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Quais são os nomes dos países com a 3a maior população? | CREATE TABLE country (Name VARCHAR, Population VARCHAR) | SELECT Name FROM country ORDER BY Population DESC LIMIT 3 |
Quais são os nomes das nações com a população mais baixa? | CREATE TABLE country (Name VARCHAR, Population VARCHAR) | SELECT Name FROM country ORDER BY Population LIMIT 3 |
Quantos países há na Ásia? | CREATE TABLE country (continent VARCHAR) | SELECT COUNT(*) FROM country WHERE continent = "Asia" |
Quais são os nomes dos países que estão no continente europeu e têm uma população de 80000? | CREATE TABLE country (Name VARCHAR, continent VARCHAR, Population VARCHAR) | SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000" |
Qual é a população total e a área média dos países do continente da América do Norte cuja área é maior que 3000 ? | CREATE TABLE country (population INTEGER, surfacearea INTEGER, continent VARCHAR) | SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000 |
Quais são as cidades com população entre 160000 e 900000? | CREATE TABLE city (name VARCHAR, Population INTEGER) | SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000 |
Devolva os nomes das cidades que têm população entre 160000 e 900000 . | CREATE TABLE city (name VARCHAR, population INTEGER) | SELECT name FROM city WHERE population BETWEEN 160000 AND 900000 |
Qual a língua falada pelo maior número de países? | CREATE TABLE countrylanguage (LANGUAGE VARCHAR) | SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é a língua falada pela maior percentagem de pessoas em cada país? | CREATE TABLE countrylanguage (LANGUAGE VARCHAR, CountryCode VARCHAR, Percentage INTEGER) | SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode |
Qual é o número total de países onde o espanhol é falado pela maior porcentagem de pessoas? | CREATE TABLE countrylanguage (Percentage INTEGER, CountryCode VARCHAR, LANGUAGE VARCHAR) | SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode |
Quais são os códigos dos países onde o espanhol é falado pela maior porcentagem de pessoas? | CREATE TABLE countrylanguage (CountryCode VARCHAR, Percentage INTEGER, LANGUAGE VARCHAR) | SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode |
Quantos condutores há? | CREATE TABLE conductor (Id VARCHAR) | SELECT COUNT(*) FROM conductor |
Escreva os nomes dos condutores em ordem ascendente de idade. | CREATE TABLE conductor (Name VARCHAR, Age VARCHAR) | SELECT Name FROM conductor ORDER BY Age |
Quais são os nomes dos condutores cujas nacionalidades não são "EUA"? | CREATE TABLE conductor (Name VARCHAR, Nationality VARCHAR) | SELECT Name FROM conductor WHERE Nationality <> 'USA' |
Quais são as companhias discográficas de orquestras em ordem decrescente de anos em que foram fundadas? | CREATE TABLE orchestra (Record_Company VARCHAR, Year_of_Founded VARCHAR) | SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC |
Qual é a média de assistência a espetáculos? | CREATE TABLE SHOW (Attendance INTEGER) | SELECT AVG(Attendance) FROM SHOW |
Qual é a parcela máxima e mínima de performances cujo tipo não é "Live final"? | CREATE TABLE performance (SHARE INTEGER, TYPE VARCHAR) | SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final" |
Quantas nacionalidades diferentes têm os condutores? | CREATE TABLE conductor (Nationality VARCHAR) | SELECT COUNT(DISTINCT Nationality) FROM conductor |
Lista os nomes dos condutores em ordem decrescente de anos de trabalho. | CREATE TABLE conductor (Name VARCHAR, Year_of_Work VARCHAR) | SELECT Name FROM conductor ORDER BY Year_of_Work DESC |
Escreva o nome do condutor com mais anos de trabalho. | CREATE TABLE conductor (Name VARCHAR, Year_of_Work VARCHAR) | SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1 |
Indique os nomes dos dirigentes e das orquestras que dirigiram. | CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR); CREATE TABLE orchestra (Orchestra VARCHAR, Conductor_ID VARCHAR) | SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID |
Indique os nomes dos maestros que dirigiram mais de uma orquestra. | CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR) | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1 |
