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Arithmetic calculation | Find the multiples of 3 of the numbers whose hundreds are 7 and whose ones are 3. How many numbers are there? | 3 | [OP_LIST_SOL] 7 A 3 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 3 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 7
var_b = 'A'
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
ans_dict = dict()
var_d = str(var_d)
list_b = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_d) == len(str(int(temp))):
new_elem = int(temp)
list_b.append(new_elem)
var_e = 3
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Correspondence | Adding 305 to a number and then dividing it by 16 results in 31. Find the number. | 191 | 31 16 [OP_MUL] 305 [OP_SUB] | var_a = 31
var_b = 16
var_c = var_a * var_b
var_d = 305
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | When you divide a certain number by 10, you get 6. Find the result of subtracting 15 from the number. | 45 | 6 10 [OP_MUL] 15 [OP_SUB] | var_a = 6
var_b = 10
var_c = var_a * var_b
var_d = 15
var_e = var_c - var_d
print(int(var_e)) |
Comparison | Hanbyul and Seulgi run around the park. During the same period, Hanbyul ran 1/100 of 10.2 kilometers (km), and Seulgi ran 100 meters (m). Who ran more? | Hanbyul | [OP_LIST_SOL] Hanbyul Seulgi [OP_LIST_EOL] [OP_LIST_SOL] 10.2 1000 [OP_MUL] 100 [OP_DIV] 100 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Hanbyul'
var_b = 'Seulgi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 10.2
var_d = 1000
var_e = var_c * var_d
var_f = 100
var_g = var_e / var_f
var_h = 100
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | There is a dice with one edge 20 centimeters (cm) long. Find the surface area of this dice. | 2400 | 20 2 [OP_POW] 6 [OP_MUL] | var_a = 20
var_b = 2
var_c = var_a ** var_b
var_d = 6
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | Among the numbers of 2.8, 2.3, 5, and 4.3, find the product of the smallest number and the largest number. | 11.5 | [OP_LIST_SOL] 2.8 2.3 5 4.3 [OP_LIST_EOL] 1 [OP_LIST_MIN] 1 [OP_LIST_MAX] [OP_MUL] | var_a = 2.8
var_b = 2.3
var_c = 5
var_d = 4.3
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 1
list_b=list_a.copy()
list_b.sort()
var_f = list_b[var_e-1]
var_g = 1
list_c=list_a.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = var_f * var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Geometry | You want to paint each face of the pentagonal prism with a different color. How many people do you need if each person paints one side? | 7 | 2 5 [OP_ADD] | var_a = 2
var_b = 5
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | Yoongi wants to subtract 57 from a four-digit number. Yoongi has mistaken 9 for 6 in the unit place of a four-digit number. When the difference Yoongi gets is 1819, find the correct result. | 1822 | 1819 57 [OP_ADD] 6 9 [OP_SUB] [OP_SUB] 57 [OP_SUB] | var_a = 1819
var_b = 57
var_c = var_a + var_b
var_d = 6
var_e = 9
var_f = var_d - var_e
var_g = var_c - var_f
var_h = 57
var_i = var_g - var_h
print(int(var_i)) |
Possibility | I'm trying to seat three second-graders and two first-graders on five chairs in a row. Find the case where two first-graders are seated consecutively. | 48 | [OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] C D [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'C'
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_g = len(list_c)
var_h = len(list_c)
var_i = 1
var_g = int(var_g)
var_h = int(var_h)
for i, elem in enumerate(range(var_h)):
var_i = var_i * (var_g-i)
var_j = 'C'
var_k = 'D'
list_d= []
if "/" in str(var_k):
var_k = eval(str(var_k))
list_d.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_d.append(var_j)
list_d.reverse()
var_l = len(list_d)
var_m = len(list_d)
var_n = 1
var_l = int(var_l)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
var_n = var_n * (var_l-i)
var_o = var_i * var_n
print(int(var_o)) |
Possibility | Make a four-digit number by using the number cards from 0 to 9 once. Find the difference between the 2nd largest number and the 2nd smallest number. | 8851 | 0 9 1 [OP_LIST_ARANGE] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS] | var_a = 0
var_b = 9
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 2
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 2
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
var_j = abs(var_i)
print(int(var_j)) |
Geometry | How many faces of a regular octahedron meet at one vertex? | 4 | 4 | var_a = 4
print(int(var_a)) |
Geometry | If all eight sides of a figure are the same in length and the perimeter of the figure is 23.6 centimeters (cm), what is the length of one side in cm (cm)? | 2.95 | 23.6 8 [OP_DIV] | var_a = 23.6
