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humaneval-HumanEval_129_minPath.json-L39
js
//Given a grid with N rows and N columns (N >= 2) and a positive integer k, // each cell of the grid contains a value. Every integer in the range [1, N * N] // inclusive appears exactly once on the cells of the grid. // You have to find the minimum path of length k in the grid. You can start // from any cell, and in each step you can move to any of the neighbor cells, // in other words, you can go to cells which share an edge with you current // cell. // Please note that a path of length k means visiting exactly k cells (not // necessarily distinct). // You CANNOT go off the grid. // A path A (of length k) is considered less than a path B (of length k) if // after making the ordered arrays of the values on the cells that A and B go // through (let's call them lst_A and lst_B), lst_A is lexicographically less // than lst_B, in other words, there exist an integer index i (1 <= i <= k) // such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have // lst_A[j] = lst_B[j]. // It is guaranteed that the answer is unique. // Return an ordered array of the values on the cells that the minimum path go through. // Examples: // >>> minPath([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) // [1, 2, 1] // >>> minPath([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) // [1] function minPath(grid, k){ let n = grid.length; let path = []; let startCell = grid[0][0]; for(let i = 0; i < n; i++){ for(let j = 0; j < n; j++){ let curr = grid[i][j]; if(curr < startCell){ startCell = curr; } } } let currCell = startCell; for(let l = 0; l < k; l++){ path.push(currCell);
let x = null; let y = null; for(let i = 0; i < n; i++){ for(let j = 0; j < n; j++){ if(grid[i][j] === currCell){ x = i; y = j; } } } if(x > 0){ neighbours.push(grid[x - 1][y]); } if(x < n - 1){ neighbours.push(grid[x + 1][y]); } if(y > 0){ neighbours.push(grid[x][y - 1]); } if(y < n - 1){ neighbours.push(grid[x][y + 1]); } let nextCell = neighbours[0]; for(let i = 0; i < neighbours.length; i++){ let curr = neighbours[i]; if(curr < nextCell){ nextCell = curr; } } currCell = nextCell; } return path; }
let neighbours = [];
const assert = require('node:assert'); function test() { let candidate = minPath; assert.deepEqual(candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3),[1, 2, 1]); assert.deepEqual(candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1),[1]); assert.deepEqual(candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4),[1, 2, 1, 2]); assert.deepEqual(candidate([[6, 4, 13, 10], [5, 7, 12, 1], [3, 16, 11, 15], [8, 14, 9, 2]], 7),[1, 10, 1, 10, 1, 10, 1]); assert.deepEqual(candidate([[8, 14, 9, 2], [6, 4, 13, 15], [5, 7, 1, 12], [3, 10, 11, 16]], 5),[1, 7, 1, 7, 1]); assert.deepEqual(candidate([[11, 8, 7, 2], [5, 16, 14, 4], [9, 3, 15, 6], [12, 13, 10, 1]], 9),[1, 6, 1, 6, 1, 6, 1, 6, 1]); assert.deepEqual(candidate([[12, 13, 10, 1], [9, 3, 15, 6], [5, 16, 14, 4], [11, 8, 7, 2]], 12),[1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6]); assert.deepEqual(candidate([[2, 7, 4], [3, 1, 5], [6, 8, 9]], 8),[1, 3, 1, 3, 1, 3, 1, 3]); assert.deepEqual(candidate([[6, 1, 5], [3, 8, 9], [2, 7, 4]], 8),[1, 5, 1, 5, 1, 5, 1, 5]); assert.deepEqual(candidate([[1, 2], [3, 4]], 10),[1, 2, 1, 2, 1, 2, 1, 2, 1, 2]); assert.deepEqual(candidate([[1, 3], [3, 2]], 10),[1, 3, 1, 3, 1, 3, 1, 3, 1, 3]); } test();
humaneval-HumanEval_123_get_odd_collatz.json-L24
js
//Given a positive integer n, return a sorted array that has the odd numbers in collatz sequence. // The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined // as follows: start with any positive integer n. Then each term is obtained from the // previous term as follows: if the previous term is even, the next term is one half of // the previous term. If the previous term is odd, the next term is 3 times the previous // term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1. // Note: // 1. Collatz(1) is [1]. // 2. returned array sorted in increasing order. // For example: // get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5. // >>> get_odd_collatz(5) // [1, 5] function get_odd_collatz(n){ var collatz_sequence = [] var odd_numbers = [] var odd_count = 0 collatz_sequence.push(n) for(var i = 0; i < collatz_sequence.length; i++){ if(collatz_sequence[i]%2 == 0){ collatz_sequence.push(collatz_sequence[i]/2) } else if(collatz_sequence[i]%2 == 1){
} if(collatz_sequence[i]%2 == 1){ odd_numbers.push(collatz_sequence[i]) odd_count += 1 } if(collatz_sequence[i] == 1){ break } } if(odd_count != 0){ odd_numbers.sort(function(a, b){return a-b}) return odd_numbers } else{ odd_numbers.push(1) return odd_numbers } }
collatz_sequence.push(collatz_sequence[i]*3+1)
const assert = require('node:assert'); function test() { let candidate = get_odd_collatz; assert.deepEqual(candidate(14),[1, 5, 7, 11, 13, 17]); assert.deepEqual(candidate(5),[1, 5]); assert.deepEqual(candidate(12),[1, 3, 5]); assert.deepEqual(candidate(1),[1]); } test();
humaneval-HumanEval_24_largest_divisor.json-L8
js
//For a given number n, find the largest number that divides n evenly, smaller than n // >>> largest_divisor(15) // 5 function largest_divisor(n){ let ld = 0; for(i=1; i<n; i++){ if(n%i===0){
ld = i; } } } return ld; }
if(i>ld){
const assert = require('node:assert'); function test() { let candidate = largest_divisor; assert.deepEqual(candidate(3),1); assert.deepEqual(candidate(7),1); assert.deepEqual(candidate(10),5); assert.deepEqual(candidate(100),50); assert.deepEqual(candidate(49),7); } test();
humaneval-HumanEval_126_is_sorted.json-L32
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 duplicate of the same // number, return false. Assume no negative numbers and only integers. // Examples // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) // (false) public static boolean isSorted(ArrayList<Long> lst) { if (lst.size() == 0) { return true;
else { int running_max = 0; int previous_number = 0; boolean first_time = true; boolean seen_2_in_a_row = false; for (Long number : lst) { if (first_time) { first_time = false; previous_number = number.intValue(); running_max = number.intValue(); } else { if (running_max > number.intValue()) { return false; } else { if (previous_number == number.intValue()) { if (seen_2_in_a_row) { return false; } else { seen_2_in_a_row = true; } } else { seen_2_in_a_row = false; } previous_number = number.intValue(); running_max = number.intValue(); } } } return true; } } }
}
} public static void main(String[] args) { assert(isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList()))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)3l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))) == (true)); } }
humaneval-HumanEval_88_sort_array.json-L33
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of non-negative integers, return a cojava of the given array array list after sorting, // you will sort the given array array list in ascending order if the sum( first index value, last index value) is odd, // or sort it in descending order if the sum( first index value, last index value) is even. // Note: // * don't change the given array array list. // Examples: // >>> sortArray((new ArrayList<Long>(Arrays.asList()))) // (new ArrayList<Long>(Arrays.asList())) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)5l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)3l, (long)4l, (long)5l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l, (long)6l)))) // (new ArrayList<Long>(Arrays.asList((long)6l, (long)5l, (long)4l, (long)3l, (long)2l, (long)1l, (long)0l))) public static ArrayList<Long> sortArray(ArrayList<Long> array) { if(array.size()==0) { return array; } if(array.size()==1) { return array; } if(array.size()>1) { if((array.get(0)+array.get(array.size()-1))%2==0) { Collections.sort(array, Collections.reverseOrder());
else { Collections.sort(array); } } return array; } }
}
} public static void main(String[] args) { assert(sortArray((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<Long>(Arrays.asList())))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)5l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)3l, (long)4l, (long)5l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)3l, (long)0l, (long)1l, (long)5l, (long)6l)))).equals((new ArrayList<Long>(Arrays.asList((long)6l, (long)5l, (long)4l, (long)3l, (long)2l, (long)1l, (long)0l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)15l, (long)42l, (long)87l, (long)32l, (long)11l, (long)0l)))).equals((new ArrayList<Long>(Arrays.asList((long)0l, (long)11l, (long)15l, (long)32l, (long)42l, (long)87l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)21l, (long)14l, (long)23l, (long)11l)))).equals((new ArrayList<Long>(Arrays.asList((long)23l, (long)21l, (long)14l, (long)11l))))); } }
humaneval-HumanEval_78_hex_key.json-L23
js
//You have been tasked to write a function that receives // a hexadecimal number as a string and counts the number of hexadecimal // digits that are primes (prime number, or a prime, is a natural number // greater than 1 that is not a product of two smaller natural numbers). // Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. // Prime numbers are 2, 3, 5, 7, 11, 13, 17,... // So you have to determine a number of the following digits: 2, 3, 5, 7, // B (=decimal 11), D (=decimal 13). // Note: you may assume the input is always correct or empty string, // and symbols A,B,C,D,E,F are always uppercase. // Examples: // >>> hex_key("AB") // 1 // >>> hex_key("1077E") // 2 // >>> hex_key("ABED1A33") // 4 // >>> hex_key("123456789ABCDEF0") // 6 // >>> hex_key("2020") // 2 function hex_key(num){
let hexadecimals = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F']; let primes = ['2', '3', '5', '7', 'B', 'D']; for(let x = 0; x < num.length; x++){ if(primes.includes(num[x])){ result += 1; } } return result; }
let result = 0;
const assert = require('node:assert'); function test() { let candidate = hex_key; assert.deepEqual(candidate("AB"),1); assert.deepEqual(candidate("1077E"),2); assert.deepEqual(candidate("ABED1A33"),4); assert.deepEqual(candidate("2020"),2); assert.deepEqual(candidate("123456789ABCDEF0"),6); assert.deepEqual(candidate("112233445566778899AABBCCDDEEFF00"),12); } test();
humaneval-HumanEval_111_histogram.json-L16
js
//Given a string representing a space separated lowercase letters, return an object // of the letter with the most repetition and containing the corresponding count. // If several letters have the same occurrence, return all of them. // Example: // >>> histogram("a b c") // {"a": 1, "b": 1, "c": 1} // >>> histogram("a b b a") // {"a": 2, "b": 2} // >>> histogram("a b c a b") // {"a": 2, "b": 2} // >>> histogram("b b b b a") // {"b": 4} // >>> histogram("") // {} function histogram(test){
return {}; } var lst = test.split(" "); var count = {}; for (var i = 0; i < lst.length; i++){ if (count[lst[i]]){ count[lst[i]] += 1; } else{ count[lst[i]] = 1; } } console.log(count); var max = 0; var result = {}; for (var key in count){ if (count[key] > max){ max = count[key]; result = {}; result[key] = max; } else if (count[key] === max){ result[key] = max; } } return result; }
if (test.length === 0){
const assert = require('node:assert'); function test() { let candidate = histogram; assert.deepEqual(candidate("a b b a"),{"a": 2, "b": 2}); assert.deepEqual(candidate("a b c a b"),{"a": 2, "b": 2}); assert.deepEqual(candidate("a b c d g"),{"a": 1, "b": 1, "c": 1, "d": 1, "g": 1}); assert.deepEqual(candidate("r t g"),{"r": 1, "t": 1, "g": 1}); assert.deepEqual(candidate("b b b b a"),{"b": 4}); assert.deepEqual(candidate("r t g"),{"r": 1, "t": 1, "g": 1}); assert.deepEqual(candidate(""),{}); assert.deepEqual(candidate("a"),{"a": 1}); } test();
humaneval-HumanEval_74_total_match.json-L31
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that accepts two array lists of strings and returns the array list that has // total number of chars in the all strings of the array list less than the other array list. // if the two array lists have the same number of chars, return the first array list. // Examples // >>> totalMatch((new ArrayList<String>(Arrays.asList())), (new ArrayList<String>(Arrays.asList()))) // (new ArrayList<String>(Arrays.asList())) // >>> totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hI", (String)"Hi")))) // (new ArrayList<String>(Arrays.asList((String)"hI", (String)"Hi"))) // >>> totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hi", (String)"hi", (String)"admin", (String)"project")))) // (new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))) // >>> totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hI", (String)"hi", (String)"hi")))) // (new ArrayList<String>(Arrays.asList((String)"hI", (String)"hi", (String)"hi"))) // >>> totalMatch((new ArrayList<String>(Arrays.asList((String)"4"))), (new ArrayList<String>(Arrays.asList((String)"1", (String)"2", (String)"3", (String)"4", (String)"5")))) // (new ArrayList<String>(Arrays.asList((String)"4"))) public static ArrayList<String> totalMatch(ArrayList<String> lst1, ArrayList<String> lst2) { int sum1 = 0; int sum2 = 0; for (String s : lst1) { sum1 += s.length(); } for (String s : lst2) { sum2 += s.length();
if (sum1 <= sum2) { return lst1; } else { return lst2; } } }
}
} public static void main(String[] args) { assert(totalMatch((new ArrayList<String>(Arrays.asList())), (new ArrayList<String>(Arrays.asList()))).equals((new ArrayList<String>(Arrays.asList())))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hi", (String)"hi")))).equals((new ArrayList<String>(Arrays.asList((String)"hi", (String)"hi"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hi", (String)"hi", (String)"admin", (String)"project")))).equals((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"4"))), (new ArrayList<String>(Arrays.asList((String)"1", (String)"2", (String)"3", (String)"4", (String)"5")))).equals((new ArrayList<String>(Arrays.asList((String)"4"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hI", (String)"Hi")))).equals((new ArrayList<String>(Arrays.asList((String)"hI", (String)"Hi"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hI", (String)"hi", (String)"hi")))).equals((new ArrayList<String>(Arrays.asList((String)"hI", (String)"hi", (String)"hi"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))), (new ArrayList<String>(Arrays.asList((String)"hI", (String)"hi", (String)"hii")))).equals((new ArrayList<String>(Arrays.asList((String)"hi", (String)"admin"))))); assert(totalMatch((new ArrayList<String>(Arrays.asList())), (new ArrayList<String>(Arrays.asList((String)"this")))).equals((new ArrayList<String>(Arrays.asList())))); assert(totalMatch((new ArrayList<String>(Arrays.asList((String)"this"))), (new ArrayList<String>(Arrays.asList()))).equals((new ArrayList<String>(Arrays.asList())))); } }
humaneval-HumanEval_116_sort_array.json-L32
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // In this Kata, you have to sort an array array list of non-negative integers according to // number of ones in their binary representation in ascending order. // For similar number of ones, sort based on decimal value. // It must be implemented like this: // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)1l, (long)5l, (long)2l, (long)3l, (long)4l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)-2l, (long)-3l, (long)-4l, (long)-5l, (long)-6l)))) // (new ArrayList<Long>(Arrays.asList((long)-6l, (long)-5l, (long)-4l, (long)-3l, (long)-2l))) // >>> sortArray((new ArrayList<Long>(Arrays.asList((long)1l, (long)0l, (long)2l, (long)3l, (long)4l)))) // (new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)3l, (long)4l))) public static ArrayList<Long> sortArray(ArrayList<Long> arr) { Collections.sort(arr, (a, b) -> { long a1 = a, b1 = b; if (a1 < 0) { a1 = -a1; } if (b1 < 0) { b1 = -b1; } return Long.bitCount(a1) == Long.bitCount(b1) ? Long.compare(a, b) : Integer.compare(Long.bitCount(a1), Long.bitCount(b1)); }); return arr; }