Indicar o nome do maestro que dirigiu o maior número de orquestras. | CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR) | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1 |
Indicar o nome do maestro que tenha dirigido orquestras fundadas após 2008. | CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR) | SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008 |
Indique as diferentes gravadoras e o número correspondente de orquestras. | CREATE TABLE orchestra (Record_Company VARCHAR) | SELECT Record_Company, COUNT(*) FROM orchestra GROUP BY Record_Company |
Mostre os formatos de gravação das orquestras em ordem ascendente de contagem. | CREATE TABLE orchestra (Major_Record_Format VARCHAR) | SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*) |
Escreva a gravadora compartilhada pelo maior número de orquestras. | CREATE TABLE orchestra (Record_Company VARCHAR) | SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1 |
Escreva os nomes das orquestras que não têm apresentação. | CREATE TABLE orchestra (Orchestra VARCHAR, Orchestra_ID VARCHAR); CREATE TABLE performance (Orchestra VARCHAR, Orchestra_ID VARCHAR) | SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance) |
Mostrar as gravadoras partilhadas por orquestras fundadas antes de 2003 e depois de 2003. | CREATE TABLE orchestra (Record_Company VARCHAR, Year_of_Founded INTEGER) | SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003 |
Encontre o número de orquestras cujo formato de gravação é "CD" ou "DVD". | CREATE TABLE orchestra (Major_Record_Format VARCHAR) | SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD" |
Indicar os anos em que foram fundadas as orquestras que tiverem dado mais de uma apresentação. | CREATE TABLE performance (Orchestra_ID VARCHAR); CREATE TABLE orchestra (Orchestra_ID VARCHAR) | SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1 |
Quantos estudantes de secundário há? | CREATE TABLE Highschooler (Id VARCHAR) | SELECT COUNT(*) FROM Highschooler |
Mostre os nomes e notas de cada estudante do ensino médio. | CREATE TABLE Highschooler (name VARCHAR, grade VARCHAR) | SELECT name, grade FROM Highschooler |
Mostra as notas dos alunos do liceu. | CREATE TABLE Highschooler (grade VARCHAR) | SELECT grade FROM Highschooler |
Em que ano está o Kyle? | CREATE TABLE Highschooler (grade VARCHAR, name VARCHAR) | SELECT grade FROM Highschooler WHERE name = "Kyle" |
Mostra os nomes de todos os alunos do secundário do 10o ano. | CREATE TABLE Highschooler (name VARCHAR, grade VARCHAR) | SELECT name FROM Highschooler WHERE grade = 10 |
Mostra a identificação do estudante do liceu chamado Kyle. | CREATE TABLE Highschooler (ID VARCHAR, name VARCHAR) | SELECT ID FROM Highschooler WHERE name = "Kyle" |
Quantos alunos do liceu estão no 9o ou 10o ano? | CREATE TABLE Highschooler (grade VARCHAR) | SELECT COUNT(*) FROM Highschooler WHERE grade = 9 OR grade = 10 |
Mostre o número de estudantes do ensino médio para cada ano. | CREATE TABLE Highschooler (grade VARCHAR) | SELECT grade, COUNT(*) FROM Highschooler GROUP BY grade |
Qual a classe que tem mais alunos do secundário? | CREATE TABLE Highschooler (grade VARCHAR) | SELECT grade FROM Highschooler GROUP BY grade ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre-me todas as notas que têm pelo menos 4 alunos. | CREATE TABLE Highschooler (grade VARCHAR) | SELECT grade FROM Highschooler GROUP BY grade HAVING COUNT(*) >= 4 |
Mostre os documentos dos alunos e o número de amigos correspondentes a cada um. | CREATE TABLE Friend (student_id VARCHAR) | SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id |
Mostre os nomes dos estudantes do ensino médio e o número correspondente de amigos. | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR) | SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id |
Qual é o nome do estudante do ensino médio que tem o maior número de amigos? | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR) | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre os nomes de estudantes do ensino secundário que têm pelo menos 3 amigos. | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR) | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3 |
