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Correspondence | Subtracting 1.9 from a number, multiplying by 1.5, adding 32 and then dividing by 2.5 results in 20. Calculate the number including the decimal point. | 13.9 | 20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD] | var_a = 20
var_b = 2.5
var_c = var_a * var_b
var_d = 32
var_e = var_c - var_d
var_f = 1.5
var_g = var_e / var_f
var_h = 1.9
var_i = var_g + var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Arithmetic calculation | At Seongmin's school, there are upper and lower math classes. The math average of the top 20 students in the upper class is 42 points, and the average of the bottom 20 students in the lower class is 38 points. What is the average math score of Seongmin's class? | 40 | 20 42 [OP_MUL] 20 38 [OP_MUL] [OP_ADD] 20 20 [OP_ADD] [OP_DIV] | var_a = 20
var_b = 42
var_c = var_a * var_b
var_d = 20
var_e = 38
var_f = var_d * var_e
var_g = var_c + var_f
var_h = 20
var_i = 20
var_j = var_h + var_i
var_k = var_g / var_j
print(int(var_k)) |
Possibility | Yeonji wants to make a three-digit number by arranging the arrows when they hit the targets which have 2, 4, 6, and 8 written on them. In this case, find the sum of all possible numbers. | 35520 | [OP_LIST_SOL] 2 4 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM] | var_a = 2
var_b = 4
var_c = 6
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print(int(var_f)) |
Comparison | Find how many three-digit numbers 7A6 are less than 756. Each of the numbers from 0 to 9 can be in the place of A. | 5 | [OP_LIST_SOL] 7 A 6 [OP_LIST_EOL] [OP_LIST2NUM] [OP_GEN_POSSIBLE_LIST] 756 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 7
var_b = 'A'
var_c = 6
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d=""
for i in list_a:
i = str(i)
var_d = var_d + i
ans_dict = dict()
var_d = str(var_d)
list_b = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_d) == len(str(int(temp))):
new_elem = int(temp)
list_b.append(new_elem)
var_e = 756
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Possibility | There is a list of numbers: 3, 5, 6, and 7. You are going to use 2 numbers from it to create a two-digit number. What is the possible smallest number that is a multiple of 7? | 35 | [OP_LIST_SOL] 3 5 6 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 7 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN] | var_a = 3
var_b = 5
var_c = 6
var_d = 7
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 7
list_c = []
var_f = int(var_f)
for i in list_b:
i = int(i)
if i % var_f == 0:
list_c.append(i)
var_g = 1
list_d=list_c.copy()
list_d.sort()
var_h = list_d[var_g-1]
print(int(var_h)) |
Correspondence | The three-digit number 7A7 rounded up to the tens place is 730. Find A. | 2 | 7A7 [OP_GEN_POSSIBLE_LIST] 730 [OP_LIST_LESS_EQUAL] 730 10 [OP_SUB] [OP_LIST_MORE] 7A7 A [OP_LIST_FIND_UNK] | var_a = '7A7'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 730
list_b = []
for i in list_a:
if i <= var_b:
list_b.append(i)
var_c = 730
var_d = 10
var_e = var_c - var_d
list_c = []
for i in list_b:
if i > var_e:
list_c.append(i)
var_f = '7A7'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Geometry | Find the value of dividing the area of a rectangle in half when the rectangle has a width of 25 centimeters (cm) and a height of 16 centimeters (cm). | 200 | 25 16 [OP_MUL] 2 [OP_DIV] | var_a = 25
var_b = 16
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Comparison | One tomato was planted in the 8th row from the front, 14th row from the back, 7th row from the left, and 13th row from the right. If you plant the same number of tomatoes in each row, how many tomatoes will there be in your garden? | 399 | 8 14 [OP_ADD] 1 [OP_SUB] 7 13 [OP_ADD] 1 [OP_SUB] [OP_MUL] | var_a = 8
var_b = 14
var_c = var_a + var_b
var_d = 1
var_e = var_c - var_d
var_f = 7
var_g = 13
var_h = var_f + var_g
var_i = 1
var_j = var_h - var_i
var_k = var_e * var_j
print(int(var_k)) |
Correspondence | The shop owner had arranged 21.52 liters (L) of milk, but only 12.64 liters (L) were sold. Find the amount of liters (L) of the remaining milk. | 8.88 | 21.52 12.64 [OP_SUB] | var_a = 21.52
var_b = 12.64
var_c = var_a - var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | There are 5 fish A, B, C, D, and E. A is faster than B and slower than C. E is slower than D. B is faster than D. Which fish is the slowest? | E | [OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B > A C < E D < B D > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'A'
var_g = 'B'
var_h = '>'
var_i = 'A'
var_j = 'C'
var_k = '<'
var_l = 'E'
var_m = 'D'
var_n = '<'
var_o = 'B'
var_p = 'D'
var_q = '>'
list_b= []
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_r = len(list_c)
var_s = list_c[var_r-1]
print(var_s) |
Arithmetic calculation | There was 1 liter (L) of milk, of which Yeseul drank 0.1 liters (L), and Gayoung drank 0.2 liters (L) more than Yeseul. After a while, Hancho came and drank the milk, and as a result, there were 0.3 liters (L) left. How many liters (L) of milk did Hancho drink? | 0.3 | 1 0.1 [OP_SUB] 0.1 0.2 [OP_ADD] [OP_SUB] 0.3 [OP_SUB] | var_a = 1
var_b = 0.1
var_c = var_a - var_b
var_d = 0.1
var_e = 0.2
var_f = var_d + var_e
var_g = var_c - var_f
var_h = 0.3
var_i = var_g - var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Correspondence | If one of the 10 natural numbers with an average of 42 is set to 50, the average is 44. Find what this number was before fixing it. | 30 | 50 44 42 [OP_SUB] 10 [OP_MUL] [OP_SUB] | var_a = 50
var_b = 44
var_c = 42
var_d = var_b - var_c
var_e = 10
var_f = var_d * var_e
var_g = var_a - var_f
print(int(var_g)) |
Comparison | 22 people stand in a line in descending order according to their heights. When Youngchul is the 13th person when counted from the back, where will Youngchul be, when counted from the back, when all the people line up in ascending order? Answer using an ordinal number. | 10 | 22 13 [OP_SUB] 1 [OP_ADD] | var_a = 22
