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import difflib | |
def remove_prefix_by_last_line(a: str, b: str, threshold: float = 0.85) -> str: | |
""" | |
基于A的最后一行定位B中的截断点,删除B中该行之前的所有内容 | |
:param a: 前缀字符串A | |
:param b: 目标字符串B | |
:param threshold: 行相似度阈值 | |
:return: 删除前缀后的B字符串 | |
""" | |
a_lines = a.splitlines() | |
b_lines = b.splitlines() | |
if not a_lines: | |
return b | |
last_a_line = a_lines[-1] | |
cut_index = -1 | |
for i, b_line in enumerate(b_lines): | |
similarity = difflib.SequenceMatcher( | |
None, last_a_line, b_line | |
).ratio() | |
if similarity >= threshold: | |
cut_index = i | |
break | |
if cut_index != -1: | |
return '\n'.join(b_lines[cut_index+1:]) | |
else: | |
return b | |
A = "#include<assert.h>\n#include<bits/stdc++.h>\n// Check if in given vector of numbers, are any two numbers closer to each other than\n// given threshold.\n// >>> has_close_elements((std::vector<float>({(float)1.0f, (float)2.0f, (float)3.0f})), (0.5f))\n// (false)\n// >>> has_close_elements((std::vector<float>({(float)1.0f, (float)2.8f, (float)3.0f, (float)4.0f, (float)5.0f, (float)2.0f})), (0.3f))\n// (true)\nbool has_close_elements(std::vector<float> numbers, float threshold) {\n" | |
B = "#include <assert.h>\n#include <bits/stdc++.h>\n\n// Check if in given vector of numbers, are any two numbers closer to each other than\n// given threshold.\n// >>> has_close_elements((std::vector<float>({(float)1.0f, (float)2.0f, (float)3.0f})), (0.5f))\n// (false)\n// >>> has_close_elements((std::vector<float>({(float)1.0f, (float)2.8f, (float)3.0f, (float)4.0f, (float)5.0f, (float)2.0f})), (0.3f))\n// (true)\nbool has_close_elements(std::vector<float> numbers, float threshold) {\n // Sort the vector in ascending order\n std::sort(numbers.begin(), numbers.end());\n\n // Iterate over the sorted vector\n for (size_t i = 0; i < numbers.size() - 1; ++i) {\n // Check if the difference between the current element and the next element is less than the threshold\n if (numbers[i + 1] - numbers[i] < threshold) {\n return true; // If a pair of elements is found that are closer than the threshold, return true\n }\n }\n\n // If no pair of elements is found that are closer than the threshold, return false\n return false;\n}\n\nint main() {\n std::vector<float> numbers1 = {1.0f, 2.0f, 3.0f};\n std::vector<float> numbers2 = {1.0f, 2.8f, 3.0f, 4.0f, 5.0f, 2.0f};\n\n std::cout << std::boolalpha << has_close_elements(numbers1, 0.5f) << std::endl; // Output: false\n std::cout << std::boolalpha << has_close_elements(numbers2, 0.3f) << std::endl; // Output: true\n\n return 0;\n}\n" | |
# print(remove_prefix_by_last_line(A, B)) | |
A = "#include<assert.h>\n#include<bits/stdc++.h>\n// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n// separate those group into separate strings and return the vector of those.\n// Separate groups are balanced (each open brace is properly closed) and not nested within each other\n// Ignore any spaces in the input string.\n// >>> separate_paren_groups((\"( ) (( )) (( )( ))\"))\n// (std::vector<std::string>({(std::string)\"()\", (std::string)\"(())\", (std::string)\"(()())\"}))\nstd::vector<std::string> separate_paren_groups(std::string paren_string) {\n" | |
B = "#include <assert.h>\n#include <bits/stdc++.h>\n\n// Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n// separate those group into separate strings and return the vector of those.\n// Separate groups are balanced (each open brace is properly closed) and not nested within each other\n// Ignore any spaces in the input string.\n// >>> separate_paren_groups(\"(( )) (( )( ))\")\n// (std::vector<std::string>({(std::string)\"()\", (std::string)\"(())\", (std::string)\"(()())\"}))\n\nstd::vector<std::string> separate_paren_groups(std::string paren_string) {\n // Remove spaces from the input string\n paren_string.erase(std::remove(paren_string.begin(), paren_string.end(), ' '), paren_string.end());\n\n // Initialize an empty vector to store the groups\n std::vector<std::string> groups;\n\n // Initialize an empty string to build the current group\n std::string current_group;\n\n // Initialize a counter to keep track of the balance of parentheses\n int balance = 0;\n\n // Iterate over the characters in the input string\n for (char c : paren_string) {\n // If the character is an open parenthesis, increment the balance\n if (c == '(') {\n balance++;\n current_group += c;\n }\n // If the character is a close parenthesis, decrement the balance\n else if (c == ')') {\n balance--;\n current_group += c;\n // If the balance is zero, it means we've found a complete group\n if (balance == 0) {\n groups.push_back(current_group);\n current_group.clear();\n }\n }\n // If the character is not a parenthesis, ignore it\n }\n\n // Return the vector of groups\n return groups;\n}\n\nint main() {\n std::string paren_string = \"(( )) (( )( ))\";\n std::vector<std::string> groups = separate_paren_groups(paren_string);\n\n // Print the groups\n for (const auto& group : groups) {\n std::cout << group << std::endl;\n }\n\n return 0;\n}\n" | |