Mostra os nomes de todos os amigos do Kyle. | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, friend_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR) | SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle" |
Quantos amigos tem o estudante do liceu Kyle? | CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR) | SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" |
Mostre identificação de todos os estudantes que não têm amigos. | CREATE TABLE Highschooler (id VARCHAR, student_id VARCHAR); CREATE TABLE Friend (id VARCHAR, student_id VARCHAR) | SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend |
Mostre os nomes de todos os estudantes do ensino médio que não têm amigos. | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Highschooler (name VARCHAR); CREATE TABLE Friend (student_id VARCHAR) | SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id |
Mostra os documentos dos alunos do secundário que têm amigos e que também são gostados por outra pessoa. | CREATE TABLE Likes (student_id VARCHAR, liked_id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, liked_id VARCHAR) | SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes |
Mostrar o nome de todos os alunos que têm alguns amigos e também são gostados por alguém. | CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Likes (student_id VARCHAR, liked_id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, liked_id VARCHAR) | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id |
Contar o número de curtidas para cada identificação de estudante. | CREATE TABLE Likes (student_id VARCHAR) | SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id |
Mostrar os nomes dos estudantes do ensino secundário que têm curtidas e o número de curtidas para cada um. | CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR) | SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id |
Qual é o nome do estudante do liceu que tem mais curtidas? | CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR) | SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1 |
Mostre os nomes dos alunos que têm pelo menos 2 curtidas. | CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR) | SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2 |
Mostrar os nomes dos alunos que têm uma nota superior a 5 e têm pelo menos 2 amigos. | CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR, grade INTEGER) | SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2 |
Quantos "likes" tem o Kyle? | CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR) | SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle" |
Encontre a nota média de todos os alunos que têm amigos. | CREATE TABLE Highschooler (id VARCHAR); CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (grade INTEGER, id VARCHAR) | SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) |
Encontre a nota mínima de estudantes que não têm amigos. | CREATE TABLE Highschooler (id VARCHAR); CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (grade INTEGER, id VARCHAR) | SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id) |
Que estados têm proprietários e profissionais que vivem lá? | CREATE TABLE Owners (state VARCHAR); CREATE TABLE Professionals (state VARCHAR) | SELECT state FROM Owners INTERSECT SELECT state FROM Professionals |
Qual é a idade média dos cães que foram tratados? | CREATE TABLE Dogs (age INTEGER, dog_id VARCHAR); CREATE TABLE Treatments (age INTEGER, dog_id VARCHAR) | SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments) |
Que profissionais vivem no estado de Indiana ou foram tratados em mais de 2 tratamentos? | CREATE TABLE Treatments (professional_id VARCHAR); CREATE TABLE Professionals (professional_id VARCHAR, last_name VARCHAR, cell_number VARCHAR); CREATE TABLE Professionals (professional_id VARCHAR, last_name VARCHAR, cell_number VARCHAR, state VARCHAR) | SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2 |
Que cães não custaram ao seu dono mais de 1000 dólares por tratamento ? | CREATE TABLE dogs (name VARCHAR, dog_id VARCHAR, cost_of_treatment INTEGER); CREATE TABLE treatments (name VARCHAR, dog_id VARCHAR, cost_of_treatment INTEGER) | SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000) |