}
} public static void main(String[] args) { assert(sortArray((new ArrayList<Long>(Arrays.asList((long)1l, (long)5l, (long)2l, (long)3l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)4l, (long)3l, (long)5l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)-2l, (long)-3l, (long)-4l, (long)-5l, (long)-6l)))).equals((new ArrayList<Long>(Arrays.asList((long)-4l, (long)-2l, (long)-6l, (long)-5l, (long)-3l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)1l, (long)0l, (long)2l, (long)3l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)0l, (long)1l, (long)2l, (long)4l, (long)3l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<Long>(Arrays.asList())))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)5l, (long)77l, (long)4l, (long)5l, (long)3l, (long)5l, (long)7l, (long)2l, (long)3l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)4l, (long)4l, (long)3l, (long)3l, (long)5l, (long)5l, (long)5l, (long)7l, (long)77l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)3l, (long)6l, (long)44l, (long)12l, (long)32l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)32l, (long)3l, (long)5l, (long)6l, (long)12l, (long)44l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)8l, (long)16l, (long)32l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)8l, (long)16l, (long)32l))))); assert(sortArray((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)8l, (long)16l, (long)32l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)4l, (long)8l, (long)16l, (long)32l))))); } }
humaneval-HumanEval_118_get_closest_vowel.json-L37
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a word. Your task is to find the closest vowel that stands between // two consonants from the right side of the word (case sensitive). // Vowels in the beginning and ending doesn't count. Return empty string if you didn't // find any vowel met the above condition. // You may assume that the given string contains English letter only. // Example: // >>> getClosestVowel(("yogurt")) // ("u") // >>> getClosestVowel(("FULL")) // ("U") // >>> getClosestVowel(("quick")) // ("") // >>> getClosestVowel(("ab")) // ("") public static String getClosestVowel(String word) { final String vowels = "aeiou"; final String consonants = "bcdfghjklmnpqrstvwxyz"; List<Integer> idx = new ArrayList<>(); word = word.toLowerCase(); for (int i = 0; i < word.length(); i++) { if (vowels.indexOf(word.charAt(i)) != -1) { idx.add(i); } } for (int i = idx.size() - 1; i >= 0; i--) { int j = idx.get(i); if (j == 0 || j == word.length() - 1) continue; char left = word.charAt(j - 1);
if (consonants.indexOf(left) != -1 && consonants.indexOf(right) != -1) { return String.valueOf(word.charAt(j)); } } return ""; } }
char right = word.charAt(j + 1);
} public static void main(String[] args) { assert(getClosestVowel(("yogurt")).equals(("u"))); assert(getClosestVowel(("full")).equals(("u"))); assert(getClosestVowel(("easy")).equals((""))); assert(getClosestVowel(("eAsy")).equals((""))); assert(getClosestVowel(("ali")).equals((""))); assert(getClosestVowel(("bad")).equals(("a"))); assert(getClosestVowel(("most")).equals(("o"))); assert(getClosestVowel(("ab")).equals((""))); assert(getClosestVowel(("ba")).equals((""))); assert(getClosestVowel(("quick")).equals((""))); assert(getClosestVowel(("anime")).equals(("i"))); assert(getClosestVowel(("Asia")).equals((""))); assert(getClosestVowel(("Above")).equals(("o"))); } }
humaneval-HumanEval_11_string_xor.json-L23
js
//Input are two strings a and b consisting only of 1s and 0s. // Perform binary XOR on these inputs and return result also as a string. // >>> string_xor("010", "110") // "100" function string_xor(a, b){ var arrayA = []; var arrayB = []; var arrayXOR = []; var result = ''; for (var i = 0; i < a.length; i++) { arrayA.push(parseInt(a[i])); } for (var j = 0; j < b.length; j++) { arrayB.push(parseInt(b[j])); } for (var k = 0; k < arrayA.length; k++) { if (arrayA[k] !== arrayB[k]) { arrayXOR.push(1); } else { arrayXOR.push(0); }
result = arrayXOR.join(''); return result; }
}
const assert = require('node:assert'); function test() { let candidate = string_xor; assert.deepEqual(candidate("111000", "101010"),"010010"); assert.deepEqual(candidate("1", "1"),"0"); assert.deepEqual(candidate("0101", "0000"),"0101"); } test();
humaneval-HumanEval_76_is_simple_power.json-L23
py
def is_simple_power(x: int, n: int) -> bool: """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x For example: >>> is_simple_power(1, 4) true >>> is_simple_power(2, 2) true >>> is_simple_power(8, 2) true >>> is_simple_power(3, 2) false >>> is_simple_power(3, 1) false >>> is_simple_power(5, 3) false """ if x == 0: return False else: while x > 1:
return False x /= n return True
if x % n != 0:
def check(candidate): assert candidate(16, 2) == True assert candidate(143214, 16) == False assert candidate(4, 2) == True assert candidate(9, 3) == True assert candidate(16, 4) == True assert candidate(24, 2) == False assert candidate(128, 4) == False assert candidate(12, 6) == False assert candidate(1, 1) == True assert candidate(1, 12) == True def test_check(): check(is_simple_power) test_check()
humaneval-HumanEval_147_get_max_triples.json-L17
js
//You are given a positive integer n. You have to create an integer array a of length n. // For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. // Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, // and a[i] + a[j] + a[k] is a multiple of 3. // Example : // >>> get_max_triples(5) // 1 // Explanation: // a = [1, 3, 7, 13, 21] // The only valid triple is (1, 7, 13). function get_max_triples(n){ let result = 0; let arr = []; for(let i = 1; i<=n; i++){ arr.push(i*i-i+1); }
for(let j = i+1; j<arr.length; j++){ for(let k = j+1; k<arr.length; k++){ if((arr[i]+arr[j]+arr[k])%3 === 0){ result++; } } } } return result; }
for(let i = 0; i<arr.length; i++){
const assert = require('node:assert'); function test() { let candidate = get_max_triples; assert.deepEqual(candidate(5),1); assert.deepEqual(candidate(6),4); assert.deepEqual(candidate(10),36); assert.deepEqual(candidate(100),53361); } test();
humaneval-HumanEval_81_numerical_letter_grade.json-L33
py
from typing import List def numerical_letter_grade(grades: List[float]) -> List[str]: """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E Example: >>> grade_equation([4.0, 3, 1.7, 2, 3.5]) ['A+', 'B', 'C-', 'C', 'A-'] """ final = [] for x in grades: if x == 4.0: final.append('A+')
final.append('A') elif x > 3.3: final.append('A-') elif x > 3.0: final.append('B+') elif x > 2.7: final.append('B') elif x > 2.3: final.append('B-') elif x > 2.0: final.append('C+') elif x > 1.7: final.append('C') elif x > 1.3: final.append('C-') elif x > 1.0: final.append('D+') elif x > 0.7: final.append('D') elif x > 0.0: final.append('D-') else: final.append('E') return final
elif x > 3.7:
def check(candidate): assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-'] assert candidate([1.2]) == ['D+'] assert candidate([0.5]) == ['D-'] assert candidate([0.0]) == ['E'] assert candidate([1.0, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+'] assert candidate([0.0, 0.7]) == ['E', 'D-'] def test_check(): check(numerical_letter_grade) test_check()
humaneval-HumanEval_27_flip_case.json-L7
py
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """ new_string = ""
if character.isupper(): new_string += character.lower() else: new_string += character.upper() return new_string
for character in string:
def check(candidate): assert candidate('') == '' assert candidate('Hello!') == 'hELLO!' assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS' def test_check(): check(flip_case) test_check()
humaneval-HumanEval_15_string_sequence.json-L19
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Return a string containing space-delimited numbers starting from 0 upto n inclusive. // >>> stringSequence((0l)) // ("0") // >>> stringSequence((5l)) // ("0 1 2 3 4 5") public static String stringSequence(long n) { String result = ""; for (long i = 0; i <= n; i++) { result += i + " "; }
} }
return result.trim();
} public static void main(String[] args) { assert(stringSequence((0l)).equals(("0"))); assert(stringSequence((3l)).equals(("0 1 2 3"))); assert(stringSequence((10l)).equals(("0 1 2 3 4 5 6 7 8 9 10"))); } }
humaneval-HumanEval_95_check_dict_case.json-L21
py
from typing import Dict def check_dict_case(dict: Dict[str, str]) -> bool: """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. Examples: >>> check_dict_case({ 'a': 'apple', 'b': 'banana' }) True >>> check_dict_case({ 'a': 'apple', 'A': 'banana', 'B': 'banana' }) False >>> check_dict_case({ 'a': 'apple', 8: 'banana', 'a': 'apple' }) False >>> check_dict_case({ 'Name': 'John', 'Age': '36', 'City': 'Houston' }) False >>> check_dict_case({ 'STATE': 'NC', 'ZIP': '12345' }) True """ if len(dict) == 0:
if any(not isinstance(x, str) for x in dict.keys()): return False if any(not x.islower() for x in dict.keys()): if any(not x.isupper() for x in dict.keys()): return False return True
return False
def check(candidate): assert candidate({ 'p': 'pineapple', 'b': 'banana' }) == True assert candidate({ 'p': 'pineapple', 'A': 'banana', 'B': 'banana' }) == False assert candidate({ 'p': 'pineapple', '5': 'banana', 'a': 'apple' }) == False assert candidate({ 'Name': 'John', 'Age': '36', 'City': 'Houston' }) == False assert candidate({ 'STATE': 'NC', 'ZIP': '12345' }) == True assert candidate({ 'fruit': 'Orange', 'taste': 'Sweet' }) == True assert candidate({ }) == False def test_check(): check(check_dict_case) test_check()
humaneval-HumanEval_137_compare_one.json-L73
py
from typing import Union def compare_one(a: Union[int, float, str], b: Union[int, float, str]) -> Union[int, float, str, None]: """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values are equal. Note: If a real number is represented as a string, the floating point might be . or , >>> compare_one(1, 2.5) 2.5 >>> compare_one(1, '2,3') '2,3' >>> compare_one('5,1', '6') '6' >>> compare_one('1', 1) None """ if isinstance(a, int) and isinstance(b, int): if a > b: return a elif a < b: return b else: return None elif isinstance(a, float) and isinstance(b, float): if a > b: return a elif a < b: return b else: return None elif isinstance(a, str) and isinstance(b, str): a_tmp = a.replace(',', '.') b_tmp = b.replace(',', '.') if float(a_tmp) > float(b_tmp): return a elif float(a_tmp) < float(b_tmp): return b else: return None elif isinstance(a, int) and isinstance(b, float): if a > b: return a elif a < b: return b else: return None elif isinstance(a, float) and isinstance(b, int): if a > b: return a elif a < b: return b else: return None elif isinstance(a, str) and isinstance(b, int): a_tmp = a.replace(',', '.') if float(a_tmp) > b: return a elif float(a_tmp) < b: return b else: return None elif isinstance(a, int) and isinstance(b, str): b_tmp = b.replace(',', '.') if a > float(b_tmp): return a elif a < float(b_tmp): return b else: return None elif isinstance(a, str) and isinstance(b, float):
if float(a_tmp) > b: return a elif float(a_tmp) < b: return b
a_tmp = a.replace(',', '.')
def check(candidate): assert candidate(1, 2) == 2 assert candidate(1, 2.5) == 2.5 assert candidate(2, 3) == 3 assert candidate(5, 6) == 6 assert candidate(1, '2,3') == '2,3' assert candidate('5,1', '6') == '6' assert candidate('1', '2') == '2' assert candidate('1', 1) == None def test_check(): check(compare_one) test_check()
humaneval-HumanEval_33_sort_third.json-L18
js
//This function takes an array l and returns an array l' such that // l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal // to the values of the corresponding indicies of l, but sorted. // >>> sort_third([1, 2, 3]) // [1, 2, 3] // >>> sort_third([5, 6, 3, 4, 8, 9, 2]) // [2, 6, 3, 4, 8, 9, 5] function sort_third(l){ let x=[]; let y=[]; let k=0; for(let i=0;i<l.length;i++){ if(i%3==0){ y[k]=l[i]; k=k+1; } else{
} } y.sort(); k=0; for(let i=0;i<l.length;i++){ if(i%3==0){ x[i]=y[k]; k=k+1; } } return x; }
x[i]=l[i];
const assert = require('node:assert'); function test() { let candidate = sort_third; assert.deepEqual(candidate([5, 6, 3, 4, 8, 9, 2]),[2, 6, 3, 4, 8, 9, 5]); assert.deepEqual(candidate([5, 8, 3, 4, 6, 9, 2]),[2, 8, 3, 4, 6, 9, 5]); assert.deepEqual(candidate([5, 6, 9, 4, 8, 3, 2]),[2, 6, 9, 4, 8, 3, 5]); assert.deepEqual(candidate([5, 6, 3, 4, 8, 9, 2, 1]),[2, 6, 3, 4, 8, 9, 5, 1]); } test();
humaneval-HumanEval_138_is_equal_to_sum_even.json-L19
js
//Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers // Example // >>> is_equal_to_sum_even(4) // false // >>> is_equal_to_sum_even(6) // false // >>> is_equal_to_sum_even(8) // true function is_equal_to_sum_even(n){ let m =0; for(let i=2;i<n;i+=2){ for(let j=2;j<n;j+=2){ for(let k=2;k<n;k+=2){ for(let l=2;l<n;l+=2){ if((i+j+k+l)==n){ m=1; break; }
} } } if(m==1){ return true; } else{ return false; } }
}
const assert = require('node:assert'); function test() { let candidate = is_equal_to_sum_even; assert.deepEqual(candidate(4),false); assert.deepEqual(candidate(6),false); assert.deepEqual(candidate(8),true); assert.deepEqual(candidate(10),true); assert.deepEqual(candidate(11),false); assert.deepEqual(candidate(12),true); assert.deepEqual(candidate(13),false); assert.deepEqual(candidate(16),true); } test();
humaneval-HumanEval_120_maximum.json-L38
py
from typing import List def maximum(arr: List[int], k: int) -> List[int]: """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: >>> maximum([-3, -4, 5], 3) [-4, -3, 5] Example 2: >>> maximum([4, -4, 4], 2) [4, 4] Example 3: >>> maximum([-3, 2, 1, 2, -1, -2, 1], 1) [2] Note: 1. The length of the array will be in the range of [1, 1000]. 2. The elements in the array will be in the range of [-1000, 1000]. 3. 0 <= k <= len(arr) """ def get_max(arr: List[int], k: int) -> List[int]: """ Returns the maximum k numbers in the given array """ if k == 0: return [] elif k == 1: return [max(arr)] else: max_num = max(arr)
return [max_num] + get_max(arr, k - 1) return sorted(get_max(arr, k))
arr.remove(max_num)
def check(candidate): assert candidate([-3, -4, 5], 3) == [-4, -3, 5] assert candidate([4, -4, 4], 2) == [4, 4] assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2] assert candidate([123, -123, 20, 0, 1, 2, -3], 3) == [2, 20, 123] assert candidate([-123, 20, 0, 1, 2, -3], 4) == [0, 1, 2, 20] assert candidate([5, 15, 0, 3, -13, -8, 0], 7) == [-13, -8, 0, 0, 3, 5, 15] assert candidate([-1, 0, 2, 5, 3, -10], 2) == [3, 5] assert candidate([1, 0, 5, -7], 1) == [5] assert candidate([4, -4], 2) == [-4, 4] assert candidate([-10, 10], 2) == [-10, 10] assert candidate([1, 2, 3, -23, 243, -400, 0], 0) == [] def test_check(): check(maximum) test_check()
humaneval-HumanEval_147_get_max_triples.json-L20
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a positive integer n. You have to create an integer array array list a of length n. // For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. // Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, // and a[i] + a[j] + a[k] is a multiple of 3. // Example : // >>> getMaxTriples((5l)) // (1l) // Explanation: // a = [1, 3, 7, 13, 21] // The only valid triple is (1, 7, 13). public static long getMaxTriples(long n) {
ArrayList<Integer> arrayList = new ArrayList<Integer>(); for (int i = 1; i <= n; i++) { arrayList.add(i * i - i + 1); } for (int i = 0; i < arrayList.size(); i++) { for (int j = i + 1; j < arrayList.size(); j++) { for (int k = j + 1; k < arrayList.size(); k++) { if ((arrayList.get(i) + arrayList.get(j) + arrayList.get(k)) % 3 == 0) { count++; } } } } return count; } }
int count = 0;
} public static void main(String[] args) { assert(getMaxTriples((5l)) == (1l)); assert(getMaxTriples((6l)) == (4l)); assert(getMaxTriples((10l)) == (36l)); assert(getMaxTriples((100l)) == (53361l)); } }
humaneval-HumanEval_125_split_words.json-L20
js