var_b = 13
var_c = var_a - var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Correspondence | A+B+B=814.8. When you move the decimal point of B one place to the right, it becomes equivalent to A. Calculate the value of A-B including the decimal point. | 611.1 | 814.8 10 2 [OP_ADD] [OP_DIV] 10 [OP_MUL] 814.8 10 2 [OP_ADD] [OP_DIV] [OP_SUB] | var_a = 814.8
var_b = 10
var_c = 2
var_d = var_b + var_c
var_e = var_a / var_d
var_f = 10
var_g = var_e * var_f
var_h = 814.8
var_i = 10
var_j = 2
var_k = var_i + var_j
var_l = var_h / var_k
var_m = var_g - var_l
print('{:.2f}'.format(round(var_m+1e-10,2))) |
Arithmetic calculation | How many two-digit natural numbers have both odd digits or both even digits? | 45 | 11 99 1 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] 2 [OP_LIST_DIVISIBLE] [OP_LIST_LEN] | var_a = 11
var_b = 99
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
list_b=[]
for i in list_a:
var_d = 0
i = int(i)
while i//10 > 0:
var_d = var_d + i%10
i = i//10
var_d = var_d + i%10
list_b.append(var_d)
var_e = 2
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = len(list_c)
print(int(var_f)) |
Arithmetic calculation | Nine oil paintings and seven watercolor paintings are pasted on the walls of the classroom. How many pictures are on the walls of the classroom? | 16 | 9 7 [OP_ADD] | var_a = 9
var_b = 7
var_c = var_a + var_b
print(int(var_c)) |
Correspondence | Young-gi gave Suji 300 won more than 2/5 of the money he had, and saved 200 won less than 1/2 of the remaining money. If the remaining money is 800 won, how much money did Young-gi have at the beginning? | 2500 | 800 200 [OP_SUB] 1 1/2 [OP_SUB] [OP_DIV] 300 [OP_ADD] 1 2/5 [OP_SUB] [OP_DIV] | var_a = 800
var_b = 200
var_c = var_a - var_b
var_d = 1
var_e = 0.5
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 300
var_i = var_g + var_h
var_j = 1
var_k = 0.4
var_l = var_j - var_k
var_m = var_i / var_l
print(int(var_m)) |
Possibility | We are trying to line up two fruits from among Apples, Peaches, Pears, Melons, and Strawberries. How many possible cases are there? | 20 | [OP_LIST_SOL] Apples Peaches Pears Melons Strawberries [OP_LIST_EOL] [OP_LIST_LEN] 2 [OP_PERM] | var_a = 'Apples'
var_b = 'Peaches'
var_c = 'Pears'
var_d = 'Melons'
var_e = 'Strawberries'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = len(list_a)
var_g = 2
var_h = 1
var_f = int(var_f)
var_g = int(var_g)
for i, elem in enumerate(range(var_g)):
var_h = var_h * (var_f-i)
print(int(var_h)) |
Correspondence | There is a number that equals twice the sum of the quotient of 40 divided by 8 and the quotient of 34 divided by 12. Find this number. | 14 | 40 8 [OP_FDIV] 34 12 [OP_FDIV] [OP_ADD] 2 [OP_MUL] | var_a = 40
var_b = 8
var_c = var_a // var_b
var_d = 34
var_e = 12
var_f = var_d // var_e
var_g = var_c + var_f
var_h = 2
var_i = var_g * var_h
print(int(var_i)) |
Arithmetic calculation | Find how many multiples of 3 ends in 3 that are less than 1000. | 34 | 1 1000 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 1 3 [OP_LIST_SEARCH_FIXED_DIGIT] [OP_LIST_LEN] | var_a = 1
var_b = 1000
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 3
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 1
var_f = 3
list_c = []
var_e = int(var_e)
var_f = int(var_f)
for i in list_b:
i = int(i)
if (i//var_e)%10 == var_f:
list_c.append(i)
var_g = len(list_c)
print(int(var_g)) |
Comparison | Students stand in a line. There is no one in front of Taehyung and there are three people between Taehyung and Namjoon. If 8 people are standing behind Namjoon, how many students are in the line? | 13 | 1 3 [OP_ADD] 1 [OP_ADD] 8 [OP_ADD] | var_a = 1
var_b = 3
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
var_f = 8
var_g = var_e + var_f
print(int(var_g)) |
Correspondence | A number is subtracted by 1.9, multiplied by 1.5, and added by 32. And finally, you divided it by 2.5 and you got 20. What is the number, including the decimal point? | 13.9 | 20 2.5 [OP_MUL] 32 [OP_SUB] 1.5 [OP_DIV] 1.9 [OP_ADD] | var_a = 20
var_b = 2.5
var_c = var_a * var_b
var_d = 32
var_e = var_c - var_d
var_f = 1.5
var_g = var_e / var_f
var_h = 1.9
var_i = var_g + var_h
print('{:.2f}'.format(round(var_i+1e-10,2))) |
Possibility | If you write down all the even numbers that are less than 100 and that are multiples of 3 on a piece of paper, how many times do you have to write down the figure '1'? | 2 | 1 100 [OP_LIST_EVEN] 3 [OP_LIST_DIVISIBLE] [OP_LIST2NUM] [OP_NUM2LIST] 1 [OP_LIST_FIND_NUM] | var_a = 1
var_b = 100
list_a = []
if var_a%2!=0:
for i in range(var_a+1, var_b+1, 2):
list_a.append(i)
else:
for i in range(var_a, var_b+1, 2):
list_a.append(i)
var_c = 3
list_b = []
var_c = int(var_c)
for i in list_a:
i = int(i)
if i % var_c == 0:
list_b.append(i)
var_d=""
for i in list_b:
i = str(i)
var_d = var_d + i
list_c = []
var_d = int(var_d)
while var_d//10 > 0:
list_c.append(var_d%10)
var_d = var_d//10
list_c.append(var_d%10)
list_c = list_c[::-1]
var_e = 1
var_f = 0
var_e = int(var_e)
for i in list_c:
i = int(i)
if i == var_e:
var_f = var_f + 1
print(int(var_f)) |
Geometry | When the roof is drawn on drawing paper, it is the trapezoid whose length of the upper side is 6 centimeters (cm) shorter than the length of the lower side, and the height is 8 centimeters (cm). If the area of the roof is 72 square centimeters (cm2), find the length of the upper side of the roof. | 6 | 72 2 [OP_MUL] 8 [OP_DIV] 6 [OP_SUB] 2 [OP_DIV] | var_a = 72
var_b = 2
var_c = var_a * var_b
var_d = 8
var_e = var_c / var_d
var_f = 6
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Correspondence | Multiply a number by 5 to get 100. What is the result when the number is divided by 10? | 2 | 100 5 [OP_DIV] 10 [OP_DIV] | var_a = 100
var_b = 5
var_c = var_a / var_b
var_d = 10