Quais os nomes de primeiro nome que são usados para profissionais ou proprietários, mas não são usados como nomes de cães? | CREATE TABLE Owners (first_name VARCHAR, name VARCHAR); CREATE TABLE Dogs (first_name VARCHAR, name VARCHAR); CREATE TABLE Professionals (first_name VARCHAR, name VARCHAR) | SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs |
Qual profissional não realizou nenhum tratamento em cães? | CREATE TABLE Professionals (professional_id VARCHAR, role_code VARCHAR, email_address VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR) | SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id |
Qual é o dono que possui mais cães? | CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR) | SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 |
Que profissionais já fizeram pelo menos dois tratamentos? | CREATE TABLE Professionals (professional_id VARCHAR, role_code VARCHAR, first_name VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR) | SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 |
Qual é o nome da raça com mais cães? | CREATE TABLE Dogs (breed_code VARCHAR); CREATE TABLE Breeds (breed_name VARCHAR, breed_code VARCHAR) | SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é o dono que mais pagou pelos tratamentos dos cães? | CREATE TABLE Owners (owner_id VARCHAR, last_name VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR) | SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1 |
Qual é a descrição do tipo de tratamento que custa menos dinheiro no total? | CREATE TABLE Treatments (treatment_type_code VARCHAR); CREATE TABLE Treatment_types (treatment_type_description VARCHAR, treatment_type_code VARCHAR) | SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) LIMIT 1 |
Que dono pagou a maior quantia total pelos cães? Mostre o número e o código postal do dono. | CREATE TABLE Treatments (dog_id VARCHAR, cost_of_treatment INTEGER); CREATE TABLE Owners (owner_id VARCHAR, zip_code VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, dog_id VARCHAR) | SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1 |
Que profissionais fizeram pelo menos dois tipos de tratamentos? | CREATE TABLE Professionals (professional_id VARCHAR, cell_number VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR) | SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2 |
Qual é o nome e o apelido dos profissionais que fizeram tratamentos com custos abaixo da média? | CREATE TABLE Treatments (cost_of_treatment INTEGER); CREATE TABLE Professionals (first_name VARCHAR, last_name VARCHAR); CREATE TABLE Treatments (Id VARCHAR) | SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments) |
Indique a data de cada tratamento, juntamente com o nome do profissional que o realizou. | CREATE TABLE Treatments (date_of_treatment VARCHAR, professional_id VARCHAR); CREATE TABLE Professionals (first_name VARCHAR, professional_id VARCHAR) | SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id |
Indicar o custo de cada tratamento e a descrição do tipo de tratamento correspondente. | CREATE TABLE Treatments (cost_of_treatment VARCHAR, treatment_type_code VARCHAR); CREATE TABLE treatment_types (treatment_type_description VARCHAR, treatment_type_code VARCHAR) | SELECT T1.cost_of_treatment, T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code |
Escreva o nome de cada dono, o apelido e o tamanho do seu para o cão. | CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (size_code VARCHAR, owner_id VARCHAR) | SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id |
Lista de pares de nome do dono e do nome do cão. | CREATE TABLE Dogs (name VARCHAR, owner_id VARCHAR); CREATE TABLE Owners (first_name VARCHAR, owner_id VARCHAR) | SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id |
Escreva os nomes dos cães da raça mais rara e as datas de tratamento deles. | CREATE TABLE Dogs (name VARCHAR, dog_id VARCHAR, breed_code VARCHAR); CREATE TABLE Treatments (date_of_treatment VARCHAR, dog_id VARCHAR); CREATE TABLE Dogs (breed_code VARCHAR) | SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) LIMIT 1) |
Que cães são de alguém que mora na Virgínia? | CREATE TABLE Dogs (name VARCHAR, owner_id VARCHAR); CREATE TABLE Owners (first_name VARCHAR, owner_id VARCHAR, state VARCHAR) | SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia' |