//Given a string of words, return an array of words split on whitespace, if no whitespaces exists in the text you // should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the // alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 // Examples // >>> split_words("Hello world!") // ["Hello", "world!"] // >>> split_words("Hello,world!") // ["Hello", "world!"] // >>> split_words("abcdef") // 3 function split_words(txt){ if(txt.includes(' ')){ return txt.split(' '); } else if(txt.includes(',')){ return txt.split(','); } else{ let count = 0;
if(i % 2 != 0){ if(txt[i] == txt[i].toLowerCase()){ count++; } } } return count; } }
for(let i = 0; i < txt.length; i++){
const assert = require('node:assert'); function test() { let candidate = split_words; assert.deepEqual(candidate("Hello world!"),["Hello", "world!"]); assert.deepEqual(candidate("Hello,world!"),["Hello", "world!"]); assert.deepEqual(candidate("Hello world,!"),["Hello", "world,!"]); assert.deepEqual(candidate("Hello,Hello,world !"),["Hello,Hello,world", "!"]); assert.deepEqual(candidate("abcdef"),3); assert.deepEqual(candidate("aaabb"),2); assert.deepEqual(candidate("aaaBb"),1); assert.deepEqual(candidate(""),0); } test();
humaneval-HumanEval_108_count_nums.json-L25
py
from typing import List def count_nums(arr: List[int]) -> int: """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) 0 >>> count_nums([-1, 11, -11]) 1 >>> count_nums([1, 1, 2]) 3 """ n = 0 for i in arr: if i < 0: i = abs(i) s = -1 * int(str(i)[0]) for j in str(i)[1:]: s += int(j) else: s = 0
s += int(j) if s > 0: n += 1 return n
for j in str(i):
def check(candidate): assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0]) == 5 assert candidate([0, 1]) == 1 assert candidate([1]) == 1 def test_check(): check(count_nums) test_check()
humaneval-HumanEval_126_is_sorted.json-L67
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of numbers, return whether or not they are sorted // in ascending order. If array list has more than 1 duplicate of the same // number, return false. Assume no negative numbers and only integers. // Examples // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) // (false) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) // (true) // >>> isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) // (false) public static boolean isSorted(ArrayList<Long> lst) { if (lst.size() == 0) { return true; } else { int running_max = 0; int previous_number = 0; boolean first_time = true; boolean seen_2_in_a_row = false; for (Long number : lst) { if (first_time) { first_time = false; previous_number = number.intValue(); running_max = number.intValue(); } else { if (running_max > number.intValue()) { return false; } else { if (previous_number == number.intValue()) { if (seen_2_in_a_row) { return false; } else { seen_2_in_a_row = true; } } else { seen_2_in_a_row = false; } previous_number = number.intValue(); running_max = number.intValue(); } } } return true; }
}
}
} public static void main(String[] args) { assert(isSorted((new ArrayList<Long>(Arrays.asList((long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)2l, (long)4l, (long)5l, (long)6l, (long)7l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList()))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)2l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)3l, (long)3l, (long)4l)))) == (false)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)2l, (long)3l, (long)3l, (long)4l)))) == (true)); assert(isSorted((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l)))) == (true)); } }
humaneval-HumanEval_99_closest_integer.json-L27
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Create a function that takes a value (string) representing a number // and returns the closest integer to it. If the number is equidistant // from two integers, round it away from zero. // Examples // >>> closestInteger(("10")) // (10l) // >>> closestInteger(("15.3")) // (15l) // Note: // Rounding away from zero means that if the given number is equidistant // from two integers, the one you should return is the one that is the // farthest from zero. For example closest_integer("14.5") should // return 15 and closest_integer("-14.5") should return -15. public static long closestInteger(String value) { BigDecimal bd = new BigDecimal(value); bd = bd.setScale(0, BigDecimal.ROUND_HALF_UP); return bd.longValue(); }
}
} public static void main(String[] args) { assert(closestInteger(("10")) == (10l)); assert(closestInteger(("14.5")) == (15l)); assert(closestInteger(("-15.5")) == (-16l)); assert(closestInteger(("15.3")) == (15l)); assert(closestInteger(("0")) == (0l)); } }
humaneval-HumanEval_69_search.json-L26
py
from typing import List def search(lst: List[int]) -> int: """ You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a value exist, return -1. Examples: >>> search([4, 1, 2, 2, 3, 1]) 2 >>> search([1, 2, 2, 3, 3, 3, 4, 4, 4]) 3 >>> search([5, 5, 4, 4, 4]) -1 """ dic = dict() for i in lst: if i in dic: dic[i] += 1 else: dic[i] = 1 maxValue = -1 for key, value in dic.items(): if value >= key and key > maxValue:
return maxValue
maxValue = key
def check(candidate): assert candidate([5, 5, 5, 5, 1]) == 1 assert candidate([4, 1, 4, 1, 4, 4]) == 4 assert candidate([3, 3]) == -1 assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8 assert candidate([2, 3, 3, 2, 2]) == 2 assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1 assert candidate([3, 2, 8, 2]) == 2 assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1 assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1 assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1 assert candidate([1, 9, 10, 1, 3]) == 1 assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5 assert candidate([1]) == 1 assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4 assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2 assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1 assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4 assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4 assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2 assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1 assert candidate([10]) == -1 assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2 assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1 assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1 assert candidate([3, 10, 10, 9, 2]) == -1 def test_check(): check(search) test_check()
humaneval-HumanEval_3_below_zero.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You're given an array array list of deposit and withdrawal operations on a bank account that starts with // zero balance. Your task is to detect if at any point the balance of account fallls below zero, and // at that point function should return true. Otherwise it should return false. // >>> belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (false) // >>> belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-4l, (long)5l)))) // (true) public static boolean belowZero(ArrayList<Long> operations) {
for (long op : operations) { balance += op; if (balance < 0) { return true; } } return false; } }
long balance = 0;
} public static void main(String[] args) { assert(belowZero((new ArrayList<Long>(Arrays.asList()))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-3l, (long)1l, (long)2l, (long)-3l)))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)-4l, (long)5l, (long)6l)))) == (true)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-4l)))) == (false)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-5l)))) == (true)); assert(belowZero((new ArrayList<Long>(Arrays.asList((long)1l, (long)-2l, (long)2l, (long)-2l, (long)5l, (long)-5l, (long)4l, (long)-4l)))) == (true)); } }
humaneval-HumanEval_74_total_match.json-L23
py
from typing import List def total_match(lst1: List[str], lst2: List[str]) -> List[str]: """ Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list. Examples >>> total_match([], []) [] >>> total_match(['hi', 'admin'], ['hI', 'Hi']) ['hI', 'Hi'] >>> total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ['hi', 'admin'] >>> total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ['hI', 'hi', 'hi'] >>> total_match(['4'], ['1', '2', '3', '4', '5']) ['4'] """ count1 = sum([len(s) for s in lst1])
if count1 == count2: return lst1 if count1 < count2: return lst1 return lst2
count2 = sum([len(s) for s in lst2])
def check(candidate): assert candidate([], []) == [] assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi'] assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin'] assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4'] assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi'] assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi'] assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin'] assert candidate([], ['this']) == [] assert candidate(['this'], []) == [] def test_check(): check(total_match) test_check()
humaneval-HumanEval_5_intersperse.json-L18
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Insert a number 'delimeter' between every two consecutive elements of input array list `numbers' // >>> intersperse((new ArrayList<Long>(Arrays.asList())), (4l)) // (new ArrayList<Long>(Arrays.asList())) // >>> intersperse((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l))), (4l)) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)2l, (long)4l, (long)3l))) public static ArrayList<Long> intersperse(ArrayList<Long> numbers, long delimeter) { ArrayList<Long> result = new ArrayList<Long>(); for (int i = 0; i < (numbers.size()); i++) { result.add(numbers.get(i));
result.add(delimeter); } } return result; } }
if ((i < (numbers.size() - 1))) {
} public static void main(String[] args) { assert(intersperse((new ArrayList<Long>(Arrays.asList())), (7l)).equals((new ArrayList<Long>(Arrays.asList())))); assert(intersperse((new ArrayList<Long>(Arrays.asList((long)5l, (long)6l, (long)3l, (long)2l))), (8l)).equals((new ArrayList<Long>(Arrays.asList((long)5l, (long)8l, (long)6l, (long)8l, (long)3l, (long)8l, (long)2l))))); assert(intersperse((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)2l))), (2l)).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)2l, (long)2l, (long)2l))))); } }
humaneval-HumanEval_51_remove_vowels.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // remove_vowels is a function that takes string and returns string without vowels. // >>> removeVowels(("")) // ("") // >>> removeVowels(("abcdef")) // ("bcdf") // >>> removeVowels(("aaaaa")) // ("") // >>> removeVowels(("aaBAA")) // ("B") // >>> removeVowels(("zbcd")) // ("zbcd") public static String removeVowels(String text) { String vowels = "aeiouAEIOU";
for (int i = 0; i < text.length(); i++) { if (vowels.indexOf(text.charAt(i)) == -1) { newText += text.charAt(i); } } return newText; } }
String newText = "";
} public static void main(String[] args) { assert(removeVowels(("")).equals((""))); assert(removeVowels(("abcdef\nghijklm")).equals(("bcdf\nghjklm"))); assert(removeVowels(("fedcba")).equals(("fdcb"))); assert(removeVowels(("eeeee")).equals((""))); assert(removeVowels(("acBAA")).equals(("cB"))); assert(removeVowels(("EcBOO")).equals(("cB"))); assert(removeVowels(("ybcd")).equals(("ybcd"))); } }
humaneval-HumanEval_8_sum_product.json-L16
js
//For a given array of integers, return an array consisting of a sum and a product of all the integers in an array. // Empty sum should be equal to 0 and empty product should be equal to 1. // >>> sum_product([]) // [0, 1] // >>> sum_product([1, 2, 3, 4]) // [10, 24] function sum_product(numbers){ if(numbers.length == 0){ return [0, 1]; } let sum = 0; let product = 1; for(let i = 0; i < numbers.length; i++){ sum += numbers[i]; product *= numbers[i];
return [sum, product]; }
}
const assert = require('node:assert'); function test() { let candidate = sum_product; assert.deepEqual(candidate([]),[0, 1]); assert.deepEqual(candidate([1, 1, 1]),[3, 1]); assert.deepEqual(candidate([100, 0]),[100, 0]); assert.deepEqual(candidate([3, 5, 7]),[15, 105]); assert.deepEqual(candidate([10]),[10, 10]); } test();
humaneval-HumanEval_108_count_nums.json-L16
py
from typing import List def count_nums(arr: List[int]) -> int: """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) 0 >>> count_nums([-1, 11, -11]) 1 >>> count_nums([1, 1, 2]) 3 """
for i in arr: if i < 0: i = abs(i) s = -1 * int(str(i)[0]) for j in str(i)[1:]: s += int(j) else: s = 0 for j in str(i): s += int(j) if s > 0: n += 1 return n
n = 0
def check(candidate): assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0]) == 5 assert candidate([0, 1]) == 1 assert candidate([1]) == 1 def test_check(): check(count_nums) test_check()
humaneval-HumanEval_96_count_up_to.json-L20
py
from typing import List def count_up_to(n: int) -> List[int]: """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. for example: >>> count_up_to(5) [2, 3] >>> count_up_to(11) [2, 3, 5, 7] >>> count_up_to(0) [] >>> count_up_to(20) [2, 3, 5, 7, 11, 13, 17, 19] >>> count_up_to(1) [] >>> count_up_to(18) [2, 3, 5, 7, 11, 13, 17] """
return [] result = [] for number in range(2, n): is_prime = True for divisor in range(2, number): if number % divisor == 0: is_prime = False break if is_prime: result.append(number) return result
if n <= 1:
def check(candidate): assert candidate(5) == [2, 3] assert candidate(6) == [2, 3, 5] assert candidate(7) == [2, 3, 5] assert candidate(10) == [2, 3, 5, 7] assert candidate(0) == [] assert candidate(22) == [2, 3, 5, 7, 11, 13, 17, 19] assert candidate(1) == [] assert candidate(18) == [2, 3, 5, 7, 11, 13, 17] assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43] assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97] def test_check(): check(count_up_to) test_check()
humaneval-HumanEval_150_x_or_y.json-L15
py
def x_or_y(n: int, x: int, y: int) -> int: """A simple program which should return the value of x if n is a prime number and should return the value of y otherwise. Examples: >>> x_or_y(7, 34, 12) 34 >>> x_or_y(15, 8, 5) 5 """ if n < 2: return y for i in range(2, n):
return y return x
if n % i == 0:
def check(candidate): assert candidate(7, 34, 12) == 34 assert candidate(15, 8, 5) == 5 assert candidate(3, 33, 5212) == 33 assert candidate(1259, 3, 52) == 3 assert candidate(7919, -1, 12) == -1 assert candidate(3609, 1245, 583) == 583 assert candidate(91, 56, 129) == 129 assert candidate(6, 34, 1234) == 1234 assert candidate(1, 2, 0) == 0 assert candidate(2, 2, 0) == 2 def test_check(): check(x_or_y) test_check()
humaneval-HumanEval_110_exchange.json-L35
js
//In this problem, you will implement a function that takes two arrays of numbers, // and determines whether it is possible to perform an exchange of elements // between them to make lst1 an array of only even numbers. // There is no limit on the number of exchanged elements between lst1 and lst2. // If it is possible to exchange elements between the lst1 and lst2 to make // all the elements of lst1 to be even, return "YES". // Otherwise, return "NO". // For example: // >>> exchange([1, 2, 3, 4], [1, 2, 3, 4]) // "YES" // >>> exchange([1, 2, 3, 4], [1, 5, 3, 4]) // "NO" // It is assumed that the input arrays will be non-empty. function exchange(lst1, lst2){ var num1 = 0; var num2 = 0; var exchange = true; while(num1 < lst1.length && exchange){ if(lst1[num1] % 2 !== 0){ exchange = false; if(num2 < lst2.length){ while(num2 < lst2.length && exchange == false){ if(lst2[num2] % 2 == 0){ lst1[num1] = lst2[num2]; exchange = true; } num2++; } } } num1++; } if(exchange){ return "YES";
return "NO"; } }
}else{
const assert = require('node:assert'); function test() { let candidate = exchange; assert.deepEqual(candidate([1, 2, 3, 4], [1, 2, 3, 4]),"YES"); assert.deepEqual(candidate([1, 2, 3, 4], [1, 5, 3, 4]),"NO"); assert.deepEqual(candidate([1, 2, 3, 4], [2, 1, 4, 3]),"YES"); assert.deepEqual(candidate([5, 7, 3], [2, 6, 4]),"YES"); assert.deepEqual(candidate([5, 7, 3], [2, 6, 3]),"NO"); assert.deepEqual(candidate([3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]),"NO"); assert.deepEqual(candidate([100, 200], [200, 200]),"YES"); } test();