# print(remove_prefix_by_last_line(A, B)) | |
A = "#include<assert.h>\n#include<bits/stdc++.h>\n// The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n// fib4(0) -> 0\n// fib4(1) -> 0\n// fib4(2) -> 2\n// fib4(3) -> 0\n// fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n// Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n// >>> fib4((5))\n// (4)\n// >>> fib4((6))\n// (8)\n// >>> fib4((7))\n// (14)\nlong fib4(long n) {\n" | |
B = "#include <assert.h>\n#include <bits/stdc++.h>\n\n// The Fib4 number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n// fib4(0) -> 0\n// fib4(1) -> 0\n// fib4(2) -> 2\n// fib4(3) -> 0\n// fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n// Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.\n\n// We can use dynamic programming to solve this problem efficiently. We will store the results of subproblems in an array to avoid redundant calculations.\n\nlong fib4(long n) {\n // Base cases\n if (n <= 1) {\n return 0;\n } else if (n == 2) {\n return 2;\n } else if (n == 3) {\n return 0;\n }\n\n // Initialize an array to store the results of subproblems\n long fib4[n + 1];\n\n // Base cases\n fib4[0] = 0;\n fib4[1] = 0;\n fib4[2] = 2;\n fib4[3] = 0;\n\n // Compute the n-th element of the fib4 number sequence\n for (long i = 4; i <= n; i++) {\n fib4[i] = fib4[i - 1] + fib4[i - 2] + fib4[i - 3] + fib4[i - 4];\n }\n\n // Return the n-th element of the fib4 number sequence\n return fib4[n];\n}\n\nint main() {\n // Test the function\n std::cout << \"fib4(5) = \" << fib4(5) << std::endl;\n std::cout << \"fib4(6) = \" << fib4(6) << std::endl;\n std::cout << \"fib4(7) = \" << fib4(7) << std::endl;\n\n return 0;\n}\n" | |
# print(remove_prefix_by_last_line(A, B)) | |
A = "package check_if_last_char_is_a_letter_test\n\nimport (\n \"testing\"\n \"fmt\"\n)\n\n// Create a function that returns true if the last character\n// of a given string is an alphabetical character and is not\n// a part of a word, and false otherwise.\n// Note: \"word\" is a group of characters separated by space.\n// Examples:\n// >>> check_if_last_char_is_a_letter(\"apple pie\")\n// false\n// >>> check_if_last_char_is_a_letter(\"apple pi e\")\n// true\n// >>> check_if_last_char_is_a_letter(\"apple pi e \")\n// false\n// >>> check_if_last_char_is_a_letter(\"\")\n// false\nfunc check_if_last_char_is_a_letter(txt string) bool {\n" | |
B = "package check_if_last_char_is_a_letter_test\n\nimport (\n \"testing\"\n \"fmt\"\n)\n\n// Create a function that returns true if the last character\n// of a given string is an alphabetical character and is not\n// a part of a word, and false otherwise.\n// Note: \"word\" is a group of characters separated by space.\n// Examples:\n// >>> check_if_last_char_is_a_letter(\"apple pie\")\n// false\n// >>> check_if_last_char_is_a_letter(\"apple pi e\")\n// true\n// >>> check_if_last_char_is_a_letter(\"apple pi e \")\n// false\n// >>> check_if_last_char_is_a_letter(\"\")\n// false\nfunc check_if_last_char_is_a_letter(txt string) bool {\n // Remove trailing spaces from the string\n txt = strings.TrimRight(txt, \" \")\n \n // Check if the string is empty\n if len(txt) == 0 {\n return false\n }\n \n // Get the last character of the string\n lastChar := txt[len(txt)-1]\n \n // Check if the last character is an alphabetical character\n if !unicode.IsLetter(rune(lastChar)) {\n return false\n }\n \n // Check if the last character is not part of a word\n if strings.Contains(txt[:len(txt)-1], \" \") {\n return true\n }\n \n return false\n}\n\nfunc TestCheckIfLastCharIsALetter(t *testing.T) {\n tests := []struct {\n input string\n want bool\n }{\n {\"apple pie\", false},\n {\"apple pi e\", true},\n {\"apple pi e \", false},\n {\"\", false},\n {\"hello world\", false},\n {\"hello world \", false},\n {\"hello world \", true},\n }\n \n for _, tt := range tests {\n got := check_if_last_char_is_a_letter(tt.input)\n if got != tt.want {\n t.Errorf(\"check_if_last_char_is_a_letter(%q) = %v, want %v\", tt.input, got, tt.want)\n }\n }\n}\n" | |
print(remove_prefix_by_last_line(A, B)) |