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Correspondence | You want to multiply 20 by some number. you mistakenly subtracted some number from 40, and the result was 52. What is the correct calculation result? | -240 | 20 40 52 [OP_SUB] [OP_MUL] | var_a = 20
var_b = 40
var_c = 52
var_d = var_b - var_c
var_e = var_a * var_d
print(int(var_e)) |
Correspondence | Rounding down the three-digit number A27 to the nearest hundred gives 200. Get a single-digit number A. | 2 | A27 [OP_GEN_POSSIBLE_LIST] 200 [OP_LIST_MORE_EQUAL] 200 100 [OP_ADD] [OP_LIST_LESS] A [OP_LIST_FIND_UNK] | var_a = 'A27'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 200
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 200
var_d = 100
var_e = var_c + var_d
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = 'A'
var_a = str(var_a)
var_f = str(var_f)
unk_idx = var_a.index(var_f)
var_g = 0
for elem in list_c:
elem = str(elem)
var_g = int(elem[unk_idx])
print(int(var_g)) |
Arithmetic calculation | If you mix 200 grams (g) of salt water with a concentration of 25% and 300 grams (g) of salt water in which 60 grams (g) of salt are dissolved, what is the concentration of the salt water? | 22 | 200 25 100 [OP_DIV] [OP_MUL] 60 [OP_ADD] 200 300 [OP_ADD] [OP_DIV] 100 [OP_MUL] | var_a = 200
var_b = 25
var_c = 100
var_d = var_b / var_c
var_e = var_a * var_d
var_f = 60
var_g = var_e + var_f
var_h = 200
var_i = 300
var_j = var_h + var_i
var_k = var_g / var_j
var_l = 100
var_m = var_k * var_l
print(int(var_m)) |
Geometry | How many centimeters (cm) is the width of a rectangle whose area is 28/3 square centimeter (cm2) and its length is 14/5 centimeters (cm)? | 3.33 | 28/3 14/5 [OP_DIV] | var_a = 9.333333333333334
var_b = 2.8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Possibility | If you write down all odd numbers that are less than 100 and that are multiples of 3 on a piece of paper, how many times do you have to write the number 1? | 4 | 1 100 [OP_LIST_ODD] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 100
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = []
var_c = int(var_c)
for i in list_a:
i = int(i)
if i % var_c == 0:
list_b.append(i)
var_d=""
for i in list_b:
i = str(i)
var_d = var_d + i
list_c = []
var_d = int(var_d)
while var_d//10 > 0:
list_c.append(var_d%10)
var_d = var_d//10
list_c.append(var_d%10)
list_c = list_c[::-1]
var_e = 1
var_f = 0
var_e = int(var_e)
for i in list_c:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Arithmetic calculation | When writing the numbers from 1 to 125, find how many times the number 2 is written. | 29 | 1 125 1 [OP_LIST_ARANGE] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 125
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
list_b = []
var_d = int(var_d)
while var_d//10 > 0:
list_b.append(var_d%10)
var_d = var_d//10
list_b.append(var_d%10)
list_b = list_b[::-1]
var_e = 2
var_f = 0
var_e = int(var_e)
for i in list_b:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Correspondence | 8 is the result of accidentally adding 12 to a certain number and then dividing by 8. If the original calculation was to subtract 12 and multiply by 9, what is the correct value? | 360 | 8 8 [OP_MUL] 12 [OP_SUB] 12 [OP_SUB] 9 [OP_MUL] | var_a = 8
var_b = 8
var_c = var_a * var_b
var_d = 12
var_e = var_c - var_d
var_f = 12
var_g = var_e - var_f
var_h = 9
var_i = var_g * var_h
print(int(var_i)) |
Comparison | What is the smallest number in 1.4, 9/10, 1.2, 0.5, and 13/10 after listing the numbers greater than 1.1? | 1.2 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE] 1 [OP_LIST_MIN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
print('{:.2f}'.format(round(var_h+1e-10,2))) |
Possibility | If there are 5 members A, B, C, D, and E, find the number of cases in which one representative and two deputies are selected. | 11 | 5 1 [OP_PERM] 5 1 [OP_SUB] 2 [OP_COMB] [OP_ADD] | var_a = 5
var_b = 1
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
var_d = 5
var_e = 1
var_f = var_d - var_e
var_g = 2
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
for i, elem in enumerate(range(var_g)):
var_h = var_h / (i+1)
var_i = var_c + var_h
print(int(var_i)) |
Arithmetic calculation | Jimin had 33 notebooks. My father bought 7 more notebooks and my mother bought 14 more. How many more notebooks does Jimin have than at first? | 21 | 33 7 [OP_ADD] 14 [OP_ADD] 33 [OP_SUB] | var_a = 33
var_b = 7
var_c = var_a + var_b
var_d = 14
var_e = var_c + var_d
var_f = 33
var_g = var_e - var_f
print(int(var_g)) |
Geometry | 5.9 centimeters (cm) and 3 centimeters (cm) are the lengths of the two sides of the rectangle. Find the area of this rectangle. | 17.7 | 5.9 3 [OP_MUL] | var_a = 5.9
var_b = 3