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | The number of apples Minjin has is divided by 8. Seongyeong gave 8 to Minjin, but Bong-Geon took 30 of them. If the remaining number of apples is 12 when multiplied by 6, how many apples does Minjin have at the beginning? | 192 | 12 6 [OP_DIV] 30 [OP_ADD] 8 [OP_SUB] 8 [OP_MUL] | var_a = 12
var_b = 6
var_c = var_a / var_b
var_d = 30
var_e = var_c + var_d
var_f = 8
var_g = var_e - var_f
var_h = 8
var_i = var_g * var_h
print(int(var_i)) |
Possibility | You are given three numbers 1, 7, and 9. How many two-digit numbers can be formed using a given number once? | 6 | [OP_LIST_SOL] 1 7 9 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 1
var_b = 7
var_c = 9
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Comparison | Hoseok kicked jegi 48 times. Jinsu kicked jegi 15 times each in the 1st and 2nd attempt. At least how many times should Jinsu kick jegi in the 3rd attempt, in order to kick more than Hoseok? | 19 | 48 15 15 [OP_ADD] [OP_SUB] 1 [OP_ADD] | var_a = 48
var_b = 15
var_c = 15
var_d = var_b + var_c
var_e = var_a - var_d
var_f = 1
var_g = var_e + var_f
print(int(var_g)) |
Possibility | I am trying to make a two-digit number by picking two different numbers from 3, 5, 7, and 8. Find the sum of the largest and smallest possible numbers. | 122 | [OP_LIST_SOL] 3 5 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD] | var_a = 3
var_b = 5
var_c = 7
var_d = 8
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 1
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
var_h = 1
list_d=list_b.copy()
list_d.sort()
var_i = list_d[var_h-1]
var_j = var_g + var_i
print(int(var_j)) |
Comparison | Which of the five numbers 5, 8, 4, 3, 2 is the second largest? | 5 | [OP_LIST_SOL] 5 8 4 3 2 [OP_LIST_EOL] 2 [OP_LIST_MAX] | var_a = 5
var_b = 8
var_c = 4
var_d = 3
var_e = 2
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 2
list_b=list_a.copy()
list_b.sort()
var_g = list_b[-var_f]
print(int(var_g)) |
Arithmetic calculation | How many meters (m) would it be if you fold a 12 meters (m) long string in half and then fold it in half again? | 3 | 12 2 [OP_DIV] 2 [OP_DIV] | var_a = 12
var_b = 2
var_c = var_a / var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Possibility | You are trying to make two digit natural numbers with 2, 3, and 7. Find the second smallest possible number. | 23 | [OP_LIST_SOL] 2 3 7 [OP_LIST_EOL] 2 [OP_LIST_GET_PRODUCT] 2 [OP_LIST_MIN] | var_a = 2
var_b = 3
var_c = 7
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 2
list_c=list_b.copy()
list_c.sort()
var_f = list_c[var_e-1]
print(int(var_f)) |
Correspondence | Subtracting a number by 69 resulted in 37. Find the value of the result by adding 55 to the number. | 161 | 69 37 [OP_ADD] 55 [OP_ADD] | var_a = 69
var_b = 37
var_c = var_a + var_b
var_d = 55
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Minyoung has 4 marbles and Yujeong has 2. Eunji has 1 more marble than Minyoung. Who has the most marbles? | Eunji | [OP_LIST_SOL] Minyoung Yujeong Eunji [OP_LIST_EOL] [OP_LIST_SOL] 4 2 4 1 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Minyoung'
var_b = 'Yujeong'
var_c = 'Eunji'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 4
var_e = 2
var_f = 4
var_g = 1
var_h = var_f + var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | There are three numbers 85.9, 5.31, and 43/2. What is the sum of them all? | 112.71 | 85.9 5.31 [OP_ADD] 43/2 [OP_ADD] | var_a = 85.9
var_b = 5.31
var_c = var_a + var_b
var_d = 21.5
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Comparison | Juri is taller than Jungwoo. Myunghyun is taller than Seokjin. Juri is shorter than Jungkook. Myunghyun is shorter than Jungwoo. Who is the tallest? | Jungkook | [OP_LIST_SOL] Juri Jungwoo Myunghyun Seokjin Jungkook [OP_LIST_EOL] [OP_LIST_SOL] Juri Jungwoo > Myunghyun Seokjin > Juri Jungkook < Myunghyun Jungwoo < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET] | var_a = 'Juri'
var_b = 'Jungwoo'
var_c = 'Myunghyun'
var_d = 'Seokjin'
var_e = 'Jungkook'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 'Juri'
var_g = 'Jungwoo'
var_h = '>'
var_i = 'Myunghyun'
var_j = 'Seokjin'
var_k = '>'
var_l = 'Juri'
var_m = 'Jungkook'
var_n = '<'
var_o = 'Myunghyun'
var_p = 'Jungwoo'
var_q = '<'
list_b= []
if "/" in str(var_q):
var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_p):
var_p = eval(str(var_p))
list_b.append(var_p)
if "/" in str(var_o):
var_o = eval(str(var_o))
list_b.append(var_o)
if "/" in str(var_n):
var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_r = 1
var_s = list_c[var_r-1]
print(var_s) |
Arithmetic calculation | There are five numbers 10, 11, 12, 13, and 14. What is the quotient of the smallest number divided by the second smallest number? | 0 | [OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_FDIV] | var_a = 10
var_b = 11
var_c = 12
var_d = 13
var_e = 14
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
list_b=list_a.copy()
list_b.sort()
var_g = list_b[var_f-1]
var_h = 2
list_c=list_a.copy()
list_c.sort()
var_i = list_c[var_h-1]
var_j = var_g // var_i
print(int(var_j)) |
Arithmetic calculation | 3 out of the 4 natural numbers 4, 6, 8, and 9 were chosen to form a three-digit natural number. How many of these are less than 500? | 6 | [OP_LIST_SOL] 4 6 8 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 500 [OP_LIST_LESS] [OP_LIST_LEN] | var_a = 4
var_b = 6
var_c = 8
var_d = 9
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 500
list_c = []
for i in list_b:
if i < var_f:
list_c.append(i)
var_g = len(list_c)
print(int(var_g)) |
Comparison | Yoongi and Jisoo rode bicycles. Starting from the same place, Jisoo ran 19,000 meters (m) in an hour and Yoongi ran 22 kilometers (km) in an hour. Who moved more in an hour? | Yoongi | [OP_LIST_SOL] Yoongi Jisoo [OP_LIST_EOL] [OP_LIST_SOL] 22 1000 [OP_MUL] 19000 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jisoo'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 22
var_d = 1000
var_e = var_c * var_d
var_f = 19000
