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Geometry | Fifteen pieces of colored paper in the shape of a rectangle, 9.4 cm (cm) wide and 3.7 cm (cm) long, overlap each other by 0.6 centimeters (cm). What is the total area of the colored paper glued together? | 490.62 | 9.4 15 [OP_MUL] 15 1 [OP_SUB] 0.6 [OP_MUL] [OP_SUB] 3.7 [OP_MUL] | var_a = 9.4
var_b = 15
var_c = var_a * var_b
var_d = 15
var_e = 1
var_f = var_d - var_e
var_g = 0.6
var_h = var_f * var_g
var_i = var_c - var_h
var_j = 3.7
var_k = var_i * var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) |
Geometry | Some parks are shaped like a regular hexagon with sides measuring 5 meters (m). Find the length of the perimeter of this park. | 30 | 5 6 [OP_MUL] | var_a = 5
var_b = 6
var_c = var_a * var_b
print(int(var_c)) |
Geometry | What is the length in centimeters (cm) of the radius of a bicycle wheel with a diameter of 26 centimeters (cm)? | 13 | 26 2 [OP_DIV] | var_a = 26
var_b = 2
var_c = var_a / var_b
print(int(var_c)) |
Correspondence | There is a company with a total of 450 people. Among them, employees working abroad accounted for 0.06 of the total number of employees. How many employees work abroad? | 27 | 450 0.06 [OP_MUL] | var_a = 450
var_b = 0.06
var_c = var_a * var_b
print(int(var_c)) |
Arithmetic calculation | Find how many times the number 2 appears in a list of all natural numbers less than or equal to 50 that are multiples of 5 or 2. | 11 | 1 50 1 [OP_LIST_ARANGE] 5 [OP_LIST_DIVISIBLE] 1 50 [OP_LIST_EVEN] [OP_SET_UNION] [OP_LIST2NUM] [OP_NUM2LIST] 2 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 50
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 5
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 1
var_f = 50
list_c = []
if var_e%2!=0:
for i in range(var_e+1, var_f+1, 2):
list_c.append(i)
else:
for i in range(var_e, var_f+1, 2):
list_c.append(i)
list_d = list(set(list_b) | set(list_c))
var_g=""
for i in list_d:
i = str(i)
var_g = var_g + i
list_e = []
var_g = int(var_g)
while var_g//10 > 0:
list_e.append(var_g%10)
var_g = var_g//10
list_e.append(var_g%10)
list_e = list_e[::-1]
var_h = 2
var_i = 0
var_h = int(var_h)
for i in list_e:
i = int(i)
if i == var_h:
var_i = var_i + 1
print(int(var_i)) |
Arithmetic calculation | Potatoes were planted in 3/5 of Woojin's field, and sweet potatoes were planted in 2/3 of the remaining. What fraction of the whole is the unplanted part? | 0.13 | 1 3/5 [OP_SUB] 1 2/3 [OP_SUB] [OP_MUL] | var_a = 1
var_b = 0.6
var_c = var_a - var_b
var_d = 1
var_e = 0.6666666666666666
var_f = var_d - var_e
var_g = var_c * var_f
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Possibility | How many three-digit integers can be made with 4 cards each numbered 0, 1, 2, 3? | 18 | [OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 1
var_c = 2
var_d = 3
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = len(list_b)
print(int(var_f)) |
Arithmetic calculation | There are 225 students in class giraffe, and class elephant as 48 more students than class giraffe. Class rabbit has 24 less students than class giraffe. How many students are in the three classes of this kindergarten on average? | 233 | 225 225 48 [OP_ADD] [OP_ADD] 225 24 [OP_SUB] [OP_ADD] 3 [OP_DIV] | var_a = 225
var_b = 225
var_c = 48
var_d = var_b + var_c
var_e = var_a + var_d
var_f = 225
var_g = 24
var_h = var_f - var_g
var_i = var_e + var_h
var_j = 3
var_k = var_i / var_j
print(int(var_k)) |
Possibility | There are five number cards 1, 3, 5, 7, and 9. What is the sum of the three-digit natural numbers that can be made using these cards that are greater than 500? (However, the card can be used repeatedly.) | 56625 | [OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_SUM] | var_a = 1
var_b = 3
var_c = 5
var_d = 7
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 500
list_c = []
for i in list_b:
if i > var_g:
list_c.append(i)
list_c = [float(i) for i in list_c]
var_h = sum(list_c)
print(int(var_h)) |
Possibility | You are going to create a two-digit number by drawing two cards among 2, 4, 6, 8, and 9 and you can use them only once. Find the product of the largest and smallest two-digit numbers that can be made. | 2352 | [OP_LIST_SOL] 2 4 6 8 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_MUL] | var_a = 2
var_b = 4
var_c = 6
var_d = 8
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 1
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h * var_j
print(int(var_k)) |
Comparison | There are 5 boxes of 50 yellow balls each weighing 50 grams (g). There are 6 boxes of 60 white balls each weighing 45 grams (g). There are also 4 boxes of 40 blue balls each weighing 55 grams (g). All the empty boxes weigh the same. What is the color of the ball in the box with the lightest weight? | blue | [OP_LIST_SOL] yellow white blue [OP_LIST_EOL] [OP_LIST_SOL] 50 50 [OP_MUL] 45 60 [OP_MUL] 55 40 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'yellow'
var_b = 'white'
var_c = 'blue'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 50
var_e = 50
var_f = var_d * var_e
var_g = 45
var_h = 60
var_i = var_g * var_h
var_j = 55
var_k = 40
var_l = var_j * var_k
list_b= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p) |