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | The blue box and the red box contain balls. After moving 152 balls from the red box to the blue box, the number of balls in the red box is 346 more than the number of balls in the blue box. Find the difference between the number of balls in the two boxes before moving the balls. | 650 | 346 152 [OP_ADD] 152 [OP_ADD] | var_a = 346
var_b = 152
var_c = var_a + var_b
var_d = 152
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There is a banner 20 meters (m) long. I'm thinking of fixating this banner with nails. Nails were driven 1 meter (m) apart from both ends of the banner, and the remaining nails were nailed in at regular intervals. A total of 7 nails were used. Find the distance between one nail and another. | 3 | 20 1 2 [OP_MUL] [OP_SUB] 7 1 [OP_SUB] [OP_DIV] | var_a = 20
var_b = 1
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 7
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Correspondence | There are two different single-digit numbers A and B. Find the sum of A and B that satisfies the following addition formula AB+640=BBB. | 8 | AB+640=BBB A [OP_DIGIT_UNK_SOLVER] AB+640=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = 'AB+640=BBB'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'AB+640=BBB'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Comparison | Suho is taller than Minyoung, and Seongju is shorter than Minyoung. Seonmi is shorter than Seongju. Write down the shortest person. | Seonmi | [OP_LIST_SOL] Suho Minyoung Seongju Seonmi [OP_LIST_EOL] [OP_LIST_SOL] Suho Minyoung > Seongju Minyoung < Seongju Seonmi > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'Suho'
var_b = 'Minyoung'
var_c = 'Seongju'
var_d = 'Seonmi'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 'Suho'
var_f = 'Minyoung'
var_g = '>'
var_h = 'Seongju'
var_i = 'Minyoung'
var_j = '<'
var_k = 'Seongju'
var_l = 'Seonmi'
var_m = '>'
list_b= []
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_n = len(list_c)
var_o = list_c[var_n-1]
print(var_o) |
Possibility | If 6 professional baseball teams play with each other once, how many matches will there be in total? | 15 | 6 2 [OP_COMB] | var_a = 6
var_b = 2
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Comparison | You are comparing the heights of 20 students. If there are 11 students taller than Yoongi, how many students are shorter than Yoongi? | 8 | 20 11 [OP_SUB] 1 [OP_SUB] | var_a = 20
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | If you add 12 to a number and subtract 27, you get 24. Find the number. | 39 | 24 27 [OP_ADD] 12 [OP_SUB] | var_a = 24
var_b = 27
var_c = var_a + var_b
var_d = 12
var_e = var_c - var_d
print(int(var_e)) |
Possibility | If there are 10, 50, and 100 won coins, and three coins are thrown at the same time, find the number of possible outcomes. (However, when a coin is thrown, it comes out either heads or tails.) | 8 | 2 3 [OP_POW] | var_a = 2
var_b = 3
var_c = var_a ** var_b
print(int(var_c)) |
Correspondence | The five digit number 26AA2 is a multiple of 3. If single-digit number A represents the same number, how many numbers can be in A? | 3 | 26AA2 [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] 26AA2 A [OP_LIST_FIND_UNK] [OP_LIST_LEN] | var_a = '26AA2'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 3
list_b = []
var_b = int(var_b)
for i in list_a:
i = int(i)
if i % var_b == 0:
list_b.append(i)
var_c = '26AA2'
var_d = 'A'
var_c = str(var_c)
var_d = str(var_d)
unk_idx = var_c.index(var_d)
list_c = []
for elem in list_b:
elem = str(elem)
list_c.append(int(elem[unk_idx]))
list_c = list(set(list_c))
var_e = len(list_c)
print(int(var_e)) |
Arithmetic calculation | Yoongi's age is 2 years younger than Hoseok's. The sum of the ages of Yoongi and Hoseok is 18 years old. How old is Yoongi? | 8 | 18 2 [OP_SUB] 2 [OP_DIV] | var_a = 18
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Geometry | What is the perimeter of an equilateral triangle with a side of 7 centimeters (cm)? | 21 | 7 3 [OP_MUL] | var_a = 7
var_b = 3
var_c = var_a * var_b
print(int(var_c)) |
Correspondence | You are about to distribute the same two-digit number of pencils to the classmates. There is nothing left when distributing to 6 students and 9 students, and 1 pencil is left when distributing to 7 students. Find how many pencils there are. | 36 | 10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET] | var_a = 10
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
var_e = 9
var_f = var_e * var_d / math.gcd(int(var_e), int(var_d))
var_g = 0
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 7
var_i = 1
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k)) |
Possibility | Adding a number to the smallest two-digit number you can make from two different numbers from 1, 3, 5, and 8 equals 88. Find the number. | 75 | [OP_LIST_SOL] 1 3 5 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 88 [OP_SUB] | var_a = 1
var_b = 3
var_c = 5
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