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Comparison | Classes 1 and 2 shared the 1000 marbles they received as prizes. At this time, class 2 took 50 less than class 1, and male students in class 2 took a total of 35 more than female students in class 2. If there are 17 boys in class 2 and the boys share equally, how many marbles will each boy in class 2 receive? | 15 | 1000 50 [OP_SUB] 2 [OP_DIV] 35 [OP_SUB] 2 [OP_DIV] 35 [OP_ADD] 17 [OP_DIV] | var_a = 1000
var_b = 50
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
var_f = 35
var_g = var_e - var_f
var_h = 2
var_i = var_g / var_h
var_j = 35
var_k = var_i + var_j
var_l = 17
var_m = var_k / var_l
print(int(var_m)) |
Possibility | How many different ways are there for Jungkook, Jimin, Seokjin, and Yuna to stand in a line and take a picture? | 24 | [OP_LIST_SOL] Jungkook Jimin Seokjin Yuna [OP_LIST_EOL] [OP_LIST_LEN] 4 [OP_PERM] | var_a = 'Jungkook'
var_b = 'Jimin'
var_c = 'Seokjin'
var_d = 'Yuna'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
var_f = 4
var_g = 1
var_e = int(var_e)
var_f = int(var_f)
for i, elem in enumerate(range(var_f)):
var_g = var_g * (var_e-i)
print(int(var_g)) |
Geometry | The perimeter of a rectangle is 46 centimeters (cm), and its width is 7 centimeters (cm) longer than its length. What is the width of this rectangle? | 15 | 46 2 [OP_DIV] 7 [OP_SUB] 2 [OP_DIV] 7 [OP_ADD] | var_a = 46
var_b = 2
var_c = var_a / var_b
var_d = 7
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 7
var_i = var_g + var_h
print(int(var_i)) |
Arithmetic calculation | You would like to install flags at intervals of 30 meters (m) on a road that is 1 kilometer (km) and 500 meters (m) long. If the price of one flag is 5,000 won, how much does it cost to buy the required flag? | 250000 | 1 1000 [OP_MUL] 500 [OP_ADD] 30 [OP_DIV] 5000 [OP_MUL] | var_a = 1
var_b = 1000
var_c = var_a * var_b
var_d = 500
var_e = var_c + var_d
var_f = 30
var_g = var_e / var_f
var_h = 5000
var_i = var_g * var_h
print(int(var_i)) |
Arithmetic calculation | When you weighed a barrel full of fish of the same weight, it was 54 kilograms (kg). Then the barrel weighed 29 kilograms (kg) after being removed of the half of fish. What is the weight of fish that was in the barrel at first in kilograms (kg)? | 50 | 54 29 [OP_SUB] 2 [OP_MUL] | var_a = 54
var_b = 29
var_c = var_a - var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Possibility | Out of 7 volleyball players, we are trying to select 6 players to start. Find the number of all possible cases. | 7 | 7 6 [OP_COMB] | var_a = 7
var_b = 6
var_c = 1
var_a = int(var_a)
var_b = int(var_b)
for i, elem in enumerate(range(var_b)):
var_c = var_c * (var_a-i)
for i, elem in enumerate(range(var_b)):
var_c = var_c / (i+1)
print(int(var_c)) |
Arithmetic calculation | Yuna is 8 years old this year. Her father is 20 years older than Yuna, and her grandfather is 25 years older than her father. How old is her grandfather this year? | 53 | 8 20 [OP_ADD] 25 [OP_ADD] | var_a = 8
var_b = 20
var_c = var_a + var_b
var_d = 25
var_e = var_c + var_d
print(int(var_e)) |
Geometry | The sum of the lengths of the four sides of a rectangle with a width of 20 cm (cm) is equal to the perimeter of a regular pentagon with a side length of 10 cm (cm). Find out what the length of this rectangle is. | 5 | 10 5 [OP_MUL] 2 [OP_DIV] 20 [OP_SUB] | var_a = 10
var_b = 5
var_c = var_a * var_b
var_d = 2
var_e = var_c / var_d
var_f = 20
var_g = var_e - var_f
print(int(var_g)) |
Arithmetic calculation | The sum of the price of a pencil and a notebook is 950 won. If a notebook costs 150 won more than a pencil, how much is the pencil? | 400 | 950 150 [OP_SUB] 2 [OP_DIV] | var_a = 950
var_b = 150
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Correspondence | You mistakenly subtracted 7/3 from a number instead of adding it, so you got 3/2 as a result. How much is it if you calculate it correctly? | 6.17 | 3/2 7/3 [OP_ADD] 7/3 [OP_ADD] | var_a = 1.5
var_b = 2.3333333333333335
var_c = var_a + var_b
var_d = 2.3333333333333335
var_e = var_c + var_d
print('{:.2f}'.format(round(var_e+1e-10,2))) |
Possibility | When 0, 2, and 4 are used once to make three-digit numbers, how many three-digit numbers can be formed? | 4 | [OP_LIST_SOL] 0 2 4 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN] | var_a = 0
var_b = 2
var_c = 4
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = len(list_b)
print(int(var_e)) |
Arithmetic calculation | If 5 out of 9 volleyballs are lent to other schools, what is the number of volleyballs left? | 4 | 9 5 [OP_SUB] | var_a = 9
var_b = 5
var_c = var_a - var_b
print(int(var_c)) |
Comparison | Of the five numbers 1.4, 9/10, 1.2, 0.5, and 13/10, how many are greater than or equal to 1.1? | 3 | [OP_LIST_SOL] 1.4 9/10 1.2 0.5 13/10 [OP_LIST_EOL] 1.1 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN] | var_a = 1.4
var_b = 0.9
var_c = 1.2
var_d = 0.5
var_e = 1.3
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1.1
list_b = []
for i in list_a:
if i >= var_f:
list_b.append(i)
var_g = len(list_b)
print(int(var_g)) |
Comparison | Find the number of numbers less than or equal to 0.4 among 0.8, 1/2, and 0.3. | 1 | [OP_LIST_SOL] 0.8 1/2 0.3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN] | var_a = 0.8
var_b = 0.5
var_c = 0.3
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 0.4
list_b = []
for i in list_a:
if i <= var_d:
list_b.append(i)
var_e = len(list_b)
print(int(var_e)) |
Arithmetic calculation | Gyungcho walked to school on 11 days out of 100 days and took a bus on other days. How many times is the day he went to school on foot compared to the entire day he went to school? | 0.11 | 11 100 [OP_DIV] | var_a = 11
var_b = 100
var_c = var_a / var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Comparison | Yoongi has 4 apples and Jungkook has 6 divided by 3 apples. Who has fewer apples? | Jungkook | [OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 4 6 3 [OP_FDIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Yoongi'