var_b = 8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | You sold 1249 candies on Day 1. On Day 2, you sold 328 more candies than Day 1. On day 3, you sold 275 more candies than Day 2, leaving 367 left. How many candies were there at the beginning? | 5045 | 367 1249 [OP_ADD] 1249 328 [OP_ADD] [OP_ADD] 1249 328 [OP_ADD] 275 [OP_ADD] [OP_ADD] | var_a = 367
var_b = 1249
var_c = var_a + var_b
var_d = 1249
var_e = 328
var_f = var_d + var_e
var_g = var_c + var_f
var_h = 1249
var_i = 328
var_j = var_h + var_i
var_k = 275
var_l = var_j + var_k
var_m = var_g + var_l
print(int(var_m)) |
Arithmetic calculation | Taehyung's uncle is 17 years older than Taehyung. Four years later, the sum of Taehyung's age and his uncle's age is 43 years old. How old is Taehyung this year? | 9 | 43 4 2 [OP_MUL] [OP_SUB] 17 [OP_SUB] 2 [OP_DIV] | var_a = 43
var_b = 4
var_c = 2
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 17
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | Heeju's school has 500 students. Among them, 289 students like ramen and 337 students like bread. If there are 56 students who do not like both ramen and bread, find how many students like both ramen and bread. | 182 | 289 337 [OP_ADD] 500 56 [OP_SUB] [OP_SUB] | var_a = 289
var_b = 337
var_c = var_a + var_b
var_d = 500
var_e = 56
var_f = var_d - var_e
var_g = var_c - var_f
print(int(var_g)) |
Arithmetic calculation | There are 19 tangerines and some persimmons in the basket. How many persimmons are there if the total number of tangerines and persimmons is 37 in the basket? | 18 | 37 19 [OP_SUB] | var_a = 37
var_b = 19
var_c = var_a - var_b
print(int(var_c)) |
Correspondence | Some trees lose 1 meter (m) of growth each year. If a tree's full growth is 91 meters (m), find the length the tree grew in the first year. | 13 | 91 2 [OP_MUL] 1/2 [OP_POW] 1 [OP_FLOOR] | var_a = 91
var_b = 2
var_c = var_a * var_b
var_d = 0.5
var_e = var_c ** var_d
var_f = 1
var_g=int((var_e//(10**(var_f-1)))*10**(var_f-1))
print(int(var_g)) |
Arithmetic calculation | If you put 12 apples in a box, you get 55 boxes. If you put 15 apples in each box, how many boxes will there be? | 44 | 12 55 [OP_MUL] 15 [OP_DIV] 1 [OP_CEIL] | var_a = 12
var_b = 55
var_c = var_a * var_b
var_d = 15
var_e = var_c / var_d
var_f = 1
var_g=int(((var_e+9*10**(var_f-2))//(10**(var_f-1)))*10**(var_f-1))
print(int(var_g)) |
Geometry | How many faces are there in the pentahedron? | 5 | 5 | var_a = 5
print(int(var_a)) |
Arithmetic calculation | If you put 18 candies in each of the 5 boxes, there is a shortage of 3 candies. If you put the equal amount of candies into 6 boxes, what is the maximum number of candies in one box? | 15 | 5 18 [OP_MUL] 3 [OP_ADD] 6 [OP_FDIV] | var_a = 5
var_b = 18
var_c = var_a * var_b
var_d = 3
var_e = var_c + var_d
var_f = 6
var_g = var_e // var_f
print(int(var_g)) |
Correspondence | There is the expression 691-6A7=4. Find the number that goes into A | 8 | 691-6A7=4 A [OP_DIGIT_UNK_SOLVER] | var_a = '691-6A7=4'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | You want to cut a loaf of bread that is 150 centimeters (cm) long by 1.5 centimeters (cm). How many pieces can be cut? | 100 | 150 1.5 [OP_DIV] | var_a = 150
var_b = 1.5
var_c = var_a / var_b
print(int(var_c)) |
Possibility | There is a calculator that only works with four buttons: 2, 3, 7, and 9. When making a four-digit number on the calculator by pressing the button without duplication, find the second largest number that can be made. | 9723 | [OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] | var_a = 2
var_b = 3
var_c = 7
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 2
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
print(int(var_g)) |
Comparison | There are five numbers 1.4, 9/10, 1.1, 0.5, and 13/10. How many of these numbers are greater than 0.9? | 3 | [OP_LIST_SOL] 1.4 9/10 1.1 0.5 13/10 [OP_LIST_EOL] 0.9 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.1
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 0.9
list_b = []
for i in list_a:
if i > var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Arithmetic calculation | You want to share 1/6 of 16 kilograms (kg) peanuts with your friends. If one person eats 4/15 kilograms (kg), how many people can eat? | 10 | 16 6 [OP_DIV] 4/15 [OP_DIV] | var_a = 16
var_b = 6
var_c = var_a / var_b
var_d = 0.26666666666666666
var_e = var_c / var_d
print(int(var_e)) |
Possibility | Each box contains 3 balls. If you have 2 boxes, what is the total number of balls? | 6 | 3 2 [OP_MUL] | var_a = 3
