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Separate each row by paragraph
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import re
def is_newline_after_text(text1, text2):
"""
Checks if text1 is in text2 and if the next non-space character after text1 is a newline.
Args:
text1: The text to search for.
text2: The text to search within.
Returns:
A tuple: (True/False if text1 is found, True/False if next char is newline, or None if not found)
"""
match = re.search(re.escape(text1), text2) #escape text1 to handle special characters
if match:
# Find the next non-space character
next_char_index = match.end()
while next_char_index < len(text2) and text2[next_char_index].isspace():
next_char_index += 1
if text2[next_char_index:next_char_index+2] == r'\n':
print("newline found")
if next_char_index < len(text2) and text2[next_char_index:next_char_index+2] == r'\n':
return True
return False
def is_newline_after_text_2(text1, text2):
"""
Checks if text1 is in text2 and if the next non-space character after text1 is a newline.
Args:
text1: The text to search for.
text2: The text to search within.
Returns:
True if next char is newline
"""
text2 = text2.replace("\n", "\\n")
ater_text = text2.split(text1)
if len(ater_text) > 1:
ater_text = ater_text[1].lstrip() # Remove spaces
if ater_text.startswith('\n'):
return True
return False
# Example usage:
text1 = "hello"
text2 = "some text hello \nmore text"
result = is_newline_after_text_2(text1, text2)
print(f"Next char is newline: {result}\n")
text1 = "hello"
text2 = "some text hello more text"
result = is_newline_after_text_2(text1, text2)
print(f"Next char is newline: {result}\n")
text1 = "hello"
text2 = "some text hello \nmore text"
result = is_newline_after_text_2(text1, text2)
print(f"Next char is newline: {result}\n")
text1 = "hello"
text2 = "some text hello\t\nmore text" #test tab space before newline
result = is_newline_after_text_2(text1, text2)
print(f"Next char is newline: {result}\n")
text1 = "hello." #test special characters
text2 = "some text hello. \nmore text"
result = is_newline_after_text_2(text1, text2)
print(f"Next char is newline: {result}\n")