Comparison | The distance from Sol's house to the community-center is 2 kilometers (km) and 280 meters (m), and the distance to the nearest subway-station is 4125 meters (m). Which is closer to Sol's house, the community-center or the subway-station? | community-center | [OP_LIST_SOL] community-center subway-station [OP_LIST_EOL] [OP_LIST_SOL] 2 1000 [OP_MUL] 280 [OP_ADD] 4125 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'community-center'
var_b = 'subway-station'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 2
var_d = 1000
var_e = var_c * var_d
var_f = 280
var_g = var_e + var_f
var_h = 4125
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Possibility | You want to buy 2 fruits by combining apple, peach, pear, melon, and banana. How many possible combinations are there when allowing duplicates? | 15 | [OP_LIST_SOL] apple peach pear melon banana [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | var_a = 'apple'
var_b = 'peach'
var_c = 'pear'
var_d = 'melon'
var_e = 'banana'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 2
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = 2
var_l = 1
var_j = int(var_j)
var_k = int(var_k)
for i, elem in enumerate(range(var_k)):
var_l = var_l * (var_j-i)
for i, elem in enumerate(range(var_k)):
var_l = var_l / (i+1)
print(int(var_l)) |
Geometry | If the perimeter of a rectangle whose length is 2 centimeters (cm) shorter than its width is 16 centimeters (cm), what is its width? | 5 | 16 2 [OP_DIV] 2 [OP_SUB] 2 [OP_DIV] 2 [OP_ADD] | var_a = 16
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g + var_h
print(int(var_i)) |
Comparison | Pine trees were planted 22.75 meters (m) on one side of the 364-meter (m) long road, and ginkgo trees were planted on the other side at intervals of 45.5 meters (m) from start to finish. Find out which of the pine trees or ginkgo trees was planted more. | pine | [OP_LIST_SOL] pine ginkgo [OP_LIST_EOL] [OP_LIST_SOL] 364 22.75 [OP_DIV] 364 45.5 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'pine'
var_b = 'ginkgo'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 364
var_d = 22.75
var_e = var_c / var_d
var_f = 364
var_g = 45.5
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | I want to plant street trees. If street trees are planted from the beginning to the end, equally divided into 4 sections from the 0.35 km (km) point to the 0.37 km (km) point, indicate the kilometers (km) of the position of the street tree planted at the fourth point as a decimal number. | 0.37 | 0.35 0.37 0.35 [OP_SUB] 4 [OP_DIV] 4 1 [OP_SUB] [OP_MUL] [OP_ADD] | var_a = 0.35
var_b = 0.37
var_c = 0.35
var_d = var_b - var_c
var_e = 4
var_f = var_d / var_e
var_g = 4
var_h = 1
var_i = var_g - var_h
var_j = var_f * var_i
var_k = var_a + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) |
Geometry | Find the number of diagonals in a nine-sided polygon. | 27 | 9 9 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 9
var_b = 9
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | In two-digit addition, the number 3 in the tens place of the number added was incorrectly counted as 6. Again, the numbers being added incorrectly read the ones digit as 9 to 2. If the result of the calculation is 119, what is the result of the correct calculation? | 96 | 119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD] | var_a = 119
var_b = 1
var_c = 9
var_d = 2
var_e = var_c - var_d
var_f = var_b * var_e
var_g = var_a + var_f
var_h = 10
var_i = 3
var_j = 6
var_k = var_i - var_j
var_l = var_h * var_k
var_m = var_g + var_l
print(int(var_m)) |
Possibility | Three numbers from 2, 0, 7, 5, and 9 were used to create a three-digit number with different digits. If the numbers made in this way are arranged from left to right in ascending order, what will be the sum of the leftmost number and the fourth number from the left? | 455 | [OP_LIST_SOL] 2 0 7 5 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 4 [OP_LIST_MIN] [OP_ADD] | var_a = 2
var_b = 0
var_c = 7
var_d = 5
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = 4
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h + var_j
print(int(var_k)) |
Geometry | There is a rectangular parallelepiped-shaped lake with a length of 9 meters (m) wide and a length of 7 meters (m) long. If the volume of this lake is 315 square centimeters (cm2), how deep is this lake in centimeters (cm)? | 5 | 315 9 [OP_DIV] 7 [OP_DIV] | var_a = 315
var_b = 9
var_c = var_a / var_b
var_d = 7
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | When a number is multiplied by 3 twice, it is 18. Find the number. | 2 | 18 3 [OP_DIV] 3 [OP_DIV] | var_a = 18
var_b = 3
var_c = var_a / var_b
var_d = 3
var_e = var_c / var_d
print(int(var_e)) |
Comparison | There are tangerine trees (a), (b), (c), and (d). (a) has more tangerines than (d), and (d) has more tangerines than (c). If (b) has more tangerines than (a), which tangerine tree has the most tangerines? | (b) | [OP_LIST_SOL] (a) (b) (c) (d) [OP_LIST_EOL] [OP_LIST_SOL] (a) (d) > (d) (c) > (b) (a) > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = '(a)'
var_b = '(b)'
var_c = '(c)'
var_d = '(d)'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = '(a)'
var_f = '(d)'
var_g = '>'
var_h = '(d)'
var_i = '(c)'
var_j = '>'
var_k = '(b)'
var_l = '(a)'
var_m = '>'
list_b= []
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_n = 1