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Geometry | How many pairs of parallel faces are there in a cube? | 3 | 6 2 [OP_DIV] | var_a = 6
var_b = 2
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | It is said that 140 U.S. dollars can be exchanged for 158,760 Korean won. What is the exchange rate of Korean money to the United States' money? | 1134 | 158760 140 [OP_DIV] | var_a = 158760
var_b = 140
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | 3 years ago, the sum of the ages of the mother and son was 49, and this year, when the mother is 4 times the age of the son, how old is the son this year? | 11 | 49 3 2 [OP_MUL] [OP_ADD] 1 4 [OP_ADD] [OP_DIV] | var_a = 49
var_b = 3
var_c = 2
var_d = var_b * var_c
var_e = var_a + var_d
var_f = 1
var_g = 4
var_h = var_f + var_g
var_i = var_e / var_h
print(int(var_i)) |
Geometry | If the length of one radius of a circle is 2, what is the length of the other radius? | 2 | 2 | var_a = 2
print(int(var_a)) |
Arithmetic calculation | Find the value of the smaller number when the difference between the two numbers is 28 and the larger number plus 13 is twice the smaller number plus 13. | 15 | 13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB] | var_a = 13
var_b = 28
var_c = 13
var_d = var_b - var_c
var_e = 2
var_f = var_d * var_e
var_g = var_a + var_f
var_h = 2
var_i = 1
var_j = var_h - var_i
var_k = var_g / var_j
var_l = 28
var_m = var_k - var_l
print(int(var_m)) |
Geometry | You have a piece of paper in the shape of a triangle with an area of 46 square centimeters (cm2). If the base is 10 centimeters (cm), what is its height in centimeters (cm)? | 9.2 | 46 2 [OP_MUL] 10 [OP_DIV] | var_a = 46
var_b = 2
var_c = var_a * var_b
var_d = 10
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | At one Wang mathematical academy, 120 students took the A Mathematical Education Evaluation. If there were 36 more students who received certificates than those who did not receive certificates, how many students received certificates? | 78 | 120 36 [OP_SUB] 2 [OP_DIV] 36 [OP_ADD] | var_a = 120
var_b = 36
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 36
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | You want to install flower beds at intervals of 6.4 meters (m) along the wall of a school whose length is 268.8 meters (m). How many flower beds would be needed if flower beds are also installed at the both ends of the school walls? | 43 | 268.8 6.4 [OP_DIV] 1 [OP_ADD] | var_a = 268.8
var_b = 6.4
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | There are 28 erasers in total. Among them, Yeonju received 1/4 of the eraser and Minji received 3/7 of them. What is the number of remaining erasers? | 9 | 28 1 1/4 [OP_SUB] 3/7 [OP_SUB] [OP_MUL] | var_a = 28
var_b = 1
var_c = 0.25
var_d = var_b - var_c
var_e = 0.42857142857142855
var_f = var_d - var_e
var_g = var_a * var_f
print(int(var_g)) |
Comparison | Kyungsoo's group of students did the long jump. When Kyungsoo jumped 2.3 meters (m), Younghee jumped 9/10 meters (m), Jinju jumped 1.8 meters (m), and Chanho jumped 2.5 meters (m), who came second? | Kyungsoo | [OP_LIST_SOL] Kyungsoo Younghee Jinju Chanho [OP_LIST_EOL] [OP_LIST_SOL] 2.3 9/10 1.8 2.5 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Kyungsoo'
var_b = 'Younghee'
var_c = 'Jinju'
var_d = 'Chanho'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2.3
var_f = 0.9
var_g = 1.8
var_h = 2.5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 2
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | If we divide this value by 2.5 and take away 10.5 and then multiply it by 0.3, we get 5.85. What is this number? | 75 | 5.85 0.3 [OP_DIV] 10.5 [OP_ADD] 2.5 [OP_MUL] | var_a = 5.85
var_b = 0.3
var_c = var_a / var_b
var_d = 10.5
var_e = var_c + var_d
var_f = 2.5
var_g = var_e * var_f
print(int(var_g)) |
Correspondence | What single digit number must be placed in A to make the equation 61A+B3=645? | 2 | 61A+B3=645 A [OP_DIGIT_UNK_SOLVER] | var_a = '61A+B3=645'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | There is a parallelogram that has a base of 3.6 and a height of 2.5 times the base. Find the area of this parallelogram. | 32.4 | 3.6 3.6 2.5 [OP_MUL] [OP_MUL] | var_a = 3.6
var_b = 3.6
var_c = 2.5
var_d = var_b * var_c
var_e = var_a * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | You want to create a two-digit number by drawing two different numbers from 7, 4, 0, 3, and 5. Find the difference between the third largest number and the third smallest number. | 38 | [OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS] | var_a = 7
var_b = 4
var_c = 0
var_d = 3
var_e = 5
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 3