Qual é a data de chegada e a data de partida dos cães que tiverem sido tratados? | CREATE TABLE Dogs (date_arrived VARCHAR, date_departed VARCHAR, dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR) | SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id |
Escreva o sobrenome do dono do cão mais novo. | CREATE TABLE Owners (last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, age INTEGER); CREATE TABLE Dogs (age INTEGER) | SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs) |
Escreva os e-mails dos profissionais que vivem no estado do Havai ou no estado de Wisconsin. | CREATE TABLE Professionals (email_address VARCHAR, state VARCHAR) | SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin' |
Qual é a data de chegada e a data de partida de todos os cães? | CREATE TABLE Dogs (date_arrived VARCHAR, date_departed VARCHAR) | SELECT date_arrived, date_departed FROM Dogs |
Quantos cães foram tratados? | CREATE TABLE Treatments (dog_id VARCHAR) | SELECT COUNT(DISTINCT dog_id) FROM Treatments |
Quantos profissionais já realizaram algum tratamento a cães? | CREATE TABLE Treatments (professional_id VARCHAR) | SELECT COUNT(DISTINCT professional_id) FROM Treatments |
Que profissionais vivem numa cidade que contenha a substring "Oeste"? | CREATE TABLE professionals (role_code VARCHAR, street VARCHAR, city VARCHAR, state VARCHAR) | SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%' |
Que proprietários vivem no estado cujo nome contém a substring "North"? | CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, email_address VARCHAR, state VARCHAR) | SELECT first_name, last_name, email_address FROM Owners WHERE state LIKE '%North%' |
Quantos cães têm uma idade abaixo da média? | CREATE TABLE Dogs (age INTEGER) | SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs) |
Quanto custa o tratamento mais recente? | CREATE TABLE Treatments (cost_of_treatment VARCHAR, date_of_treatment VARCHAR) | SELECT cost_of_treatment FROM Treatments ORDER BY date_of_treatment DESC LIMIT 1 |
Quantos cães não foram tratados? | CREATE TABLE Dogs (dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR) | SELECT COUNT(*) FROM Dogs WHERE NOT dog_id IN (SELECT dog_id FROM Treatments) |
Diga-me quantos cães não receberam tratamento . | CREATE TABLE treatments (dog_id VARCHAR); CREATE TABLE dogs (dog_id VARCHAR) | SELECT COUNT(*) FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments) |
Quantos donos não têm cães temporariamente? | CREATE TABLE Dogs (owner_id VARCHAR); CREATE TABLE Owners (owner_id VARCHAR) | SELECT COUNT(*) FROM Owners WHERE NOT owner_id IN (SELECT owner_id FROM Dogs) |
Quantos profissionais não realizaram nenhum tratamento em cães? | CREATE TABLE Professionals (professional_id VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR) | SELECT COUNT(*) FROM Professionals WHERE NOT professional_id IN (SELECT professional_id FROM Treatments) |
Escreva o nome, idade e peso dos cães que foram abandonados? 1 significa sim e 0 significa não. | CREATE TABLE Dogs (name VARCHAR, age VARCHAR, weight VARCHAR, abandoned_yn VARCHAR) | SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1 |
Qual é a idade média de todos os cães? | CREATE TABLE Dogs (age INTEGER) | SELECT AVG(age) FROM Dogs |
Qual é a idade do cão mais velho? | CREATE TABLE Dogs (age INTEGER) | SELECT MAX(age) FROM Dogs |
Quanto custa cada tipo de cobrança? | CREATE TABLE Charges (charge_type VARCHAR, charge_amount VARCHAR) | SELECT charge_type, charge_amount FROM Charges |
Quanto custa o tipo de carregamento mais caro? | CREATE TABLE Charges (charge_amount INTEGER) | SELECT MAX(charge_amount) FROM Charges |
Escreva o e-mail, o telemóvel e o telefone de casa de todos os profissionais. | CREATE TABLE professionals (email_address VARCHAR, cell_number VARCHAR, home_phone VARCHAR) | SELECT email_address, cell_number, home_phone FROM professionals |
Quais são todas as combinações possíveis de tipo de raça e tamanho? | CREATE TABLE dogs (breed_code VARCHAR, size_code VARCHAR) | SELECT DISTINCT breed_code, size_code FROM dogs |
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