var_o = list_c[var_n-1]
print(var_o) |
Correspondence | 632-5AB=41. How much is B? | 1 | 632-5AB=41 B [OP_DIGIT_UNK_SOLVER] | var_a = '632-5AB=41'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Possibility | Dohun is playing a numbers game with Changu and Chanhee. It is a game in which ranks are ranked according to the size of the number made using all the number-written cards you have, and Dohun has numbers of 3, 9, and 8. When Changu made 850 and Chanhee made 920, what is the number of cases in which Dohun rank in second place? | 1 | [OP_LIST_SOL] 3 9 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 850 [OP_LIST_MORE] 920 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 3
var_b = 9
var_c = 8
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 850
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = 920
list_d = []
for i in list_c:
if i < var_f:
list_d.append(i)
var_g = len(list_d)
print(int(var_g)) |
Correspondence | 9A6-BB=BBB is true and A and B are not the same numbers. Find the sum of A and B. | 15 | 9A6-BB=BBB A [OP_DIGIT_UNK_SOLVER] 9A6-BB=BBB B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = '9A6-BB=BBB'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = '9A6-BB=BBB'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Geometry | Coins of the same size are arranged without gaps to form a square so that there are 36 coins placed around the perimeter. Find the number of coins lying on the outermost of one side. | 10 | 36 4 [OP_DIV] 1 [OP_ADD] | var_a = 36
var_b = 4
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Geometry | A rectangle has a side length of 4 centimeters (cm) and an area of 25/2 square centimeters (cm2). Find the length in centimeters (cm) of the side of this rectangle that is not 4 centimeters (cm) long. | 3.13 | 25/2 4 [OP_DIV] | var_a = 12.5
var_b = 4
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Possibility | There is a clothing store that sells red, blue and black clothes. When purchasing two sets of clothes, find the number of all possible choices, allowing duplicates. | 6 | [OP_LIST_SOL] red blue black [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_ADD] 1 [OP_SUB] 2 [OP_COMB] | var_a = 'red'
var_b = 'blue'
var_c = 'black'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = len(list_a)
var_e = 2
var_f = var_d + var_e
var_g = 1
var_h = var_f - var_g
var_i = 2
var_j = 1
var_h = int(var_h)
var_i = int(var_i)
for i, elem in enumerate(range(var_i)):
var_j = var_j * (var_h-i)
for i, elem in enumerate(range(var_i)):
var_j = var_j / (i+1)
print(int(var_j)) |
Arithmetic calculation | How many numbers greater than 50 and less than 100 are not divisible by 8 and have a remainder of 4? | 6 | 50 1 [OP_ADD] 100 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 4 [OP_LIST_DIVIDE_AND_REMAIN] [OP_LIST_LEN] | var_a = 50
var_b = 1
var_c = var_a + var_b
var_d = 100
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = 8
var_i = 4
list_b = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_a:
i = int(i)
if i%var_h == var_i:
list_b.append(i)
var_j = len(list_b)
print(int(var_j)) |
Correspondence | A number multiplied by 6 plus 17 divided by 5 equals 25. Find the number. | 18 | 25 5 [OP_MUL] 17 [OP_SUB] 6 [OP_DIV] | var_a = 25
var_b = 5
var_c = var_a * var_b
var_d = 17
var_e = var_c - var_d
var_f = 6
var_g = var_e / var_f
print(int(var_g)) |
Arithmetic calculation | As a result of the long jump in PE class, Eunseol's record was 1 meter (m) 35 centimeters (cm), and Jeongyeon jumped 9 centimeters (cm) more than Eunseol. How many meters (m) was Jeongyeon's long jump record as a decimal number? | 1.44 | 1 35 100 [OP_DIV] [OP_ADD] 9 100 [OP_DIV] [OP_ADD] | var_a = 1
var_b = 35
var_c = 100
var_d = var_b / var_c
var_e = var_a + var_d
var_f = 9
var_g = 100
var_h = var_f / var_g
var_i = var_e + var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | How many natural numbers are greater than 40 and less than or equal to 70? | 30 | 70 40 [OP_SUB] | var_a = 70
var_b = 40
var_c = var_a - var_b
print(int(var_c)) |
Comparison | I made a cake with 3 and 2/6 tablespoons of blueberry syrup and 21/6 tablespoons of grapefruit syrup. Find which one is contained more in the cake. | grapefruit | [OP_LIST_SOL] blueberry grapefruit [OP_LIST_EOL] [OP_LIST_SOL] 3 2 6 [OP_DIV] [OP_ADD] 21 6 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'blueberry'
var_b = 'grapefruit'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 3
var_d = 2
var_e = 6
var_f = var_d / var_e
var_g = var_c + var_f
var_h = 21
var_i = 6
var_j = var_h / var_i
list_b= []
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
var_k = 1
list_c=list_b.copy()
list_c.sort()
var_l = list_c[-var_k]
var_m = list_b.index(var_l)+1
var_n = list_a[var_m-1]
print(var_n) |
Geometry | There is a cube with the sum of the lengths of all its edges equal to 132 centimeters (cm). What is the area of one side of this cube in square centimeters (cm2)? | 121 | 132 12 [OP_DIV] 132 12 [OP_DIV] [OP_MUL] | var_a = 132
var_b = 12
var_c = var_a / var_b
var_d = 132
var_e = 12
var_f = var_d / var_e
var_g = var_c * var_f
print(int(var_g)) |
Arithmetic calculation | 32 apples were divided into 7 boxes, leaving 4 apples. How many apples are there in one box? | 4 | 32 4 [OP_SUB] 7 [OP_DIV] | var_a = 32