humaneval-HumanEval_161_solve.json-L26
js
//You are given a string s. // if s[i] is a letter, reverse its case from lower to upper or vise versa, // otherwise keep it as it is. // If the string contains no letters, reverse the string. // The function should return the resulted string. // Examples // >>> solve("1234") // "4321" // >>> solve("ab") // "AB" // >>> solve("#a@C") // "#A@c" function solve(s){ let letters = s.match(/[a-z]/ig); if(letters) { const swapped = s.split('').map(char => { if(/[a-z]/i.test(char)) { return char === char.toLowerCase() ? char.toUpperCase() : char.toLowerCase(); } return char; }); return swapped.join(''); }
}
return s.split('').reverse().join('');
const assert = require('node:assert'); function test() { let candidate = solve; assert.deepEqual(candidate("AsDf"),"aSdF"); assert.deepEqual(candidate("1234"),"4321"); assert.deepEqual(candidate("ab"),"AB"); assert.deepEqual(candidate("#a@C"),"#A@c"); assert.deepEqual(candidate("#AsdfW^45"),"#aSDFw^45"); assert.deepEqual(candidate("#6@2"),"2@6#"); assert.deepEqual(candidate("#$a^D"),"#$A^d"); assert.deepEqual(candidate("#ccc"),"#CCC"); } test();
humaneval-HumanEval_52_below_threshold.json-L12
py
from typing import List def below_threshold(l: List[int], t: int) -> bool: """Return True if all numbers in the list l are below threshold t. >>> below_threshold([1, 2, 4, 10], 100) True >>> below_threshold([1, 20, 4, 10], 5) False """ for num in l: if num >= t:
return True
return False
def check(candidate): assert candidate([1, 2, 4, 10], 100) == True assert candidate([1, 20, 4, 10], 5) == False assert candidate([1, 20, 4, 10], 21) == True assert candidate([1, 20, 4, 10], 22) == True assert candidate([1, 8, 4, 10], 11) == True assert candidate([1, 8, 4, 10], 10) == False def test_check(): check(below_threshold) test_check()
humaneval-HumanEval_97_multiply.json-L26
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Complete the function that takes two integers and returns // the product of their unit digits. // Assume the input is always valid. // Examples: // >>> multiply((148l), (412l)) // (16l) // >>> multiply((19l), (28l)) // (72l) // >>> multiply((2020l), (1851l)) // (0l) // >>> multiply((14l), (-15l)) // (20l) public static long multiply(long a, long b) { long x = Math.abs(a % 10); long y = Math.abs(b % 10); return x * y; }
}
} public static void main(String[] args) { assert(multiply((148l), (412l)) == (16l)); assert(multiply((19l), (28l)) == (72l)); assert(multiply((2020l), (1851l)) == (0l)); assert(multiply((14l), (-15l)) == (20l)); assert(multiply((76l), (67l)) == (42l)); assert(multiply((17l), (27l)) == (49l)); assert(multiply((0l), (1l)) == (0l)); assert(multiply((0l), (0l)) == (0l)); } }
humaneval-HumanEval_33_sort_third.json-L27
js
//This function takes an array l and returns an array l' such that // l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal // to the values of the corresponding indicies of l, but sorted. // >>> sort_third([1, 2, 3]) // [1, 2, 3] // >>> sort_third([5, 6, 3, 4, 8, 9, 2]) // [2, 6, 3, 4, 8, 9, 5] function sort_third(l){ let x=[]; let y=[]; let k=0; for(let i=0;i<l.length;i++){ if(i%3==0){ y[k]=l[i]; k=k+1; } else{ x[i]=l[i]; } } y.sort(); k=0; for(let i=0;i<l.length;i++){ if(i%3==0){ x[i]=y[k]; k=k+1;
} return x; }
}
const assert = require('node:assert'); function test() { let candidate = sort_third; assert.deepEqual(candidate([5, 6, 3, 4, 8, 9, 2]),[2, 6, 3, 4, 8, 9, 5]); assert.deepEqual(candidate([5, 8, 3, 4, 6, 9, 2]),[2, 8, 3, 4, 6, 9, 5]); assert.deepEqual(candidate([5, 6, 9, 4, 8, 3, 2]),[2, 6, 9, 4, 8, 3, 5]); assert.deepEqual(candidate([5, 6, 3, 4, 8, 9, 2, 1]),[2, 6, 3, 4, 8, 9, 5, 1]); } test();
humaneval-HumanEval_44_change_base.json-L26
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Change numerical base of input number x to base. // return string representation after the conversion. // base numbers are less than 10. // >>> changeBase((8l), (3l)) // ("22") // >>> changeBase((8l), (2l)) // ("1000") // >>> changeBase((7l), (2l)) // ("111") public static String changeBase(long x, long base) { if (x<0 || base<2 || base>9) { throw new IllegalArgumentException("bad input"); } if (x==0) { return "0"; } StringBuilder sb = new StringBuilder();
sb.append(x%base); x = x/base; } return sb.reverse().toString(); } }
while (x>0) {
} public static void main(String[] args) { assert(changeBase((8l), (3l)).equals(("22"))); assert(changeBase((9l), (3l)).equals(("100"))); assert(changeBase((234l), (2l)).equals(("11101010"))); assert(changeBase((16l), (2l)).equals(("10000"))); assert(changeBase((8l), (2l)).equals(("1000"))); assert(changeBase((7l), (2l)).equals(("111"))); assert(changeBase((2l), (3l)).equals(("2"))); assert(changeBase((3l), (4l)).equals(("3"))); assert(changeBase((4l), (5l)).equals(("4"))); assert(changeBase((5l), (6l)).equals(("5"))); assert(changeBase((6l), (7l)).equals(("6"))); assert(changeBase((7l), (8l)).equals(("7"))); } }
humaneval-HumanEval_140_fix_spaces.json-L29
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a string text, replace all spaces in it with underscores, // and if a string has more than 2 consecutive spaces, // then replace all consecutive spaces with - // >>> fixSpaces((" Example")) // ("Example") // >>> fixSpaces((" Example 1")) // ("Example_1") // >>> fixSpaces((" Example 2")) // ("_Example_2") // >>> fixSpaces((" Example 3")) // ("_Example-3") public static String fixSpaces(String text) { String result = text.replace(" ", "_"); int i = 0; while (i < result.length() - 2) { if (result.charAt(i) == '_' && result.charAt(i + 1) == '_' && result.charAt(i + 2) == '_') { result = result.substring(0, i) + "-" + result.substring(i + 3); } i++; }
} }
return result;
} public static void main(String[] args) { assert(fixSpaces(("Example")).equals(("Example"))); assert(fixSpaces(("Mudasir Hanif ")).equals(("Mudasir_Hanif_"))); assert(fixSpaces(("Yellow Yellow Dirty Fellow")).equals(("Yellow_Yellow__Dirty__Fellow"))); assert(fixSpaces(("Exa mple")).equals(("Exa-mple"))); assert(fixSpaces((" Exa 1 2 2 mple")).equals(("-Exa_1_2_2_mple"))); } }
humaneval-HumanEval_119_match_parens.json-L30
py
from typing import List def match_parens(lst: List[str]) -> str: """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. Examples: >>> match_parens(['()(', ')']) 'Yes' >>> match_parens([')', ')']) 'No' """ s1, s2 = lst strings = [s1 + s2, s2 + s1] for s in strings: open_parens = 0 close_parens = 0 for c in s: if c == '(': open_parens += 1 elif c == ')': if open_parens:
else: close_parens += 1 if open_parens == 0 and close_parens == 0: return 'Yes' return 'No'
open_parens -= 1
def check(candidate): assert candidate(['()(', ')']) == 'Yes' assert candidate([')', ')']) == 'No' assert candidate(['(()(())', '())())']) == 'No' assert candidate([')())', '(()()(']) == 'Yes' assert candidate(['(())))', '(()())((']) == 'Yes' assert candidate(['()', '())']) == 'No' assert candidate(['(()(', '()))()']) == 'Yes' assert candidate(['((((', '((())']) == 'No' assert candidate([')(()', '(()(']) == 'No' assert candidate([')(', ')(']) == 'No' assert candidate(['(', ')']) == 'Yes' assert candidate([')', '(']) == 'Yes' def test_check(): check(match_parens) test_check()
humaneval-HumanEval_31_is_prime.json-L22
js
//Return true if a given number is prime, and false otherwise. // >>> is_prime(6) // false // >>> is_prime(101) // true // >>> is_prime(11) // true // >>> is_prime(13441) // true // >>> is_prime(61) // true // >>> is_prime(4) // false // >>> is_prime(1) // false function is_prime(n){ if (n==1) { return false; } if (n==2) {
} if (n%2==0) { return false; } var limit = Math.sqrt(n); for (var i = 3; i <= limit; i += 2) { if (n%i==0) { return false; } } return true; }
return true;
const assert = require('node:assert'); function test() { let candidate = is_prime; assert.deepEqual(candidate(6),false); assert.deepEqual(candidate(101),true); assert.deepEqual(candidate(11),true); assert.deepEqual(candidate(13441),true); assert.deepEqual(candidate(61),true); assert.deepEqual(candidate(4),false); assert.deepEqual(candidate(1),false); assert.deepEqual(candidate(5),true); assert.deepEqual(candidate(11),true); assert.deepEqual(candidate(17),true); assert.deepEqual(candidate(85),false); assert.deepEqual(candidate(77),false); assert.deepEqual(candidate(255379),false); } test();
humaneval-HumanEval_119_match_parens.json-L24
py
from typing import List def match_parens(lst: List[str]) -> str: """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. Examples: >>> match_parens(['()(', ')']) 'Yes' >>> match_parens([')', ')']) 'No' """ s1, s2 = lst strings = [s1 + s2, s2 + s1] for s in strings: open_parens = 0
for c in s: if c == '(': open_parens += 1 elif c == ')': if open_parens: open_parens -= 1 else: close_parens += 1 if open_parens == 0 and close_parens == 0: return 'Yes' return 'No'
close_parens = 0
def check(candidate): assert candidate(['()(', ')']) == 'Yes' assert candidate([')', ')']) == 'No' assert candidate(['(()(())', '())())']) == 'No' assert candidate([')())', '(()()(']) == 'Yes' assert candidate(['(())))', '(()())((']) == 'Yes' assert candidate(['()', '())']) == 'No' assert candidate(['(()(', '()))()']) == 'Yes' assert candidate(['((((', '((())']) == 'No' assert candidate([')(()', '(()(']) == 'No' assert candidate([')(', ')(']) == 'No' assert candidate(['(', ')']) == 'Yes' assert candidate([')', '(']) == 'Yes' def test_check(): check(match_parens) test_check()
humaneval-HumanEval_48_is_palindrome.json-L15
py
def is_palindrome(text: str) -> bool: """ Checks if given string is a palindrome >>> is_palindrome('') True >>> is_palindrome('aba') True >>> is_palindrome('aaaaa') True >>> is_palindrome('zbcd') False """ length = len(text) for i in range(length):
return False return True
if text[i] != text[-i - 1]:
def check(candidate): assert candidate('') == True assert candidate('aba') == True assert candidate('aaaaa') == True assert candidate('zbcd') == False assert candidate('xywyx') == True assert candidate('xywyz') == False assert candidate('xywzx') == False def test_check(): check(is_palindrome) test_check()
humaneval-HumanEval_161_solve.json-L18
py
def solve(s: str) -> str: """You are given a string s. if s[i] is a letter, reverse its case from lower to upper or vise versa, otherwise keep it as it is. If the string contains no letters, reverse the string. The function should return the resulted string. Examples >>> solve('1234') '4321' >>> solve('ab') 'AB' >>> solve('#a@C') '#A@c' """ if not any(l.isalpha() for l in s): return s[::-1] else:
return ''.join(l.swapcase() if l.isalpha() else l for l in s)
def check(candidate): assert candidate('AsDf') == 'aSdF' assert candidate('1234') == '4321' assert candidate('ab') == 'AB' assert candidate('#a@C') == '#A@c' assert candidate('#AsdfW^45') == '#aSDFw^45' assert candidate('#6@2') == '2@6#' assert candidate('#$a^D') == '#$A^d' assert candidate('#ccc') == '#CCC' def test_check(): check(solve) test_check()
humaneval-HumanEval_46_fib4.json-L24
py
def fib4(n: int) -> int: """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. >>> fib4(5) 4 >>> fib4(6) 8 >>> fib4(7) 14 """ if n == 0: return 0 elif n == 1: return 0 elif n == 2: return 2 elif n == 3: return 0
return fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4)
else:
def check(candidate): assert candidate(5) == 4 assert candidate(8) == 28 assert candidate(10) == 104 assert candidate(12) == 386 def test_check(): check(fib4) test_check()
humaneval-HumanEval_161_solve.json-L29
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given a string s. // if s[i] is a letter, reverse its case from lower to upper or vise versa, // otherwise keep it as it is. // If the string contains no letters, reverse the string. // The function should return the resulted string. // Examples // >>> solve(("1234")) // ("4321") // >>> solve(("ab")) // ("AB") // >>> solve(("#a@C")) // ("#A@c") public static String solve(String s) { boolean letterNotFound = true; StringBuilder sb = new StringBuilder(); if (s.length() == 0) return s; for (int i = 0; i < s.length(); i++) { if (Character.isLetter(s.charAt(i))) { letterNotFound = false; if (Character.isUpperCase(s.charAt(i))) {
} else { sb.append(Character.toUpperCase(s.charAt(i))); } } else { sb.append(s.charAt(i)); } } if (letterNotFound) { return sb.reverse().toString(); } return sb.toString(); } }
sb.append(Character.toLowerCase(s.charAt(i)));
} public static void main(String[] args) { assert(solve(("AsDf")).equals(("aSdF"))); assert(solve(("1234")).equals(("4321"))); assert(solve(("ab")).equals(("AB"))); assert(solve(("#a@C")).equals(("#A@c"))); assert(solve(("#AsdfW^45")).equals(("#aSDFw^45"))); assert(solve(("#6@2")).equals(("2@6#"))); assert(solve(("#$a^D")).equals(("#$A^d"))); assert(solve(("#ccc")).equals(("#CCC"))); } }
humaneval-HumanEval_73_smallest_change.json-L23
py
from typing import List def smallest_change(arr: List[int]) -> int: """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element. For example: >>> smallest_change([1, 2, 3, 5, 4, 7, 9, 6]) 4 >>> smallest_change([1, 2, 3, 4, 3, 2, 2]) 1 >>> smallest_change([1, 2, 3, 2, 1]) 0 """ start = 0 end = len(arr) - 1 count = 0 while start < end: if arr[start] != arr[end]: count += 1
end -= 1 return count
start += 1
def check(candidate): assert candidate([1, 2, 3, 5, 4, 7, 9, 6]) == 4 assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1 assert candidate([1, 4, 2]) == 1 assert candidate([1, 4, 4, 2]) == 1 assert candidate([1, 2, 3, 2, 1]) == 0 assert candidate([3, 1, 1, 3]) == 0 assert candidate([1]) == 0 assert candidate([0, 1]) == 1 def test_check(): check(smallest_change) test_check()
humaneval-HumanEval_11_string_xor.json-L17
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input are two strings a and b consisting only of 1s and 0s. // Perform binary XOR on these inputs and return result also as a string. // >>> stringXor(("010"), ("110")) // ("100") public static String stringXor(String a, String b) { StringBuilder c = new StringBuilder(); for (int i = 0; i < a.length(); i++) { c.append(a.charAt(i) ^ b.charAt(i));
return c.toString(); } }
}
} public static void main(String[] args) { assert(stringXor(("111000"), ("101010")).equals(("010010"))); assert(stringXor(("1"), ("1")).equals(("0"))); assert(stringXor(("0101"), ("0000")).equals(("0101"))); } }
humaneval-HumanEval_64_vowels_count.json-L29
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function vowels_count which takes a string representing // a word as input and returns the number of vowels in the string. // Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a // vowel, but only when it is at the end of the given word. // Example: // >>> vowelsCount(("abcde")) // (2l) // >>> vowelsCount(("ACEDY")) // (3l) public static long vowelsCount(String s) { long sum = 0; String sUpper = s.toUpperCase(); int lastIndex = sUpper.length() - 1; for (int i = 0; i < sUpper.length(); i++) { if (sUpper.charAt(i) == 'A' || sUpper.charAt(i) == 'E' || sUpper.charAt(i) == 'I' || sUpper.charAt(i) == 'O' || sUpper.charAt(i) == 'U') { sum++; } if (sUpper.charAt(i) == 'Y' && i == lastIndex) { sum++; }
return sum; } }
}
} public static void main(String[] args) { assert(vowelsCount(("abcde")) == (2l)); assert(vowelsCount(("Alone")) == (3l)); assert(vowelsCount(("key")) == (2l)); assert(vowelsCount(("bye")) == (1l)); assert(vowelsCount(("keY")) == (2l)); assert(vowelsCount(("bYe")) == (1l)); assert(vowelsCount(("ACEDY")) == (3l)); } }
humaneval-HumanEval_76_is_simple_power.json-L28
js
//Your task is to write a function that returns true if a number x is a simple // power of n and false in other cases. // x is a simple power of n if n**int=x // For example: // >>> is_simple_power(1, 4) // true // >>> is_simple_power(2, 2) // true // >>> is_simple_power(8, 2) // true // >>> is_simple_power(3, 2) // false // >>> is_simple_power(3, 1) // false // >>> is_simple_power(5, 3) // false function is_simple_power(x, n){ if(x===1){ return true; } if(x < n){ return false; } if(x % n !== 0){ return false; } return is_simple_power(x/n, n);
