salt. When the remaining salt became 8% of the total salt water after the water evaporated from this salt water, find how many grams (g) of water has evaporated. | 75 | 200 200 5 100 [OP_DIV] [OP_MUL] 100 8 [OP_DIV] [OP_MUL] [OP_SUB] | var_a = 200
var_b = 200
var_c = 5
var_d = 100
var_e = var_c / var_d
var_f = var_b * var_e
var_g = 100
var_h = 8
var_i = var_g / var_h
var_j = var_f * var_i
var_k = var_a - var_j
print(int(var_k)) |
Comparison | There are 28 identical bookshelves in the library. Each bookshelf has 6 floors, and the number of books on each floor is the same. It is said that when two books are taken from one floor of a bookshelf, there are 20 books left on that floor. How many books are on the shelves in the library? | 3696 | 20 2 [OP_ADD] 6 [OP_MUL] 28 [OP_MUL] | var_a = 20
var_b = 2
var_c = var_a + var_b
var_d = 6
var_e = var_c * var_d
var_f = 28
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | In the process of division, Seokjin left out the 0 in the tens place of the three-digit subtracting number, so he saw it as 15 by mistake. If he gets a quotient of 182 without any remainder, find the quotient of the correct calculation.
| 26 | 15 182 [OP_MUL] 105 [OP_FDIV] | var_a = 15
var_b = 182
var_c = var_a * var_b
var_d = 105
var_e = var_c // var_d
print(int(var_e)) |
Comparison | Which of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10 is greater than or equal to 1.1? Find the smallest or the equal number. | 1.2 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] 1 [OP_LIST_MIN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Correspondence | Subtracting 17 from a number gives 55. What number is it when the number is divided by 9? | 8 | 55 17 [OP_ADD] 9 [OP_DIV] | var_a = 55
var_b = 17
var_c = var_a + var_b
var_d = 9
var_e = var_c / var_d
print(int(var_e)) |
Possibility | How many faces in a tetrahedron meet at one vertex? | 3 | 3 | var_a = 3
print(int(var_a)) |
Geometry | Using 28 centimeters (cm) long wire, I made a rectangle with a width of 6. Find the area of the rectangle. | 48 | 28 2 [OP_DIV] 6 [OP_SUB] 6 [OP_MUL] | var_a = 28
var_b = 2
var_c = var_a / var_b
var_d = 6
var_e = var_c - var_d
var_f = 6
var_g = var_e * var_f
print(int(var_g)) |
Correspondence | While Yoongi was subtracting 57 from the three-digit number, Yoongi mistakenly saw the three-digit ones digit 9 as 6. If the difference that Yoongi found is 819, what is the correct calculation? | 822 | 819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB] | var_a = 819
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 57
var_i = var_g - var_h
print(int(var_i)) |
Geometry | Find the number of semi-straight lines for three points that are not on a straight line. | 6 | 3 2 [OP_PERM] | var_a = 3
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) |
Arithmetic calculation | When three people have marbles, 5 times the number of marbles that Namjoon has is 11 more than what Yoongi has. 2 multiply by the number that Yoongi has is 8 fewer than Hoseok's marbles. Find the sum of marbles for each person: Namjoon, Yoongi, and Hoseok. | 247 | 17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD] | var_a = 17
var_b = 17
var_c = 5
var_d = var_b * var_c
var_e = 11
var_f = var_d - var_e
var_g = var_a + var_f
var_h = 17
var_i = 5
var_j = var_h * var_i
var_k = 11
var_l = var_j - var_k
var_m = 2
var_n = var_l * var_m
var_o = 8
var_p = var_n + var_o
var_q = var_g + var_p
print(int(var_q)) |
Arithmetic calculation | A large bucket is filled with water. You want to divide this water into 7 smaller buckets of the same shape and size. If you divide it by 900 grams (g), 200 grams (g) remain. How many kilograms (kg) of water is in the large bucket? | 6.5 | 900 7 [OP_MUL] 200 [OP_ADD] 1000 [OP_DIV] | var_a = 900
var_b = 7
var_c = var_a * var_b
var_d = 200
var_e = var_c + var_d
var_f = 1000
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Arithmetic calculation | When writing numbers from 1 to 125, find out how many times 2 are written. | 29 | 1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 125
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 2