var_b = 4
var_c = var_a - var_b
var_d = 7
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | 81 is the result of adding 43 to some number. What number is 25 greater than this number? | 63 | 81 43 [OP_SUB] 25 [OP_ADD] | var_a = 81
var_b = 43
var_c = var_a - var_b
var_d = 25
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Assuming that the distance between the school and the park is 396 meters (m) and the distance between the school and the pharmacy is 0.389 kilometers (km), find the one closer to the school between the park and the pharmacy. | pharmacy | [OP_LIST_SOL] park pharmacy [OP_LIST_EOL] [OP_LIST_SOL] 396 0.389 1000 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'park'
var_b = 'pharmacy'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 396
var_d = 0.389
var_e = 1000
var_f = var_d * var_e
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Geometry | Find the area of a square whose diagonal is 12 centimeters (cm). | 72 | 12 2 [OP_POW] 2 [OP_DIV] | var_a = 12
var_b = 2
var_c = var_a ** var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | If the reciprocal of -0.4 is A and the reciprocal of +5/2 is B, find the reciprocal of 3/A + 2/B. | 0.26 | 1 3 1 -0.4 [OP_DIV] [OP_DIV] 2 1 5/2 [OP_DIV] [OP_DIV] [OP_ADD] [OP_DIV] | var_a = 1
var_b = 3
var_c = 1
var_d = -0.4
var_e = var_c / var_d
var_f = var_b / var_e
var_g = 2
var_h = 1
var_i = 2.5
var_j = var_h / var_i
var_k = var_g / var_j
var_l = var_f + var_k
var_m = var_a / var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Comparison | Jungsoo put 28 marbles equally divided into 4 bags, and Hyeonju put 18 marbles equally divided into 3 bags. Who has fewer marbles in one bag, Jungsoo or Hyeonju? | Hyeonju | [OP_LIST_SOL] Jungsoo Hyeonju [OP_LIST_EOL] [OP_LIST_SOL] 28 4 [OP_DIV] 18 3 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungsoo'
var_b = 'Hyeonju'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 28
var_d = 4
var_e = var_c / var_d
var_f = 18
var_g = 3
var_h = var_f / var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Comparison | There are a total of three numbers: 0.8, 1/2, and 0.5. What is the sum of all numbers less than 2? | 1.8 | [OP_LIST_SOL] 0.8 1/2 0.5 [OP_LIST_EOL] 2 [OP_LIST_LESS] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.5
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = []
for i in list_a:
if i < var_d:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_e = sum(list_b)
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Arithmetic calculation | Minyoung has 9 candies and Taehyung has 3. How many candies must Minyoung give to Taehyung so that Minyoung and Taehyung have the same number of candies? | 3 | 9 3 [OP_SUB] 2 [OP_DIV] | var_a = 9
var_b = 3
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Geometry | If the volume of 4 squares with side length 3 is equal to the volume of a circle, find the length of the radius of the circle. (Note that the pi is calculated as 3.1) | 3.41 | 4 3 2 [OP_POW] [OP_MUL] 3.1 [OP_DIV] 1/2 [OP_POW] | var_a = 4
var_b = 3
var_c = 2
var_d = var_b ** var_c
var_e = var_a * var_d
var_f = 3.1
var_g = var_e / var_f
var_h = 0.5
var_i = var_g ** var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Geometry | I'm trying to make a square as small as possible by arranging rectangular tiles that are 12 centimeters (cm) wide and 15 centimeters (cm) tall without any overlap. How many tiles will you need in total? | 20 | 12 15 [OP_LCM] 2 [OP_POW] 12 15 [OP_MUL] [OP_DIV] | var_a = 12
var_b = 15
var_c = var_b * var_a / math.gcd(int(var_b), int(var_a))
var_d = 2
var_e = var_c ** var_d
var_f = 12
var_g = 15
var_h = var_f * var_g
var_i = var_e / var_h
print(int(var_i)) |
Arithmetic calculation | How many numbers are there greater than 40 and less than 80 are multiples of 8? | 4 | 40 1 [OP_ADD] 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 8 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 40
var_b = 1
var_c = var_a + var_b
var_d = 80
var_e = 1
var_f = var_d - var_e
var_g = 1
list_a = [i for i in range(var_c, var_f + 1, var_g)]
var_h = 8
list_b = []
var_h = int(var_h)
for i in list_a:
i = int(i)
if i % var_h == 0:
list_b.append(i)
var_i = len(list_b)
print(int(var_i)) |
Correspondence | I have a single digit A. If division 9A5÷5<197, count all possible numbers that can be A. | 8 | 9A5÷5<197 A [OP_DIGIT_UNK_SOLVER] [OP_LIST_LEN] | var_a = '9A5÷5<197'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = []
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k].append(int(c[i]))
list_a = list(set(ans_dict[var_b]))
var_c = len(list_a)
print(int(var_c)) |
Arithmetic calculation | There are 8 students in Minsu's class, and Jinho's class has one more student than Minsu's class. From 3.944 meters (m) of ribbon, 29.05 centimeters (cm) were divided to each student in Minsu's class. After that, if you cut and distribute the remaining ribbons equally to Jinho's classmates, find how many centimeters (cm) of ribbons Jinho received. | 18 | 3.944 100 [OP_MUL] 29.05 8 [OP_MUL] [OP_SUB] 8 1 [OP_ADD] [OP_DIV] | var_a = 3.944
var_b = 100
var_c = var_a * var_b
var_d = 29.05
var_e = 8
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 8
var_i = 1
var_j = var_h + var_i
var_k = var_g / var_j
print(int(eval('{:.2f}'.format(round(var_k+1e-10,2))))) |