var_b = 'Jungkook'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 4
var_d = 6
var_e = 3
var_f = var_d // var_e
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[var_g-1]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Correspondence | When a number is multiplied by 5 and then divided by 8, the quotient is 156 and the remainder is 2. Find a number. | 250 | 156 8 [OP_MUL] 2 [OP_ADD] 5 [OP_DIV] | var_a = 156
var_b = 8
var_c = var_a * var_b
var_d = 2
var_e = var_c + var_d
var_f = 5
var_g = var_e / var_f
print(int(var_g)) |
Geometry | How many centimeters (cm) is one edge of a cube-shaped cabinet the volume of which is 204,000 cubic centimeters (cm3) smaller than the volume of a rectangular cuboid-shaped cabinet with a base width of 70 centimeters (cm), a base length of 40 centimeters (cm), and a height of 150 centimeters (cm)? | 60 | 70 40 [OP_MUL] 150 [OP_MUL] 204000 [OP_SUB] 1/3 [OP_POW] | var_a = 70
var_b = 40
var_c = var_a * var_b
var_d = 150
var_e = var_c * var_d
var_f = 204000
var_g = var_e - var_f
var_h = 0.3333333333333333
var_i = var_g ** var_h
print(int(eval('{:.2f}'.format(round(var_i+1e-10,2))))) |
Geometry | The width of the rectangle is 3 centimeters (cm) longer than the length of the rectangle. If the perimeter of the rectangle is 54 centimeters (cm), what is the length of its width? | 15 | 54 2 [OP_DIV] 3 [OP_SUB] 2 [OP_DIV] 3 [OP_ADD] | var_a = 54
var_b = 2
var_c = var_a / var_b
var_d = 3
var_e = var_c - var_d
var_f = 2
var_g = var_e / var_f
var_h = 3
var_i = var_g + var_h
print(int(var_i)) |
Comparison | Jungkook, Taehyung, and Minyoung had a running race. Jungkook arrived at the finish line first, followed by Minyoung and Taehyung. What rank does Taehyung in? | 3 | [OP_LIST_SOL] Jungkook Minyoung Taehyung [OP_LIST_EOL] Taehyung [OP_LIST_INDEX] | var_a = 'Jungkook'
var_b = 'Minyoung'
var_c = 'Taehyung'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 'Taehyung'
var_e = list_a.index(var_d)+1
print(int(var_e)) |
Geometry | There is a chair in the shape of a parallelogram. One side is 18 centimeters (cm) and the other side is 12 centimeters (cm). What is the circumference of this chair? | 60 | 18 12 [OP_ADD] 2 [OP_MUL] | var_a = 18
var_b = 12
var_c = var_a + var_b
var_d = 2
var_e = var_c * var_d
print(int(var_e)) |
Correspondence | Rounding down 6A35 to the nearest hundreds gives 6100. Find A. | 1 | 6A35 [OP_GEN_POSSIBLE_LIST] 6100 [OP_LIST_MORE_EQUAL] 6100 100 [OP_ADD] [OP_LIST_LESS] 6A35 A [OP_LIST_FIND_UNK] | var_a = '6A35'
ans_dict = dict()
var_a = str(var_a)
list_a = []
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 0
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
if len(var_a) == len(str(int(temp))):
new_elem = int(temp)
list_a.append(new_elem)
var_b = 6100
list_b = []
for i in list_a:
if i >= var_b:
list_b.append(i)
var_c = 6100
var_d = 100
var_e = var_c + var_d
list_c = []
for i in list_b:
if i < var_e:
list_c.append(i)
var_f = '6A35'
var_g = 'A'
var_f = str(var_f)
var_g = str(var_g)
unk_idx = var_f.index(var_g)
var_h = 0
for elem in list_c:
elem = str(elem)
var_h = int(elem[unk_idx])
print(int(var_h)) |
Comparison | Minyoung has 13 breads and Eunji has 21. Who has more bread? | Eunji | [OP_LIST_SOL] Minyoung Eunji [OP_LIST_EOL] [OP_LIST_SOL] 13 21 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Minyoung'
var_b = 'Eunji'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 13
var_d = 21
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = list_b.index(var_f)+1
var_h = list_a[var_g-1]
print(var_h) |
Arithmetic calculation | There are 2180 liters (L) of water. There are a total of 12 200 liters (L) barrels and 150 liters (L) barrels. When all the water was divided, 30 liters (L) remained. How many 200-liter (L) barrels are there? | 7 | 2180 30 [OP_SUB] 150 12 [OP_MUL] [OP_SUB] 200 150 [OP_SUB] [OP_DIV] | var_a = 2180
var_b = 30
var_c = var_a - var_b
var_d = 150
var_e = 12
var_f = var_d * var_e
var_g = var_c - var_f
var_h = 200
var_i = 150
var_j = var_h - var_i
var_k = var_g / var_j
print(int(var_k)) |
Possibility | Find the difference between the largest and smallest four-digit numbers that can be made using the number cards 2, 0, 3, 5, and 8. | 6497 | [OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 2
var_b = 0
var_c = 3
var_d = 5
var_e = 8
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 4
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 1
list_d=list_b.copy()
list_d.sort()
var_j = list_d[var_i-1]
var_k = var_h - var_j
print(int(var_k)) |
Comparison | What is the sum of the numbers greater than 0.4 among 0.8, 1/2, 0.3, and 1/3? | 1.3 | [OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_MORE] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.3
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.4
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Arithmetic calculation | It is said that one doll factory makes an average of 18 dolls per hour. If you sell dolls that were made in this factory for 25 days with 8 hours a day, for 2,750 won for each doll, how much money can you get from selling all the dolls? | 9900000 | 18 8 [OP_MUL] 25 [OP_MUL] 2750 [OP_MUL] | var_a = 18
var_b = 8
var_c = var_a * var_b
var_d = 25
var_e = var_c * var_d
var_f = 2750
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | You want to plant trees at intervals of 10 meters (m) on a 100-meter (m) long road. If trees are to be planted at the beginning and end of the road, how many trees are needed if they are planted on both sides of the road? | 22 | 100 10 [OP_DIV] 1 [OP_ADD] 2 [OP_MUL] | var_a = 100
var_b = 10
var_c = var_a / var_b
var_d = 1
var_e = var_c + var_d
var_f = 2
var_g = var_e * var_f
print(int(var_g)) |