var_h = 88
var_i = var_g - var_h
print(int(var_i)) |
Arithmetic calculation | Of the people who visited the pool during the week, 1518 were women, of whom 536 were students. There were 525 more men than women, of whom 1257 were non-students. How many students visited the pool in total? | 1322 | 1518 525 [OP_ADD] 1257 [OP_SUB] 536 [OP_ADD] | var_a = 1518
var_b = 525
var_c = var_a + var_b
var_d = 1257
var_e = var_c - var_d
var_f = 536
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | When 13 is divided by A, the quotient is 4, the remainder is B. A and B are both natural numbers. Find the largest possible value of A. | 3 | 13 1 [OP_SUB] 4 [OP_FDIV] | var_a = 13
var_b = 1
var_c = var_a - var_b
var_d = 4
var_e = var_c // var_d
print(int(var_e)) |
Geometry | How many edges does a cube have? | 12 | 6 2 [OP_SUB] 3 [OP_MUL] | var_a = 6
var_b = 2
var_c = var_a - var_b
var_d = 3
var_e = var_c * var_d
print(int(var_e)) |
Geometry | If the ratio of the surface areas of two cubes is 9:25, how many times the volume of the larger cube is the smaller one? | 4.63 | 25 1/2 [OP_POW] 3 [OP_POW] 9 1/2 [OP_POW] 3 [OP_POW] [OP_DIV] | var_a = 25
var_b = 0.5
var_c = var_a ** var_b
var_d = 3
var_e = var_c ** var_d
var_f = 9
var_g = 0.5
var_h = var_f ** var_g
var_i = 3
var_j = var_h ** var_i
var_k = var_e / var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) |
Comparison | Sangwoo's midterm math score is higher than Hana's score, and Yunyong's math score is lower than Hana's score. Which of the three friends has the highest midterm math score? | Sangwoo | [OP_LIST_SOL] Sangwoo Hana Yunyong [OP_LIST_EOL] [OP_LIST_SOL] Sangwoo Hana > Yunyong Hana < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Sangwoo'
var_b = 'Hana'
var_c = 'Yunyong'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Sangwoo'
var_e = 'Hana'
var_f = '>'
var_g = 'Yunyong'
var_h = 'Hana'
var_i = '<'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = 1
var_k = list_c[var_j-1]
print(var_k) |
Comparison | Taehyung and 10 of his friends are standing in a line. If 5 people are standing to Taehyung's left, how many people are standing to Taehyung's right? | 4 | 10 5 [OP_SUB] 1 [OP_SUB] | var_a = 10
var_b = 5
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | Seongjun spent half of his money and 300 won at the first store, half of the remaining money and 300 won at the second store, and 500 won at the third store. How much money did Seongjun have at the beginning? | 4200 | 0 400 [OP_ADD] 500 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 1/2 [OP_SUB] [OP_DIV] | var_a = 0
var_b = 400
var_c = var_a + var_b
var_d = 500
var_e = var_c + var_d
var_f = 1
var_g = 0.5
var_h = var_f - var_g
var_i = var_e / var_h
var_j = 300
var_k = var_i + var_j
var_l = 1
var_m = 0.5
var_n = var_l - var_m
var_o = var_k / var_n
print(int(var_o)) |
Correspondence | A number divided by 6 is 26. What is the value of the number? | 156 | 26 6 [OP_MUL] | var_a = 26
var_b = 6
var_c = var_a * var_b
print(int(var_c)) |
Correspondence | You need to add 8 to a number and subtract 11. But ended up subtracting 9 and 12 by mistake, and got 24. Find the product of the correctly calculated value and the incorrectly calculated value. | 1008 | 24 12 [OP_ADD] 9 [OP_ADD] 8 [OP_ADD] 11 [OP_SUB] 24 [OP_MUL] | var_a = 24
var_b = 12
var_c = var_a + var_b
var_d = 9
var_e = var_c + var_d
var_f = 8
var_g = var_e + var_f
var_h = 11
var_i = var_g - var_h
var_j = 24
var_k = var_i * var_j
print(int(var_k)) |
Arithmetic calculation | If you can process 240 kg (kg) of rice in 4 days, how many days will it take to process 1920 kg (kg)? | 32 | 1920 240 4 [OP_DIV] [OP_FDIV] | var_a = 1920
var_b = 240
var_c = 4
var_d = var_b / var_c
var_e = var_a // var_d
print(int(var_e)) |
Comparison | Among the four students, Minyoung passed the finish line faster than Yoongi, and Yoongi crossed the finish line faster than Jimin. If Jimin and Minyoung got through later than Yuna, who came in first? | Yuna | [OP_LIST_SOL] Minyoung Yoongi Jimin Yuna [OP_LIST_EOL] [OP_LIST_SOL] Minyoung Yoongi > Yoongi Jimin > Jimin Yuna < Minyoung Yuna < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Minyoung'
var_b = 'Yoongi'
var_c = 'Jimin'
var_d = 'Yuna'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 'Minyoung'
var_f = 'Yoongi'
var_g = '>'
var_h = 'Yoongi'
var_i = 'Jimin'
var_j = '>'
var_k = 'Jimin'
var_l = 'Yuna'
var_m = '<'
var_n = 'Minyoung'
var_o = 'Yuna'
var_p = '<'
list_b= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_q = 1
var_r = list_c[var_q-1]
print(var_r) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the sum of the 3rd and 2nd smallest numbers? | 23 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 3 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_ADD] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g + var_i
print(int(var_j)) |