}
const assert = require('node:assert'); function test() { let candidate = is_simple_power; assert.deepEqual(candidate(16, 2),true); assert.deepEqual(candidate(143214, 16),false); assert.deepEqual(candidate(4, 2),true); assert.deepEqual(candidate(9, 3),true); assert.deepEqual(candidate(16, 4),true); assert.deepEqual(candidate(24, 2),false); assert.deepEqual(candidate(128, 4),false); assert.deepEqual(candidate(12, 6),false); assert.deepEqual(candidate(1, 1),true); assert.deepEqual(candidate(1, 12),true); } test();
humaneval-HumanEval_9_rolling_max.json-L11
js
//From a given array of integers, generate an array of rolling maximum element found until given moment // in the sequence. // >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) // [1, 2, 3, 3, 3, 4, 4] function rolling_max(numbers){ let max = []; let tempMax = 0; for(let i = 0; i < numbers.length; i++){ if(tempMax < numbers[i]){ tempMax = numbers[i];
max.push(tempMax); } return max; }
}
const assert = require('node:assert'); function test() { let candidate = rolling_max; assert.deepEqual(candidate([]),[]); assert.deepEqual(candidate([1, 2, 3, 4]),[1, 2, 3, 4]); assert.deepEqual(candidate([4, 3, 2, 1]),[4, 4, 4, 4]); assert.deepEqual(candidate([3, 2, 3, 100, 3]),[3, 3, 3, 100, 100]); } test();
humaneval-HumanEval_94_skjkasdkd.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You are given an array array list of integers. // You need to find the largest prime value and return the sum of its digits. // Examples: // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)3l, (long)2l, (long)1l, (long)3l, (long)5l, (long)7l, (long)4l, (long)5l, (long)5l, (long)5l, (long)2l, (long)181l, (long)32l, (long)4l, (long)32l, (long)3l, (long)2l, (long)32l, (long)324l, (long)4l, (long)3l)))) // (10l) // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)1l, (long)0l, (long)1l, (long)8l, (long)2l, (long)4597l, (long)2l, (long)1l, (long)3l, (long)40l, (long)1l, (long)2l, (long)1l, (long)2l, (long)4l, (long)2l, (long)5l, (long)1l)))) // (25l) // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)1l, (long)32l, (long)5107l, (long)34l, (long)83278l, (long)109l, (long)163l, (long)23l, (long)2323l, (long)32l, (long)30l, (long)1l, (long)9l, (long)3l)))) // (13l) // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)724l, (long)32l, (long)71l, (long)99l, (long)32l, (long)6l, (long)0l, (long)5l, (long)91l, (long)83l, (long)0l, (long)5l, (long)6l)))) // (11l) // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)81l, (long)12l, (long)3l, (long)1l, (long)21l)))) // (3l) // >>> skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)8l, (long)1l, (long)2l, (long)1l, (long)7l)))) // (7l) public static long skjkasdkd(ArrayList<Long> lst) { long largestPrime = 0l; for (Long item : lst) { long number = item; int counter = 0; if (item == 1) { continue; } if (item == 2) { counter = 1;
else { int l = 1; while (l <= (int) number) { if (number % l == 0) { counter++; } l++; } } if (counter == 2) { if (number > largestPrime) { largestPrime = number; } } } if (largestPrime == 0) { return 0l; } else { long output = 0l; while (largestPrime > 0) { output += largestPrime % 10; largestPrime /= 10; } return output; } } }
}
} public static void main(String[] args) { assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)3l, (long)2l, (long)1l, (long)3l, (long)5l, (long)7l, (long)4l, (long)5l, (long)5l, (long)5l, (long)2l, (long)181l, (long)32l, (long)4l, (long)32l, (long)3l, (long)2l, (long)32l, (long)324l, (long)4l, (long)3l)))) == (10l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)1l, (long)0l, (long)1l, (long)8l, (long)2l, (long)4597l, (long)2l, (long)1l, (long)3l, (long)40l, (long)1l, (long)2l, (long)1l, (long)2l, (long)4l, (long)2l, (long)5l, (long)1l)))) == (25l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)1l, (long)3l, (long)1l, (long)32l, (long)5107l, (long)34l, (long)83278l, (long)109l, (long)163l, (long)23l, (long)2323l, (long)32l, (long)30l, (long)1l, (long)9l, (long)3l)))) == (13l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)724l, (long)32l, (long)71l, (long)99l, (long)32l, (long)6l, (long)0l, (long)5l, (long)91l, (long)83l, (long)0l, (long)5l, (long)6l)))) == (11l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)81l, (long)12l, (long)3l, (long)1l, (long)21l)))) == (3l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)0l, (long)8l, (long)1l, (long)2l, (long)1l, (long)7l)))) == (7l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)8191l)))) == (19l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)8191l, (long)123456l, (long)127l, (long)7l)))) == (19l)); assert(skjkasdkd((new ArrayList<Long>(Arrays.asList((long)127l, (long)97l, (long)8192l)))) == (10l)); } }
humaneval-HumanEval_1_separate_paren_groups.json-L15
py
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string. >>> separate_paren_groups('( ) (( )) (( )( ))') ['()', '(())', '(()())'] """ paren_string = paren_string.replace(' ', '') groups = [] group = '' open_count = 0
if c == '(': open_count += 1 elif c == ')': open_count -= 1 group += c if open_count == 0: groups.append(group) group = '' return groups
for c in paren_string:
def check(candidate): assert candidate('(()()) ((())) () ((())()())') == ['(()())', '((()))', '()', '((())()())'] assert candidate('() (()) ((())) (((())))') == ['()', '(())', '((()))', '(((())))'] assert candidate('(()(())((())))') == ['(()(())((())))'] assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())'] def test_check(): check(separate_paren_groups) test_check()
humaneval-HumanEval_105_by_length.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given an array array list of integers, sort the integers that are between 1 and 9 inclusive, // reverse the resulting array array list, and then replace each digit by its corresponding name from // "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". // For example: // >>> byLength((new ArrayList<Long>(Arrays.asList((long)2l, (long)1l, (long)1l, (long)4l, (long)5l, (long)8l, (long)2l, (long)3l)))) // (new ArrayList<String>(Arrays.asList((String)"Eight", (String)"Five", (String)"Four", (String)"Three", (String)"Two", (String)"Two", (String)"One", (String)"One"))) // If the array array list is empty, return an empty array array list: // >>> byLength((new ArrayList<Long>(Arrays.asList()))) // (new ArrayList<String>(Arrays.asList())) // If the array array list has any strange number ignore it: // >>> byLength((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)55l)))) // (new ArrayList<String>(Arrays.asList((String)"One"))) public static ArrayList<String> byLength(ArrayList<Long> arr) {
ArrayList<String> res = new ArrayList<String>(); ArrayList<Long> good = new ArrayList<Long>(); for (Long i : arr) { if (i >= 1 && i <= 9) { good.add(i); } } good.sort(new Comparator<Long>() { public int compare(Long i1, Long i2) { return i1.compareTo(i2); } }); Collections.reverse(good); for (Long i : good) { res.add(a[i.intValue() - 1]); } return res; } }
String[] a = new String[] {"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine"};
} public static void main(String[] args) { assert(byLength((new ArrayList<Long>(Arrays.asList((long)2l, (long)1l, (long)1l, (long)4l, (long)5l, (long)8l, (long)2l, (long)3l)))).equals((new ArrayList<String>(Arrays.asList((String)"Eight", (String)"Five", (String)"Four", (String)"Three", (String)"Two", (String)"Two", (String)"One", (String)"One"))))); assert(byLength((new ArrayList<Long>(Arrays.asList()))).equals((new ArrayList<String>(Arrays.asList())))); assert(byLength((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)55l)))).equals((new ArrayList<String>(Arrays.asList((String)"One"))))); assert(byLength((new ArrayList<Long>(Arrays.asList((long)1l, (long)-1l, (long)3l, (long)2l)))).equals((new ArrayList<String>(Arrays.asList((String)"Three", (String)"Two", (String)"One"))))); assert(byLength((new ArrayList<Long>(Arrays.asList((long)9l, (long)4l, (long)8l)))).equals((new ArrayList<String>(Arrays.asList((String)"Nine", (String)"Eight", (String)"Four"))))); } }
humaneval-HumanEval_108_count_nums.json-L18
py
from typing import List def count_nums(arr: List[int]) -> int: """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) 0 >>> count_nums([-1, 11, -11]) 1 >>> count_nums([1, 1, 2]) 3 """ n = 0 for i in arr:
i = abs(i) s = -1 * int(str(i)[0]) for j in str(i)[1:]: s += int(j) else: s = 0 for j in str(i): s += int(j) if s > 0: n += 1 return n
if i < 0:
def check(candidate): assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0]) == 5 assert candidate([0, 1]) == 1 assert candidate([1]) == 1 def test_check(): check(count_nums) test_check()
humaneval-HumanEval_124_valid_date.json-L36
py
def valid_date(date: str) -> bool: """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2. 3. The months should not be less than 1 or higher than 12. 4. The date should be in the format: mm-dd-yyyy >>> valid_date('03-11-2000') True >>> valid_date('15-01-2012') False >>> valid_date('04-0-2040') False >>> valid_date('06-04-2020') True >>> valid_date('06/04/2020') False """ if not date: return False days_per_month = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] date_list = [int(d) for d in date.split('-')] if len(date_list) != 3: return False if date_list[0] < 1 or date_list[0] > 12: return False if date_list[1] < 1 or date_list[1] > days_per_month[date_list[0] - 1]: return False if len(str(date_list[2])) != 4:
return True
return False
def check(candidate): assert candidate('03-11-2000') == True assert candidate('15-01-2012') == False assert candidate('04-0-2040') == False assert candidate('06-04-2020') == True assert candidate('01-01-2007') == True assert candidate('03-32-2011') == False assert candidate('') == False assert candidate('04-31-3000') == False assert candidate('06-06-2005') == True assert candidate('21-31-2000') == False assert candidate('04-12-2003') == True assert candidate('04122003') == False assert candidate('20030412') == False assert candidate('2003-04') == False assert candidate('2003-04-12') == False assert candidate('04-2003') == False def test_check(): check(valid_date) test_check()
humaneval-HumanEval_108_count_nums.json-L21
py
from typing import List def count_nums(arr: List[int]) -> int: """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) 0 >>> count_nums([-1, 11, -11]) 1 >>> count_nums([1, 1, 2]) 3 """ n = 0 for i in arr: if i < 0: i = abs(i) s = -1 * int(str(i)[0])
s += int(j) else: s = 0 for j in str(i): s += int(j) if s > 0: n += 1 return n
for j in str(i)[1:]:
def check(candidate): assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0]) == 5 assert candidate([0, 1]) == 1 assert candidate([1]) == 1 def test_check(): check(count_nums) test_check()
humaneval-HumanEval_53_add.json-L8
py
def add(x: int, y: int) -> int: """Add two numbers x and y >>> add(2, 3) 5 >>> add(5, 7) 12 """
return x + y
def check(candidate): assert candidate(0, 1) == 1 assert candidate(1, 0) == 1 assert candidate(2, 3) == 5 assert candidate(5, 7) == 12 assert candidate(7, 5) == 12 def test_check(): check(add) test_check()
humaneval-HumanEval_46_fib4.json-L21
js
//The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: // fib4(0) -> 0 // fib4(1) -> 0 // fib4(2) -> 2 // fib4(3) -> 0 // fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). // Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. // >>> fib4(5) // 4 // >>> fib4(6) // 8 // >>> fib4(7) // 14 function fib4(n){ var prev = [0,0,2,0]; if(n<prev.length){ return prev[n]; } for(var i=4;i<=n;i++){ var curr = prev[0]+prev[1]+prev[2]+prev[3];
prev[1] = prev[2]; prev[2] = prev[3]; prev[3] = curr; } return prev[3]; }
prev[0] = prev[1];
const assert = require('node:assert'); function test() { let candidate = fib4; assert.deepEqual(candidate(5),4); assert.deepEqual(candidate(8),28); assert.deepEqual(candidate(10),104); assert.deepEqual(candidate(12),386); } test();
humaneval-HumanEval_4_mean_absolute_deviation.json-L19
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // For a given array list of input numbers, calculate Mean Absolute Deviation // around the mean of this dataset. // Mean Absolute Deviation is the average absolute difference between each // element and a centerpoint (mean in this case): // MAD = average | x - x_mean | // >>> meanAbsoluteDeviation((new ArrayList<Float>(Arrays.asList((float)1.0f, (float)2.0f, (float)3.0f, (float)4.0f)))) // (1.0f) public static float meanAbsoluteDeviation(ArrayList<Float> numbers) { float mean = (float)numbers.stream().mapToDouble(Float::floatValue).average().getAsDouble(); return (float)numbers.stream().mapToDouble(n -> Math.abs(n - mean)).average().getAsDouble();
}
}
} public static void main(String[] args) { assert(meanAbsoluteDeviation((new ArrayList<Float>(Arrays.asList((float)1.0f, (float)2.0f)))) == (0.5f)); assert(meanAbsoluteDeviation((new ArrayList<Float>(Arrays.asList((float)1.0f, (float)2.0f, (float)3.0f, (float)4.0f)))) == (1.0f)); assert(meanAbsoluteDeviation((new ArrayList<Float>(Arrays.asList((float)1.0f, (float)2.0f, (float)3.0f, (float)4.0f, (float)5.0f)))) == (1.2f)); } }
humaneval-HumanEval_105_by_length.json-L23
js
//Given an array of integers, sort the integers that are between 1 and 9 inclusive, // reverse the resulting array, and then replace each digit by its corresponding name from // "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". // For example: // >>> by_length([2, 1, 1, 4, 5, 8, 2, 3]) // ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"] // If the array is empty, return an empty array: // >>> by_length([]) // [] // If the array has any strange number ignore it: // >>> by_length([1, -1, 55]) // ["One"] function by_length(arr){ var arr2 = []; for(var i = 0; i < arr.length; i++){ var num = arr[i]; if(num > 0 && num < 10){ arr2.push(num); } } arr2.sort(); arr2.reverse();
for(var i = 0; i < arr2.length; i++){ var num = arr2[i]; if(num == 1){ arr3.push("One"); } else if(num == 2){ arr3.push("Two"); } else if(num == 3){ arr3.push("Three"); } else if(num == 4){ arr3.push("Four"); } else if(num == 5){ arr3.push("Five"); } else if(num == 6){ arr3.push("Six"); } else if(num == 7){ arr3.push("Seven"); } else if(num == 8){ arr3.push("Eight"); } else if(num == 9){ arr3.push("Nine"); } } return arr3; }
var arr3 = [];
const assert = require('node:assert'); function test() { let candidate = by_length; assert.deepEqual(candidate([2, 1, 1, 4, 5, 8, 2, 3]),["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"]); assert.deepEqual(candidate([]),[]); assert.deepEqual(candidate([1, -1, 55]),["One"]); assert.deepEqual(candidate([1, -1, 3, 2]),["Three", "Two", "One"]); assert.deepEqual(candidate([9, 4, 8]),["Nine", "Eight", "Four"]); } test();
humaneval-HumanEval_79_decimal_to_binary.json-L22
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given a number in decimal form and your task is to convert it to // binary format. The function should return a string, with each character representing a binary // number. Each character in the string will be '0' or '1'. // There will be an extra couple of characters 'db' at the beginning and at the end of the string. // The extra characters are there to help with the format. // Examples: // >>> decimalToBinary((15l)) // ("db1111db") // >>> decimalToBinary((32l)) // ("db100000db") public static String decimalToBinary(long decimal) { return "db" + Long.toBinaryString(decimal) + "db"; }
}
} public static void main(String[] args) { assert(decimalToBinary((0l)).equals(("db0db"))); assert(decimalToBinary((32l)).equals(("db100000db"))); assert(decimalToBinary((103l)).equals(("db1100111db"))); assert(decimalToBinary((15l)).equals(("db1111db"))); } }
humaneval-HumanEval_131_digits.json-L20
js