Arithmetic calculation | In a two-digit natural number whose tens digit is 3, when the tens and ones digits are switched, the first number is the same as adding 9 to the switched number. What is the original number? | 32 | 3 10 [OP_MUL] 9 [OP_SUB] 3 [OP_SUB] 10 1 [OP_SUB] [OP_DIV] 3 10 [OP_MUL] [OP_ADD] | var_a = 3
var_b = 10
var_c = var_a * var_b
var_d = 9
var_e = var_c - var_d
var_f = 3
var_g = var_e - var_f
var_h = 10
var_i = 1
var_j = var_h - var_i
var_k = var_g / var_j
var_l = 3
var_m = 10
var_n = var_l * var_m
var_o = var_k + var_n
print(int(var_o)) |
Comparison | What is the total of numbers less than or equal to 0.4 among 0.8, 1/2, 0.3, and 1/3? | 0.63 | [OP_LIST_SOL] 0.8 1/2 0.3 1/3 [OP_LIST_EOL] 0.4 [OP_LIST_LESS_EQUAL] [OP_LIST_SUM] | var_a = 0.8
var_b = 0.5
var_c = 0.3
var_d = 0.3333333333333333
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 0.4
list_b = []
for i in list_a:
if i <= var_e:
list_b.append(i)
list_b = [float(i) for i in list_b]
var_f = sum(list_b)
print('{:.2f}'.format(round(var_f+1e-10,2))) |
Comparison | Two people are standing in front of Jungkook, and four people are standing behind him. If there are 8 people in Jungkook's line and there are the same number of people in each line, how many people are there in total? | 56 | 2 4 [OP_ADD] 1 [OP_ADD] 8 [OP_MUL] | var_a = 2
var_b = 4
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
var_f = 8
var_g = var_e * var_f
print(int(var_g)) |
Geometry | There is a cube with one edge 9 centimeters (cm) long. If you cut a cube from the middle of each edge with one edge 3 centimeters (cm) long, what is the volume in cubic centimeters (cm3) of the remaining part? | 702 | 9 3 [OP_POW] 3 3 [OP_POW] [OP_SUB] | var_a = 9
var_b = 3
var_c = var_a ** var_b
var_d = 3
var_e = 3
var_f = var_d ** var_e
var_g = var_c - var_f
print(int(var_g)) |
Comparison | You found two round-shaped jewels in the cave. A gem A is 10 centimeters (cm) in diameter, and the other gem B is 4 centimeters (cm) in radius. The larger size is more expensive. If you're going to bring something more expensive, what should you bring? | A | [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 2 [OP_DIV] 4 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 10
var_d = 2
var_e = var_c / var_d
var_f = 4
list_b= []
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_g = 1
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = list_b.index(var_h)+1
var_j = list_a[var_i-1]
print(var_j) |
Geometry | There is an isosceles triangle. When the bisector of the vertical angle is drawn, the length of the base is divided by 4 centimeters (cm). What is the length of the base in centimeters (cm) ? | 8 | 4 2 [OP_MUL] | var_a = 4
var_b = 2
var_c = var_a * var_b
print(int(var_c)) |
Correspondence | I mistakenly subtracted a certain number from 954 instead of adding, and I got 468. Find out how much it is if you calculate it correctly. | 1440 | 954 468 [OP_SUB] 954 [OP_ADD] | var_a = 954
var_b = 468
var_c = var_a - var_b
var_d = 954
var_e = var_c + var_d
print(int(var_e)) |
Comparison | Jungkook, Hoseok, and Seokjin shared colored paper. Jungkook took 10 cards, Hoseok took 7, and Seokjin took 2 less than Jungkook. Which of the three people took the fewest pieces of colored paper? | Hoseok | [OP_LIST_SOL] Jungkook Hoseok Seokjin [OP_LIST_EOL] [OP_LIST_SOL] 10 7 10 2 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'Jungkook'
var_b = 'Hoseok'
var_c = 'Seokjin'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 10
var_e = 7
var_f = 10
var_g = 2
var_h = var_f - var_g
list_b= []
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[var_i-1]
var_k = list_b.index(var_j)+1
var_l = list_a[var_k-1]
print(var_l) |
Arithmetic calculation | There is a certain number that, when divided by 12, have a quotient of 25 and a remainder of 11. What is the difference between 25 and the number? | 286 | 12 25 [OP_MUL] 11 [OP_ADD] 25 [OP_SUB] | var_a = 12
var_b = 25
var_c = var_a * var_b
var_d = 11
var_e = var_c + var_d
var_f = 25
var_g = var_e - var_f
print(int(var_g)) |
Arithmetic calculation | The father's age will double the daughter's age in 12 years and is now triple. How old is the daughter this year? | 12 | 12 2 [OP_MUL] 12 [OP_SUB] 3 2 [OP_SUB] [OP_DIV] | var_a = 12
var_b = 2
var_c = var_a * var_b
var_d = 12
var_e = var_c - var_d
var_f = 3
var_g = 2
var_h = var_f - var_g
var_i = var_e / var_h
print(int(var_i)) |
Possibility | You want to make a 7-digit number using the numbers 3, 9, 6, 0, 5, 1, and 7 only once. What is the difference between the largest and smallest number in all possible numbers? | 8729631 | [OP_LIST_SOL] 3 9 6 0 5 1 7 [OP_LIST_EOL] 7 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB] | var_a = 3
var_b = 9
var_c = 6
var_d = 0
var_e = 5
var_f = 1
var_g = 7
list_a= []
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 7
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_h))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_i = 1
list_c=list_b.copy()
list_c.sort()
var_j = list_c[-var_i]
var_k = 1
list_d=list_b.copy()
list_d.sort()
var_l = list_d[var_k-1]
var_m = var_j - var_l
print(int(var_m)) |
Arithmetic calculation | If 63 people are equally in 9 cars, how many people are in one car? | 7 | 63 9 [OP_DIV] | var_a = 63
var_b = 9
var_c = var_a / var_b
print(int(var_c)) |
Comparison | Namjoon was the 43rd to buy the book at the bookstore, and Taehyung bought the book after 10 more people bought the book after Namjoon. In what number did Taehyung buy the book? | 54 | 43 10 [OP_ADD] 1 [OP_ADD] | var_a = 43
var_b = 10
var_c = var_a + var_b
var_d = 1
var_e = var_c + var_d
print(int(var_e)) |
Comparison | As a result of the Korean language test conducted at the school, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung received the highest score in that order. Who got the highest score? | Taehyung | [OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET] | var_a = 'Taehyung'
var_b = 'Minju'
var_c = 'Sangmin'
var_d = 'Yoonjung'
var_e = 'Yoojung'
list_a= []
if "/" in str(var_e):
var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 1