Arithmetic calculation | Minyoung ate 10 tangerines from the basket. And an hour later, when she ate 6 more tangerines, the basket was empty. How many tangerines were in the basket? | 16 | 10 6 [OP_ADD] | var_a = 10
var_b = 6
var_c = var_a + var_b
print(int(var_c)) |
Geometry | If a rectangle has the width of 0.9 times its length, and the length of 15 centimeters (cm), what is the area of this rectangle? | 202.5 | 15 15 0.9 [OP_MUL] [OP_MUL] | var_a = 15
var_b = 15
var_c = 0.9
var_d = var_b * var_c
var_e = var_a * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | Minha's hair grows at a rate of 0.39 millimeters (mm) per day. If the length of Minha's hair is 32.8 centimeters (cm) today, how many centimeters (cm) will it be after 30 days? | 33.97 | 0.39 10 [OP_DIV] 30 [OP_MUL] 32.8 [OP_ADD] | var_a = 0.39
var_b = 10
var_c = var_a / var_b
var_d = 30
var_e = var_c * var_d
var_f = 32.8
var_g = var_e + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | Sort 1.23, 3/4, 2.34, 2.12, 4.23, and 5/3 by largest to smallest. What could be the third? | 2.12 | [OP_LIST_SOL] 1.23 3 4 [OP_DIV] 2.34 2.12 4.23 5 3 [OP_DIV] [OP_LIST_EOL] 3 [OP_LIST_MAX] | var_a = 1.23
var_b = 3
var_c = 4
var_d = var_b / var_c
var_e = 2.34
var_f = 2.12
var_g = 4.23
var_h = 5
var_i = 3
var_j = var_h / var_i
list_a= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_a.append(var_j)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_k = 3
list_b=list_a.copy()
list_b.sort()
var_l = list_b[-var_k]
print('{:.2f}'.format(round(var_l+1e-10,2))) |
Comparison | There are 5 people: Juri, Jungwoo, Myunghyun, Seokjin, and Jungkook. Jungwoo is smaller than Juri and Seokjin is smaller than Myunghyun. Juri is shorter than Jungkook. Myunghyun is shorter than Jungwoo. Who is the tallest? | Jungkook | [OP_LIST_SOL] Juri Jungwoo Myunghyun Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myunghyun Seokjin > Juri Jungkook < Myunghyun Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Juri'
var_b = 'Jungwoo'
var_c = 'Myunghyun'
var_d = 'Seokjin'
var_e = 'Jungkook'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'Juri'
var_g = 'Jungwoo'
var_h = '>'
var_i = 'Myunghyun'
var_j = 'Seokjin'
var_k = '>'
var_l = 'Juri'
var_m = 'Jungkook'
var_n = '<'
var_o = 'Myunghyun'
var_p = 'Jungwoo'
var_q = '<'
list_b= []
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_r = 1
var_s = list_c[var_r-1]
print(var_s) |
Correspondence | The result of dividing a certain number by 7 mistake of dividing a certain number by 6 is 42. How much is it if you calculate it correctly? | 49 | 42 7 [OP_MUL] 6 [OP_DIV] | var_a = 42
var_b = 7
var_c = var_a * var_b
var_d = 6
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | Subtracting 17 from a number gives 55. If Yoongi wants to divide the number by 9, how much does Yoongi get? | 8 | 55 17 [OP_ADD] 9 [OP_DIV] | var_a = 55
var_b = 17
var_c = var_a + var_b
var_d = 9
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | What is the smallest 4-digit number that is a multiple of 3 and a multiple of 5? | 1005 | 1000 9999 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 1000
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[var_f-1]
print(int(var_g)) |
Correspondence | Sunye's house has no electricity, so she has to rely on matches. There are 8 matches in a matchbox. Sunye has 9 matchboxes and 7 single matches. If she uses 6 matches a day, find the maximum number of days she can last completely. | 13 | 8 9 [OP_MUL] 7 [OP_ADD] 6 [OP_FDIV] | var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 7
var_e = var_c + var_d
var_f = 6
var_g = var_e // var_f
print(int(var_g)) |
Arithmetic calculation | You want to drink 19 liters (L) of water equally over 9 days. Find how many liters (l) of water you need to drink per day. | 2.11 | 19 9 [OP_DIV] | var_a = 19
var_b = 9
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | Suppose several monsters are trying to attack. If you shoot 4 times at a monster, 3 shots remain, and if you try to shoot 5 times, then you lack 6 shots. How many monsters are there? | 9 | 3 6 [OP_ADD] 5 4 [OP_SUB] [OP_DIV] | var_a = 3
var_b = 6
var_c = var_a + var_b
var_d = 5
var_e = 4
var_f = var_d - var_e
var_g = var_c / var_f
print(int(var_g)) |
Geometry | A parallelogram has an area of 44 square centimeters (cm2) and a height of 11 centimeters (cm). What is the length of the base? | 4 | 44 11 [OP_DIV] | var_a = 44
var_b = 11
var_c = var_a / var_b
print(int(var_c)) |
Correspondence | You mistakenly added what should have subtracted 0.42 from a number, and ended up with 0.9. What is 0.5 added to the correctly calculated value? | 0.56 | 0.9 0.42 [OP_SUB] 0.42 [OP_SUB] 0.5 [OP_ADD] | var_a = 0.9
var_b = 0.42
var_c = var_a - var_b
var_d = 0.42
var_e = var_c - var_d
var_f = 0.5
var_g = var_e + var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Correspondence | When A is divided by 7, the quotient is 5 and the remainder is 3. Get A. | 38 | 7 5 [OP_MUL] 3 [OP_ADD] | var_a = 7