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Arithmetic calculation | I bought 7 boxes of soda, each box containing 16 cans. Thirteen of them are discarded because the cans were crushed during transport, and I plan to distribute the remaining beverages equally among the eight cartons. How many cans of beverages do not fit in the box? | 3 | 16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_MOD] | var_a = 16
var_b = 7
var_c = var_a * var_b
var_d = 13
var_e = var_c - var_d
var_f = 8
var_g = var_e % var_f
print(int(var_g)) |
Comparison | In a running competition, Jungkook came in the 7th and Minyoung came in the 5th. Taehyung did worse than Minyoung but better than Jungkook. In what place did Taehyung come in? | 6 | 5 7 [OP_ADD] 2 [OP_FDIV] | var_a = 5
var_b = 7
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e)) |
Correspondence | When a number is divided by 24, it becomes 19. What number is it? | 456 | 19 24 [OP_MUL] | var_a = 19
var_b = 24
var_c = var_a * var_b
print(int(var_c)) |
Geometry | Find the sum of the vertices, faces, and edges of the octagonal pyramid. | 34 | 8 1 [OP_ADD] 8 2 [OP_MUL] [OP_ADD] 8 1 [OP_ADD] [OP_ADD] | var_a = 8
var_b = 1
var_c = var_a + var_b
var_d = 8
var_e = 2
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 8
var_i = 1
var_j = var_h + var_i
var_k = var_g + var_j
print(int(var_k)) |
Comparison | There are three numbers A, B, and C. A is 8 multiplied by 9 minus 3. B is the quotient of A divided by 3. C is equal to 2 times B plus 4. Find the sum of the largest and smallest numbers. | 92 | [OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD] | var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 3
var_e = var_c - var_d
var_f = 8
var_g = 9
var_h = var_f * var_g
var_i = 3
var_j = var_h - var_i
var_k = 3
var_l = var_j / var_k
var_m = 8
var_n = 9
var_o = var_m * var_n
var_p = 3
var_q = var_o - var_p
var_r = 3
var_s = var_q / var_r
var_t = 2
var_u = var_s * var_t
var_v = 4
var_w = var_u + var_v
list_a= []
if "/" in str(var_w):
var_w = eval(str(var_w))
list_a.append(var_w)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_a.append(var_l)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
list_a.reverse()
var_x = 1
list_b=list_a.copy()
list_b.sort()
var_y = list_b[-var_x]
var_z = 3
list_c=list_a.copy()
list_c.sort()
var_A = list_c[-var_z]
var_B = var_y + var_A
print(int(var_B)) |
Possibility | Find the sum of possible four digit numbers that can be formed by using each 3, 5, 7, and 9. | 159984 | [OP_LIST_SOL] 3 5 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] [OP_LIST_SUM] | var_a = 3
var_b = 5
var_c = 7
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print(int(var_f)) |
Possibility | You are going to clean the classroom with 5 friends including Eunhee. When picking 2 people in charge of the classroom floor and 1 person in charge of the window, find the number of cases where Eunhee be in charge of the classroom floor. | 12 | 5 1 [OP_SUB] 2 1 [OP_SUB] 1 [OP_ADD] [OP_PERM] | var_a = 5
var_b = 1
var_c = var_a - var_b
var_d = 2
var_e = 1
var_f = var_d - var_e
var_g = 1
var_h = var_f + var_g
var_i = 1
var_c = int(var_c)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_c-i)
print(int(var_i)) |
Geometry | A lake has a circumference of 30 meters (m) and a circumference of 94.2 meters (m). How many times the circumference of the lake is greater than its diameter? | 3.14 | 94.2 30 [OP_DIV] | var_a = 94.2
var_b = 30
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | There are three numbers 10, 11 and 12. What is the value of difference between the 3rd smallest number and the 2nd smallest number? | 1 | [OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] | var_a = 10
var_b = 11
var_c = 12
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b=list_a.copy()
list_b.sort()
var_e = list_b[var_d-1]
var_f = 2
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = var_e - var_g
print(int(var_h)) |
Geometry | Sumin has 6 square-shaped pieces of paper with each side measuring 30 centimeters (cm). To connect these papers in a single line, she overlapped them by 7 centimeters (cm) and attached them with glue. Find the area of the connected paper. | 4350 | 30 6 [OP_MUL] 7 6 1 [OP_SUB] [OP_MUL] [OP_SUB] 30 [OP_MUL] | var_a = 30