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 3
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h - var_j
var_l = abs(var_k)
print(int(var_l)) |
Comparison | There are 108 marbles of red marbles, blue marbles and white marbles. The number of blue marbles is 1/3 of the red marbles and the number of white marbles is 1/2 of the blue marbles. Which color has the least number of marbles? | white | [OP_LIST_SOL] red blue white [OP_LIST_EOL] [OP_LIST_SOL] 1 1/3 1/3 1/2 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'red'
var_b = 'blue'
var_c = 'white'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
var_e = 0.3333333333333333
var_f = 0.3333333333333333
var_g = 0.5
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | A rectangle 6 centimetres (cm) wide, 5 centimetres (cm) long and 4 centimetres (cm) high has been painted green on all sides. This rectangle is cut into 120 cubes, each 1 centimetre (cm) long. How many of the cubes have no coloured faces? | 24 | 6 2 [OP_SUB] 5 2 [OP_SUB] [OP_MUL] 4 2 [OP_SUB] [OP_MUL] | var_a = 6
var_b = 2
var_c = var_a - var_b
var_d = 5
var_e = 2
var_f = var_d - var_e
var_g = var_c * var_f
var_h = 4
var_i = 2
var_j = var_h - var_i
var_k = var_g * var_j
print(int(var_k)) |
Geometry | How many meters (m) is the width of Jeong Su's field if it is a rectangle with an area of 143.2 square meters (m2) and the length of this field is 4 meters (m)? | 35.8 | 143.2 4 [OP_DIV] | var_a = 143.2
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | A number multiplied by 8. 64 was added to the multiplied result. If the result of the calculation is 336, what is the number? | 34 | 336 64 [OP_SUB] 8 [OP_DIV] | var_a = 336
var_b = 64
var_c = var_a - var_b
var_d = 8
var_e = var_c / var_d
print(int(var_e)) |
Comparison | There are three numbers A, B and C. A is 38 greater than 18. B is 26 less than A. C is the quotient of B divided by 3. Which number is the smallest? | C | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 18 38 [OP_ADD] 18 38 [OP_ADD] 26 [OP_SUB] 18 38 [OP_ADD] 26 [OP_SUB] 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 18
var_e = 38
var_f = var_d + var_e
var_g = 18
var_h = 38
var_i = var_g + var_h
var_j = 26
var_k = var_i - var_j
var_l = 18
var_m = 38
var_n = var_l + var_m
var_o = 26
var_p = var_n - var_o
var_q = 3
var_r = var_p / var_q
list_b= []
if "/" in str(var_r):
var_r = eval(str(var_r))
list_b.append(var_r)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_s = 1
list_c=list_b.copy()
list_c.sort()
var_t = list_c[var_s-1]
var_u = list_b.index(var_t)+1
var_v = list_a[var_u-1]
print(var_v) |
Geometry | If the coin's radius is 7 centimeters (cm), how many centimeters (cm) is the coin's diameter? | 14 | 7 2 [OP_MUL] | var_a = 7
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Geometry | He painted all the faces of a cube with an edge of 3 cm (cm) red. Then he cut this cube into 27 small cubes, each 1 cm (cm) long. How many of the small cubes have 3 faces painted red? | 8 | 8 | var_a = 8
print(int(var_a)) |
Possibility | Seokjin, Taehyung, Namjoon, Yoojeong, and Yuna are standing in line to checkout. At this time, how many ways are there to line up so that the order of payment differs? | 120 | [OP_LIST_SOL] Seokjin Taehyung Namjoon Yoojeong Yuna [OP_LIST_EOL] [OP_LIST_LEN] 5 [OP_PERM] | var_a = 'Seokjin'
var_b = 'Taehyung'
var_c = 'Namjoon'
var_d = 'Yoojeong'
var_e = 'Yuna'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 5
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
print(int(var_h)) |
Comparison | Horses, cows, pigs, sheep, rabbits, and squirrels entered the pen in this order. Which animal took 4th place? | sheep | [OP_LIST_SOL] Horses cows pigs sheep rabbits squirrels [OP_LIST_EOL] 4 [OP_LIST_GET] | var_a = 'Horses'
var_b = 'cows'
var_c = 'pigs'
var_d = 'sheep'
var_e = 'rabbits'
var_f = 'squirrels'
list_a= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 4
var_h = list_a[var_g-1]
print(var_h) |
Possibility | How many two-digit numbers can be made using two of the number cards 1, 2, and 7? | 6 | [OP_LIST_SOL] 1 2 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 1
var_b = 2
var_c = 7
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Geometry | In one exhibition hall, there was not enough space to hang the work, so we decided to install a temporary wall. If the width of this wall is 5.4 meters (m) and the length is 2.5 meters (m), how many square meters (m2) will the area be? | 13.5 | 5.4 2.5 [OP_MUL] | var_a = 5.4
var_b = 2.5