var_b = 5
var_c = var_a * var_b
var_d = 3
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | A bucket full of water weighs 320 kilograms (kg). After using 1/2 of the water, the bucket weighs 175 kilograms (kg). What is the weight of the empty bucket in kilograms (kg)? | 30 | 320 320 175 [OP_SUB] 2 [OP_MUL] [OP_SUB] | var_a = 320
var_b = 320
var_c = 175
var_d = var_b - var_c
var_e = 2
var_f = var_d * var_e
var_g = var_a - var_f
print(int(var_g)) |
Arithmetic calculation | I bought 7 boxes of soda, each box containing 16 cans. Thirteen of them were discarded because the cans were crushed during transport. I plan to distribute the remaining beverages equally among the eight boxes. How many pieces should I put in each box? | 12 | 16 7 [OP_MUL] 13 [OP_SUB] 8 [OP_FDIV] | var_a = 16
var_b = 7
var_c = var_a * var_b
var_d = 13
var_e = var_c - var_d
var_f = 8
var_g = var_e // var_f
print(int(var_g)) |
Geometry | There is a cube with 6 centimeters (cm) edge. If a smaller cube whose edge is 2 centimeters (cm) is cut out from the middle of each side of the original one, what will be the surface area in square centimeters (cm2)? | 312 | 6 2 [OP_POW] 6 [OP_MUL] 2 2 [OP_POW] 4 [OP_MUL] 6 [OP_MUL] [OP_ADD] | var_a = 6
var_b = 2
var_c = var_a ** var_b
var_d = 6
var_e = var_c * var_d
var_f = 2
var_g = 2
var_h = var_f ** var_g
var_i = 4
var_j = var_h * var_i
var_k = 6
var_l = var_j * var_k
var_m = var_e + var_l
print(int(var_m)) |
Arithmetic calculation | The box contains 23 green and 23 purple marbles. If there are 7 more green marbles than purple marbles, how many green marbles are there? | 8 | 23 7 [OP_SUB] 2 [OP_DIV] | var_a = 23
var_b = 7
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Possibility | Seven classes play soccer. If they play against each other once, how many matches are there in total? | 21 | 7 7 1 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 7
var_b = 7
var_c = 1
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Comparison | If a cinema has 4 rows of 8 chairs each, what is the total number of chairs in the cinema? | 32 | 8 4 [OP_MUL] | var_a = 8
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Comparison | The average number of books the three had was 23 fewer than the average of the first and second persons, and 17 more than the average of the second and third persons. If the second person has 66 books, find the sum of the number of books the first person and the third person have. | 96 | 66 23 [OP_SUB] 17 [OP_ADD] 2 3 [OP_DIV] 66 [OP_MUL] [OP_SUB] 2 3 [OP_DIV] 1 2 [OP_DIV] [OP_SUB] [OP_DIV] | var_a = 66
var_b = 23
var_c = var_a - var_b
var_d = 17
var_e = var_c + var_d
var_f = 2
var_g = 3
var_h = var_f / var_g
var_i = 66
var_j = var_h * var_i
var_k = var_e - var_j
var_l = 2
var_m = 3
var_n = var_l / var_m
var_o = 1
var_p = 2
var_q = var_o / var_p
var_r = var_n - var_q
var_s = var_k / var_r
print(int(eval('{:.2f}'.format(round(var_s+1e-10,2))))) |
Possibility | The number cards have numbers from 1 to 12 written on them. When a number card is drawn, find the number of cases where the number on the card is a multiple of 3. | 4 | 1 12 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 1
var_b = 12
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Possibility | You have two chances to pick fruit from a basket that contains one apple, one peach, one pear, one melon, and one strawberry. How many orders of fruit can there be? | 20 | [OP_LIST_SOL] apple peach pear melon strawberry [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM] | var_a = 'apple'
var_b = 'peach'
var_c = 'pear'
var_d = 'melon'
var_e = 'strawberry'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 2
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
print(int(var_h)) |
Arithmetic calculation | Multiplying product (a) produced in August by 8 gives you the number of product (a) produced in September. If you produced 72 items in September, how many items did you produce in August and September in total? | 648 | 72 72 8 [OP_MUL] [OP_ADD] | var_a = 72
var_b = 72
var_c = 8
var_d = var_b * var_c
var_e = var_a + var_d
print(int(var_e)) |
Arithmetic calculation | The average of 7 numbers is 7. If you take one of these numbers and change it to 9, the average is 8. What was the original number before changing? | 2 | 7 7 [OP_MUL] 7 8 [OP_MUL] 9 [OP_SUB] [OP_SUB] | var_a = 7
var_b = 7
var_c = var_a * var_b
var_d = 7
var_e = 8
var_f = var_d * var_e
var_g = 9
var_h = var_f - var_g
var_i = var_c - var_h
print(int(var_i)) |
Correspondence | While Yoongi was subtracting 57 from the three-digit number, Yoongi mistakenly saw the units digit of the three-digit number 9 as 6. When Yoongi got the result of 819, what is the three-digit number? | 879 | 819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] | var_a = 819