var_b = 6
var_c = var_a * var_b
var_d = 7
var_e = 6
var_f = 1
var_g = var_e - var_f
var_h = var_d * var_g
var_i = var_c - var_h
var_j = 30
var_k = var_i * var_j
print(int(var_k)) |
Possibility | You want to divide 7 bananas into 2 different baskets. The basket must contain at least 1 banana. How many ways are there to share bananas? | 6 | 7 2 1 [OP_MUL] [OP_SUB] 1 [OP_ADD] | var_a = 7
var_b = 2
var_c = 1
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | Some school divides classes into upper and lower classes according to math skills. If there are a total of 120 students and there are 36 more students in the lower class than in the upper class, how many students are in the lower class? | 78 | 120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD] | var_a = 120
var_b = 36
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 36
var_g = var_e + var_f
print(int(var_g)) |
Comparison | There are 2 people standing in front of Jungkook and four people behind him. If there are a total of 8 lines with the same number of people for each line, how many people are there? | 56 | 2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL] | var_a = 2
var_b = 4
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
var_f = 8
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | There are 3 numbers: 3/25, 1/5, and 55.21. What is the sum of these numbers? | 55.53 | 3/25 1/5 [OP_ADD] 55.21 [OP_ADD] | var_a = 0.12
var_b = 0.2
var_c = var_a + var_b
var_d = 55.21
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Geometry | If A and B are the numbers of sides and vertices of a pentagon, what is the value of A+B? | 10 | 5 5 [OP_ADD] | var_a = 5
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Possibility | Find the number of combinations of numbers that add up to 19 by selecting 3 of the number cards from 1 to 9. | 30 | 1 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 19 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = 19
var_g = 0
var_f = int(var_f)
for i in list_c:
i = int(i)
if i == var_f:
var_g = var_g + 1
print(int(var_g)) |
Comparison | Which of 2.23, 3.12, 9.434, and 2.453 is the second smallest number? | 2.45 | [OP_LIST_SOL] 2.23 3.12 9.434 2.453 [OP_LIST_EOL] 2 [OP_LIST_MIN] | var_a = 2.23
var_b = 3.12
var_c = 9.434
var_d = 2.453
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | Of the students who played on the playground, 16 went home, and 9 more came, resulting in a total of 25. How many students were playing on the playground at first? | 32 | 25 9 [OP_SUB] 16 [OP_ADD] | var_a = 25
var_b = 9
var_c = var_a - var_b
var_d = 16
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Yuna and her friends are of different heights. The teacher lined up in order from the smallest height, and Yuna was 4th from the front and 6th from the back. How many Yuna and her friends are there? | 9 | 4 6 [OP_ADD] 1 [OP_SUB] | var_a = 4
var_b = 6
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | There are 240 pencils and erasers in the pencil case. If there are 2 fewer pencils than erasers, how many erasers are there in the pencil case? | 121 | 240 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD] | var_a = 240
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 2
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | There are numbers which are 38, 114, 152, and 95. What is the value when the largest number is divided by the smallest number? | 4 | [OP_LIST_SOL] 38 114 152 95 [OP_LIST_EOL] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_DIV] | var_a = 38
var_b = 114
var_c = 152
var_d = 95
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[-var_e]
var_g = 1
list_c=list_a.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = var_f / var_h
print(int(var_i)) |
Comparison | 5 different boxes contain 20, 15, 18, 17, and 20 chocolates respectively. If all the chocolates are taken out of boxes containing 18 or more chocolates and put into one large box, find how many chocolates will fit in this box. | 58 | [OP_LIST_SOL] 20 15 18 17 20 [OP_LIST_EOL] 18 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] | var_a = 20