//Given a positive integer n, return the product of the odd digits. // Return 0 if all digits are even. // For example: // >>> digits(1) // 1 // >>> digits(4) // 0 // >>> digits(235) // 15 function digits(n){ if(!n){ return "error"; } if(n < 0){ return "error"; } var temp = 0; var prod = 1; var odd = true;
temp = n % 10; if(temp % 2 != 0){ prod *= temp; odd = false; } } if(odd){ return 0; } return prod; }
for(n; n > 0; n = Math.floor(n/10)){
const assert = require('node:assert'); function test() { let candidate = digits; assert.deepEqual(candidate(5),5); assert.deepEqual(candidate(54),5); assert.deepEqual(candidate(120),1); assert.deepEqual(candidate(5014),5); assert.deepEqual(candidate(98765),315); assert.deepEqual(candidate(5576543),2625); assert.deepEqual(candidate(2468),0); } test();
humaneval-HumanEval_156_int_to_mini_roman.json-L27
py
def int_to_mini_roman(number: int) -> str: """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) 'xix' >>> int_to_mini_roman(152) 'clii' >>> int_to_mini_roman(426) 'cdxxvi' """ roman_numerals = { 1000: 'm', 900: 'cm', 500: 'd', 400: 'cd', 100: 'c', 90: 'xc', 50: 'l', 40: 'xl', 10: 'x', 9: 'ix', 5: 'v',
1: 'i' } roman_numeral = '' for key in sorted(roman_numerals.keys(), reverse=True): roman_numeral += roman_numerals[key] * (number // key) number = number % key return roman_numeral
4: 'iv',
def check(candidate): assert candidate(19) == 'xix' assert candidate(152) == 'clii' assert candidate(251) == 'ccli' assert candidate(426) == 'cdxxvi' assert candidate(500) == 'd' assert candidate(1) == 'i' assert candidate(4) == 'iv' assert candidate(43) == 'xliii' assert candidate(90) == 'xc' assert candidate(94) == 'xciv' assert candidate(532) == 'dxxxii' assert candidate(900) == 'cm' assert candidate(994) == 'cmxciv' assert candidate(1000) == 'm' def test_check(): check(int_to_mini_roman) test_check()
humaneval-HumanEval_124_valid_date.json-L34
py
def valid_date(date: str) -> bool: """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2. 3. The months should not be less than 1 or higher than 12. 4. The date should be in the format: mm-dd-yyyy >>> valid_date('03-11-2000') True >>> valid_date('15-01-2012') False >>> valid_date('04-0-2040') False >>> valid_date('06-04-2020') True >>> valid_date('06/04/2020') False """ if not date: return False days_per_month = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] date_list = [int(d) for d in date.split('-')] if len(date_list) != 3: return False if date_list[0] < 1 or date_list[0] > 12: return False if date_list[1] < 1 or date_list[1] > days_per_month[date_list[0] - 1]:
if len(str(date_list[2])) != 4: return False return True
return False
def check(candidate): assert candidate('03-11-2000') == True assert candidate('15-01-2012') == False assert candidate('04-0-2040') == False assert candidate('06-04-2020') == True assert candidate('01-01-2007') == True assert candidate('03-32-2011') == False assert candidate('') == False assert candidate('04-31-3000') == False assert candidate('06-06-2005') == True assert candidate('21-31-2000') == False assert candidate('04-12-2003') == True assert candidate('04122003') == False assert candidate('20030412') == False assert candidate('2003-04') == False assert candidate('2003-04-12') == False assert candidate('04-2003') == False def test_check(): check(valid_date) test_check()
humaneval-HumanEval_102_choose_num.json-L14
py
def choose_num(x: int, y: int) -> int: """This function takes two positive numbers x and y and returns the biggest even integer number that is in the range [x, y] inclusive. If there's no such number, then the function should return -1. For example: >>> choose_num(12, 15) 14 >>> choose_num(13, 12) -1 """ numbers = list(range(x, y + 1)) even_numbers = list(filter(lambda num: num % 2 == 0, numbers))
return max(even_numbers) if even_numbers else -1
def check(candidate): assert candidate(12, 15) == 14 assert candidate(13, 12) == -1 assert candidate(33, 12354) == 12354 assert candidate(5234, 5233) == -1 assert candidate(6, 29) == 28 assert candidate(27, 10) == -1 assert candidate(7, 7) == -1 assert candidate(546, 546) == 546 def test_check(): check(choose_num) test_check()
humaneval-HumanEval_6_parse_nested_parens.json-L13
js
//Input to this function is a string represented multiple groups for nested parentheses separated by spaces. // For each of the group, output the deepest level of nesting of parentheses. // E.g. (()()) has maximum two levels of nesting while ((())) has three. // >>> parse_nested_parens("(()()) ((())) () ((())()())") // [2, 3, 1, 3] function parse_nested_parens(paren_string){ var level = 0; var maxlevel = 0; var result = []; for (var i = 0; i < paren_string.length; i++){ if (paren_string[i] == "("){ level += 1;
maxlevel = level; } } else if (paren_string[i] == ")"){ level -= 1; } else if (paren_string[i] == " "){ result.push(maxlevel); maxlevel = 0; level = 0; } } result.push(maxlevel); return result; }
if (level > maxlevel){
const assert = require('node:assert'); function test() { let candidate = parse_nested_parens; assert.deepEqual(candidate("(()()) ((())) () ((())()())"),[2, 3, 1, 3]); assert.deepEqual(candidate("() (()) ((())) (((())))"),[1, 2, 3, 4]); assert.deepEqual(candidate("(()(())((())))"),[4]); } test();
humaneval-HumanEval_1_separate_paren_groups.json-L29
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string containing multiple groups of nested parentheses. Your goal is to // separate those group into separate strings and return the array list of those. // Separate groups are balanced (each open brace is properly closed) and not nested within each other // Ignore any spaces in the input string. // >>> separateParenGroups(("( ) (( )) (( )( ))")) // (new ArrayList<String>(Arrays.asList((String)"()", (String)"(())", (String)"(()())"))) public static ArrayList<String> separateParenGroups(String paren_string) { ArrayList<String> output = new ArrayList<String>(); StringBuffer temp = new StringBuffer(); int open_paren = 0; for (int i = 0; i < paren_string.length(); i++) { char c = paren_string.charAt(i); if (c == '(') { if (open_paren == 0) { temp = new StringBuffer(); } open_paren++; temp.append(c); } else if (c == ')') { open_paren--;
if (open_paren == 0) { output.add(temp.toString()); } } } return output; } }
temp.append(c);
} public static void main(String[] args) { assert(separateParenGroups(("(()()) ((())) () ((())()())")).equals((new ArrayList<String>(Arrays.asList((String)"(()())", (String)"((()))", (String)"()", (String)"((())()())"))))); assert(separateParenGroups(("() (()) ((())) (((())))")).equals((new ArrayList<String>(Arrays.asList((String)"()", (String)"(())", (String)"((()))", (String)"(((())))"))))); assert(separateParenGroups(("(()(())((())))")).equals((new ArrayList<String>(Arrays.asList((String)"(()(())((())))"))))); assert(separateParenGroups(("( ) (( )) (( )( ))")).equals((new ArrayList<String>(Arrays.asList((String)"()", (String)"(())", (String)"(()())"))))); } }
humaneval-HumanEval_55_fib.json-L14
js
//Return n-th Fibonacci number. // >>> fib(10) // 55 // >>> fib(1) // 1 // >>> fib(8) // 21 function fib(n){ if(n <= 2){ return 1; } else { return fib(n-1) + fib(n-2); }
}
const assert = require('node:assert'); function test() { let candidate = fib; assert.deepEqual(candidate(10),55); assert.deepEqual(candidate(1),1); assert.deepEqual(candidate(8),21); assert.deepEqual(candidate(11),89); assert.deepEqual(candidate(12),144); } test();
humaneval-HumanEval_51_remove_vowels.json-L29
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // remove_vowels is a function that takes string and returns string without vowels. // >>> removeVowels(("")) // ("") // >>> removeVowels(("abcdef")) // ("bcdf") // >>> removeVowels(("aaaaa")) // ("") // >>> removeVowels(("aaBAA")) // ("B") // >>> removeVowels(("zbcd")) // ("zbcd") public static String removeVowels(String text) { String vowels = "aeiouAEIOU"; String newText = ""; for (int i = 0; i < text.length(); i++) { if (vowels.indexOf(text.charAt(i)) == -1) { newText += text.charAt(i); } } return newText;
}
}
} public static void main(String[] args) { assert(removeVowels(("")).equals((""))); assert(removeVowels(("abcdef\nghijklm")).equals(("bcdf\nghjklm"))); assert(removeVowels(("fedcba")).equals(("fdcb"))); assert(removeVowels(("eeeee")).equals((""))); assert(removeVowels(("acBAA")).equals(("cB"))); assert(removeVowels(("EcBOO")).equals(("cB"))); assert(removeVowels(("ybcd")).equals(("ybcd"))); } }
humaneval-HumanEval_37_sort_even.json-L12
py
from typing import List def sort_even(l: List[int]) -> List[int]: """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) [3, 6, 5, 4] """
temp: List[int] = [] for i in range(0, len(l), 2): temp.append(l[i]) temp.sort() for i in range(0, len(l), 2): l[i] = temp[i // 2] return l
if l:
def check(candidate): assert candidate([1, 2, 3]) == [1, 2, 3] assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) == [-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123] assert candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]) == [-12, 8, 3, 4, 5, 2, 12, 11, 23, -10] def test_check(): check(sort_even) test_check()
humaneval-HumanEval_74_total_match.json-L24
js
//Write a function that accepts two arrays of strings and returns the array that has // total number of chars in the all strings of the array less than the other array. // if the two arrays have the same number of chars, return the first array. // Examples // >>> total_match([], []) // [] // >>> total_match(["hi", "admin"], ["hI", "Hi"]) // ["hI", "Hi"] // >>> total_match(["hi", "admin"], ["hi", "hi", "admin", "project"]) // ["hi", "admin"] // >>> total_match(["hi", "admin"], ["hI", "hi", "hi"]) // ["hI", "hi", "hi"] // >>> total_match(["4"], ["1", "2", "3", "4", "5"]) // ["4"] function total_match(lst1, lst2){ let sum_lst1 = 0; let sum_lst2 = 0; for(let item of lst1){ sum_lst1 += item.length; } for(let item of lst2){ sum_lst2 += item.length; }
return lst2; } else{ return lst1; } }
if(sum_lst1 > sum_lst2){
const assert = require('node:assert'); function test() { let candidate = total_match; assert.deepEqual(candidate([], []),[]); assert.deepEqual(candidate(["hi", "admin"], ["hi", "hi"]),["hi", "hi"]); assert.deepEqual(candidate(["hi", "admin"], ["hi", "hi", "admin", "project"]),["hi", "admin"]); assert.deepEqual(candidate(["4"], ["1", "2", "3", "4", "5"]),["4"]); assert.deepEqual(candidate(["hi", "admin"], ["hI", "Hi"]),["hI", "Hi"]); assert.deepEqual(candidate(["hi", "admin"], ["hI", "hi", "hi"]),["hI", "hi", "hi"]); assert.deepEqual(candidate(["hi", "admin"], ["hI", "hi", "hii"]),["hi", "admin"]); assert.deepEqual(candidate([], ["this"]),[]); assert.deepEqual(candidate(["this"], []),[]); } test();
humaneval-HumanEval_94_skjkasdkd.json-L21
js
//You are given an array of integers. // You need to find the largest prime value and return the sum of its digits. // Examples: // >>> skjkasdkd([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]) // 10 // >>> skjkasdkd([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]) // 25 // >>> skjkasdkd([1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]) // 13 // >>> skjkasdkd([0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]) // 11 // >>> skjkasdkd([0, 81, 12, 3, 1, 21]) // 3 // >>> skjkasdkd([0, 8, 1, 2, 1, 7]) // 7 function skjkasdkd(lst){ function prime(n){ if (n<2) return false; for (let i=2; i<=Math.sqrt(n); i++){ if (n%i==0) return false;
return true; } let max = Math.max(...lst.filter(x=>prime(x))); let digits = String(max).split(''); let sum = 0; for (let i=0; i<digits.length; i++){ sum += Number(digits[i]); } return sum; }
}
const assert = require('node:assert'); function test() { let candidate = skjkasdkd; assert.deepEqual(candidate([0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3]),10); assert.deepEqual(candidate([1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1]),25); assert.deepEqual(candidate([1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3]),13); assert.deepEqual(candidate([0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6]),11); assert.deepEqual(candidate([0, 81, 12, 3, 1, 21]),3); assert.deepEqual(candidate([0, 8, 1, 2, 1, 7]),7); assert.deepEqual(candidate([8191]),19); assert.deepEqual(candidate([8191, 123456, 127, 7]),19); assert.deepEqual(candidate([127, 97, 8192]),10); } test();
humaneval-HumanEval_135_can_arrange.json-L15
py
from typing import List def can_arrange(arr: List[int]) -> int: """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: >>> can_arrange([1, 2, 4, 3, 5]) 3 >>> can_arrange([1, 2, 3]) -1 """
for i in range(len(arr)): if i != 0 and arr[i] < arr[i - 1]: ans = i return ans
ans = -1
def check(candidate): assert candidate([1, 2, 4, 3, 5]) == 3 assert candidate([1, 2, 4, 5]) == -1 assert candidate([1, 4, 2, 5, 6, 7, 8, 9, 10]) == 2 assert candidate([4, 8, 5, 7, 3]) == 4 assert candidate([]) == -1 def test_check(): check(can_arrange) test_check()
humaneval-HumanEval_62_derivative.json-L18
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // xs represent coefficients of a polynomial. // xs[0] + xs[1] * x + xs[2] * x^2 + .... // Return derivative of this polynomial in the same form. // >>> derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long)4l, (long)5l)))) // (new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)12l, (long)20l))) // >>> derivative((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))) // (new ArrayList<Long>(Arrays.asList((long)2l, (long)6l))) public static ArrayList<Long> derivative(ArrayList<Long> xs) { ArrayList<Long> ans = new ArrayList<Long>();
ans.add(xs.get(i) * i); } return ans; } }
for (int i = 1; i < xs.size(); i++) {
} public static void main(String[] args) { assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)1l, (long)2l, (long)4l, (long)5l)))).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)4l, (long)12l, (long)20l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)6l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)3l, (long)2l, (long)1l, (long)0l, (long)4l)))).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)2l, (long)0l, (long)16l))))); assert(derivative((new ArrayList<Long>(Arrays.asList((long)1l)))).equals((new ArrayList<Long>(Arrays.asList())))); } }
humaneval-HumanEval_119_match_parens.json-L29
js
//You are given an array of two strings, both strings consist of open // parentheses '(' or close parentheses ')' only. // Your job is to check if it is possible to concatenate the two strings in // some order, that the resulting string will be good. // A string S is considered to be good if and only if all parentheses in S // are balanced. For example: the string '(())()' is good, while the string // '())' is not. // Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. // Examples: // >>> match_parens(["()(", ")"]) // "Yes" // >>> match_parens([")", ")"]) // "No" function match_parens(lst){ const open = '('; const close = ')'; const is_good = (s) => { let stack = []; for (let p of s){ if (p === open){ stack.push(p); } else if (p === close){ if (stack.length === 0){ return false; } stack.pop(); } }
}; const str1 = lst[0]; const str2 = lst[1]; if (is_good(str1 + str2)){ return 'Yes'; } if (is_good(str2 + str1)){ return 'Yes'; } return 'No'; }
return stack.length === 0;
const assert = require('node:assert'); function test() { let candidate = match_parens; assert.deepEqual(candidate(["()(", ")"]),"Yes"); assert.deepEqual(candidate([")", ")"]),"No"); assert.deepEqual(candidate(["(()(())", "())())"]),"No"); assert.deepEqual(candidate([")())", "(()()("]),"Yes"); assert.deepEqual(candidate(["(())))", "(()())(("]),"Yes"); assert.deepEqual(candidate(["()", "())"]),"No"); assert.deepEqual(candidate(["(()(", "()))()"]),"Yes"); assert.deepEqual(candidate(["((((", "((())"]),"No"); assert.deepEqual(candidate([")(()", "(()("]),"No"); assert.deepEqual(candidate([")(", ")("]),"No"); assert.deepEqual(candidate(["(", ")"]),"Yes"); assert.deepEqual(candidate([")", "("]),"Yes"); } test();
humaneval-HumanEval_153_Strongest_Extension.json-L31