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | There is a box A that is 3 centimeters (cm) high and box B with 3.5 centimeters (cm) high. Taehyung stacked the boxes A and Yoongi stacked the boxes B. If Taehyung and Yoongi each stacked the boxes up to 16th and 14th floors, respectively, find out who stacked the boxes higher. | Yoongi | [OP_LIST_SOL] Taehyung Yoongi [OP_LIST_EOL] [OP_LIST_SOL] 3 16 [OP_MUL] 3.5 14 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Taehyung'
var_b = 'Yoongi'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 3
var_d = 16
var_e = var_c * var_d
var_f = 3.5
var_g = 14
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | Yoongi is going to multiply a number by 7. But when he accidentally added 9, the result was 30. Find the correct calculation result. | 147 | 30 9 [OP_SUB] 7 [OP_MUL] | var_a = 30
var_b = 9
var_c = var_a - var_b
var_d = 7
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | It took Minsu 10 days to complete 2/9 of the job. Find how many days it will take to complete 2/5 of the work. | 18 | 10 2/9 [OP_DIV] 2/5 [OP_MUL] | var_a = 10
var_b = 0.2222222222222222
var_c = var_a / var_b
var_d = 0.4
var_e = var_c * var_d
print(int(var_e)) |
Possibility | You want to create a two-digit number by drawing two different numbers from 7, 4, 0, 3, and 5. Find the product of the third largest number and the third smallest number. | 2555 | [OP_LIST_SOL] 7 4 0 3 5 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 3 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_MUL] | var_a = 7
var_b = 4
var_c = 0
var_d = 3
var_e = 5
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 3
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 3
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h * var_j
print(int(var_k)) |
Correspondence | A number multiplied by 6 and divided by 1.5 equals 3.8. Find a number. | 0.95 | 3.8 1.5 [OP_MUL] 6 [OP_DIV] | var_a = 3.8
var_b = 1.5
var_c = var_a * var_b
var_d = 6
var_e = var_c / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | The seven digits 0, 1, 2, 3, 4, 5, and 6 are used once to form a seven-digit number. If this number is a multiple of 55, find the third smallest of this number. | 1062435 | [OP_LIST_SOL] 0 1 2 3 4 5 6 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 55 [OP_LIST_DIVISIBLE] 3 [OP_LIST_MIN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
var_g = 6
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 7
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_h))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_i = 55
list_c = []
var_i = int(var_i)
for i in list_b:
i = int(i)
if i % var_i == 0:
list_c.append(i)
var_j = 3
list_d=list_c.copy()
list_d.sort()
var_k = list_d[var_j-1]
print(int(var_k)) |
Geometry | What is the length of the radius of the circumcircle of a right triangle with sides 10 centimeters (cm), 8 centimeters (cm), and 6 centimeters (cm), respectively? | 5 | 10 2 [OP_DIV] | var_a = 10
var_b = 2
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | As Yoojung gave 7 candies to her older sister and 6 to her younger sister, there were 15 left on hand. Find number of candies Yoojung had at first. | 28 | 15 6 [OP_ADD] 7 [OP_ADD] | var_a = 15
var_b = 6
var_c = var_a + var_b
var_d = 7
var_e = var_c + var_d
print(int(var_e)) |
Comparison | A pumpkin weighs 2 kilograms (kg) and 9/10 kilograms (kg), and a watermelon weighs 41/10 kilograms (kg). Which is heavier, pumpkin or watermelon? | watermelon | [OP_LIST_SOL] pumpkin watermelon [OP_LIST_EOL] [OP_LIST_SOL] 2 9 10 [OP_DIV] [OP_ADD] 41 10 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'pumpkin'
var_b = 'watermelon'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
var_d = 9
var_e = 10
var_f = var_d / var_e
var_g = var_c + var_f
var_h = 41
var_i = 10
var_j = var_h / var_i
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n) |
Arithmetic calculation | Sangheon is 1.56 meters (m) tall. Chiho is 0.14 meters (m) shorter than Sangheon, and Nara is 0.27 meters (m) taller than Chiho. How tall is Nara in meters (m)? | 1.69 | 1.56 0.14 [OP_SUB] 0.27 [OP_ADD] | var_a = 1.56
var_b = 0.14
var_c = var_a - var_b
var_d = 0.27
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | Subtract 29 from this number and add 64 to get 76. Find the number. | 41 | 76 64 [OP_SUB] 29 [OP_ADD] | var_a = 76
var_b = 64
var_c = var_a - var_b
var_d = 29