var_g = list_a[var_f-1]
print(var_g) |
Possibility | Play ball toss. If you hit inside the red circle, you get 5 points, if you hit inside the yellow circle, you get 2 points, and if you don't fit inside both circles, you get 0 points. How many possible points can you get by throwing the ball three times? | 18 | [OP_LIST_SOL] 5 2 0 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] [OP_LIST_LEN] | var_a = 5
var_b = 2
var_c = 0
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
var_e = 0
i = int(i)
while i//10 > 0:
var_e = var_e + i%10
i = i//10
var_e = var_e + i%10
list_c.append(var_e)
var_f = len(list_c)
print(int(var_f)) |
Geometry | Find the difference between the area of a square with a perimeter of 36 centimeters (cm) and a rectangle with a width of 15 centimeters (cm) and a perimeter of 38 centimeters (cm). | 21 | 36 4 [OP_DIV] 2 [OP_POW] 38 2 [OP_DIV] 15 [OP_SUB] 15 [OP_MUL] [OP_SUB] [OP_ABS] | var_a = 36
var_b = 4
var_c = var_a / var_b
var_d = 2
var_e = var_c ** var_d
var_f = 38
var_g = 2
var_h = var_f / var_g
var_i = 15
var_j = var_h - var_i
var_k = 15
var_l = var_j * var_k
var_m = var_e - var_l
var_n = abs(var_m)
print(int(var_n)) |
Arithmetic calculation | It is said that the average Korean language test scores of the four classes is 64, 73, 69, and 82, respectively. How many classes are there with an average above 70? | 2 | [OP_LIST_SOL] 64 73 69 82 [OP_LIST_EOL] 70 [OP_LIST_MORE] [OP_LIST_LEN] | var_a = 64
var_b = 73
var_c = 69
var_d = 82
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 70
list_b = []
for i in list_a:
if i > var_e:
list_b.append(i)
var_f = len(list_b)
print(int(var_f)) |
Correspondence | You had to subtract 16 from a certain number, but you mistakenly add it, and the result was 64. What is the value if you calculate correctly? | 32 | 64 16 [OP_SUB] 16 [OP_SUB] | var_a = 64
var_b = 16
var_c = var_a - var_b
var_d = 16
var_e = var_c - var_d
print(int(var_e)) |
Arithmetic calculation | When Sungmo solved and scored the math problems, he got 1/5 of the questions wrong. How many times the number of questions answered correctly is the total number of questions? | 0.8 | 1 1/5 [OP_SUB] | var_a = 1
var_b = 0.2
var_c = var_a - var_b
print('{:.2f}'.format(round(var_c+1e-10,2))) |
Arithmetic calculation | A baseball is 1/4 the radius of a basketball. When calculating the volume of a baseball and basketball, how many times bigger is the volume of a basketball compared to that of a baseball? | 64 | 1 1/4 3 [OP_POW] [OP_DIV] | var_a = 1
var_b = 0.25
var_c = 3
var_d = var_b ** var_c
var_e = var_a / var_d
print(int(var_e)) |
Comparison | Seokjin is heavier than Hoseok and lighter than Jimin. Namjoon is heavier than Jimin. Which of the 4 is the lightest? | Hoseok | [OP_LIST_SOL] Seokjin Hoseok Jimin Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Seokjin Hoseok > Seokjin Jimin < Namjoon Jimin > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET] | var_a = 'Seokjin'
var_b = 'Hoseok'
var_c = 'Jimin'
var_d = 'Namjoon'
list_a= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 'Seokjin'
var_f = 'Hoseok'
var_g = '>'
var_h = 'Seokjin'
var_i = 'Jimin'
var_j = '<'
var_k = 'Namjoon'
var_l = 'Jimin'
var_m = '>'
list_b= []
if "/" in str(var_m):
var_m = eval(str(var_m))
list_b.append(var_m)
if "/" in str(var_l):
var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_j):
var_j = eval(str(var_j))
list_b.append(var_j)
if "/" in str(var_i):
var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_h):
var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
global item_name_index_dict
items_name_list = list_a.copy()
conditions = []
condition_list = list_b.copy()
temp_stack = []
for index_, cond_ in enumerate(map(str, condition_list)):
if cond_ in ("<", ">", "="):
operand_right = temp_stack.pop()
operand_left = temp_stack.pop()
if cond_ == "=":
cond_ = "=="
conditions.append(f"{operand_left} {cond_} {operand_right}")
else:
if not cond_.isdigit():
cond_ = "{" + cond_ + "}"
temp_stack.append(cond_)
item_name_index_dict = {}
for perm in itertools.permutations(range(1, len(items_name_list) + 1)):
item_name_index_dict = dict(zip(items_name_list, perm))
formatted_conditions = \
[condition.format_map(item_name_index_dict) for condition in conditions]
if all(map(eval, formatted_conditions)):
break
list_c = list(item_name_index_dict.keys())
list_c.sort(key=item_name_index_dict.get, reverse=True)
var_n = len(list_c)
var_o = list_c[var_n-1]
print(var_o) |
Arithmetic calculation | The sum of the prices of an apple and a pear is 15,000 won. If an apple costs 2,400 won more than a pear, what is the price of the pear? | 6300 | 15000 2400 [OP_SUB] 2 [OP_DIV] | var_a = 15000
var_b = 2400
var_c = var_a - var_b
var_d = 2
var_e = var_c / var_d
print(int(var_e)) |
Arithmetic calculation | When a number is divided by 75, the quotient is 11. Find the largest number. | 899 | 11 75 [OP_MUL] 75 1 [OP_SUB] [OP_ADD] | var_a = 11
var_b = 75
var_c = var_a * var_b
var_d = 75
var_e = 1
var_f = var_d - var_e
var_g = var_c + var_f
print(int(var_g)) |
Comparison | In a multiplication where both numbers are two digits, you multiplied 2 instead of 5 in the ones place of the number by mistake, and got a value of 704. If the correctly calculated value is 800, find what the larger digit of the two two-digit numbers is. | 32 | [OP_LIST_SOL] 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] 800 704 800 [OP_SUB] 2 5 [OP_SUB] [OP_DIV] [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MAX] | var_a = 704
var_b = 800
var_c = var_a - var_b
var_d = 2
var_e = 5
var_f = var_d - var_e
var_g = var_c / var_f
var_h = 800
var_i = 704
var_j = 800
var_k = var_i - var_j
var_l = 2
var_m = 5
var_n = var_l - var_m
var_o = var_k / var_n
var_p = var_h / var_o
list_a= []
if "/" in str(var_p):
var_p = eval(str(var_p))
list_a.append(var_p)
if "/" in str(var_g):
var_g = eval(str(var_g))
list_a.append(var_g)
list_a.reverse()
var_q = 1