Comparison | At school, you took exams in the order of Korean, Social, Mathematics, English, and Science. What subject did you take the test for the third time? | Mathematics | [OP_LIST_SOL] Korean Social Mathematics English Science [OP_LIST_EOL] 3 [OP_LIST_GET] | var_a = 'Korean'
var_b = 'Social'
var_c = 'Mathematics'
var_d = 'English'
var_e = 'Science'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
var_g = list_a[var_f-1]
print(var_g) |
Arithmetic calculation | Moving a decimal point to the right by one place makes a some number to become 2.7 larger than it originally was. Find the original decimal number. | 0.3 | 2.7 10 1 [OP_SUB] [OP_DIV] | var_a = 2.7
var_b = 10
var_c = 1
var_d = var_b - var_c
var_e = var_a / var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | The teacher gave candy to Yoongi, Jimin, and Taehyung. If Yoongi got more candies than Taehyung and Taehyung got more candies than Jimin, who got the fewest candies? | Jimin | [OP_LIST_SOL] Yoongi Jimin Taehyung [OP_LIST_EOL] [OP_LIST_SOL] Yoongi Taehyung > Taehyung Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jimin'
var_c = 'Taehyung'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Yoongi'
var_e = 'Taehyung'
var_f = '>'
var_g = 'Taehyung'
var_h = 'Jimin'
var_i = '>'
list_b= []
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_j = len(list_c)
var_k = list_c[var_j-1]
print(var_k) |
Correspondence | What number must be in B to make 1A+4B3=469? | 5 | 1A+4B3=469 B [OP_DIGIT_UNK_SOLVER] | var_a = '1A+4B3=469'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | An elementary school has 1256 students. Of these, the difference between the number of students who like math and those who like other subjects is 408. How many students like math? (However, students who like math are fewer than 500.) | 424 | 1256 408 [OP_SUB] 2 [OP_DIV] | var_a = 1256
var_b = 408
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Comparison | You want to choose a figure with a longer perimeter. Given a square whose side is 3 centimeters (cm) and an equilateral-triangle whose side is 5 centimeters (cm), which shape has a longer perimeter? | equilateral-triangle | [OP_LIST_SOL] square equilateral-triangle [OP_LIST_EOL] [OP_LIST_SOL] 3 4 [OP_MUL] 5 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'square'
var_b = 'equilateral-triangle'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 3
var_d = 4
var_e = var_c * var_d
var_f = 5
var_g = 3
var_h = var_f * var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Geometry | If the sum of all the edges of a polyhedron made of 6 equal-sized squares is 144 centimeters (cm), what is the length of one side of the square in centimeters (cm)? | 12 | 144 12 [OP_DIV] | var_a = 144
var_b = 12
var_c = var_a / var_b
print(int(var_c)) |
Arithmetic calculation | Yuna gave 12 marbles to her younger brother and got 5 marbles to her sister. After that, Yuna gave half of the marbles to Namjoon and received 3 from Yoongi, so the number of marbles She currently have is 17. How many marbles did Yuna have in the first place? | 35 | 17 3 [OP_SUB] 2 [OP_MUL] 5 [OP_SUB] 12 [OP_ADD] | var_a = 17
var_b = 3
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
var_f = 5
var_g = var_e - var_f
var_h = 12
var_i = var_g + var_h
print(int(var_i)) |
Comparison | Yuri ate 6 plates of tteokbokki at the restaurant, and Jisoo ate 8 plates. Taehyung ate more than Yuri and less than Jisoo. How many plates of tteokbokki did Taehyung eat? | 7 | 6 8 [OP_ADD] 2 [OP_FDIV] | var_a = 6
var_b = 8
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e)) |
Arithmetic calculation | Hyunwoo's family uses 215 liters (L) of water a day. If they adjust the water pressure valve weakly, they can save as much as 0.32 times the usual amount. How many liters (L) of water can Hyunwoo's family save in a day when the water pressure valve is adjusted weakly? | 68.8 | 215 0.32 [OP_MUL] | var_a = 215
var_b = 0.32
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | If you pack 6 or 9 candies, you will have nothing left, and if you pack 7 candies, you will have 1 candy left. If the number of candies is a natural number between 11 and 100, how many candies are there? | 36 | 10 100 1 [OP_LIST_ARANGE] 6 9 [OP_LCM] 0 [OP_LIST_DIVIDE_AND_REMAIN] 7 1 [OP_LIST_DIVIDE_AND_REMAIN] 1 [OP_LIST_GET] | var_a = 10
var_b = 100
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 6
var_e = 9
var_f = var_e * var_d / math.gcd(int(var_e), int(var_d))
var_g = 0
list_b = []
var_f = int(var_f)
var_g = int(var_g)
if var_g < 0:
var_g = var_g + var_f
for i in list_a:
i = int(i)
if i%var_f == var_g:
list_b.append(i)
var_h = 7
var_i = 1
list_c = []
var_h = int(var_h)
var_i = int(var_i)
if var_i < 0:
var_i = var_i + var_h
for i in list_b:
i = int(i)
if i%var_h == var_i:
list_c.append(i)
var_j = 1
var_k = list_c[var_j-1]
print(int(var_k)) |
Geometry | You drew diagonals from one vertex of an octagon. Find the number of triangles formed in this case. | 6 | 8 3 [OP_SUB] 1 [OP_ADD] | var_a = 8
var_b = 3
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | How many natural numbers from 1 to 1000 have 3 in the tens place? | 100 | 1 1000 1 [OP_LIST_ARANGE] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN] | var_a = 1
var_b = 1000
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 10