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Jungkook collected 6 plus 3 points, Yoongi collected 4 points, and Yuna collected 5 points. Who has the smallest number? | Yoongi | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_ADD] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d + var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | A and B are different single-digit numbers. Find the value of A+B that correspond to the following multiplication equation AB×6=BBB. | 11 | AB×6=BBB A [OP_DIGIT_UNK_SOLVER] AB×6=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = 'AB×6=BBB'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = 'AB×6=BBB'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Geometry | There is a farm in the shape of a rectangle with a length of 3.6 kilometers (km) and a width 2.5 times its length. If half of this farm is for cattle and half is for pigs, find the area of the cattle area in square kilometers (km2). | 16.2 | 3.6 3.6 2.5 [OP_MUL] [OP_MUL] 2 [OP_DIV] | var_a = 3.6
var_b = 3.6
var_c = 2.5
var_d = var_b * var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Comparison | Minhyun drank 0.41 times more milk than 6 liters (L) and Jinyoung drank 2.3 liters (L). Who has drunk more milk? | Minhyun | [OP_LIST_SOL] Minhyun Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 0.41 [OP_MUL] 2.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Minhyun'
var_b = 'Jinyoung'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 6
var_d = 0.41
var_e = var_c * var_d
var_f = 2.3
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Arithmetic calculation | 1250 people participated in a marathon. If there were 124 more people who gave up during running than finished people, how many people finished? | 563 | 1250 124 [OP_SUB] 2 [OP_DIV] | var_a = 1250
var_b = 124
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | There are 6 students playing (a) sports, and the number of students playing (b) sports is 4 times the number of students playing (a) sports. How many students do (b) sports? | 24 | 6 4 [OP_MUL] | var_a = 6
var_b = 4
var_c = var_a * var_b
print(int(var_c)) |
Arithmetic calculation | Among the numbers from 1 to 15, only odd numbers were selected and arranged in ascending order from left to right. Find the sum of the second number from the right and the second number from the left. | 16 | 1 15 [OP_LIST_ODD] 2 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD] | var_a = 1
var_b = 15
list_a = []
if var_a%2==0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 2
list_b=list_a.copy()
list_b.sort()
var_d = list_b[-var_c]
var_e = 2
list_c=list_a.copy()
list_c.sort()
var_f = list_c[var_e-1]
var_g = var_d + var_f
print(int(var_g)) |
Geometry | There is a pyramid whose base side is a dodecagon. How many faces does this pyramid have? | 13 | 12 1 [OP_ADD] | var_a = 12
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Comparison | There are 16 of Hoseok and his friends. How many friends are to Hoseok's left when there are 8 friends to Hoseok's right? | 7 | 16 8 [OP_SUB] 1 [OP_SUB] | var_a = 16
var_b = 8
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | What is the largest three-digit number that is a multiple of 4 and a multiple of 5? | 980 | 100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 100
var_b = 999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[-var_f]
print(int(var_g)) |
Arithmetic calculation | Five watermelons that weigh 1050 grams (g) each were placed on one side of a pan balance scale. Two of nine apples of equal weight, each weighing 4.5 kilograms (kg), were placed on the opposite side of that scale. How many more melons weighing 850 grams (g) each must be placed on the side of the apples to level the scale? | 5 | 1050 5 [OP_MUL] 4.5 1000 [OP_MUL] 9 [OP_DIV] 2 [OP_MUL] [OP_SUB] 850 [OP_DIV] | var_a = 1050
var_b = 5
var_c = var_a * var_b
var_d = 4.5
var_e = 1000
var_f = var_d * var_e
var_g = 9
var_h = var_f / var_g
var_i = 2
var_j = var_h * var_i
var_k = var_c - var_j
var_l = 850
var_m = var_k / var_l
print(int(var_m)) |
Comparison | Minyoung crossed the finish line in 33rd place in the running race, and Eunji crossed the finish line before Minyoung while there are 11 people between them. What is Eunji's rank? | 21 | 33 11 [OP_SUB] 1 [OP_SUB] | var_a = 33
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Possibility | When choosing three numbers from 0, 2, 4, and 6 to make a three-digit number, find the sum of all the possible three-digit numbers. | 7728 | [OP_LIST_SOL] 0 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_SUM] | var_a = 0
var_b = 2
var_c = 4
var_d = 6
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print(int(var_f)) |
Arithmetic calculation | There are 1 to 25 buildings in Jungkook's apartment complex, and each building has up to 10 floors. If there are 8 households on each floor, how many households can live in Jungkook's apartment complex? | 2000 | 25 10 [OP_MUL] 8 [OP_MUL] | var_a = 25
var_b = 10
var_c = var_a * var_b