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
print(int(var_g)) |
Arithmetic calculation | The stationery shop sold all 15 bundles of notebooks in 5 days. If each bundle contained 40 notebooks, how many notebooks did you sell on average per day? | 120 | 15 40 [OP_MUL] 5 [OP_FDIV] | var_a = 15
var_b = 40
var_c = var_a * var_b
var_d = 5
var_e = var_c // var_d
print(int(var_e)) |
Arithmetic calculation | When Young-soo held the puppy and weighed it, it was 31 kilograms (kg), and when Ga-young held the same puppy and weighed it, it was 27 kilograms (kg) and 350 grams (g). If the weight of the dog is 1 kilogram (kg) and 400 grams (g), how many kilograms (kg) is the sum of the weights of Youngsoo, Gayoung, and the dog? | 56.95 | 31 27 350 1000 [OP_DIV] [OP_ADD] [OP_ADD] 1 400 1000 [OP_DIV] [OP_ADD] [OP_SUB] | var_a = 31
var_b = 27
var_c = 350
var_d = 1000
var_e = var_c / var_d
var_f = var_b + var_e
var_g = var_a + var_f
var_h = 1
var_i = 400
var_j = 1000
var_k = var_i / var_j
var_l = var_h + var_k
var_m = var_g - var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Arithmetic calculation | The airport is 300 kilometers (km) away from the house. Find the remaining distance after 2 hours when Jinwoo leaves home in a car traveling at 60 kilometers (km) per hour. | 180 | 300 60 2 [OP_MUL] [OP_SUB] | var_a = 300
var_b = 60
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
print(int(var_e)) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the product of the second largest number and the second smallest number? | 143 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_MUL] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g * var_i
print(int(var_j)) |
Correspondence | You need to add 41 to a number, but mistakenly added 14, and got 68. Find the sum of a number and its correctly calculated value. | 149 | 68 14 [OP_SUB] 68 14 [OP_SUB] 41 [OP_ADD] [OP_ADD] | var_a = 68
var_b = 14
var_c = var_a - var_b
var_d = 68
var_e = 14
var_f = var_d - var_e
var_g = 41
var_h = var_f + var_g
var_i = var_c + var_h
print(int(var_i)) |
Correspondence | 14A+2B3=418. How much is A? | 5 | 14A+2B3=418 A [OP_DIGIT_UNK_SOLVER] | var_a = '14A+2B3=418'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Comparison | Find the number of numbers less than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3. | 2 | [OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.3
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.4
list_b = []
for i in list_a:
if i <= var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Geometry | When tossing two different coins, calculate the numbers of cases where both tails come up. | 1 | 1 | var_a = 1
print(int(var_a)) |
Arithmetic calculation | Namjoon rode his bike and traveled 96.967 kilometers (km) in 1.3 hours. If Namjoon went at a steady speed, how many kilometers (km) did he travel in 1 hour? | 74.59 | 96.967 1.3 [OP_DIV] 1 [OP_MUL] | var_a = 96.967
var_b = 1.3
var_c = var_a / var_b
var_d = 1
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | How many three-digit numbers are there in which each digit has only odd numbers less than or equal to 3? | 8 | 0 3 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 0
var_b = 3
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = len(list_b)
print(int(var_d)) |
Comparison | Jimin drank 0.7 liters (L) of juice. Eunji drank 1/10 liter (L) less than Jimin. Yoongi drank 4/5 liters (L), and Yuna drank 0.2 liters (L) more than Jimin. Who drank the most juice? | Yuna | [OP_LIST_SOL] Jimin Eunji Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 0.7 0.7 1 10 [OP_DIV] [OP_SUB] 4 5 [OP_DIV] 0.7 0.2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jimin'
var_b = 'Eunji'
var_c = 'Yoongi'
var_d = 'Yuna'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.7
var_f = 0.7
var_g = 1
var_h = 10
var_i = var_g / var_h
var_j = var_f - var_i
var_k = 4
var_l = 5
var_m = var_k / var_l
var_n = 0.7
var_o = 0.2
var_p = var_n + var_o
list_b= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_q = 1
list_c=list_b.copy()
list_c.sort()
var_r = list_c[-var_q]
var_s = list_b.index(var_r)+1
var_t = list_a[var_s-1]
print(var_t) |
Comparison | Jian has 5,000 won, Doyun has 2,000 won, Harin has 8,000 won, and Joowon has 4,000 won. Who is the 3rd richest person? | Joowon | [OP_LIST_SOL] Jian Doyun Harin Joowon [OP_LIST_EOL] [OP_LIST_SOL] 5000 2000 8000 4000 [OP_LIST_EOL] 3 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jian'
var_b = 'Doyun'
var_c = 'Harin'
var_d = 'Joowon'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 5000
var_f = 2000
var_g = 8000
var_h = 4000
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 3
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | 10 times a number is 17, what is 1/100 times the number? | 0.02 | 17 10 [OP_DIV] 1/100 [OP_MUL] | var_a = 17
var_b = 10
var_c = var_a / var_b
var_d = 0.01