var_e = 3
list_b = []
var_d = int(var_d)
var_e = int(var_e)
for i in list_a:
i = int(i)
if (i//var_d)%10 == var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Comparison | There are two numbers. When you add 30 to the smaller numbers and multiply it by 4, you get the larger number. If the difference between these two numbers is 480, what is the larger number? | 600 | 480 30 4 [OP_MUL] [OP_SUB] 4 1 [OP_SUB] [OP_DIV] 30 [OP_ADD] 4 [OP_MUL] | var_a = 480
var_b = 30
var_c = 4
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 4
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
var_j = 30
var_k = var_i + var_j
var_l = 4
var_m = var_k * var_l
print(int(var_m)) |
Correspondence | When 632-5AB=41, what number should be in B? | 1 | 632-5AB=41 B [OP_DIGIT_UNK_SOLVER] | var_a = '632-5AB=41'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Geometry | If four points B, C, D, and E of the five points A, B, C, D, and E are on a straight line, how many straight lines can be formed by connecting these two points? | 5 | 4 1 [OP_ADD] | var_a = 4
var_b = 1
var_c = var_a + var_b
print(int(var_c)) |
Possibility | You want to create a five-digit number using the numbers 7, 2, 3, 4, and 9. How many five-digit numbers can you make? The same number can appear multiple times. | 3125 | [OP_LIST_SOL] 7 2 3 4 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PRODUCT] [OP_LIST_LEN] | var_a = 7
var_b = 2
var_c = 3
var_d = 4
var_e = 9
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 5
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = len(list_b)
print(int(var_g)) |
Possibility | How many three-digit integers can be made by drawing 3 cards from 1 through 4? | 24 | 4 3 [OP_PERM] | var_a = 4
var_b = 3
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
print(int(var_c)) |
Correspondence | You want to multiply 20 by some number. But you mistakenly divided a number by 10, and the result was 5. What is the correct calculation result? | 40 | 20 10 5 [OP_DIV] [OP_MUL] | var_a = 20
var_b = 10
var_c = 5
var_d = var_b / var_c
var_e = var_a * var_d
print(int(var_e)) |
Geometry | Find how many centimeters (cm) per side of a rhombus is 60 centimeters (cm) when the lengths of the four sides are added. | 15 | 60 4 [OP_DIV] | var_a = 60
var_b = 4
var_c = var_a / var_b
print(int(var_c)) |
Possibility | You want to create a three-digit number by picking three of 1, 0, 7, 4, and 5 and using them only once. Find the difference between the second largest number and the third smallest number that can be made. | 644 | [OP_LIST_SOL] 1 0 7 4 5 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_SUB] [OP_ABS] | var_a = 1
var_b = 0
var_c = 7
var_d = 4
var_e = 5
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 2
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 3
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h - var_j
var_l = abs(var_k)
print(int(var_l)) |
Geometry | The sum of the lengths of the sides of a rectangle with sides of 8 centimeters (cm) and 10 centimeters (cm) and a square is equal. How many centimeters (cm) is the length of one side of the square? | 9 | 8 10 [OP_ADD] 2 [OP_MUL] 4 [OP_DIV] | var_a = 8
var_b = 10
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
var_f = 4
var_g = var_e / var_f
print(int(var_g)) |
Comparison | There is a box full of sand weighing 1 kilogram (kg) 780 grams (g) and a barrel weighing 2 kilograms (kg) 250 grams (g). If the box weighs 250 grams (g) and the barrel weighs 460 grams (g), which contains more sand, the box or the barrel? | barrel | [OP_LIST_SOL] box barrel [OP_LIST_EOL] [OP_LIST_SOL] 1 1000 [OP_MUL] 780 [OP_ADD] 250 [OP_SUB] 2 1000 [OP_MUL] 250 [OP_ADD] 460 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'box'
var_b = 'barrel'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1
var_d = 1000
var_e = var_c * var_d
var_f = 780
var_g = var_e + var_f
var_h = 250
var_i = var_g - var_h
var_j = 2
var_k = 1000
var_l = var_j * var_k
var_m = 250
var_n = var_l + var_m
var_o = 460
var_p = var_n - var_o
list_b= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
list_b.reverse()
var_q = 1
list_c=list_b.copy()
list_c.sort()
var_r = list_c[-var_q]
var_s = list_b.index(var_r)+1
var_t = list_a[var_s-1]
print(var_t) |
Arithmetic calculation | You are trying to make a team of 6 people to play the game. How many teams can you make if there are 72 students in all? | 12 | 72 6 [OP_FDIV] | var_a = 72
var_b = 6
var_c = var_a // var_b
print(int(var_c)) |
Correspondence | The number that is 204 less than C is A, and A is 520. Calculate B when adding 179 to B equals C. | 545 | 520 204 [OP_ADD] 179 [OP_SUB] | var_a = 520
var_b = 204
var_c = var_a + var_b
var_d = 179
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | The second-year students participated in the running competition, which is five times the number of students who participated in the running competition among the first-year students participated in the running competition. If eight of the first graders participated in the race, how many first and second graders participated in the race? | 48 | 8 8 5 [OP_MUL] [OP_ADD] | var_a = 8
var_b = 8
var_c = 5
var_d = var_b * var_c
var_e = var_a + var_d
print(int(var_e)) |