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // You will be given the name of a class (a string) and an array array list of extensions. // The extensions are to be used to load additional classes to the class. The // strength of the extension is as follows: Let CAP be the number of the uppercase // letters in the extension's name, and let SM be the number of lowercase letters // in the extension's name, the strength is given by the fraction CAP - SM. // You should find the strongest extension and return a string in this // format: ClassName.StrongestExtensionName. // If there are two or more extensions with the same strength, you should // choose the one that comes first in the array list. // For example, if you are given "Slices" as the class and an array array list of the // extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should // return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension // (its strength is -1). // Example: // >>> StrongestExtension(("my_class"), (new ArrayList<String>(Arrays.asList((String)"AA", (String)"Be", (String)"CC")))) // ("my_class.AA") public static String StrongestExtension(String class_name, ArrayList<String> extensions) { if (extensions.size() == 0) { return class_name; } int strength = Integer.MIN_VALUE; String strongest = "";
int cap = (int)s.chars().filter(c -> Character.isUpperCase(c)).count(); int sm = (int)s.chars().filter(c -> Character.isLowerCase(c)).count(); int diff = cap - sm; if (diff > strength) { strength = diff; strongest = s; } } return class_name + "." + strongest; } }
for (String s : extensions) {
} public static void main(String[] args) { assert(StrongestExtension(("Watashi"), (new ArrayList<String>(Arrays.asList((String)"tEN", (String)"niNE", (String)"eIGHt8OKe")))).equals(("Watashi.eIGHt8OKe"))); assert(StrongestExtension(("Boku123"), (new ArrayList<String>(Arrays.asList((String)"nani", (String)"NazeDa", (String)"YEs.WeCaNe", (String)"32145tggg")))).equals(("Boku123.YEs.WeCaNe"))); assert(StrongestExtension(("__YESIMHERE"), (new ArrayList<String>(Arrays.asList((String)"t", (String)"eMptY", (String)"nothing", (String)"zeR00", (String)"NuLl__", (String)"123NoooneB321")))).equals(("__YESIMHERE.NuLl__"))); assert(StrongestExtension(("K"), (new ArrayList<String>(Arrays.asList((String)"Ta", (String)"TAR", (String)"t234An", (String)"cosSo")))).equals(("K.TAR"))); assert(StrongestExtension(("__HAHA"), (new ArrayList<String>(Arrays.asList((String)"Tab", (String)"123", (String)"781345", (String)"-_-")))).equals(("__HAHA.123"))); assert(StrongestExtension(("YameRore"), (new ArrayList<String>(Arrays.asList((String)"HhAas", (String)"okIWILL123", (String)"WorkOut", (String)"Fails", (String)"-_-")))).equals(("YameRore.okIWILL123"))); assert(StrongestExtension(("finNNalLLly"), (new ArrayList<String>(Arrays.asList((String)"Die", (String)"NowW", (String)"Wow", (String)"WoW")))).equals(("finNNalLLly.WoW"))); assert(StrongestExtension(("_"), (new ArrayList<String>(Arrays.asList((String)"Bb", (String)"91245")))).equals(("_.Bb"))); assert(StrongestExtension(("Sp"), (new ArrayList<String>(Arrays.asList((String)"671235", (String)"Bb")))).equals(("Sp.671235"))); } }
humaneval-HumanEval_124_valid_date.json-L23
js
//You have to write a function which validates a given date string and // returns true if the date is valid otherwise false. // The date is valid if all of the following rules are satisfied: // 1. The date string is not empty. // 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2. // 3. The months should not be less than 1 or higher than 12. // 4. The date should be in the format: mm-dd-yyyy // >>> valid_date("03-11-2000") // true // >>> valid_date("15-01-2012") // false // >>> valid_date("04-0-2040") // false // >>> valid_date("06-04-2020") // true // >>> valid_date("06/04/2020") // false function valid_date(date){ var date_arr = date.split("-"); if(date_arr.length == 3){ var month = parseInt(date_arr[0]); var day = parseInt(date_arr[1]);
if(month < 1 || month > 12){ return false; }else if(month == 2){ if(day < 1 || day > 29){ return false; } }else if((month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12) && (day < 1 || day > 31)){ return false; }else if((month == 4 || month == 6 || month == 9 || month == 11) && (day < 1 || day > 30)){ return false; } return true; } return false; }
var year = parseInt(date_arr[2]);
const assert = require('node:assert'); function test() { let candidate = valid_date; assert.deepEqual(candidate("03-11-2000"),true); assert.deepEqual(candidate("15-01-2012"),false); assert.deepEqual(candidate("04-0-2040"),false); assert.deepEqual(candidate("06-04-2020"),true); assert.deepEqual(candidate("01-01-2007"),true); assert.deepEqual(candidate("03-32-2011"),false); assert.deepEqual(candidate(""),false); assert.deepEqual(candidate("04-31-3000"),false); assert.deepEqual(candidate("06-06-2005"),true); assert.deepEqual(candidate("21-31-2000"),false); assert.deepEqual(candidate("04-12-2003"),true); assert.deepEqual(candidate("04122003"),false); assert.deepEqual(candidate("20030412"),false); assert.deepEqual(candidate("2003-04"),false); assert.deepEqual(candidate("2003-04-12"),false); assert.deepEqual(candidate("04-2003"),false); } test();
humaneval-HumanEval_136_largest_smallest_integers.json-L27
py
from typing import List, Tuple, Optional def largest_smallest_integers(lst: List[int]) -> Tuple[Optional[int], Optional[int]]: """ Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no negative or positive integers, return them as None. Examples: >>> largest_smallest_integers([2, 4, 1, 3, 5, 7]) (None, 1) >>> largest_smallest_integers([]) (None, None) >>> largest_smallest_integers([0]) (None, None) """ smallest_positive = None largest_negative = None for num in lst: if num > 0: if smallest_positive is None or num < smallest_positive: smallest_positive = num elif num < 0: if largest_negative is None or num > largest_negative: largest_negative = num
return (largest_negative, smallest_positive)
def check(candidate): assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1) assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1) assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1) assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2) assert candidate([7, 3, 8, 4, 9, 2, 5, -9]) == (-9, 2) assert candidate([]) == (None, None) assert candidate([0]) == (None, None) assert candidate([-1, -3, -5, -6]) == (-1, None) assert candidate([-1, -3, -5, -6, 0]) == (-1, None) assert candidate([-6, -4, -4, -3, 1]) == (-3, 1) assert candidate([-6, -4, -4, -3, -100, 1]) == (-3, 1) def test_check(): check(largest_smallest_integers) test_check()
humaneval-HumanEval_109_move_one_ball.json-L24
js
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array will be randomly ordered. Your task is to determine if // it is possible to get an array sorted in non-decreasing order by performing // the following operation on the given array: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array by one // position in the right direction. The last element of the array will be moved to // the starting position in the array i.e. 0th index. // If it is possible to obtain the sorted array by performing the above operation // then return true else return false. // If the given array is empty then return true. // Note: The given array is guaranteed to have unique elements. // For Example: // >>> move_one_ball([3, 4, 5, 1, 2]) // true // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array. // >>> move_one_ball([3, 5, 4, 1, 2]) // false // Explanation:It is not possible to get non-decreasing order for the given // array by performing any number of right shift operations. function move_one_ball(arr){ var diff_count = 0;
var temp = 0; for(var i = 0; i < arr.length - 1; i++){ if(arr[i] > arr[i + 1]){ diff_count += 1; } } if(diff_count > 1){ return false; } else{ return true; } }
var i = 0;
const assert = require('node:assert'); function test() { let candidate = move_one_ball; assert.deepEqual(candidate([3, 4, 5, 1, 2]),true); assert.deepEqual(candidate([3, 5, 10, 1, 2]),true); assert.deepEqual(candidate([4, 3, 1, 2]),false); assert.deepEqual(candidate([3, 5, 4, 1, 2]),false); assert.deepEqual(candidate([]),true); } test();
humaneval-HumanEval_155_even_odd_count.json-L16
js
//Given an integer. return an array that has the number of even and odd digits respectively. // Example: // >>> even_odd_count(-12) // [1, 1] // >>> even_odd_count(123) // [1, 2] function even_odd_count(num){ num = Math.abs(num); var evens = 0; var odds = 0; for(var i = 0; i < num.toString().length; i++){ if(num.toString()[i] % 2 == 0){ evens ++; } else{
} } return [evens, odds]; }
odds ++;
const assert = require('node:assert'); function test() { let candidate = even_odd_count; assert.deepEqual(candidate(7),[0, 1]); assert.deepEqual(candidate(-78),[1, 1]); assert.deepEqual(candidate(3452),[2, 2]); assert.deepEqual(candidate(346211),[3, 3]); assert.deepEqual(candidate(-345821),[3, 3]); assert.deepEqual(candidate(-2),[1, 0]); assert.deepEqual(candidate(-45347),[2, 3]); assert.deepEqual(candidate(0),[1, 0]); } test();
humaneval-HumanEval_57_monotonic.json-L13
js
//Return true is array elements are monotonically increasing or decreasing. // >>> monotonic([1, 2, 4, 20]) // true // >>> monotonic([1, 20, 4, 10]) // false // >>> monotonic([4, 1, 0, -10]) // true function monotonic(l){ if(l.length <= 1){ return true; } if(l[0] < l[1]){
if(l[i] > l[i + 1]){ return false; } } } else{ for(var i = 1; i < l.length - 1; i++){ if(l[i] < l[i + 1]){ return false; } } } return true; }
for(var i = 1; i < l.length - 1; i++){
const assert = require('node:assert'); function test() { let candidate = monotonic; assert.deepEqual(candidate([1, 2, 4, 10]),true); assert.deepEqual(candidate([1, 2, 4, 20]),true); assert.deepEqual(candidate([1, 20, 4, 10]),false); assert.deepEqual(candidate([4, 1, 0, -10]),true); assert.deepEqual(candidate([4, 1, 1, 0]),true); assert.deepEqual(candidate([1, 2, 3, 2, 5, 60]),false); assert.deepEqual(candidate([1, 2, 3, 4, 5, 60]),true); assert.deepEqual(candidate([9, 9, 9, 9]),true); } test();
humaneval-HumanEval_114_minSubArraySum.json-L12
js
//Given an array of integers nums, find the minimum sum of any non-empty sub-array // of nums. // Example // >>> minSubArraySum([2, 3, 4, 1, 2, 4]) // 1 // >>> minSubArraySum([-1, -2, -3]) // -6 function minSubArraySum(nums){ let sum = 0; let minSum = nums[0]; for(let i = 0; i < nums.length; i++){
if(sum < minSum){ minSum = sum; } if(sum > 0){ sum = 0; } } return minSum; }
sum += nums[i];
const assert = require('node:assert'); function test() { let candidate = minSubArraySum; assert.deepEqual(candidate([2, 3, 4, 1, 2, 4]),1); assert.deepEqual(candidate([-1, -2, -3]),-6); assert.deepEqual(candidate([-1, -2, -3, 2, -10]),-14); assert.deepEqual(candidate([-9999999999999999]),-9999999999999999); assert.deepEqual(candidate([0, 10, 20, 1000000]),0); assert.deepEqual(candidate([-1, -2, -3, 10, -5]),-6); assert.deepEqual(candidate([100, -1, -2, -3, 10, -5]),-6); assert.deepEqual(candidate([10, 11, 13, 8, 3, 4]),3); assert.deepEqual(candidate([100, -33, 32, -1, 0, -2]),-33); assert.deepEqual(candidate([-10]),-10); assert.deepEqual(candidate([7]),7); assert.deepEqual(candidate([1, -1]),-1); } test();
humaneval-HumanEval_66_digitSum.json-L21
js
//Task // Write a function that takes a string as input and returns the sum of the upper characters only' // ASCII codes. // Examples: // >>> digitSum("") // 0 // >>> digitSum("abAB") // 131 // >>> digitSum("abcCd") // 67 // >>> digitSum("helloE") // 69 // >>> digitSum("woArBld") // 131 // >>> digitSum("aAaaaXa") // 153 function digitSum(s){ var sum = 0; for(var i = 0; i < s.length; i++){ if(s[i] >= 'A' && s[i] <= 'Z'){
} } return sum; }
sum += s.charCodeAt(i);
const assert = require('node:assert'); function test() { let candidate = digitSum; assert.deepEqual(candidate(""),0); assert.deepEqual(candidate("abAB"),131); assert.deepEqual(candidate("abcCd"),67); assert.deepEqual(candidate("helloE"),69); assert.deepEqual(candidate("woArBld"),131); assert.deepEqual(candidate("aAaaaXa"),153); assert.deepEqual(candidate(" How are yOu?"),151); assert.deepEqual(candidate("You arE Very Smart"),327); } test();
humaneval-HumanEval_117_select_words.json-L20
js
//Given a string s and a natural number n, you have been tasked to implement // a function that returns an array of all words from string s that contain exactly // n consonants, in order these words appear in the string s. // If the string s is empty then the function should return an empty array. // Note: you may assume the input string contains only letters and spaces. // Examples: // >>> select_words("Mary had a little lamb", 4) // ["little"] // >>> select_words("Mary had a little lamb", 3) // ["Mary", "lamb"] // >>> select_words("simple white space", 2) // [] // >>> select_words("Hello world", 4) // ["world"] // >>> select_words("Uncle sam", 3) // ["Uncle"] function select_words(s, n){ let words = s.split(' ').filter(e => e != ''); let selected = words.filter(e => e.match(/[bcdfghjklmnpqrstvwxyz]/gi) != null);
return selected.filter(e => e.match(/[bcdfghjklmnpqrstvwxyz]/gi).length == n); }else{ return []; } }
if(n > 0){
const assert = require('node:assert'); function test() { let candidate = select_words; assert.deepEqual(candidate("Mary had a little lamb", 4),["little"]); assert.deepEqual(candidate("Mary had a little lamb", 3),["Mary", "lamb"]); assert.deepEqual(candidate("simple white space", 2),[]); assert.deepEqual(candidate("Hello world", 4),["world"]); assert.deepEqual(candidate("Uncle sam", 3),["Uncle"]); assert.deepEqual(candidate("", 4),[]); assert.deepEqual(candidate("a b c d e f", 1),["b", "c", "d", "f"]); } test();
humaneval-HumanEval_156_int_to_mini_roman.json-L34
js
//Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> int_to_mini_roman(19) // "xix" // >>> int_to_mini_roman(152) // "clii" // >>> int_to_mini_roman(426) // "cdxxvi" function int_to_mini_roman(number){ var roman_conversion = { 1000: "m", 900: "cm", 500: "d", 400: "cd", 100: "c", 90: "xc", 50: "l", 40: "xl", 10: "x", 9: "ix", 5: "v", 4: "iv", 1: "i" }; var output = ""; while (number > 0){ var key_list = Object.keys(roman_conversion).map(Number); key_list.sort(function(a, b){return b-a}); for (var i = 0; i < key_list.length; i++){ if (key_list[i] <= number){ output += roman_conversion[key_list[i]];
break; } } } return output; }
number -= key_list[i];
const assert = require('node:assert'); function test() { let candidate = int_to_mini_roman; assert.deepEqual(candidate(19),"xix"); assert.deepEqual(candidate(152),"clii"); assert.deepEqual(candidate(251),"ccli"); assert.deepEqual(candidate(426),"cdxxvi"); assert.deepEqual(candidate(500),"d"); assert.deepEqual(candidate(1),"i"); assert.deepEqual(candidate(4),"iv"); assert.deepEqual(candidate(43),"xliii"); assert.deepEqual(candidate(90),"xc"); assert.deepEqual(candidate(94),"xciv"); assert.deepEqual(candidate(532),"dxxxii"); assert.deepEqual(candidate(900),"cm"); assert.deepEqual(candidate(994),"cmxciv"); assert.deepEqual(candidate(1000),"m"); } test();
humaneval-HumanEval_73_smallest_change.json-L17
js
//Given an array arr of integers, find the minimum number of elements that // need to be changed to make the array palindromic. A palindromic array is an array that // is read the same backwards and forwards. In one change, you can change one element to any other element. // For example: // >>> smallest_change([1, 2, 3, 5, 4, 7, 9, 6]) // 4 // >>> smallest_change([1, 2, 3, 4, 3, 2, 2]) // 1 // >>> smallest_change([1, 2, 3, 2, 1]) // 0 function smallest_change(arr){ let changes = 0; for(let i = 0; i < arr.length/2; i++){ if(arr[i] != arr[arr.length - 1 - i]){ changes++; }
return changes; }
}