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | Bottles of milk are 18 less than slices of bread, and cookies are 27 more than slices of bread. If there are 58 slices of bread, how many bread, bottles of milk, and cookies are there in total? | 183 | 58 58 18 [OP_SUB] [OP_ADD] 58 27 [OP_ADD] [OP_ADD] | var_a = 58
var_b = 58
var_c = 18
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 58
var_g = 27
var_h = var_f + var_g
var_i = var_e + var_h
print(int(var_i)) |
Arithmetic calculation | A hardware store sells wire for 200 won for 0.1 meter (m). How many meters (m) of wire can you buy with 1200 won? | 0.6 | 1200 200 [OP_DIV] 0.1 [OP_MUL] | var_a = 1200
var_b = 200
var_c = var_a / var_b
var_d = 0.1
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | Yujeong arranged several colored balls on the desk. If the red, blue, yellow, purple and white balls are arranged in this order, what color is the first ball? | red | [OP_LIST_SOL] red blue yellow purple white [OP_LIST_EOL] 1 [OP_LIST_GET] | var_a = 'red'
var_b = 'blue'
var_c = 'yellow'
var_d = 'purple'
var_e = 'white'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
var_g = list_a[var_f-1]
print(var_g) |
Geometry | Find the length in centimeters (cm) of a side of an equilateral triangle with length 9/20 centimeters (cm) and a regular pentagon with the same perimeter. | 0.27 | 9/20 3 [OP_MUL] 5 [OP_DIV] | var_a = 0.45
var_b = 3
var_c = var_a * var_b
var_d = 5
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | You should have divided a certain number by 8, but you mistakenly divided it by 6 and got a quotient of 124 and a remainder of 4. Find the answer to the correct calculation. | 93.5 | 124 6 [OP_MUL] 4 [OP_ADD] 8 [OP_DIV] | var_a = 124
var_b = 6
var_c = var_a * var_b
var_d = 4
var_e = var_c + var_d
var_f = 8
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Correspondence | The number of first-year students attending Woojung High School is 468 less than the number of non-first-year students. If the number of non-first year students is 954, how many students attend Woojung High School? | 1440 | 954 468 [OP_SUB] 954 [OP_ADD] | var_a = 954
var_b = 468
var_c = var_a - var_b
var_d = 954
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are 68 soccer balls, which are 12 less compared to volleyballs and 23 more than basketballs. How many soccer balls, volleyballs, and basketballs are there altogether? | 193 | 68 12 [OP_ADD] 68 23 [OP_SUB] [OP_ADD] 68 [OP_ADD] | var_a = 68
var_b = 12
var_c = var_a + var_b
var_d = 68
var_e = 23
var_f = var_d - var_e
var_g = var_c + var_f
var_h = 68
var_i = var_g + var_h
print(int(var_i)) |
Comparison | Among 1.4, 9/10, 1.2, 0.5, and 13/10, find how many numbers are less than or equal to 1.1. | 2 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i <= var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Possibility | Three out of five digits 0, 1, 2, 3, and 4 were chosen to make a three-digit odd number. If you can use the same number multiple times, how many odd numbers can you make? | 40 | [OP_LIST_SOL] 0 1 2 3 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 2
list_c = []
var_g = int(var_g)
for i in list_b:
i = int(i)
if i % var_g == 0:
list_c.append(i)
list_d = list(set(list_b) - set(list_c))
var_h = len(list_d)
print(int(var_h)) |
Geometry | Consider a rectangle whose long side is 1 meter (m) and whose short side is 2/8 meter (m) shorter than the long side. What is the sum of the lengths of the four sides of this rectangle in meters (m)? | 3.5 | 1 1 2 8 [OP_DIV] [OP_SUB] [OP_ADD] 2 [OP_MUL] | var_a = 1
var_b = 1
var_c = 2
var_d = 8
var_e = var_c / var_d
var_f = var_b - var_e
var_g = var_a + var_f
var_h = 2
var_i = var_g * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Correspondence | A, B, and C are different numbers from 0 to 9. Find C from the subtraction sentence AAA-BB=AC. | 2 | AAA-BB=AC C [OP_DIGIT_UNK_SOLVER] | var_a = 'AAA-BB=AC'
var_b = 'C'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | Woo-gyeong is 9 centimeters (cm) shorter than Eun-mi. If Woo-gyeong's height is 1 meter (m) and 35 centimeters (cm), how many meters (m) is Eun-mi's height expressed as a decimal number? | 1.44 | 1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD] | var_a = 1
var_b = 35
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 9
var_g = 100
var_h = var_f / var_g
var_i = var_e + var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Geometry | You are trying to find the number of vertices of a shape. If this figure is a cube, find the number of vertices. | 8 | 6 2 [OP_SUB] 2 [OP_MUL] | var_a = 6
var_b = 2
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | There are Seoraksan, Jirisan, Hallasan, and Baekdusan. Jirisan is 207 meters (m) higher than Seoraksan. Hallasan is 252 meters (m) higher than Seoraksan. Baekdusan is 839 meters (m) higher than Jirisan. Find the difference in height between Seoraksan and Baekdusan. | 1046 | 207 839 [OP_ADD] | var_a = 207