var_b = 15
var_c = 18
var_d = 17
var_e = 20
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 18
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_g = sum(list_b)
print(int(var_g)) |
Arithmetic calculation | Father's age divided by daughter's age equals 4. When the sum of their ages after 5 years is 50, how old is your father this year? | 32 | 50 5 2 [OP_MUL] [OP_SUB] 1 4 [OP_ADD] [OP_DIV] 4 [OP_MUL] | var_a = 50
var_b = 5
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 1
var_g = 4
var_h = var_f + var_g
var_i = var_e / var_h
var_j = 4
var_k = var_i * var_j
print(int(var_k)) |
Geometry | The length of each side of the parallelogram is 18 centimeters (cm) and 12 centimeters (cm), respectively. Find the circumference of this parellelogram. | 60 | 18 12 [OP_ADD] 2 [OP_MUL] | var_a = 18
var_b = 12
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | A total of 30 trees are planted 9 meters (m) apart on either side of a road from beginning to end. Find the length of this road in meters (m). | 126 | 30 2 [OP_DIV] 1 [OP_SUB] 9 [OP_MUL] | var_a = 30
var_b = 2
var_c = var_a / var_b
var_d = 1
var_e = var_c - var_d
var_f = 9
var_g = var_e * var_f
print(int(var_g)) |
Comparison | There are three numbers A, B, and C. A is 1/2 and B is 9/10. If C is 2/5, what is the smallest among A, B, or C? | C | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1 2 [OP_DIV] 9 10 [OP_DIV] 2 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
var_e = 2
var_f = var_d / var_e
var_g = 9
var_h = 10
var_i = var_g / var_h
var_j = 2
var_k = 5
var_l = var_j / var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Geometry | There are planks that are 36 centimeters (cm), 42 centimeters (cm), and 48 centimeters (cm) respectively. After cutting out 1/6 of this plank while trimming it, I overlapped and glued certain parts together, and the total length is 97 centimeters (cm). If all overlapping parts are the same length, find how many centimeters (cm) is the overlapping part. | 4 | 36 42 [OP_ADD] 48 [OP_ADD] 1 1/6 [OP_SUB] [OP_MUL] 97 [OP_SUB] 3 1 [OP_SUB] [OP_DIV] | var_a = 36
var_b = 42
var_c = var_a + var_b
var_d = 48
var_e = var_c + var_d
var_f = 1
var_g = 0.16666666666666666
var_h = var_f - var_g
var_i = var_e * var_h
var_j = 97
var_k = var_i - var_j
var_l = 3
var_m = 1
var_n = var_l - var_m
var_o = var_k / var_n
print(int(var_o)) |
Correspondence | A number needs to be multiplied by 5, but I mistakenly added 5 to get 43. Find the result of the correct calculation. | 190 | 43 5 [OP_SUB] 5 [OP_MUL] | var_a = 43
var_b = 5
var_c = var_a - var_b
var_d = 5
var_e = var_c * var_d
print(int(var_e)) |
Geometry | You want to plant trees at intervals of 4 meters (m) in a circle-shaped park with a circumference of 28 meters (m). Find how many trees you can plant. | 7 | 28 4 [OP_DIV] | var_a = 28
var_b = 4
var_c = var_a / var_b
print(int(var_c)) |
Geometry | There is a prism whose sum of the number of edges, faces, and vertices is 50. How many edges of the pyramid have the same base shape as the prism? | 16 | 50 2 [OP_SUB] 2 3 [OP_ADD] 1 [OP_ADD] [OP_DIV] 2 [OP_MUL] | var_a = 50
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = 3
var_f = var_d + var_e
var_g = 1
var_h = var_f + var_g
var_i = var_c / var_h
var_j = 2
var_k = var_i * var_j
print(int(var_k)) |
Possibility | You want to draw two numbers from the digits 0, 1, 2, and 5 to create a number greater than 10 and less than 100. In how many cases does each digit of the drawn number differ? | 8 | [OP_LIST_SOL] 0 1 2 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 10 [OP_LIST_MORE] 100 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 5
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 10
list_c = []
for i in list_b:
if i > var_f:
list_c.append(i)
var_g = 100
list_d = []
for i in list_c:
if i < var_g:
list_d.append(i)
var_h = len(list_d)
print(int(var_h)) |