Correspondence | The quotient of a number subtracted by 8 and then subtracted by 12 and then divided by 5 equals 7. Find the number. | 55 | 5 7 [OP_MUL] 12 [OP_ADD] 8 [OP_ADD] | var_a = 5
var_b = 7
var_c = var_a * var_b
var_d = 12
var_e = var_c + var_d
var_f = 8
var_g = var_e + var_f
print(int(var_g)) |
Arithmetic calculation | To go to school, Woojun walked 1/5 of the total distance and took the subway for the remaining distance. How many times is the total distance taken by subway? | 0.8 | 1 1/5 [OP_SUB] | var_a = 1
var_b = 0.2
var_c = var_a - var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Possibility | There are four types of animals in the fence: chicken, duck, rabbit, and dog. Find a way to get 15 animals out of the fence. | 816 | 4 1 [OP_SUB] 15 [OP_ADD] 15 [OP_COMB] | var_a = 4
var_b = 1
var_c = var_a - var_b
var_d = 15
var_e = var_c + var_d
var_f = 15
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
for i, elem in enumerate(range(var_f)):
var_g = var_g / (i+1)
print(int(var_g)) |
Comparison | Which number is the smallest among 5, 8, 3, 2, and 6? | 2 | [OP_LIST_SOL] 5 8 3 2 6 [OP_LIST_EOL] 1 [OP_LIST_MIN] | var_a = 5
var_b = 8
var_c = 3
var_d = 2
var_e = 6
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
print(int(var_g)) |
Arithmetic calculation | There are 19 boxes of apples, each containing 46 pieces, and several boxes of tangerines, each containing 170 pieces. If there are 1894 apples and tangerines, how many boxes of tangerines are there? | 6 | 1894 46 19 [OP_MUL] [OP_SUB] 170 [OP_FDIV] | var_a = 1894
var_b = 46
var_c = 19
var_d = var_b * var_c
var_e = var_a - var_d
var_f = 170
var_g = var_e // var_f
print(int(var_g)) |
Comparison | What is the sum of the numbers greater than or equal to 1.1 in 1.4, 9/10, 1.2, 0.5, and 13/10? | 3.9 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_SUM] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_g = sum(list_b)
print('{:.2f}'.format(round(var_g+1e-10,2))) |
Correspondence | A number subtract by 7 is a multiple of 9, and the quotient of a number divided by 9 is 25. Find the value of a number multiplied by 9. | 2088 | 25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL] | var_a = 25
var_b = 9
var_c = var_a * var_b
var_d = 7
var_e = var_c + var_d
var_f = 9
var_g = var_e * var_f
print(int(var_g)) |
Comparison | Nana and Gaeun are playing a game of tossing paper airplanes far. Nana flew the paper airplane 1.618 meters (m), and Gaeun flew the paper airplane 162.3 centimeters (cm). Find out who flew the paper plane farther. | Gaeun | [OP_LIST_SOL] Nana Gaeun [OP_LIST_EOL] [OP_LIST_SOL] 1.618 100 [OP_MUL] 162.3 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Nana'
var_b = 'Gaeun'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 1.618
var_d = 100
var_e = var_c * var_d
var_f = 162.3
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Comparison | Jungkook collected the number 6 multiplied by 3, Yoongi collected 4, and Yuna collected 5. Who got the smallest number? | Yoongi | [OP_LIST_SOL] Jungkook Yoongi Yuna [OP_LIST_EOL] [OP_LIST_SOL] 6 3 [OP_MUL] 4 5 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Yoongi'
var_c = 'Yuna'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 6
var_e = 3
var_f = var_d * var_e
var_g = 4
var_h = 5
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Correspondence | Today, I poured 7/3 liter (L) of water from Suho's beaker into Seohyun's beaker. If the water in Suho's beaker is 3/2 liter (L) more than the water in Seohyun's beaker, how many more water was in Suho's beaker than in Seohyun's beaker originally in liters (L)? | 6.17 | 3/2 7/3 [OP_ADD] 7/3 [OP_ADD] | var_a = 1.5
var_b = 2.3333333333333335
var_c = var_a + var_b
var_d = 2.3333333333333335
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Correspondence | In the multiplication of two-digit numbers, 2432 was calculated because I had mistaken the number 2 in the tens place of the number being multiplied for 6. If the correctly calculated value is 912, write the smaller of the two two-digit numbers. | 24 | [OP_LIST_SOL] 2432 912 [OP_SUB] 40 [OP_DIV] 912 2432 912 [OP_SUB] 40 [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] | var_a = 2432
var_b = 912
var_c = var_a - var_b
var_d = 40
var_e = var_c / var_d
var_f = 912
var_g = 2432
var_h = 912
var_i = var_g - var_h
var_j = 40
var_k = var_i / var_j
var_l = var_f / var_k
list_a= []
if "/" in str(var_l):
var_l = eval(str(var_l))
list_a.append(var_l)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
list_a.reverse()
var_m = 1
list_b=list_a.copy()
list_b.sort()
var_n = list_b[var_m-1]
print(int(var_n)) |
Correspondence | Seungho gave 273 of his marbles to Hyukjin. At this time, if Seungho has 477 more marbles than Hyukjin, find out how many more marbles he had before giving them. | 1023 | 477 273 [OP_ADD] 273 [OP_ADD] | var_a = 477
var_b = 273
var_c = var_a + var_b
var_d = 273
var_e = var_c + var_d
print(int(var_e)) |
Arithmetic calculation | When four 250 centimeters (cm) long tapes were attached together, the total length was 925 centimeters (cm). How many centimeters (cm) is the length of one overlapping segment, assuming that each overlapping segment is the same length? | 25 | 250 4 [OP_MUL] 925 [OP_SUB] 4 1 [OP_SUB] [OP_DIV] | var_a = 250
var_b = 4
var_c = var_a * var_b
var_d = 925
var_e = var_c - var_d