var_d = 8
var_e = var_c * var_d
print(int(var_e)) |
Arithmetic calculation | Find the smallest number of natural numbers in excess of 12. | 13 | 12 1 [OP_ADD] 999 1 [OP_LIST_ARANGE] 1 [OP_LIST_MIN] | var_a = 12
var_b = 1
var_c = var_a + var_b
var_d = 999
var_e = 1
list_a = [i for i in range(var_c, var_d + 1, var_e)]
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
print(int(var_g)) |
Arithmetic calculation | Minjeong's family drinks 0.2 liters (L) of juices three times every day. How many liters (L) of juice does Minjeong's family drink in a week? | 4.2 | 0.2 3 [OP_MUL] 7 [OP_MUL] | var_a = 0.2
var_b = 3
var_c = var_a * var_b
var_d = 7
var_e = var_c * var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | 32 students of different heights are lined up in order from tallest to shortest. Jimin stands 27th from the front, and Yuna stands 11th from the front. How many students are standing between Jimin and Yuna? | 15 | 27 11 [OP_SUB] 1 [OP_SUB] | var_a = 27
var_b = 11
var_c = var_a - var_b
var_d = 1
var_e = var_c - var_d
print(int(var_e)) |
Comparison | There are four numbers: 0.8, 1/2, 0.9, 1/3. What is the sum of numbers less than 3? | 2.53 | [OP_LIST_SOL] 0.8 1/2 0.9 1/3 [OP_LIST_EOL] 3 [OP_LIST_LESS] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.9
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = []
for i in list_a:
if i < var_e:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | Express the decimal value when 22 is divided by 8 without remainder. | 2.75 | 22 8 [OP_DIV] | var_a = 22
var_b = 8
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | When 21 is divided by A, the quotient becomes B and the remainder 5. A and B are natural numbers. What is the smallest number out of all possible Bs? | 1 | 1 | var_a = 1
print(int(var_a)) |
Possibility | The supermarket sells carrots, pears, and cucumbers, but Youngbin only has enough money to buy two kinds. How many cases can Youngbin buy? | 3 | [OP_LIST_SOL] carrots cucumbers pears [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_COMB] | var_a = 'carrots'
var_b = 'cucumbers'
var_c = 'pears'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = 1
var_d = int(var_d)
var_e = int(var_e)
for i, elem in enumerate(range(var_e)):
var_f = var_f * (var_d-i)
for i, elem in enumerate(range(var_e)):
var_f = var_f / (i+1)
print(int(var_f)) |
Possibility | Using all single-digit whole numbers greater than 6 once, find the sum of the largest three-digit number and the third largest three-digit number. | 1884 | 6 1 [OP_ADD] 9 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD] | var_a = 6
var_b = 1
var_c = var_a + var_b
var_d = 9
var_e = 1
list_a = [i for i in range(var_c, var_d + 1, var_e)]
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 3
list_d=list_b.copy()
list_d.sort()
var_j = list_d[-var_i]
var_k = var_h + var_j
print(int(var_k)) |
Arithmetic calculation | Yeonjeong and Donghun rode bicycles on a lake with a circumference of 3 kilometers (km) and started at the same time in opposite directions from the same place. Yeonjeong rides at a speed of 100 meters (m) per minute, and Donghun rides a bicycle at a speed of 150 meters (m) per minute. Find how many minutes later the two meet again for the first time. | 12 | 3 100 1000 [OP_DIV] 150 1000 [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 3
var_b = 100
var_c = 1000
var_d = var_b / var_c
var_e = 150
var_f = 1000
var_g = var_e / var_f
var_h = var_d + var_g
var_i = var_a / var_h
print(int(var_i)) |
Correspondence | 123 is the result of adding 84 by mistake instead of 48 to a number. Find the number. | 39 | 123 84 [OP_SUB] | var_a = 123
var_b = 84
var_c = var_a - var_b
print(int(var_c)) |
Arithmetic calculation | There are 2 straps of different lengths. The sum of the lengths of the two straps is 64 centimeters (cm), and the longer strap is 48 centimeters (cm) longer than the shorter strap. Find how many pieces of strap that equal the length of the shorter strap can be cut from the longer strap. | 7 | 64 48 [OP_SUB] 2 [OP_DIV] 48 [OP_ADD] 64 48 [OP_SUB] 2 [OP_DIV] [OP_DIV] | var_a = 64
var_b = 48
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 48
var_g = var_e + var_f
var_h = 64
var_i = 48
var_j = var_h - var_i
var_k = 2
var_l = var_j / var_k
var_m = var_g / var_l
print(int(var_m)) |
Comparison | To fill the fishbowl with water, you need to pour water 7 times with the A bowl, 8 times with the B bowl, and 5 times with the C bowl. Which bowl has the largest capacity? | C | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 1 7 [OP_DIV] 1 8 [OP_DIV] 1 5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
var_e = 7