Geometry | There are several ttakjis. I laid out the ttakjis to make a large square, and there were residual 36 ttakjis that were not used to make the square. I increased one horizontal and one vertical side by one column, and there are still three residual ttakjis left. How many ttakjis are there in all? | 292 | 36 3 [OP_SUB] 1 [OP_SUB] 2 [OP_DIV] 2 [OP_POW] 36 [OP_ADD] | var_a = 36
var_b = 3
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g ** var_h
var_j = 36
var_k = var_i + var_j
print(int(var_k)) |
Correspondence | When a number is multiplied by 4 and divided by 8, the quotient is 6 and the remainder is 4. Find out what this number is. | 13 | 6 8 [OP_MUL] 4 [OP_ADD] 4 [OP_DIV] | var_a = 6
var_b = 8
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
var_f = 4
var_g = var_e / var_f
print(int(var_g)) |
Geometry | A cube is made by stacking 8 smaller cubes. If the volume of the stacked cubes is 1000 cubic centimeters (cm3), find the length of one corner of the smaller cube. | 5 | 1000 8 [OP_DIV] 1/3 [OP_POW] | var_a = 1000
var_b = 8
var_c = var_a / var_b
var_d = 0.3333333333333333
var_e = var_c ** var_d
print(int(eval('{:.2f}'.format(round(var_e+1e-10,2))))) |
Arithmetic calculation | There is a two-digit natural number whose tens digit is 3. If the number of digits in the tens digit and the ones digit of this natural number that are interchanged is 9 less than the initial number, find the initial number. | 32 | 3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD] | var_a = 3
var_b = 10
var_c = var_a * var_b
var_d = 9
var_e = var_c - var_d
var_f = 3
var_g = var_e - var_f
var_h = 10
var_i = 1
var_j = var_h - var_i
var_k = var_g / var_j
var_l = 3
var_m = 10
var_n = var_l * var_m
var_o = var_k + var_n
print(int(var_o)) |
Arithmetic calculation | Among the numbers from 1 to 100, find the smallest number whose remainder when divided by 7 is 2 and when divided by 8 is also 2. | 2 | 1 100 1 [OP_LIST_ARANGE] 7 2 [OP_LIST_DIVIDE_AND_REMAIN] 8 2 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_MIN] | var_a = 1
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 7
var_e = 2
list_b = []
var_d = int(var_d)
var_e = int(var_e)
if var_e < 0:
var_e = var_e + var_d
for i in list_a:
i = int(i)
if i%var_d == var_e:
list_b.append(i)
var_f = 8
var_g = 2
list_c = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_b:
i = int(i)
if i%var_f == var_g:
list_c.append(i)
var_h = 1
list_d=list_c.copy()
list_d.sort()
var_i = list_d[var_h-1]
print(int(var_i)) |
Correspondence | AB+21=58. Calculate the value of A. | 3 | AB+21=58 A [OP_DIGIT_UNK_SOLVER] | var_a = 'AB+21=58'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | There is a soap in the shape of a rectangular parallelepiped measuring 4 centimeters (cm) wide, 6 centimeters (cm) long, and 5 centimeters (cm) high. If you use this soap and it becomes a cube, what is the maximum volume of the soap? | 64 | [OP_LIST_SOL] 4 6 4 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MIN] 3 [OP_POW] | var_a = 4
var_b = 6
var_c = 4
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
list_b=list_a.copy()
list_b.sort()
var_e = list_b[var_d-1]
var_f = 1
list_c=list_a.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = 3
var_i = var_g ** var_h
print(int(var_i)) |
Arithmetic calculation | This year the mother is 43 years old and the daughter is 11 years old. How many years ago was the mother's age five times her daughter's age? | 3 | 5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV] | var_a = 5
var_b = 11
var_c = var_a * var_b
var_d = 43
var_e = var_c - var_d
var_f = 5
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Possibility | How many edges are there on a face of an octahedron? | 3 | 3 | var_a = 3
print(int(var_a)) |
Correspondence | How many multiples of 7 are three-digit numbers with 7 in the hundreds place? | 15 | 7AB [OP_GEN_POSSIBLE_LIST] 7 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = '7AB'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 7
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = len(list_b)
print(int(var_c)) |