list_b=list_a.copy()
list_b.sort()
var_r = list_b[-var_q]
print(int(var_r)) |
Arithmetic calculation | There is a tape measure that is 5 meters (m) long and weighs 29/8 kilograms (kg) and a computer that is 4 meters (m) long and weighs 2.8 kilograms (kg). If you cut a tape measure and computer into 2 meters (m) and weigh them together, how many kilograms (kg) do you get? | 2.85 | 29/8 5 [OP_DIV] 2 [OP_MUL] 2.8 4 [OP_DIV] 2 [OP_MUL] [OP_ADD] | var_a = 3.625
var_b = 5
var_c = var_a / var_b
var_d = 2
var_e = var_c * var_d
var_f = 2.8
var_g = 4
var_h = var_f / var_g
var_i = 2
var_j = var_h * var_i
var_k = var_e + var_j
print('{:.2f}'.format(round(var_k+1e-10,2))) |
Geometry | If you draw diagonals in a hexagon, what is the total number of diagonals? | 9 | 6 6 3 [OP_SUB] [OP_MUL] 2 [OP_DIV] | var_a = 6
var_b = 6
var_c = 3
var_d = var_b - var_c
var_e = var_a * var_d
var_f = 2
var_g = var_e / var_f
print(int(var_g)) |
Correspondence | B is C plus 185, and A is greater than B by 157. Find C when A is 680. | 338 | 680 157 [OP_SUB] 185 [OP_SUB] | var_a = 680
var_b = 157
var_c = var_a - var_b
var_d = 185
var_e = var_c - var_d
print(int(var_e)) |
Correspondence | There are two different numbers A and B. Find the sum of A and B given the two-digit subtraction equation 8A-B2=45. | 11 | 8A-B2=45 A [OP_DIGIT_UNK_SOLVER] 8A-B2=45 B [OP_DIGIT_UNK_SOLVER] [OP_ADD] | var_a = '8A-B2=45'
var_b = 'A'
ans_dict = dict()
var_a = var_a.replace('×','*')
var_a = var_a.replace('x','*')
var_a = var_a.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_a):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_a
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_a):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_c = ans_dict[var_b]
var_d = '8A-B2=45'
var_e = 'B'
ans_dict = dict()
var_d = var_d.replace('×','*')
var_d = var_d.replace('x','*')
var_d = var_d.replace('÷','/')
variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'])
for v in set(var_d):
if v in variable_candi:
ans_dict[v] = 1
candi = list(itertools.product('0123456789', repeat=len(ans_dict)))
for c in candi:
temp = var_d
for i, (k, _) in enumerate(ans_dict.items()):
temp = temp.replace(k, str(c[i]))
term_list = []
op_list = []
temp_c = ''
for tc in temp:
if tc not in '+-*/=><().':
temp_c += tc
else:
op_list.append(tc)
term_list.append(temp_c)
temp_c = ''
term_list.append(temp_c)
new_eq = ''
for i in range(len(op_list)):
new_eq += str(int(term_list[i]))+op_list[i]
new_eq += str(int(term_list[-1]))
if len(new_eq) == len(var_d):
new_eq=new_eq.replace('=', '==')
new_eq=new_eq.replace('>==', '>=')
new_eq=new_eq.replace('<==', '<=')
eval_result = False
try:
eval_result = eval(new_eq)
except:
pass
if eval_result:
for i, (k, _) in enumerate(ans_dict.items()):
ans_dict[k] = int(c[i])
var_f = ans_dict[var_e]
var_g = var_c + var_f
print(int(var_g)) |
Comparison | There are three different numbers A, B, and C. A is equal to 95 minus 35. B is 12 more than A. C is B minus 19. Which of A, B, and C is the greatest? | B | [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_SOL] 95 35 [OP_SUB] 95 35 [OP_SUB] 12 [OP_ADD] 95 35 [OP_SUB] 12 [OP_ADD] 19 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'A'
var_b = 'B'
var_c = 'C'
list_a= []
if "/" in str(var_c):
var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 95
var_e = 35
var_f = var_d - var_e
var_g = 95
var_h = 35
var_i = var_g - var_h
var_j = 12
var_k = var_i + var_j
var_l = 95
var_m = 35
var_n = var_l - var_m
var_o = 12
var_p = var_n + var_o
var_q = 19
var_r = var_p - var_q
list_b= []
if "/" in str(var_r):
var_r = eval(str(var_r))
list_b.append(var_r)
if "/" in str(var_k):
var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_f):
var_f = eval(str(var_f))
list_b.append(var_f)
list_b.reverse()
var_s = 1
list_c=list_b.copy()
list_c.sort()
var_t = list_c[-var_s]
var_u = list_b.index(var_t)+1
var_v = list_a[var_u-1]
print(var_v) |
Geometry | The length of the radius of the smallest circle enclosing a rhombus was 10 centimeters (cm). What is the area of the smaller rhombus drawn through the midpoints of all four sides of the rhombus? | 100 | 10 2 [OP_MUL] 2 [OP_POW] 2 [OP_DIV] 2 [OP_DIV] | var_a = 10
var_b = 2
var_c = var_a * var_b
var_d = 2
var_e = var_c ** var_d
var_f = 2
var_g = var_e / var_f
var_h = 2
var_i = var_g / var_h
print(int(var_i)) |
Arithmetic calculation | What is the largest three-digit number divisible by two numbers, 4 and 5? | 980 | 100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MAX] | var_a = 100
var_b = 999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 4
list_b = []
var_d = int(var_d)
for i in list_a:
i = int(i)
if i % var_d == 0:
list_b.append(i)
var_e = 5
list_c = []
var_e = int(var_e)
for i in list_b:
i = int(i)
if i % var_e == 0:
list_c.append(i)
var_f = 1
list_d=list_c.copy()
list_d.sort()
var_g = list_d[-var_f]
print(int(var_g)) |
Comparison | I have two puppies, an apple and a tangerine. The weight of an apple is 3/5 kilograms (kg), and the weight of a tangerine is 0.49 kilograms (kg). Which of the two is the heavier dog? | apple | [OP_LIST_SOL] apple tangerine [OP_LIST_EOL] [OP_LIST_SOL] 3/5 0.49 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET] | var_a = 'apple'
var_b = 'tangerine'
list_a= []
if "/" in str(var_b):
var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_c = 0.6
var_d = 0.49
list_b= []
if "/" in str(var_d):
var_d = eval(str(var_d))
list_b.append(var_d)
if "/" in str(var_c):
var_c = eval(str(var_c))
list_b.append(var_c)
list_b.reverse()
var_e = 1
list_c=list_b.copy()
list_c.sort()
var_f = list_c[-var_e]
var_g = list_b.index(var_f)+1
var_h = list_a[var_g-1]
print(var_h) |
Correspondence | When 14 is divided by A, the quotient is 3 and the remainder is 2. A is a natural number. Find A. | 4 | 14 2 [OP_SUB] 3 [OP_DIV] | var_a = 14
var_b = 2
var_c = var_a - var_b
var_d = 3
var_e = var_c / var_d
print(int(var_e)) |
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