var_f = var_d / var_e
var_g = 1
var_h = 8
var_i = var_g / var_h
var_j = 1
var_k = 5
var_l = var_j / var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[-var_m]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Correspondence | A number divided by 9 is 8. Yoongi added 11 to the number. How much is this value? | 83 | 8 9 [OP_MUL] 11 [OP_ADD] | var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 11
var_e = var_c + var_d
print(int(var_e)) |
Possibility | Find the difference between the largest and smallest three-digit numbers that can be formed by using the three number cards 6, 3, and 8 only once. | 495 | [OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 6
var_b = 3
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = 1
list_d=list_b.copy()
list_d.sort()
var_h = list_d[var_g-1]
var_i = var_f - var_h
print(int(var_i)) |
Arithmetic calculation | What is the sum of the two numbers 1/6 and 5/12? | 0.58 | 1/6 5/12 [OP_ADD] | var_a = 0.16666666666666666
var_b = 0.4166666666666667
var_c = var_a + var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | The sum of 25 consecutive even numbers is 750. Write the smallest even number among these. | 6 | 750 25 [OP_DIV] 25 2 [OP_FDIV] 2 [OP_MUL] [OP_SUB] | var_a = 750
var_b = 25
var_c = var_a / var_b
var_d = 25
var_e = 2
var_f = var_d // var_e
var_g = 2
var_h = var_f * var_g
var_i = var_c - var_h
print(int(var_i)) |
Correspondence | Subtracting 16 from a certain number is divisible by 37, and the quotient is 23. Find what the number is that. | 867 | 23 37 [OP_MUL] 16 [OP_ADD] | var_a = 23
var_b = 37
var_c = var_a * var_b
var_d = 16
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | Jimin wanted to subtract by a number from 34 but instead added the number to 20 to get 60. Find the correctly calculated value. | -6 | 34 60 20 [OP_SUB] [OP_SUB] | var_a = 34
var_b = 60
var_c = 20
var_d = var_b - var_c
var_e = var_a - var_d
print(int(var_e)) |
Geometry | A cube has a volume of 2744 cubic centimeters (cm3). If you divide the area of the base of this cube by the height, what is the quotient? | 14 | 2744 1/3 [OP_POW] | var_a = 2744
var_b = 0.3333333333333333
var_c = var_a ** var_b
print(int(eval('{:.2f}'.format(round(var_c+1e-10,2))))) |
Arithmetic calculation | Find the sum of even numbers from 1 to 100. | 2550 | 1 100 [OP_LIST_EVEN] [OP_LIST_SUM] | var_a = 1
var_b = 100
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
list_a = [float(i) for i in list_a]
var_c = sum(list_a)
print(int(var_c)) |
Possibility | Sunwoo is playing a game of making the smallest number using all the number cards he has. If Sunwoo has cards with 2 and 4 written on them, what number should he make? | 24 | [OP_LIST_SOL] 2 4 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] | var_a = 2
var_b = 4
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = 1
list_c=list_b.copy()
list_c.sort()
var_e = list_c[var_d-1]
print(int(var_e)) |
Possibility | You want to choose 15 out of 4 types of fruits. Calculate the total number of choices of fruit, if you choose two or more of each fruit. | 120 | 4 15 [OP_ADD] 4 2 [OP_MUL] [OP_SUB] 1 [OP_SUB] 15 4 2 [OP_MUL] [OP_SUB] [OP_COMB] | var_a = 4
var_b = 15
var_c = var_a + var_b
var_d = 4
var_e = 2
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 1
var_i = var_g - var_h
var_j = 15
var_k = 4
var_l = 2
var_m = var_k * var_l
var_n = var_j - var_m
var_o = 1
var_i = int(var_i)
var_n = int(var_n)
for i, elem in enumerate(range(var_n)):
var_o = var_o * (var_i-i)
for i, elem in enumerate(range(var_n)):
var_o = var_o / (i+1)
print(int(var_o)) |
Arithmetic calculation | There are 24 students. Among them, 50 sheets of colored paper were equally distributed to female students only, and 2 sheets were left. If the number of boys is twice the number of girls, how many pieces of colored paper will each girl receive? | 6 | 50 2 [OP_SUB] 24 2 1 [OP_ADD] [OP_FDIV] [OP_FDIV] | var_a = 50
var_b = 2
var_c = var_a - var_b
var_d = 24
var_e = 2
var_f = 1
var_g = var_e + var_f
var_h = var_d // var_g
var_i = var_c // var_h
print(int(var_i)) |
Correspondence | Multiply a number by 2.5 then subtract 2.49 to get 22.01. Divide the number by 2.5, add 2.49, multiply by 2.3, and add 22.01 to get the result. | 36.75 | 22.01 2.49 [OP_ADD] 2.5 [OP_DIV] 2.5 [OP_DIV] 2.49 [OP_ADD] 2.3 [OP_MUL] 22.01 [OP_ADD] | var_a = 22.01
var_b = 2.49
var_c = var_a + var_b
var_d = 2.5
var_e = var_c / var_d
var_f = 2.5
var_g = var_e / var_f
var_h = 2.49
var_i = var_g + var_h
var_j = 2.3
var_k = var_i * var_j
var_l = 22.01
var_m = var_k + var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
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