const assert = require('node:assert'); function test() { let candidate = smallest_change; assert.deepEqual(candidate([1, 2, 3, 5, 4, 7, 9, 6]),4); assert.deepEqual(candidate([1, 2, 3, 4, 3, 2, 2]),1); assert.deepEqual(candidate([1, 4, 2]),1); assert.deepEqual(candidate([1, 4, 4, 2]),1); assert.deepEqual(candidate([1, 2, 3, 2, 1]),0); assert.deepEqual(candidate([3, 1, 1, 3]),0); assert.deepEqual(candidate([1]),0); assert.deepEqual(candidate([0, 1]),1); } test();
humaneval-HumanEval_69_search.json-L26
js
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Examples: // >>> search([4, 1, 2, 2, 3, 1]) // 2 // >>> search([1, 2, 2, 3, 3, 3, 4, 4, 4]) // 3 // >>> search([5, 5, 4, 4, 4]) // -1 function search(lst){ var h = {}; for (var i=0; i<lst.length; i++){ var x = lst[i]; if (x in h){ h[x] += 1; } else{ h[x] = 1; } } var keys = Object.keys(h); var max = 0; for (var i=0; i<keys.length; i++){
max = keys[i]; } } if (max == 0){ return -1; } return max; }
if (keys[i] > max && h[keys[i]] >= keys[i]){
const assert = require('node:assert'); function test() { let candidate = search; assert.deepEqual(candidate([5, 5, 5, 5, 1]),1); assert.deepEqual(candidate([4, 1, 4, 1, 4, 4]),4); assert.deepEqual(candidate([3, 3]),-1); assert.deepEqual(candidate([8, 8, 8, 8, 8, 8, 8, 8]),8); assert.deepEqual(candidate([2, 3, 3, 2, 2]),2); assert.deepEqual(candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]),1); assert.deepEqual(candidate([3, 2, 8, 2]),2); assert.deepEqual(candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]),1); assert.deepEqual(candidate([8, 8, 3, 6, 5, 6, 4]),-1); assert.deepEqual(candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]),1); assert.deepEqual(candidate([1, 9, 10, 1, 3]),1); assert.deepEqual(candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]),5); assert.deepEqual(candidate([1]),1); assert.deepEqual(candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]),4); assert.deepEqual(candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]),2); assert.deepEqual(candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]),1); assert.deepEqual(candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]),4); assert.deepEqual(candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]),4); assert.deepEqual(candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]),2); assert.deepEqual(candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]),-1); assert.deepEqual(candidate([10]),-1); assert.deepEqual(candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]),2); assert.deepEqual(candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]),1); assert.deepEqual(candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]),1); assert.deepEqual(candidate([3, 10, 10, 9, 2]),-1); } test();
humaneval-HumanEval_156_int_to_mini_roman.json-L71
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Given a positive integer, obtain its roman numeral equivalent as a string, // and return it in lowercase. // Restrictions: 1 <= num <= 1000 // Examples: // >>> intToMiniRoman((19l)) // ("xix") // >>> intToMiniRoman((152l)) // ("clii") // >>> intToMiniRoman((426l)) // ("cdxxvi") public static String intToMiniRoman(long number) { int num = (int) number; String res = ""; if (num == 0) return ""; while (num >= 1000) { res += "m"; num -= 1000; } if (num >= 900) { res += "cm"; num -= 900; } if (num >= 500) { res += "d"; num -= 500; } if (num >= 400) { res += "cd"; num -= 400; } while (num >= 100) { res += "c"; num -= 100; } if (num >= 90) { res += "xc"; num -= 90; } if (num >= 50) { res += "l"; num -= 50; } if (num >= 40) { res += "xl"; num -= 40; } while (num >= 10) { res += "x"; num -= 10; } if (num >= 9) { res += "ix"; num -= 9; } if (num >= 5) { res += "v"; num -= 5; } if (num >= 4) { res += "iv"; num -= 4;
while (num >= 1) { res += "i"; num -= 1; } return res; } }
}
} public static void main(String[] args) { assert(intToMiniRoman((19l)).equals(("xix"))); assert(intToMiniRoman((152l)).equals(("clii"))); assert(intToMiniRoman((251l)).equals(("ccli"))); assert(intToMiniRoman((426l)).equals(("cdxxvi"))); assert(intToMiniRoman((500l)).equals(("d"))); assert(intToMiniRoman((1l)).equals(("i"))); assert(intToMiniRoman((4l)).equals(("iv"))); assert(intToMiniRoman((43l)).equals(("xliii"))); assert(intToMiniRoman((90l)).equals(("xc"))); assert(intToMiniRoman((94l)).equals(("xciv"))); assert(intToMiniRoman((532l)).equals(("dxxxii"))); assert(intToMiniRoman((900l)).equals(("cm"))); assert(intToMiniRoman((994l)).equals(("cmxciv"))); assert(intToMiniRoman((1000l)).equals(("m"))); } }
humaneval-HumanEval_109_move_one_ball.json-L25
js
//We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The // numbers in the array will be randomly ordered. Your task is to determine if // it is possible to get an array sorted in non-decreasing order by performing // the following operation on the given array: // You are allowed to perform right shift operation any number of times. // One right shift operation means shifting all elements of the array by one // position in the right direction. The last element of the array will be moved to // the starting position in the array i.e. 0th index. // If it is possible to obtain the sorted array by performing the above operation // then return true else return false. // If the given array is empty then return true. // Note: The given array is guaranteed to have unique elements. // For Example: // >>> move_one_ball([3, 4, 5, 1, 2]) // true // Explanation: By performin 2 right shift operations, non-decreasing order can // be achieved for the given array. // >>> move_one_ball([3, 5, 4, 1, 2]) // false // Explanation:It is not possible to get non-decreasing order for the given // array by performing any number of right shift operations. function move_one_ball(arr){ var diff_count = 0; var i = 0;
for(var i = 0; i < arr.length - 1; i++){ if(arr[i] > arr[i + 1]){ diff_count += 1; } } if(diff_count > 1){ return false; } else{ return true; } }
var temp = 0;
const assert = require('node:assert'); function test() { let candidate = move_one_ball; assert.deepEqual(candidate([3, 4, 5, 1, 2]),true); assert.deepEqual(candidate([3, 5, 10, 1, 2]),true); assert.deepEqual(candidate([4, 3, 1, 2]),false); assert.deepEqual(candidate([3, 5, 4, 1, 2]),false); assert.deepEqual(candidate([]),true); } test();
humaneval-HumanEval_148_bf.json-L41
js
//There are eight planets in our solar system: the closerst to the Sun // is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, // Uranus, Neptune. // Write a function that takes two planet names as strings planet1 and planet2. // The function should return an array containing all planets whose orbits are // located between the orbit of planet1 and the orbit of planet2, sorted by // the proximity to the sun. // The function should return an empty array if planet1 or planet2 // are not correct planet names. // Examples // >>> bf("Jupiter", "Neptune") // ["Saturn", "Uranus"] // >>> bf("Earth", "Mercury") // "Venus" // >>> bf("Mercury", "Uranus") // ["Venus", "Earth", "Mars", "Jupiter", "Saturn"] function bf(planet1, planet2){ var planets = { 'Mercury':1, 'Venus':2, 'Earth':3, 'Mars':4, 'Jupiter':5, 'Saturn':6, 'Uranus':7, 'Neptune':8 } if(!planets[planet1] || !planets[planet2]){ return []; } var keys = Object.keys(planets); var position1 = keys.indexOf(planet1); var position2 = keys.indexOf(planet2); if(position1 > position2){ var temp = position1; position1 = position2; position2 = temp; } var res = []; for(var i = position1 + 1; i < position2; i++){
} return res; }
res.push(keys[i]);
const assert = require('node:assert'); function test() { let candidate = bf; assert.deepEqual(candidate("Jupiter", "Neptune"),["Saturn", "Uranus"]); assert.deepEqual(candidate("Earth", "Mercury"),["Venus"]); assert.deepEqual(candidate("Mercury", "Uranus"),["Venus", "Earth", "Mars", "Jupiter", "Saturn"]); assert.deepEqual(candidate("Neptune", "Venus"),["Earth", "Mars", "Jupiter", "Saturn", "Uranus"]); assert.deepEqual(candidate("Earth", "Earth"),[]); assert.deepEqual(candidate("Mars", "Earth"),[]); assert.deepEqual(candidate("Jupiter", "Makemake"),[]); } test();
humaneval-HumanEval_162_string_to_md5.json-L10
js
//Given a string 'text', return its md5 hash equivalent string. // If 'text' is an empty string, return undefined. // >>> string_to_md5("Hello world") // "3e25960a79dbc69b674cd4ec67a72c62" function string_to_md5(text){ if(text === ''){ return undefined; } return require('crypto').createHash('md5').update(text).digest('hex');
}
const assert = require('node:assert'); function test() { let candidate = string_to_md5; assert.deepEqual(candidate("Hello world"),"3e25960a79dbc69b674cd4ec67a72c62"); assert.deepEqual(candidate(""),undefined); assert.deepEqual(candidate("A B C"),"0ef78513b0cb8cef12743f5aeb35f888"); assert.deepEqual(candidate("password"),"5f4dcc3b5aa765d61d8327deb882cf99"); } test();
humaneval-HumanEval_4_mean_absolute_deviation.json-L19
js
//For a given array of input numbers, calculate Mean Absolute Deviation // around the mean of this dataset. // Mean Absolute Deviation is the average absolute difference between each // element and a centerpoint (mean in this case): // MAD = average | x - x_mean | // >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0]) // 1.0 function mean_absolute_deviation(numbers){ var sum = 0; for(var i = 0; i < numbers.length; i++){ sum += numbers[i]; } var mean = sum / numbers.length; var sum_abs_diff = 0; for(var i = 0; i < numbers.length; i++){ sum_abs_diff += Math.abs(numbers[i] - mean); } return sum_abs_diff / numbers.length;
}
const assert = require('node:assert'); function test() { let candidate = mean_absolute_deviation; assert.deepEqual(candidate([1.0, 2.0]),0.5); assert.deepEqual(candidate([1.0, 2.0, 3.0, 4.0]),1.0); assert.deepEqual(candidate([1.0, 2.0, 3.0, 4.0, 5.0]),1.2); } test();
humaneval-HumanEval_6_parse_nested_parens.json-L26
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Input to this function is a string represented multiple groups for nested parentheses separated by spaces. // For each of the group, output the deepest level of nesting of parentheses. // E.g. (()()) has maximum two levels of nesting while ((())) has three. // >>> parseNestedParens(("(()()) ((())) () ((())()())")) // (new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)1l, (long)3l))) public static ArrayList<Long> parseNestedParens(String paren_string) { ArrayList<Long> result = new ArrayList<Long>(); String[] paren_strings = paren_string.split(" "); for (String paren : paren_strings) { long max_depth = 0; long current_depth = 0; for (char c : paren.toCharArray()) { if (c == '(') { current_depth += 1; max_depth = Math.max(max_depth, current_depth); } else if (c == ')') { current_depth -= 1;
} result.add(max_depth); } return result; } }
}
} public static void main(String[] args) { assert(parseNestedParens(("(()()) ((())) () ((())()())")).equals((new ArrayList<Long>(Arrays.asList((long)2l, (long)3l, (long)1l, (long)3l))))); assert(parseNestedParens(("() (()) ((())) (((())))")).equals((new ArrayList<Long>(Arrays.asList((long)1l, (long)2l, (long)3l, (long)4l))))); assert(parseNestedParens(("(()(())((())))")).equals((new ArrayList<Long>(Arrays.asList((long)4l))))); } }
humaneval-HumanEval_69_search.json-L32
js
//You are given a non-empty array of positive integers. Return the greatest integer that is greater than // zero, and has a frequency greater than or equal to the value of the integer itself. // The frequency of an integer is the number of times it appears in the array. // If no such a value exist, return -1. // Examples: // >>> search([4, 1, 2, 2, 3, 1]) // 2 // >>> search([1, 2, 2, 3, 3, 3, 4, 4, 4]) // 3 // >>> search([5, 5, 4, 4, 4]) // -1 function search(lst){ var h = {}; for (var i=0; i<lst.length; i++){ var x = lst[i]; if (x in h){ h[x] += 1; } else{ h[x] = 1; } } var keys = Object.keys(h); var max = 0; for (var i=0; i<keys.length; i++){ if (keys[i] > max && h[keys[i]] >= keys[i]){ max = keys[i]; } } if (max == 0){ return -1;
return max; }
}
const assert = require('node:assert'); function test() { let candidate = search; assert.deepEqual(candidate([5, 5, 5, 5, 1]),1); assert.deepEqual(candidate([4, 1, 4, 1, 4, 4]),4); assert.deepEqual(candidate([3, 3]),-1); assert.deepEqual(candidate([8, 8, 8, 8, 8, 8, 8, 8]),8); assert.deepEqual(candidate([2, 3, 3, 2, 2]),2); assert.deepEqual(candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]),1); assert.deepEqual(candidate([3, 2, 8, 2]),2); assert.deepEqual(candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]),1); assert.deepEqual(candidate([8, 8, 3, 6, 5, 6, 4]),-1); assert.deepEqual(candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]),1); assert.deepEqual(candidate([1, 9, 10, 1, 3]),1); assert.deepEqual(candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]),5); assert.deepEqual(candidate([1]),1); assert.deepEqual(candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]),4); assert.deepEqual(candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]),2); assert.deepEqual(candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]),1); assert.deepEqual(candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]),4); assert.deepEqual(candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]),4); assert.deepEqual(candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]),2); assert.deepEqual(candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]),-1); assert.deepEqual(candidate([10]),-1); assert.deepEqual(candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]),2); assert.deepEqual(candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]),1); assert.deepEqual(candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]),1); assert.deepEqual(candidate([3, 10, 10, 9, 2]),-1); } test();
humaneval-HumanEval_93_encode.json-L34
java
import java.util.*; import java.lang.reflect.*; import org.javatuples.*; import java.security.*; import java.math.*; import java.io.*; import java.util.stream.*; class Problem { // Write a function that takes a message, and encodes in such a // way that it swaps case of all letters, replaces all vowels in // the message with the letter that appears 2 places ahead of that // vowel in the english alphabet. // Assume only letters. // Examples: // >>> encode(("test")) // ("TGST") // >>> encode(("This is a message")) // ("tHKS KS C MGSSCGG") public static String encode(String message) { char[] arr = message.toCharArray(); char[] vowels = "AEIOUaeiou".toCharArray(); for (int i = 0; i < arr.length; i++) { if (Arrays.binarySearch(vowels, arr[i]) > -1) { arr[i] = (char) (arr[i] + 2); } if (Character.isUpperCase(arr[i])) { arr[i] = Character.toLowerCase(arr[i]); } else { arr[i] = Character.toUpperCase(arr[i]); } } return new String(arr); }
}
} public static void main(String[] args) { assert(encode(("TEST")).equals(("tgst"))); assert(encode(("Mudasir")).equals(("mWDCSKR"))); assert(encode(("YES")).equals(("ygs"))); assert(encode(("This is a message")).equals(("tHKS KS C MGSSCGG"))); assert(encode(("I DoNt KnOw WhAt tO WrItE")).equals(("k dQnT kNqW wHcT Tq wRkTg"))); } }
humaneval-HumanEval_71_triangle_area.json-L12
js
//Given the lengths of the three sides of a triangle. Return the area of // the triangle rounded to 2 decimal points if the three sides form a valid triangle. // Otherwise return -1 // Three sides make a valid triangle when the sum of any two sides is greater // than the third side. // Example: // >>> triangle_area(3, 4, 5) // 6.0 // >>> triangle_area(1, 2, 10) // -1 function triangle_area(a, b, c){
var s = (a+b+c)/2; return Math.sqrt(s*(s-a)*(s-b)*(s-c)).toFixed(2); }else{ return -1; } }
if(a+b>c && a+c>b && b+c>a){
const assert = require('node:assert'); function test() { let candidate = triangle_area; assert.deepEqual(candidate(3, 4, 5),6.0); assert.deepEqual(candidate(1, 2, 10),-1); assert.deepEqual(candidate(4, 8, 5),8.18); assert.deepEqual(candidate(2, 2, 2),1.73); assert.deepEqual(candidate(1, 2, 3),-1); assert.deepEqual(candidate(10, 5, 7),16.25); assert.deepEqual(candidate(2, 6, 3),-1); assert.deepEqual(candidate(1, 1, 1),0.43); assert.deepEqual(candidate(2, 2, 10),-1); } test();