var_b = 839
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | When A is divided by 9, the quotient is 2 and the remainder is 6. Find out the value of A. | 24 | 9 2 [OP_MUL] 6 [OP_ADD] | var_a = 9
var_b = 2
var_c = var_a * var_b
var_d = 6
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are 17 candies and two pouches with 19 candies. If you divide the candy equally among 9 people, how many can each person get? | 4 | 17 19 [OP_ADD] 9 [OP_FDIV] | var_a = 17
var_b = 19
var_c = var_a + var_b
var_d = 9
var_e = var_c // var_d
print(int(var_e)) |
Possibility | Find the number of ways in which a card numbered 1 through 9 is drawn and multiplied by 21 is greater than 84 multiplied by 2. | 1 | 1 9 1 [OP_LIST_ARANGE] 84 2 [OP_MUL] 21 [OP_DIV] [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 84
var_e = 2
var_f = var_d * var_e
var_g = 21
var_h = var_f / var_g
list_b = []
for i in list_a:
if i > var_h:
list_b.append(i)
var_i = len(list_b)
print(int(var_i)) |
Arithmetic calculation | In the set of even numbers from 600 to 800, find the sum of the digits of all the numbers in the set. | 1508 | 600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM] | var_a = 600
var_b = 800
var_c = 2
list_a = [i for i in range(var_a, var_b + 1, var_c)]
list_b=[]
for i in list_a:
var_d = 0
i = int(i)
while i//10 > 0:
var_d = var_d + i%10
i = i//10
var_d = var_d + i%10
list_b.append(var_d)
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print(int(var_e)) |
Correspondence | When you multiply a number by 6, you get 72. What number do you get when you add 8 to the number? | 20 | 72 6 [OP_DIV] 8 [OP_ADD] | var_a = 72
var_b = 6
var_c = var_a / var_b
var_d = 8
var_e = var_c + var_d
print(int(var_e)) |
Comparison | While Toy (A) is larger than (B), it is smaller than (C). If Toy (B) is bigger than Toy (D) and Toy (C) is smaller than Toy (E), which toy is the biggest? | (E) | [OP_LIST_SOL] (A) (B) (C) (D) (E) [OP_LIST_EOL] [OP_LIST_SOL] (A) (B) > (A) (C) < (B) (D) > (C) (E) < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = '(A)'
var_b = '(B)'
var_c = '(C)'
var_d = '(D)'
var_e = '(E)'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = '(A)'
var_g = '(B)'
var_h = '>'
var_i = '(A)'
var_j = '(C)'
var_k = '<'
var_l = '(B)'
var_m = '(D)'
var_n = '>'
var_o = '(C)'
var_p = '(E)'
var_q = '<'
list_b= []
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_r = 1
var_s = list_c[var_r-1]
print(var_s) |
Geometry | Minyeong has drawn the largest circle that can be drawn inside a square with an area of 400 square centimeters (cm2). If pi is 3.1, how many square centimeters (cm2) is the area of the circle Minyeong drew? | 310 | 3.1 400 1/2 [OP_POW] 2 [OP_DIV] 2 [OP_POW] [OP_MUL] | var_a = 3.1
var_b = 400
var_c = 0.5
var_d = var_b ** var_c
var_e = 2
var_f = var_d / var_e
var_g = 2
var_h = var_f ** var_g
var_i = var_a * var_h
print(int(var_i)) |
Geometry | Make a rectangle out of a wire that is 52 centimeters (cm) long. What is the maximum area of a rectangle that can be made? | 169 | 52 4 [OP_DIV] 2 [OP_POW] | var_a = 52
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
print(int(var_e)) |
Comparison | In Seokjin's classroom, the number of desks in each row, both horizontally and vertically, is placed in a square shape. Seokjin's seat is 3rd from the front, 5th from the back, 4th from the right, and 2nd from the left. How many desks are there in Seokjin's classroom? | 35 | 3 5 [OP_ADD] 1 [OP_SUB] 4 2 [OP_ADD] 1 [OP_SUB] [OP_MUL] | var_a = 3
var_b = 5
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 4
var_g = 2
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
print(int(var_k)) |
Correspondence | The multiplication of the five-digit number ABCDE and 3 is 111111. Find the sum of A, B, C, D, and E. | 20 | 111111 3 [OP_DIV] [OP_NUM2LIST] [OP_LIST_SUM] | var_a = 111111
var_b = 3
var_c = var_a / var_b
list_a = []
var_c = int(var_c)
while var_c//10 > 0:
list_a.append(var_c%10)
var_c = var_c//10
list_a.append(var_c%10)
list_a = list_a[::-1]
list_a = [float(i) for i in list_a]
var_d = sum(list_a)
print(int(var_d)) |
Arithmetic calculation | Which of the five-digit numbers is the greatest common multiple of 9, 6, and 2? | 99990 | 10000 99999 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] 6 [OP_LIST_DIVISIBLE] 2 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 10000
var_b = 99999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 9
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 6
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 2
list_d = []
var_f = int(var_f)
for i in list_c:
i = int(i)
if i % var_f == 0:
list_d.append(i)
var_g = 1
list_e=list_d.copy()
list_e.sort()
var_h = list_e[-var_g]
print(int(var_h)) |
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