Comparison | Three people each have a number card. If X is the average of the number cards of each person, the average of the number cards of two people A and B is 23 greater than X, and the average of the number cards of two people B and C is 17 less than X. The number written on B's number card was 66. Find the number written on A's number card. | 124 | 66 23 2 [OP_MUL] [OP_ADD] 3 [OP_MUL] 17 23 [OP_ADD] 2 [OP_MUL] [OP_SUB] 66 2 [OP_MUL] [OP_SUB] 2 2 [OP_ADD] 3 [OP_SUB] [OP_DIV] | var_a = 66
var_b = 23
var_c = 2
var_d = var_b * var_c
var_e = var_a + var_d
var_f = 3
var_g = var_e * var_f
var_h = 17
var_i = 23
var_j = var_h + var_i
var_k = 2
var_l = var_j * var_k
var_m = var_g - var_l
var_n = 66
var_o = 2
var_p = var_n * var_o
var_q = var_m - var_p
var_r = 2
var_s = 2
var_t = var_r + var_s
var_u = 3
var_v = var_t - var_u
var_w = var_q / var_v
print(int(var_w)) |
Geometry | A rabbit is walking in a park with a side length measuring 13 meters (m). How many meters (m) did the rabbit walk? | 52 | 13 4 [OP_MUL] | var_a = 13
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Correspondence | When 10 is divided by A, the quotient is B and the remainder is C. A, B, and C are natural numbers. If B and C are equal, find the largest possible number of A. | 9 | 10 1 [OP_SUB] | var_a = 10
var_b = 1
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | Yoongi multiplied 15 by a certain number to get 45. Find the exact result of subtracting 1 from the number. | 2 | 45 15 [OP_DIV] 1 [OP_SUB] | var_a = 45
var_b = 15
var_c = var_a / var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Jungkook has 3 marbles, Jimin has 4 more marbles than what Jungkook has. What is a total number of their marbles? | 10 | 3 3 4 [OP_ADD] [OP_ADD] | var_a = 3
var_b = 3
var_c = 4
var_d = var_b + var_c
var_e = var_a + var_d
print(int(var_e)) |
Geometry | The sum of the edges of a hexagonal pyramid is 120 centimeters (cm). What is the sum of the edges divided by the number of edges? | 10 | 120 6 2 [OP_MUL] [OP_DIV] | var_a = 120
var_b = 6
var_c = 2
var_d = var_b * var_c
var_e = var_a / var_d
print(int(var_e)) |
Correspondence | We have the expression 31+6AB=683. Find the number that goes into B | 2 | 31+6AB=683 B [OP_DIGIT_UNK_SOLVER] | var_a = '31+6AB=683'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Comparison | Jungkook ate 3 out of 6 apples. If Yoongi has 4 apples, who has more apples? | Yoongi | [OP_LIST_SOL] Jungkook Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_SUB] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 3
var_e = var_c - var_d
var_f = 4
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Possibility | You want to create a three-digit number using the numbers 7, 2, and 9 only once. How many three-digit numbers can you make? | 6 | [OP_LIST_SOL] 7 2 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 7
var_b = 2
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Arithmetic calculation | At intervals of 50 meters (m), statues are erected on both sides of the street a distance of 1650 meters (m). If there are statues at the beginning and end of the street, how many statues are there on both sides of the street? | 68 | 1650 50 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL] | var_a = 1650
var_b = 50
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
var_f = 2
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | Jimin had three dozen pencils. He gave 8 of them to his younger brother and a few to Yuna, so he has 17 left. If one dozen is 12 pencils, how many pencils did Jimin give Yuna? | 11 | 3 12 [OP_MUL] 8 [OP_SUB] 17 [OP_SUB] | var_a = 3
var_b = 12
var_c = var_a * var_b
var_d = 8
var_e = var_c - var_d
var_f = 17
var_g = var_e - var_f
print(int(var_g)) |
Arithmetic calculation | If the sum of three consecutive natural numbers is 30, find the smallest natural number of them. | 9 | 30 3 [OP_DIV] 1 [OP_SUB] | var_a = 30
var_b = 3
var_c = var_a / var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Possibility | Yoongi wants to buy 3 out of 5 books at the bookstore. Find how many possible cases there are. | 10 | 5 3 [OP_COMB] | var_a = 5
var_b = 3
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
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