var_f = 4
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Geometry | There is a square with sides of 11 centimeters (cm) and a square with sides of 5 centimeters (cm). What is the sum of the areas of the two squares in square centimeters (cm2)? | 146 | 11 2 [OP_POW] 5 2 [OP_POW] [OP_ADD] | var_a = 11
var_b = 2
var_c = var_a ** var_b
var_d = 5
var_e = 2
var_f = var_d ** var_e
var_g = var_c + var_f
print(int(var_g)) |
Correspondence | The four-digit number 18A4 is less than 1853. A is in the tens place and can contain any digit from 0 to 9. How many digits can go in A? | 5 | 18A4 [OP_GEN_POSSIBLE_LIST] 1853 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = '18A4'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 1853
list_b = []
for i in list_a:
if i < var_b:
list_b.append(i)
var_c = len(list_b)
print(int(var_c)) |
Correspondence | A7B+23=695. How much is B? | 2 | A7B+23=695 B [OP_DIGIT_UNK_SOLVER] | var_a = 'A7B+23=695'
var_b = 'B'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
print(int(var_c)) |
Arithmetic calculation | Minseok and Jaeyoon ate 3 apples each, so there are 2 apples left. How many apples were there initially? | 8 | 2 3 2 [OP_MUL] [OP_ADD] | var_a = 2
var_b = 3
var_c = 2
var_d = var_b * var_c
var_e = var_a + var_d
print(int(var_e)) |
Arithmetic calculation | There are 20 books (a) and books (b) in total, and there are four more books (a) than books (b). How many books (a) are there? | 12 | 20 4 [OP_ADD] 2 [OP_FDIV] | var_a = 20
var_b = 4
var_c = var_a + var_b
var_d = 2
var_e = var_c // var_d
print(int(var_e)) |
Possibility | What is the third largest three-digit number with a tens digit of 2 formed by using 2, 0, 3, and 8 once? | 328 | [OP_LIST_SOL] 2 0 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 2 [OP_LIST_SEARCH_FIXED_DIGIT] 3 [OP_LIST_MAX] | var_a = 2
var_b = 0
var_c = 3
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 10
var_g = 2
list_c = []
var_f = int(var_f)
var_g = int(var_g)
for i in list_b:
i = int(i)
if (i//var_f)%10 == var_g:
list_c.append(i)
var_h = 3
list_d=list_c.copy()
list_d.sort()
var_i = list_d[-var_h]
print(int(var_i)) |
Correspondence | 61 is the result of accidentally adding 26 to a number, to which 62 should have been added. How much do you get if calculated correctly? | 97 | 61 26 [OP_SUB] 62 [OP_ADD] | var_a = 61
var_b = 26
var_c = var_a - var_b
var_d = 62
var_e = var_c + var_d
print(int(var_e)) |
Possibility | The number of the room where the treasure is hidden is four digits, each digit does not overlap, and is the second largest number which can be made of 2, 3, 7, and 9. What is the number of the room where the treasure is hidden? | 9723 | [OP_LIST_SOL] 2 3 7 9 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] | var_a = 2
var_b = 3
var_c = 7
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 2
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
print(int(var_g)) |
Arithmetic calculation | If the hundreds digit of a three-digit natural number is 5, the tens digit is 1, and the units digit is 3, what is this number? | 513 | [OP_LIST_SOL] 5 1 3 [OP_LIST_EOL] [OP_LIST2NUM] | var_a = 5
var_b = 1
var_c = 3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
print(int(var_d)) |
Correspondence | Subtracting 46 from a number gives 15. What is the number obtained when 29 is subtracted from a number? | 32 | 15 46 [OP_ADD] 29 [OP_SUB] | var_a = 15
var_b = 46
var_c = var_a + var_b
var_d = 29
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | Namjoon has 17 marbles. Yoongi has 11 fewer marbles than Namjoon's marbles times 5, and Hoseok has 8 more marbles than 2 times Yoongi's. How many marbles do Namjoon, Yoongi, and Hoseok have? | 247 | 17 17 5 [OP_MUL] 11 [OP_SUB] [OP_ADD] 17 5 [OP_MUL] 11 [OP_SUB] 2 [OP_MUL] 8 [OP_ADD] [OP_ADD] | var_a = 17
var_b = 17
var_c = 5
var_d = var_b * var_c
var_e = 11
var_f = var_d - var_e
var_g = var_a + var_f
var_h = 17
var_i = 5
var_j = var_h * var_i
var_k = 11
var_l = var_j - var_k
var_m = 2
var_n = var_l * var_m
var_o = 8
var_p = var_n + var_o
var_q = var_g + var_p
print(int(var_q)) |
Arithmetic calculation | You are going to make a fence by connecting 3 wooden planks that are 217 centimeters (cm) long. If the length of the overlapping part of the wooden planks is the same, and the length of the fence made is 627 centimeters (cm), find how many centimeters (cm) is the length of one overlapping part of the planks. | 12 | 217 3 [OP_MUL] 627 [OP_SUB] 3 1 [OP_SUB] [OP_DIV] | var_a = 217
var_b = 3
var_c = var_a * var_b
var_d = 627
var_e = var_c - var_d
var_f = 3
var_g = 1
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Geometry | If the length of one side of the parallelogram is 3.8 meters (m) and the distance between this side and the opposite side is 6.36 meters (m), what is the area of the parallelogram? | 24.17 | 3.8 6.36 [OP_MUL] | var_a = 3.8
var_b = 6.36
var_c = var_a * var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Correspondence | If A is the number less than -3 by -5, and B is the number greater than +2 by -2, find the value of A+B. | 2 | -3 -5 [OP_SUB] 2 -2 [OP_ADD] [OP_ADD] | var_a = -3
var_b = -5
var_c = var_a - var_b
var_d = 2
var_e = -2
var_f = var_d + var_e
var_g = var_c + var_f
print(int(var_g)) |
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